Prasanna – Page 349

CBSE Sample Papers for Class 10 Sanskrit Term 2 Set 1 with Solutions

February 17, 2022

Students can access the CBSE Sample Papers for Class 10 Sanskrit with Solutions and marking scheme Term 2 Set 1 will help students in understanding the difficulty level of the exam.

CBSE Sample Papers for Class 10 Sanskrit Term 2 Set 1 with Solutions

समयः : होरात्रयम्
सम्पूर्णाङ्काः : 40

प्रश्नपत्रस्वरूपम :

कृपया सम्यक्तया परीक्षणं कुर्वन्तु यत् अस्मिन् प्रश्नपत्रे 9 प्रश्नाः सन्ति।
अस्य प्रश्नपत्रस्य पठनाय 20 निमेषाः निर्धारिताः सन्ति। अस्मिन् अवधौ केवलं प्रश्नपत्रं पठनीयम् उत्तरपुस्तिकायां च किमपि न लेखनीयम्।
उत्तरलेखनात् पूर्व प्रश्नस्य क्रमाङ्कः अवश्यं लेखनीयः।
प्रश्नसङ्ख्या प्रश्नपत्रानुसारम् एवं लेखनीया।
सर्वेषां प्रश्नानाम् उत्तराणि संस्कृतेन लेखनीयानि।
प्रश्नानां निर्देशाः ध्यानेन अवश्यं पठनीयाः।

(वर्णनात्मकाः प्रश्नाः)
अपठित-अवबोधनम् (40 अङ्काः)

प्रश्न 1.
अधोलिखितं गद्यांशं पठित्वा प्रदत्तप्रश्नानाम् उत्तराणि संस्कृतेन लिखत (10)
(निम्नलिखित गद्यांश को पढ़कर दिए गए प्रश्नों के उत्तर संस्कृत में लिखिए।)
भारतीय संस्कृतिः संसारे श्रेष्ठा संस्कृतिः इति वयं कथयामः। तत्किमर्थम् ? भारतीयैः मानवजीवनस्य उन्नत्यै साङ्गीणः विचारः कृतः अस्ति। तत्र किं नाम संस्कृतिः? प्रत्येकस्य मानवस्य, समाजस्य, देशस्य वा सा स्वाभाविकी प्रवृत्तिः भवति तदैव तस्य प्रकृतिः कथ्यते प्रकृत्याः उन्नत्यै यः प्रयासः क्रियते, तदेव संस्कृतिः उच्यते। सदाचरणम्, त्यागभावना, परोपकारम्, विश्व बन्धुत्वभावना, धर्म-समन्वय चादयः अस्माकं संस्कृतेः उच्चादर्शाः सन्ति। अतः सुष्ठु जीवन पद्धत्या सुष्ठुचिन्तने, परस्परम् ऐक्य भावेन च अस्माकं संस्कृतिः अद्यापि सततं विकासमाना दृश्यते। धन्येयं संस्कृतिः या सर्वेभ्यः प्रेरणाप्रदा वर्तते।।

(अ) एकपदेन उत्तरत। (केवलं प्रश्न-द्वयम्) (1 × 2 = 2)
(एक शब्द में उत्तर लिखिए) (केवल दो प्रश्न)
(i) मानवजीवनस्य उन्नत्यै कैः विचारः कृत?
उत्तरः
भारतीयैः।

(ii) सर्वेभ्यः प्रेरणाप्रदा का वर्तते?
उत्तरः
संस्कृतिः।

(iii) सततं विकासमाना का?
उत्तरः
भारतीया संस्कृतिः।

(आ) पूर्णवाक्येन उत्तरत। (केवलं प्रश्न-द्वयम्) (2 × 2 = 4)
(पूर्णवाक्य में उत्तर लिखिए) (केवल दो प्रश्न)
(i) अस्माकं संस्कृतेः उच्चादर्शाः केः सन्ति?
उत्तरः
अस्माकं सस्कृतेः सदाचरणम्, त्यागभावना उच्चादर्शाः सन्ति।

