RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6D

RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6D

These Solutions are part of RS Aggarwal Solutions Class 7. Here we have given RS Aggarwal Solutions Class 7 Chapter 6 Algebraic Expressions Ex 6D.

Other Exercises

Find each of the following products.
Question 1.
Solution:
(5x + 7) (3x + 4)
= 5x (3x + 4) + 7 (3x + 4)
= 5x x 3x + 5x x 4 + 7 x 3x + 7 x 4
= 15x2 + 20x + 21x + 28
= 15x2 + 41x + 28

Question 2.
Solution:
(4x – 3) (2x + 5)
= 4x (2x + 5) – 3 (2x + 5)
= 4x x 2x + 4x x 5 – 3 x 2x -3 x 5
= 8x2 + 20x – 6x – 15
= 8x2 + 14x – 15

Question 3.
Solution:
(x – 6) (4x + 9)
= x (4x + 9) – 6 (4x + 9)
= x x 4x + x x 9 – 6 x 4x – 6 x 9
= 4x2 + 9x – 24x – 54
= 4x2 – 15x – 54

Question 4.
Solution:
(5y – 1) (3y – 8)
= 5y x 3y – 5y x 8 – 1 x 3y – 8 x (-1)
= 15y2 – 40y – 3y + 8
= 15y2 – 43y + 8

Question 5.
Solution:
(7x + 2y) (x + 4y)
= 7x (x + 4y) + 2y (x + 4y)
= 7x x x + 7x x 4y + 2y x x + 2y x 4y
= 7x2 + 28xy + 2xy + 8y2
= 7x2 + 30xy + 8y2

Question 6.
Solution:
(9x + 5y) (4x + 3y)
= 9x (4x + 3y) + 5y (4x + 3y)
= 9x x 4x + 9x x 3y + 5y x 4x + 5y x 3y
= 36x2 + 27xy + 20xy + 15y2
= 36x2 + 47xy +15y2

Question 7.
Solution:
(3m – 4n) (2m – 3n)
= 3m (2m – 3n) – 4n (2m – 3n)
= 3m x 2m – 3m x 3n – 4n x 2m – 4n x (-3n)
= 6m2 – 9mn – 8mn + 12n2
= 6m2 – 17mn + 12n2

Question 8.
Solution:
(0.8x – 0.5y) (1.5x – 3y)
= 0.8x (1.5x – 3y) – 0.5y (1.5x – 3y)
= 0.8x x 1.5x – 0.8x x 3y – 0.5y x 1.5x – 0.5y x (-3y)
= 1.20x2 – 2.4xy – 0.75xy + 1.5y2
= 1.2x2 – 3.15xy + 1.5y2

Question 9.
Solution:
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6D 1
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6D 2

Question 10.
Solution:
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6D 3

Question 11.
Solution:
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6D 4
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6D 5

Question 12.
Solution:
(x2 – a2) (x – a)
= x2 (x – a) – a2 (x – a)
= x2 x x – x2 x a – a2 x x – a2 (-a)
= x3 – xa – xa2 + a3

Question 13.
Solution:
(3p2 + q2) (2p2 – 3q2)
= 3p2 (2p2 – 3q2) + q2 (2p2 – 3q2)
= 3p2 x 2p2 – 3p2 x 3q2 + q2 x 2p2 – q2 x 3q2
= 6q4 – 9p2q2 + 2p2q2 – 3q4
= 6p4 – 7p2q2 – 3q4

Question 14.
Solution:
(2x2 – 5y2) (x2 + 3y2)
= 2x2 (x2 + 3y2) – 5y2 (x2 + 3y2)
= 2x2 x x2 + 2x2 x 3y2 – 5y2 x x2 – 5y2 x 3y2
= 2x4 + 6xy2 – 5xy2 – 15y4
= 2y4 + xy2 – 15y4

Question 15.
Solution:
(x3 – y3) (x2 + y2)
= x3 (x2 + y2) – y3 (x2 + y2)
= x3 x x2 + x3 x y2 – y3 x x2 – y3 x y2
= x5 + xy2 – xy3 – y5

Question 16.
Solution:
(x4 + y4) (x2 – y2)
= x4 (x2 – y2) + y4 (x2 – y2)
= x4 x x2 – x4 x y2 + y4 x x2 – y4 x y2
= x6 – xy2 + xy4 – y6

Question 17.
Solution:
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6D 6

Question 18.
Solution:
(x2 – y2) (x + 2y)
= x2 (x + 2y) – y2 (x + 2y)
= x2 x x + x2 x 2y – y2 x x – y2 x 2y
= x3 + 2xy – xy2 – 2y3

Question 19.
Solution:
(2x + 3y – 5) (x + y)
= 2x (x + y) + 3y (x + y) – 5 (x + y)
= 2x x x + 2x x y + 3y x x + 3y x y – 5 x x – 5 x y
= 2x2 + 2xy + 3xy + 3y2 – 5x – 5y
= 2x2 + 5xy + 3y2 – 5x – 5y

