RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13D

These Solutions are part of RS Aggarwal Solutions Class 9. Here we have given RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13D.

Other Exercises

Question 1.
Solution:
(i) Radius of sphere = 3.5cm
(a) Volume = $$\frac { 4 }{ 3 }$$ πr3  Question 2.
Solution:
Let r be the radius of the sphere and volume = 38808 cm3
∴$$\frac { 4 }{ 3 }$$ πr3 = 38803
=> $$\frac { 4 }{ 3 }$$ x $$\frac { 22 }{ 7 }$$ r3 = 38803 Question 3.
Solution:
Let r be the radius of the sphere
∴ Volume = $$\frac { 4 }{ 3 }$$ πr3 Question 4.
Solution:
Surface area of a sphere = 394.24 m2
Let r be the radius, then 4πr2 = 394.24 Question 5.
Solution:
Surface area of sphere = 576π cm2
Let r be the radius, then 4r2 = 576π Question 6.
Solution:
Outer diameter of shell = 12cm,
Outer radius (R) = $$\frac { 12 }{ 2 }$$ = 6cm
and inner diameter = 8cm  Question 7.
Solution:
Length of cuboid of (l) = 12cm
and height (h) = 9cm  Question 8.
Solution:
Radius of sphere (r) = 8cm
Volume = $$\frac { 4 }{ 3 }$$πr3  Question 9.
Solution:
Radius of solid sphere (R) = 3cm.
Volume = $$\frac { 4 }{ 3 }$$π(R)3 = $$\frac { 4 }{ 3 }$$π(3)3 cm3  Question 10.
Solution:
Radius of metallic sphere (R) = 10.5cm Question 11.
Solution:
Diameter of a cylinder = 8cm
Radius (r) = $$\frac { 8 }{ 2 }$$ = 4cm Question 12.
Solution:
Diameter of sphere = 6cm
Radius (R) = $$\frac { 6 }{ 2 }$$ = 3cm Question 13.
Solution:
Diameter of sphere = 18cm
Radius (R) = $$\frac { 18 }{ 2 }$$ = 9cm. Question 14.
Solution:
Diameter of the sphere = 15.6 cm
Radius (R) = $$\frac { 15.6 }{ 2 }$$ = 7.8 cm  Question 15.
Solution:
Diameter of the canonball = 28cm
Radius (R) = $$\frac { 28 }{ 2 }$$ = 14 cm  Question 16.
Solution:
Given,
Radius of spherical big ball (R) = 3cm  Question 17.
Solution:
Ratio in the radii of two spheres = 1:2
Let radius of smaller sphere = r then,
radius of bigger sphere = 2r Question 18.
Solution:
Let r1 and r2 be the radii of two spheres Question 19.
Solution:
Radius of the cylindrical tub = 12cm.
First level of water = 20cm
Raised water level = 6.75cm. Question 20.
Solution:
Radius of the ball (r) = 9cm.
Volume of ball = $$\frac { 4 }{ 3 }$$πr³ Question 21.
Solution:
Given,  Question 22.
Solution:
Given,
Radius of hemispherical bowl (r) = 9cm  Question 23.
Solution:
External radius of spherical shell (R) = 9cm  Question 24.
Solution:
Inner radius (r) = 4 cm
Thickness of steel used = 0.5 Hope given RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13D are helpful to complete your math homework.

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