(ii) अस्माकं संस्कृतिः कथं सतत् विकासमाना दृश्यते?
उत्तरः
सुष्ठु जीवन पद्धत्या सुष्ठुचिन्तने, परस्परम्, ऐक्य भावेन च अस्माकं संस्कृतिः अद्यापि सततं विकासमाना दृश्यते।

(iii) वयं किम् कथयामः?
उत्तरः
भारतीयः संस्कृतिः संसारे श्रेष्ठाः संस्कृतिः इति वयं कथयामः।

(इ) अस्य अनुच्छेदस्य कृते उपयुक्तं शीर्षकं संस्कृतेन लिखत। (द्वित्रिशष्दात्मक-वाक्यम्) (1)
(इस अनुच्छेद के लिए उपयुक्त शीर्षक संस्कृत में लिखिए।) (दो-तीन शब्द का वाक्य)
उत्तरः
भारतीय संस्कृतेः विशेषता …….

(ई) निर्देशानुसारं उत्तरत। (केवलं प्रश्न-त्रयम्) (एकपदेन) (1 × 3 = 3)
(निर्देशानुसार उत्तर दीजिए) (केवल तीन प्रश्न)
(i) ‘कथयामः’ इति क्रियापदस्य किं कर्तृपदं प्रयुक्तम्?
(क) इति
(ख) वयं
(ग) संस्कृतिः
उत्तरः
(ख) वयं

(ii) ‘स्वाभाविकी प्रवृत्तिः’ इत्यत्र किं विशेष्यपदं
प्रयुक्तम्?
(क) प्रवृत्तिः
(ख) स्वाभाविकी
(ग) सा
उत्तरः
(क) प्रवृत्तिः

(iii) ‘अवनत्यै’ इति पदस्य विलोमपदम् अत्र किमस्ति?
(क) प्रकृत्याः
(ख) उन्नत्यै
(ग) प्रयासः
उत्तरः
(ख) उन्नत्यै

(iv) ‘निरन्तरम्’ इति पदस्य किं पर्यायपदं प्रयुक्तम् ?
(क) सततं
(ख) अद्यापि
(ग) विकासमाना
उत्तरः
(क) सततं

रचनात्मकं-कार्यम्

प्रश्न 2.
मित्रं प्रति अधोलिखितम् पत्रं मञ्जूषापदसहातया पूरयित्वा पुनः लिखत। (½ × 10 = 5)
(i) ………..
दिनांङ्कः
प्रिय मित्र (ii) ………..
अत्र सर्वं कुशलम्।
भवान् अपि तत्र कुशली इति मन्ये। गतसप्ताहे (iii) ……….. विद्यालये संस्कृत संभाषण-शिविरम् आयोजितम् (iv) ……….. दशदिनानि वयं (v) ……….. संभाषणस्य अभ्यासम् अकुर्मः। तत्र एकस्याः नटिकायाः (vi) ………… अभवत्। अहं विदूषकस्य (vii) ……….. कृतवान्। अहम् इदानीं सर्वदा संस्कृतेन एव (viii) …………. । मम शिक्षिकाः मयि स्निह्यन्ति। भवान् अपि संस्कृतेन (ix) ………… प्रयत्नं करोतु। पितरौ (x) ……….. मम प्रणामाञ्जलिं निवेदयतु।
भवतः मित्रम्,
आकाशः।
[मञ्जूषा-संभाषणस्य, अस्माकम्, वदामि, जयपुरतः, अभिनयम्, प्रति, विकाश!, मञ्चनम्, आसीत्, संस्कृतेन।]
उत्तरः
(i) जयपुरतः
(ii) विकाश!
(iii) अस्माकम्
(iv) आसीत्
(v) संस्कृतेन
(vi) मञ्चनम्
(vi) अभिनयम्
(viii) वदामि
(ix) संभाषणस्य
(x) प्रति