Question 20.
Solution:
(3x + 2y – 4) (x – y)
= 3x (x – y) + 2y (x – y) – 4 (x – y)
= 3x x x – 3x x y + 2y x x – 2y x y – 4 x x – 4 x (-y)
= 3x2 – 3xy + 2xy – 2y2 – 4x + 4y
= 3x2 – xy – 2y2 – 4x + 4y

Question 21.
Solution:
(x2 – 3x + 7) (2x + 3)
= x2 (2x + 3) – 3x (2x + 3) + 7 (2x + 3)
= x2 x 2x + x2 x 3 – 3x x 2x – 3x x 3 + 7 x 2x + 7 x 3
= 2x3 + 3x2 – 6x2 – 9x + 14x + 21
= 2x3 – 3x2 + 5x + 21

Question 22.
Solution:
(3x2 + 5x – 9) (3x – 9)
= 3x2 (3x – 9) + 5x (3x – 9) – 9 (3x – 9)
= 3x2 x 3x – 3×2 x 9 + 5x x 3x + 5x x (-9) – 9 x 3x – 9 x (-9)
= 9x3 – 27x2 + 15x2 – 45x – 27x + 81
= 9x3 – 12x2 – 72x + 81

Question 23.
Solution:
(9x2 – x + 15) (x2 – 3)
= 9x2 (x2 – 3) – x (x2 – 3) + 15 (x2 – 3)
= 9x2 x x2 – 9x2 x 3 – x x x2 + x x 3 + 15 x x2 – 15 x 3
= 9x4 – 27x2 – x3 + 3x + 15x2 – 45
= 9x4 – x3 – 12x2 + 3x – 45

Question 24.
Solution:
(x2 + xy + y2) (x – y)
= x2 (x – y) + xy (x – y) + y2 (x – y)
= x2 x x – x2 x y + xy x x – xy x y + y2 x x – y2 x y
= x3 – x2y + x2y – xy2 + xy2 – y2
= x3 – y3

Question 25.
Solution:
(x2 – xy + y2) (x + y)
= x2 (x + y) – xy (x + y) + y2 (x + y)
= x3 + xy – xy – xy2 + xy2 + y3
= x3 + y3

Question 26.
Solution:
(x2 – 5x + 8) (x2 + 2)
= x2 (x2 + 2) – 5x (x2 + 2) + 8 (x2 + 2)
= x2 x x2 + x2 x 2 – 5x x x2 – 5x x 2 + 8 x x2 + 8 x 2
= x4 + 2x2 – 5x3 – 10x + 8x2 + 16
= x4 – 5x3 + 2x2 + 8x2 – 10x + 16
= x4 – 5x3 + 10x2 – 10x + 16

Simplify:
Question 27.
Solution:
(3x + 4) (2x – 3) + (5x – 4) (x + 2)
= [3x (2x – 3) + 4 (2x – 3)] + [5x (x + 2) – 4 (x + 2)]
= [3x x 2x – 3x x 3 + 4 x 2x – 4 x 3] + [5x x x + 5x x 2 – 4 x x – 4 x 2]
= [6x2 – 9x + 8x – 12] + [5x2 + 10x – 4x – 8]
= (6x2 – x – 12) + (5x2 + 6x – 8)
= 6x2 – x – 12 + 5x2 + 6x – 8
= 6x2 + 5x2 – x + 6x – 12 – 8
= 11x2 + 5x – 20

Question 28.
Solution:
(5x – 3) (x + 4) – (2x + 5) (3x – 4)
= [5x x x + 5x x 4 – 3 x x – 3 x 4] – [2x x 3x + 2x x (-4) + 5 x 3x + 5x (-4)]
= [5x2 + 20x – 3x – 12] – [6x2 – 8x + 15x – 20]
= (5x2 + 17x – 12) – (6x2 + 7x – 20)
= 5x2 + 17x – 12 – 6x2 – 7x + 20
= 5x2 – 6x2 + 17x – 7x – 12 + 20
= -x2 + 10x + 8

Question 29.
Solution:
(9x – 7) (2x – 5) – (3x – 8) (5x – 3)
= [9x (2x – 5) -7 (2x – 5)] – [3x (5x – 3) -8 (5x – 3)]
= [9x x 2x – 9x x 5 – 7 x 2x – 7 x (-5)] – [3x x 5x – 3x x 3 – 8 x 5x – 8 x (-3)]
= [18x2 – 45x – 14x + 35] – [15x2 – 9x – 40x + 24]
= 18x2 – 45x – 14x + 35 – 15x2 + 9x + 40x – 24
= 18x2 – 15x2 – 45x – 14x + 9x + 40x + 35 – 24
= 3x2 – 59x + 49x + 11
= 3x2 – 10x + 11

