## RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13D

These Solutions are part of RS Aggarwal Solutions Class 9. Here we have given RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13D.

**Other Exercises**

- RS Aggarwal Solutions Class 9 Chapter 13 Volume and Surface Area Ex 13A
- RS Aggarwal Solutions Class 9 Chapter 13 Volume and Surface Area Ex 13B
- RS Aggarwal Solutions Class 9 Chapter 13 Volume and Surface Area Ex 13C
- RS Aggarwal Solutions Class 9 Chapter 13 Volume and Surface Area Ex 13D

**Question 1.**

**Solution:**

(i) Radius of sphere = 3.5cm

(a) Volume = \(\frac { 4 }{ 3 } \) πr^{3}

**Question 2.**

**Solution:**

Let r be the radius of the sphere and volume = 38808 cm^{3}

∴\(\frac { 4 }{ 3 } \) πr^{3} = 38803

=> \(\frac { 4 }{ 3 } \) x \(\frac { 22 }{ 7 } \) r^{3} = 38803

**Question 3.**

**Solution:**

Let r be the radius of the sphere

∴ Volume = \(\frac { 4 }{ 3 } \) πr^{3}

**Question 4.**

**Solution:**

Surface area of a sphere = 394.24 m^{2}

Let r be the radius, then 4πr^{2} = 394.24

**Question 5.**

**Solution:**

Surface area of sphere = 576π cm^{2}

Let r be the radius, then 4r^{2} = 576π

**Question 6.**

**Solution:**

Outer diameter of shell = 12cm,

Outer radius (R) = \(\frac { 12 }{ 2 } \) = 6cm

and inner diameter = 8cm

**Question 7.**

**Solution:**

Length of cuboid of (l) = 12cm

Breadth (b) = 11cm

and height (h) = 9cm

**Question 8.**

**Solution:**

Radius of sphere (r) = 8cm

Volume = \(\frac { 4 }{ 3 } \)πr^{3}

**Question 9.**

**Solution:**

Radius of solid sphere (R) = 3cm.

Volume = \(\frac { 4 }{ 3 } \)π(R)^{3} = \(\frac { 4 }{ 3 } \)π(3)^{3} cm^{3}

**Question 10.**

**Solution:**

Radius of metallic sphere (R) = 10.5cm

**Question 11.**

**Solution:**

Diameter of a cylinder = 8cm

Radius (r) = \(\frac { 8 }{ 2 } \) = 4cm

**Question 12.**

**Solution:**

Diameter of sphere = 6cm

Radius (R) = \(\frac { 6 }{ 2 } \) = 3cm

**Question 13.**

**Solution:**

Diameter of sphere = 18cm

Radius (R) = \(\frac { 18 }{ 2 } \) = 9cm.

**Question 14.**

**Solution:**

Diameter of the sphere = 15.6 cm

Radius (R) = \(\frac { 15.6 }{ 2 } \) = 7.8 cm

**Question 15.**

**Solution:**

Diameter of the canonball = 28cm

Radius (R) = \(\frac { 28 }{ 2 } \) = 14 cm

**Question 16.**

**Solution:**

Given,

Radius of spherical big ball (R) = 3cm

**Question 17.**

**Solution:**

Ratio in the radii of two spheres = 1:2

Let radius of smaller sphere = r then,

radius of bigger sphere = 2r

**Question 18.**

**Solution:**

Let r1 and r2 be the radii of two spheres

**Question 19.**

**Solution:**

Radius of the cylindrical tub = 12cm.

First level of water = 20cm

Raised water level = 6.75cm.

**Question 20.**

**Solution:**

Radius of the ball (r) = 9cm.

Volume of ball = \(\frac { 4 }{ 3 } \)πr³

**Question 21.**

**Solution:**

Given,

Radius of hemisphere of lead (r) = 9cm.

**Question 22.**

**Solution:**

Given,

Radius of hemispherical bowl (r) = 9cm

**Question 23.**

**Solution:**

External radius of spherical shell (R) = 9cm

**Question 24.**

**Solution:**

Inner radius (r) = 4 cm

Thickness of steel used = 0.5

Hope given RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13D are helpful to complete your math homework.

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