प्रश्न 3.
अधः प्रदत्तं चित्रं दृष्ट्वा मञ्जूषायां प्रदत्तशब्दानां साहाय्येन पञ्च वाक्यानि संस्कृतेन लिखत (1 × 5 = 5)
(नीचे दिए गए चित्र को देखकर मञ्जूषा में दिए गए शब्दों की सहायता से पाँच वाक्य संस्कृत में लिखिए।)
CBSE Sample Papers for Class 10 Sanskrit Term 2 Set 1 with Solutions 1
[मञ्जूषा-वनस्य, सिंहः, गजः, वृक्षाः, पादपाः सन्ति, धावन्ति, वृक्षेषु, मृगाः, गर्जति, इतस्ततः, वानराः कूर्दन्ति।]
अथवा
मञ्जूषायां प्रदत्तशब्दानां सहाय्येन निम्नलिखितं विषयं अधिकृत्य पञ्चभिः संस्कृतवाक्यैः एकम् अनुच्छेदं लिखत।
(मञ्जूषा में दिए गए शब्दों की सहायता से निम्नलिखित विषय पर पाँच संस्कृत वाक्यों में एक अनुच्छेद लिखिए।)
“अतिवृष्ट्या हानिः”
[मञ्जूषा-सर्वत्र, जलम्, निमग्नाः, रोगाः, जायते, पशवः, वृक्षा, जलौघः, नद्यः, नष्यन्ति, जीवतं।]
उत्तरः

अस्मिन चित्रे वनस्य दृश्यम् अस्ति।
अत्र अनेके वृक्षाः पादपाः च सन्ति।
अत्र वनराज सिंहः गर्जति।
अस्मिन् चित्रे वानराः वृक्षेषु कूर्दन्ति मृगाः चधावन्ति।
अस्मिन् चित्रे ‘गजः’ अन्ये पशवः च इतस्ततः भ्रमन्ति।

अथवा

वर्षा ऋतो: नद्यः जलेन जलौघः आगच्छन्ति।
अतिवृष्ट्या नदीनां कुलानि नष्यानि जायन्ते।
अतिवृष्ट्या अनेके रोगाः जायन्ते जना च अस्वस्था भवन्ति।
सर्वत्र जलं निमग्नाः मानवाः पशवः वृक्षा विनष्टाः भवन्ति।
अतिवृष्टि कारणेन जन जीवनं अति अस्त व्यस्तं भवति।

प्रश्न 4.
अधोलिखितानि वाक्यानि संस्कृतभाषया अनूद्य लिखत-(केवलं पञ्चवाक्यम्, रचनात्मकम्) (1 × 5 = 5)
(निम्नलिखित वाक्यों का संस्कृत भाषा में अनुवाद लिखिए) (केवल पाँच वाक्य)
(i) तुम सब क्या चाहते हो?
What do you all want?
उत्तरः
यूयम् किम् इच्छथ?

(ii) सज्जन परोपकार के लिए जीते हैं।
Gentlemen live for appreciation
उत्तरः
सज्जनाः परोपकाराय जीवन्ति।

(iii) माता-पिता का सदैव सम्मान करो।
Always respect parents.
उत्तरः
मातरं पितरं च सर्वदा सम्मानं कुरुत।

(iv) कल मैं घूमने के लिए जयपुर जाऊँगा।
Tomorrow I will go to Jaipur for a walk.
उत्तरः
श्व अहम् भ्रमणाय जयपुरं गमिष्यामि।

(v) परिश्रमी छात्र ही सफलता प्राप्त करते हैं।
Hard working students Succeed.
उत्तरः
परिश्रमिणः छात्राः एव सफलतां प्राप्नुवन्ति।

(vi) क्या मैं अब श्लोक बोलूँ ?
Can I say shloka now?
उत्तरः
किम् अधुना अहम् श्लोकं वदानि?

(vii) उद्यान में प्रकृति का मनमोहक दृश्य है।
The park had an enchanting view of nature.
उत्तरः
उद्याने प्रकृते: मनमोहक दृश्यम् अस्ति। पठित-अवबोधनम्