Question 30.
Solution:
(2x + 5y) (3x + 4y) – (7x + 3y) (2x + y)
= [2x (3x + 4y) + 5y (3x + 4y)] – [7x (2x + y) + 3y (2x + y)]
= [2x x 3x + 2x x 4y + 5y x 3x + 5y x 4y] – [7x x 2x + 7x x y + 3y x 2x + 3y x y]
= [6x2 + 8xy + 15xy + 20y2] – [14x2 + 7xy + 6xy + 3y2]
= [6x2 + 23xy + 20y2] – [14x2 + 13xy + 3y2]
= 6x2 + 23xy + 20y2 – 14x2 – 13xy – 3y2
= 6x2 – 14x2 + 23xy – 13xy + 20y2 – 3y2
= -8x2 + 10xy + 11y2

Question 31.
Solution:
(3x2 + 5x – 7) (x – 1) – (x2 – 2x + 3) (x + 4)
= [3x2 (x – 1) + 5x (x – 1) – 7 (x – 1)] – [x2 (x + 4) – 2x (x + 4) + 3 (x + 4)]
= [3x2 x x – 3x2 x 1 + 5x x x – 5x x (-1) – 7 x x -7 x (-1)] -[x2 x x + x2 x 4 – 2x x x – 2x x 4 + 3 x x + 3 x 4]
= [3x3 – 3x2 + 5x2 – 5x – 7x + 7] – [x3 + 4x2 – 2x2 – 8x + 3x + 12]
= [3x3 + 2x2 – 12x + 7] – [x3 + 2x2 – 5x + 12]
= 3x3 + 2x2 – 12x + 7 – x3 – 2x2 + 5x – 12
= 3x3 – x3 + 2x2 – 2x2 – 12x + 5x – 12 + 7
= 2x3 – 7x – 5

Hope given RS Aggarwal Solutions Class 7 Chapter 6 Algebraic Expressions Ex 6D are helpful to complete your math homework.

If you have any doubts, please comment below. Learn Insta try to provide online math tutoring for you.

RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4F

RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4F

These Solutions are part of RS Aggarwal Solutions Class 7. Here we have given RS Aggarwal Solutions Class 7 Chapter 4 Rational Numbers Ex 4F.

Other Exercises

Question 1.
Solution:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4F 1
(vii) Reciprocal of -1 = -1
(viii) Reciprocal of 0 does not exist.

Question 2.
Solution:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4F 2
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4F 3
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4F 4

Question 3.
Solution:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4F 5
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4F 6
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4F 7

Question 4.
Solution:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4F 8

Question 5.
Solution:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4F 9
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4F 10

Question 6.
Solution:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4F 11

Question 7.
Solution:
Product of two number = 10
One number = -8
Second number = 10 ÷ (-8)
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4F 12

Question 8.
Solution:
Product of two rational numbers = – 9
One number = -12
Second number = (-9) ÷ (-12)
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4F 13

Question 9.
Solution:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4F 14

Question 10.
Solution:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4F 15
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4F 16

Question 11.
Solution:
Cloth required for 24 pairs of trousers =54 m
Cloth required for one pair = (54 ÷ 24) m
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4F 17

Question 12.
Solution:
Total length of rape = 30 m
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4F 18

Question 13.
Solution:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4F 19

Hope given RS Aggarwal Solutions Class 7 Chapter 4 Rational Numbers Ex 4F are helpful to complete your math homework.

If you have any doubts, please comment below. Learn Insta try to provide online math tutoring for you.

RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4E

RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4E

These Solutions are part of RS Aggarwal Solutions Class 7. Here we have given RS Aggarwal Solutions Class 7 Chapter 4 Rational Numbers Ex 4E.

Other Exercises

Question 1.
Solution:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4E 1
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4E 2
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4E 3

Question 2.
Solution:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4E 4
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4E 5
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4E 6

Question 3.
Solution:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4E 7
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4E 8

Question 4.
Solution:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4E 9
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4E 10
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4E 11

Question 5.
Solution:
Cost of 1 metre of cloth
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4E 12

Question 6.
Solution:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4E 13

Hope given RS Aggarwal Solutions Class 7 Chapter 4 Rational Numbers Ex 4E are helpful to complete your math homework.

If you have any doubts, please comment below. Learn Insta try to provide online math tutoring for you.

RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6C

RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6C

These Solutions are part of RS Aggarwal Solutions Class 7. Here we have given RS Aggarwal Solutions Class 7 Chapter 6 Algebraic Expressions Ex 6C.

Other Exercises

Find each of the following products:
Question 1.
Solution:
4a(3a + 7b) = 4a x 3a + 4a x 7b = 12a2 + 28ab

Question 2.
Solution:
5a(6a – 3b) = 5a x 6a – 5a x 3b = 30a2 – 15ab

Question 3.
Solution:
8a(2a + 5b) = 8a2 x 2a + 8a2 x 5b = 16a3 + 40a2b

Question 4.
Solution:
9x2 (5x + 7) = 9x2 x 5x + 9x2 x 7 = 45x3 + 63x2

Question 5.
Solution:
ab(a2 – b2) = ab x a2 – ab x b2 = a3b – ab3

Question 6.
Solution:
2x2 (3x – 4x2) = 2x2 x 3x – 2x2 x 4x2 = 6x3 – 8x4

Question 7.
Solution:
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6C 1

Question 8.
Solution:
-1 7x2 (3x – 4) = -17x2 x 3x – 17x2 x (-4) = -51x3 + 68x2

Question 9.
Solution:
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6C 2

Question 10.
Solution:
-4x2y (3x2 – 5y)
= -4xy x 3x2 – 4xy x (-5y)
= -12xy + 20xy2

Question 11.
Solution:
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6C 3

Question 12.
Solution:
9t2 (t + 7t3) = 9t2 x t + 9t2 x 7t3 = 9t3 + 63t5

Question 13.
Solution:
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6C 4

Question 14.
Solution:
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6C 5

Question 15.
Solution:
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6C 6

Question 16.
Solution:
24x2 (1 – 2x)
= 24x2 x 1 – 24x2 x 2x
= 24x2 – 48x3
If x = 2, then
24x2 – 48x3
= 24(2)2 – 48(2)3
= 24 x 4 – 48 x 8
= 96 – 384
= -288

Question 17.
Solution:
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6C 7

Question 18.
Solution:
s (s2 – st) = s x s2 – s x st = s3 – s2t
If s = 2, t = 3, then
s3 – s2t = (2)3 – (2)2 x 3 = 8 – 4 x 3 = 8 – 12 = -4

Question 19.
Solution:
-3y (xy + y2) = -3y x xy + (-3y) x y2 = -3xy2 – 3y3
if x = 4, y = 5, then
-3xy2 – 3y3
= -3(4)(5)2 – 3(5)3 = -3 x 4 x 25 – 3 x 125 = -300 – 375 = -675

Simplify each of the following:
Question 20.
Solution:
a(b – c) + b(c – a) + c(a – b) = ab – ac + bc – ab + ac – bc = 0

Question 21.
Solution:
a(b – c) – b(c – a) – c(a – b) = ab – ac – bc + ab – ac + bc = 2ab – 2ac

Question 22.
Solution:
3x2 + 2(x + 2) – 3x (2x + 1)
= 3x2 + 2x + 4 – 6x2 – 3x = 3x2 – 6x2 + 2x – 3x + 4 = -3x2 – x + 4

Question 23.
Solution:
x (x + 4) + 3x (2x2 – 1) + 4x2 + 4
= x2 + 4x + 6x3 – 3x + 4x2 + 4
= 6x3 + x2 + 4x2 + 4x – 3x + 4
= 6x3 + 5x2 + x + 4

Question 24.
Solution:
2x2 + 3x (1 – 2x3) + x (x + 1)
= 2x2 + 3x – 6x4 + x2 + x
= – 6x4 + 2x2 + x2 + 3x + x
= – 6x4 + 3x2 + 4x

Question 25.
Solution:
a2b (a – b2) + ab(4ab – 2a2) – a3b (1 – 2b)
= a3b – a2b3 – 2a3b2 + 4a2b3 – 2a3b2 – a3b + 2a3b2
= a3b – a3b + 2a3b2 – a2b3 + 4a263
= 3a2b3

Question 26.
Solution:
4st (s – t) – 6s2 (t – t2) – 3t2 (2s2 – s) + 2st(s – t)
= 4s2t – 4st2 – 6s2t + 6s2t2 – 6s2t2 + 3st2 + 2s2t – 2st2
= 4s2t – 6s2t + 2s2t – 4st2 + 3st2 – 2st2 + 6s2t2 – 6s2t2
= 6s2t – 6s2t – 6st2 + 3st2 + 6s2t2 – 6s2t2
= – 3st2

Hope given RS Aggarwal Solutions Class 7 Chapter 6 Algebraic Expressions Ex 6C are helpful to complete your math homework.

If you have any doubts, please comment below. Learn Insta try to provide online math tutoring for you.

RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6B

RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6B

These Solutions are part of RS Aggarwal Solutions Class 7. Here we have given RS Aggarwal Solutions Class 7 Chapter 6 Algebraic Expressions Ex 6B.

Other Exercises

Find the products:
Question 1.
Solution:
3 x 8 a2+4 = 24a6

Question 2.
Solution:
(-6x3) x (5x2) = -6 x 5x2+3 = -30x5

Question 3.
Solution:
(-4ab) x (-3a2bc)
= (-4) x (-3) a. a2.b. b. c
= 12.a2+1. b1+1.c
= 12a3b2c

Question 4.
Solution:
= (2a2b3) x (-3a3b)
= 2 x (-3) a2. a3. b3. b. b
= -6a2+3.b3+1
= -6a5.b4

Question 5.
Solution:
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6B 1

Question 6.
Solution:
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6B 2

Question 7.
Solution:
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6B 3

Question 8.
Solution:
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6B 4

Question 9.
Solution:
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6B 5

Question 10.
Solution:
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6B 6

Question 11.
Solution:
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6B 7
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6B 8

Question 12.
Solution:
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6B 9

Question 13.
Solution:
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6B 10

Question 14.
Solution:
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6B 11

Question 15.
Solution:
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6B 12
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6B 13

Question 16.
Solution:
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6B 14

Question 17.
Solution:
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6B 15

Question 18.
Solution:
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6B 16
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6B 17

Question 19.
Solution:
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6B 18
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6B 19

Question 20.
Solution:
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6B 20

Question 21.
Solution:
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6B 21
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6B 22

Find the products given below and in each case verify the result for a = 1, b = 2 and c = 3 :
Question 22.
Solution:
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6B 23

Question 23.
Solution:
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6B 24
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6B 25
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6B 26

Question 24.
Solution:
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6B 27
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6B 28

Question 25.
Solution:
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6B 29
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6B 30

Hope given RS Aggarwal Solutions Class 7 Chapter 6 Algebraic Expressions Ex 6B are helpful to complete your math homework.

If you have any doubts, please comment below. Learn Insta try to provide online math tutoring for you.

RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6A

RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6A

These Solutions are part of RS Aggarwal Solutions Class 7. Here we have given RS Aggarwal Solutions Class 7 Chapter 6 Algebraic Expressions Ex 6A.

Other Exercises

Question 1.
Solution:
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6A 1
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6A 2
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6A 3
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6A 4
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6A 5
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6A 6

Question 2.
Solution:
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6A 7

Question 3.
Solution:
Sum of (a + 3b – 4c), (4a – b + 9c) and (-2b + 3c – a)
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6A 8
Now subtract (2a – 3b + 4c) from 4a + 8c
= 4a + 8c – (2a – 3b + 4c)
= 4a + 8c – 2a + 3b – 4c
= 4a – 2a + 3b + 8c – 4c
= 2a + 3b + 4c

Question 4.
Solution:
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6A 9

Question 5.
Solution:
Sum of (8a – 6a² + 9) and (-10a – 8 + 8a²)
= 8a – 6a² + 9 + (-10a) – 8 + 8a²
= 8a – 10a – 6a² + 8a² + 9 – 8
= -2a + 2a² + 1
Now -3 – (-2a + 2a² + 1)
= (-3 + 2a – 2a² – 1)
= -4 + 2a – 2a²

Question 6.
Solution:
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6A 10
RS Aggarwal Class 7 Solutions Chapter 6 Algebraic Expressions Ex 6A 11

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RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4B

RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4B

These Solutions are part of RS Aggarwal Solutions Class 7. Here we have given RS Aggarwal Solutions Class 7 Chapter 4 Rational Numbers Ex 4B.

Other Exercises

Question 1.
Solution:
(i) Draw a number line and locate a point O on it. Let it represent 0 Now \(\frac { 1 }{ 3 }\) has been presented on the number line given below.
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4B 1
(ii) Draw a number line and locate a point O on it. Let it represent 0. The number \(\frac { 2 }{ 7 }\) has been represented on the number line given below:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4B 2
(iii) Draw a number line and locate a point O on it. Let it represent 0. The number \(\frac { 7 }{ 3 }\) has been represented on the number line given below:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4B 3
(iv) Draw a number line and locate a point O on it. Let it represent 0. The number \(\frac { 7 }{ 3 }\) has been represented on it as given below:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4B 4
(v) Draw a number line and locate a point O on it. Let it represented 0. The number \(\frac { 37 }{ 8 }\) has been represented on it as given below:
\(\frac { 37 }{ 8 }\) = 4\(\frac { 5 }{ 8 }\)
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4B 5
(vi) Draw a number line and locate a point O on it. Let it represent 0. The number \(\frac { -1 }{ 3 }\) has been represented on it as given below:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4B 6
(vii) Draw a number line and locate a point O on it. Let it represent 0. The number \(\frac { -3 }{ 4 }\) has been represented on it is as given below:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4B 7
(viii) Draw a number line and locate a point on it. Let it represent 0. The number \(\frac { -12 }{ 7 }\) has been represented on it as given below:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4B 8
(ix) Draw a number line and locate a point O on it. Let it represent 0. The number \(\frac { 36 }{ -5 }\) has been represented on it as given below:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4B 9
(x) Draw a number line and locate is point O on it. Let is represent 0. The number \(\frac { -43 }{ 9 }\) has been represented on it as given below:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4B 10

Question 2.
Solution:
(i) \(\frac { 5 }{ 6 }\) or 0, \(\frac { 5 }{ 6 }\) is greater as any positive number is always greater than 0.
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4B 11

Question 3.
Solution:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4B 12
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4B 13
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4B 14
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4B 15
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4B 16
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4B 17

Question 4.
Solution:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4B 18
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4B 19
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4B 20
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4B 21
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4B 22

Question 5.
Solution:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4B 23
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4B 24
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4B 25
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4B 26
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4B 27
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4B 28
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4B 29

Question 6.
Solution:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4B 30
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4B 31
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4B 32
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4B 33
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4B 34
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4B 35
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4B 36
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4B 37

Question 7.
Solution:
(i) True: All negative numbers lie on the left of 0.
(ii) False: All negative numbers lie on the left of 0.
(iii) True: All positive numbers lie on the right of 0 and all negative numbers on the left of 0.
(iv) False: \(\frac { -18 }{ -13 }\) = \(\frac { 18 }{ 13 }\) which is positive and positive number lie on the left of 0.
(v) True: \(\frac { -5 }{ -8 }\) = \(\frac { 5 }{ 8 }\) which is positive and all positive number lie on the right of negative numbers.
(i), (iii) and (iv) are true.

Question 8.
Solution:
5 rational numbers between -3 and -2.
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4B 38

Question 9.
Solution:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4B 39
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4B 40

Question 10.
Solution:
L.C.M. of 5 and 2 = 10
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4B 41

Hope given RS Aggarwal Solutions Class 7 Chapter 4 Rational Numbers Ex 4B are helpful to complete your math homework.

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RS Aggarwal Class 7 Solutions Chapter 3 Decimals Ex 3D

RS Aggarwal Class 7 Solutions Chapter 3 Decimals Ex 3D

These Solutions are part of RS Aggarwal Solutions Class 7. Here we have given RS Aggarwal Solutions Class 7 Chapter 3 Decimals Ex 3D.

Other Exercises

Question 1.
Solution:
We know that a decimal divided by 10, the decimal point is shifted to the left by one place. Therefore
(i) 131.6 ÷ 10 = 13.16
(ii) 32.56 ÷ 10 = 3.256
(iii) 4.38 ÷ 10 = 0.438
(iv) 0.34 ÷ 10 = 0.034
(v) 0.08 ÷ 10 = 0.008
(vi) 0.062 ÷ 10 = 0.0062

Question 2.
Solution:
We know that decimal divided by 100, the decimal point is shifted to the left by two place. Therefore
(i) 137.2 ÷ 100 = 1.372
(ii) 23.4 ÷ 100= 0.234
(iii) 4.1 ÷ 100 = 0.047
(iv) 0.3 ÷ 100 = 0.003
(v) 0.58 ÷ 100 = 0.0058
(vi) 0.02 ÷ 100 = 0.0002

Question 3.
Solution:
We know that a decimal divided by 1000, the decimal point is shifted to the left by three places. Therefore:
(i) 1286.5 ÷ 1000= 1.2865
(ii) 354.16 ÷ 1000 = 0.35416
(iii) 38.9 ÷ 1000 = 0.0389
(iv) 4.6 ÷ 1000 = 0.0046
(v) 0.8 ÷ 1000 = 0.0008
(vi) 2 ÷ 1000 = 0.002

Question 4.
Solution:
RS Aggarwal Class 7 Solutions Chapter 3 Decimals Ex 3D 1
RS Aggarwal Class 7 Solutions Chapter 3 Decimals Ex 3D 2
RS Aggarwal Class 7 Solutions Chapter 3 Decimals Ex 3D 3
RS Aggarwal Class 7 Solutions Chapter 3 Decimals Ex 3D 4

Question 5.
Solution:
RS Aggarwal Class 7 Solutions Chapter 3 Decimals Ex 3D 5
RS Aggarwal Class 7 Solutions Chapter 3 Decimals Ex 3D 6
RS Aggarwal Class 7 Solutions Chapter 3 Decimals Ex 3D 7
RS Aggarwal Class 7 Solutions Chapter 3 Decimals Ex 3D 8
RS Aggarwal Class 7 Solutions Chapter 3 Decimals Ex 3D 9
RS Aggarwal Class 7 Solutions Chapter 3 Decimals Ex 3D 10
RS Aggarwal Class 7 Solutions Chapter 3 Decimals Ex 3D 11

Question 6.
Solution:
RS Aggarwal Class 7 Solutions Chapter 3 Decimals Ex 3D 12
RS Aggarwal Class 7 Solutions Chapter 3 Decimals Ex 3D 13
RS Aggarwal Class 7 Solutions Chapter 3 Decimals Ex 3D 14
RS Aggarwal Class 7 Solutions Chapter 3 Decimals Ex 3D 15

Question 7.
Solution:
RS Aggarwal Class 7 Solutions Chapter 3 Decimals Ex 3D 16
RS Aggarwal Class 7 Solutions Chapter 3 Decimals Ex 3D 17
RS Aggarwal Class 7 Solutions Chapter 3 Decimals Ex 3D 18
RS Aggarwal Class 7 Solutions Chapter 3 Decimals Ex 3D 19
RS Aggarwal Class 7 Solutions Chapter 3 Decimals Ex 3D 20
RS Aggarwal Class 7 Solutions Chapter 3 Decimals Ex 3D 21
RS Aggarwal Class 7 Solutions Chapter 3 Decimals Ex 3D 22
RS Aggarwal Class 7 Solutions Chapter 3 Decimals Ex 3D 23
RS Aggarwal Class 7 Solutions Chapter 3 Decimals Ex 3D 24

Question 8.
Solution:
Cost of 24 chairs = Rs. 9255.60
Cost of one chair = Rs. \(\frac { 9255.60 }{ 24 }\) = Rs. 385.65

Question 9.
Solution:
Length of cloth for one shirt = 1.8 m
Total length of piece of cloth = 45 m
Number of shirts will be = 45 ÷ 1.8
RS Aggarwal Class 7 Solutions Chapter 3 Decimals Ex 3D 25

Question 10.
Solution:
A car covers in 2.4 litre = 22.8 km
It will cover in 1 litre = \(\frac { 22.8 }{ 2.4 }\) km = 9.5 km

Question 11.
Solution:
Oil in one tin = 16.5 l
Total oil = 478.5 l
RS Aggarwal Class 7 Solutions Chapter 3 Decimals Ex 3D 26

Question 12.
Solution:
Weight of 37 bags of sugar=3644.5 kg
Weight of one bag of sugar = 3644.5 ÷ 37
RS Aggarwal Class 7 Solutions Chapter 3 Decimals Ex 3D 27

Question 13.
Solution:
Capacity of 69 buckets = 586.5 litres
Capacity of 1 bucket = 586.5 ÷ 69
RS Aggarwal Class 7 Solutions Chapter 3 Decimals Ex 3D 28

Question 14.
Solution:
Number of pieces in 1.15 m = 1
RS Aggarwal Class 7 Solutions Chapter 3 Decimals Ex 3D 29

Question 15.
Solution:
Total weight of cement = 1792.8 kg
Cement in one bag = 49.8 kg
Number of bags = 1792.8 ÷ 49.8
RS Aggarwal Class 7 Solutions Chapter 3 Decimals Ex 3D 30
RS Aggarwal Class 7 Solutions Chapter 3 Decimals Ex 3D 31

Question 16.
Solution:
Total thickness = 1.89 m = 189 cm
Thickness of one piece = 0.3 5 cm
Number of pieces = 189 ÷ 0.35
RS Aggarwal Class 7 Solutions Chapter 3 Decimals Ex 3D 32

Question 17.
Solution:
Product of two decimals = 261.36
One decimal = 17.6
Second decimal = 261.36 ÷ 17.6
RS Aggarwal Class 7 Solutions Chapter 3 Decimals Ex 3D 33

Hope given RS Aggarwal Solutions Class 7 Chapter 3 Decimals Ex 3D are helpful to complete your math homework.

If you have any doubts, please comment below. Learn Insta try to provide online math tutoring for you.

RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4A

RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4A

These Solutions are part of RS Aggarwal Solutions Class 7. Here we have given RS Aggarwal Solutions Class 7 Chapter 4 Rational Numbers Ex 4A.

Other Exercises

Question 1.
Solution:
(i) Rational numbers: The numbers of the form \(\frac { p }{ q }\) where p and q are integers and q ≠ 0, are called rational numbers.
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4A 1
(iv) Yes, there is one rational number (0) which is neither positive nor negative.

Question 2.
Solution:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4A 2
(viii) \(\frac { 0 }{ 1 }\) are all rational number but \(\frac { 1 }{ 0 }\) and \(\frac { 0 }{ 0 }\) are not rational number as their denominator is zero.

Question 3.
Solution:
(i) Numerator = 8, denominator =19
(ii) Numerator = 5, denominator = – 8
(iii) Numerator =-13, denominator =15
(iv) Numerator = – 8, denominator = -11
(v) Numerator = 9, denominator = 1

Question 4.
Solution:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4A 3

Question 5.
Solution:
According to the definition, a rational number is positive if both of numerator and denominator have same signs. Therefore
(iii), (iv) and (vi) 8 are positive rational numbers.

Question 6.
Solution:
According to the definition, a rational number is negative if numerator and denominator have opposite sign. Therefore.
(iii), (iv), (v), (vi) are all negative rational numbers.

Question 7.
Solution:
Equivalent rational numbers of each are given below:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4A 4

Question 8.
Solution:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4A 5

Question 9.
Solution:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4A 6

Question 10.
Solution:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4A 7

Question 11.
Solution:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4A 8

Question 12.
Solution:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4A 9

Question 13.
Solution:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4A 10

Question 14.
Solution:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4A 11
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4A 12

Question 15.
Solution:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4A 13

Question 16.
Solution:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4A 14

Question 17.
Solution:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4A 15
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4A 16
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4A 17

Question 18.
Solution:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4A 18
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4A 19

Question 19.
Solution:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4A 20
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4A 21
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4A 22

Question 20.
Solution:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4A 23
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4A 24

Question 21.
Solution:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4A 25

Question 22.
Solution:
(i) False, as there is no end of smallest and largest rational number,
(ii) True.
(iii) False, as zero is a rational number but the division of zero is meaningless.
(iv) True.
(v) False, every rational is not a fraction
In a fraction, numerator and denominators is a whole number but the denominator can’t be zero

 

Hope given RS Aggarwal Solutions Class 7 Chapter 4 Rational Numbers Ex 4A are helpful to complete your math homework.

If you have any doubts, please comment below. Learn Insta try to provide online math tutoring for you.

RS Aggarwal Class 7 Solutions Chapter 2 Fractions Ex 2A

RS Aggarwal Class 7 Solutions Chapter 2 Fractions Ex 2A

These Solutions are part of RS Aggarwal Solutions Class 7. Here we have given RS Aggarwal Solutions Class 7 Chapter 2 Fractions Ex 2A.

Other Exercises

Question 1.
Solution:
RS Aggarwal Class 7 Solutions Chapter 2 Fractions Ex 2A 1
RS Aggarwal Class 7 Solutions Chapter 2 Fractions Ex 2A 2

Question 2.
Solution:
RS Aggarwal Class 7 Solutions Chapter 2 Fractions Ex 2A 3
RS Aggarwal Class 7 Solutions Chapter 2 Fractions Ex 2A 4
RS Aggarwal Class 7 Solutions Chapter 2 Fractions Ex 2A 5

Question 3.
Solution:
RS Aggarwal Class 7 Solutions Chapter 2 Fractions Ex 2A 6
RS Aggarwal Class 7 Solutions Chapter 2 Fractions Ex 2A 7
RS Aggarwal Class 7 Solutions Chapter 2 Fractions Ex 2A 8

Question 4.
Solution:
Reenu get \(\frac { 2 }{ 7 }\) of an apple while Sonal gets \(\frac { 4 }{ 5 }\) part of it
RS Aggarwal Class 7 Solutions Chapter 2 Fractions Ex 2A 9

Question 5.
Solution:
RS Aggarwal Class 7 Solutions Chapter 2 Fractions Ex 2A 10
RS Aggarwal Class 7 Solutions Chapter 2 Fractions Ex 2A 11
RS Aggarwal Class 7 Solutions Chapter 2 Fractions Ex 2A 12
RS Aggarwal Class 7 Solutions Chapter 2 Fractions Ex 2A 13
RS Aggarwal Class 7 Solutions Chapter 2 Fractions Ex 2A 14

Question 6.
Solution:
RS Aggarwal Class 7 Solutions Chapter 2 Fractions Ex 2A 15
RS Aggarwal Class 7 Solutions Chapter 2 Fractions Ex 2A 16
RS Aggarwal Class 7 Solutions Chapter 2 Fractions Ex 2A 17
RS Aggarwal Class 7 Solutions Chapter 2 Fractions Ex 2A 18

Question 7.
Solution:
RS Aggarwal Class 7 Solutions Chapter 2 Fractions Ex 2A 19
RS Aggarwal Class 7 Solutions Chapter 2 Fractions Ex 2A 20
RS Aggarwal Class 7 Solutions Chapter 2 Fractions Ex 2A 21
RS Aggarwal Class 7 Solutions Chapter 2 Fractions Ex 2A 22

Question 8.
Solution:
RS Aggarwal Class 7 Solutions Chapter 2 Fractions Ex 2A 23

Question 9.
Solution:
RS Aggarwal Class 7 Solutions Chapter 2 Fractions Ex 2A 24

Question 10.
Solution:
RS Aggarwal Class 7 Solutions Chapter 2 Fractions Ex 2A 25

Question 11.
Solution:
For finding the required fraction, we have to subtract 7\(\frac { 3 }{ 5 }\) from 18
RS Aggarwal Class 7 Solutions Chapter 2 Fractions Ex 2A 26

Question 12.
Solution:
For finding the required fraction we should subtract 7\(\frac { 4 }{ 15 }\) from 8\(\frac { 2 }{ 5 }\)
RS Aggarwal Class 7 Solutions Chapter 2 Fractions Ex 2A 27

Question 13.
Solution:
RS Aggarwal Class 7 Solutions Chapter 2 Fractions Ex 2A 28

Question 14.
Solution:
RS Aggarwal Class 7 Solutions Chapter 2 Fractions Ex 2A 29

Question 15.
Solution:
RS Aggarwal Class 7 Solutions Chapter 2 Fractions Ex 2A 30

Question 16.
Solution:
RS Aggarwal Class 7 Solutions Chapter 2 Fractions Ex 2A 31
RS Aggarwal Class 7 Solutions Chapter 2 Fractions Ex 2A 32

Hope given RS Aggarwal Solutions Class 7 Chapter 2 Fractions Ex 2A are helpful to complete your math homework.

If you have any doubts, please comment below. Learn Insta try to provide online math tutoring for you.

RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4C

RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4C

These Solutions are part of RS Aggarwal Solutions Class 7. Here we have given RS Aggarwal Solutions Class 7 Chapter 4 Rational Numbers Ex 4C.

Other Exercises

Question 1.
Solution:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4C 1
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4C 2
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4C 3

Question 2.
Solution:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4C 4
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4C 5
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4C 6
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4C 7
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4C 8
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4C 9

Question 3.
Solution:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4C 10
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4C 11
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4C 12
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4C 13
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4C 14
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4C 15
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4C 16

Question 4.
Solution:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4C 17
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4C 18
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4C 19
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4C 20
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4C 21
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4C 22
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4C 23

Question 5.
Solution:
RS Aggarwal Class 7 Solutions Chapter 4 Rational Numbers Ex 4C 24

Hope given RS Aggarwal Solutions Class 7 Chapter 4 Rational Numbers Ex 4C are helpful to complete your math homework.

If you have any doubts, please comment below. Learn Insta try to provide online math tutoring for you.