पठित-अवबोधनम्

प्रश्न 5.
अधोलिखितं गद्यांशं पठित्वा प्रदत्तप्रश्नानाम् उत्तराणि संस्कृतेन लिखत (3)
(निम्नलिखित गद्यांश को पढ़कर दिए गए प्रश्नों के उत्तर संस्कृत में लिखिए।)
(वनस्य दृश्यम् समीपे एवैका नदी अपि वहति।)
एकः सिंहः सुखेन विश्राम्यते तदैव एकः वानरः आगत्य तस्य पुच्छं धुनोति। क्रुद्धः सिंहः तं प्रहर्तुमिच्छति परं वानरस्तु कूर्दित्वा वृक्षमारूढ;। तदैव अन्यस्मात् वृक्षात् अपरः वानरः सिंहस्य कर्णमाकृष्य पुनः वृक्षोपरि आरोहति। एवमेव वानराः वारं-वारं सिंहं तुदन्ति । क्रुद्धः सिंहः इतस्ततः धावति, गर्जति परं किमपि कर्तुमसमर्थः एव तिष्ठति। वानराः हसन्ति वृक्षोपरि च विविधाः पक्षिणः अपि सिंहस्य एतादृशीं दशां दृष्ट्वा हर्षमिश्रितं कलरवं कुर्वन्ति।

(अ) एकपदेन उत्तरत। (केवलं प्रश्न द्वयम्) (½ × 2 = 1)
(एक शब्द में उत्तर लिखिए) (केवल दो प्रश्न)
(i) नदी कुत्र वहति?
उत्तरः
वनस्य समीपे।

(ii) वानरः कस्य पुच्छं धुनोति?
उत्तरः
सिंहस्य

(iii) के हसन्ति ?
उत्तरः
वानराः

(आ) पूर्णवाक्येन उत्तरत। (केवलं प्रश्न द्वेयम्) (1 × 2 = 2)
(पूर्ण वाक्य में उत्तर लिखिए।) (केवल दो प्रश्न)
(i) क्रुद्धः सिंहः किं करोति?
उत्तरः
क्रुद्धः सिंहः इतस्ततः धावति, गर्जति किमपि कर्तुं न एव तिष्ठति।

(ii) सिंहस्य दशां दृष्ट्वा पक्षिणः किं कुर्वन्ति?
उत्तरः
सिंहस्य दशां दृष्ट्वा पक्षिणः हर्षमिश्रितं कलरवं कुर्वन्ति।

(iii) सिंहस्य दशां दृष्ट्वा काः प्रतिक्रिया अभवत्?
उत्तरः
सिंहस्य दशां दृष्ट्वा वानराः वृक्षोपरि हसन्तिच विविधाः पक्षिणः कलरवं कुर्वन्ति।

प्रश्न 6.
अधोलिखितं पद्यांशं पठित्वा प्रदत्तप्रश्नानाम् उत्तराणि संस्कृतेन लिखत (3)
(निम्नलिखित पद्यांश को पढ़कर दिए गए प्रश्नों के उत्तर संस्कृत में लिखिए।)
पिता यच्छति पुत्राय बाल्ये विद्याधनं महत्।
पिताऽस्य किं तपस्तेपे इत्युक्तिस्तत्कृतज्ञता॥

(अ) एकपदेन उत्तरत। (केवलं प्रश्न द्वयम्) (½ × 2 = 1)
(एक शब्द में उत्तर लिखिए।) (केवल दो प्रश्न)
(i) पिता कस्मै यच्छति?
उत्तरः
पुत्राय

(ii) पिता किं ददाति?
उत्तरः
विद्याधनं

(iii) पिता कियत् ददाति?
उत्तरः
महत्

(आ) पूर्णवाक्येन उत्तरत। (केवलं प्रश्न द्वेयम्) (1 × 2 = 2)
(पूर्ण वाक्य में उत्तर लिखिए।) (केवल दो प्रश्न)
(i) पुत्राय कदा विद्याधनं यच्छति?
उत्तरः
पिता पुत्राय बाल्ये यच्छति।

(ii) पिता पुत्राय किं यच्छति?
उत्तरः
पिता पुत्राय विद्याधनं यच्छति।

(iii) पिता अस्य किम् अकरोत् ?
उत्तरः
पिता अस्य तपस्याम् अकरोत्।

प्रश्न 7.
अधोलिखितं नाट्यांशं पठित्वा प्रदत्तप्रश्नानाम् उत्तराणि संस्कृतेन लिखत (3 )
(निम्नलिखित नाट्यांश को पढ़कर दिए गए प्रश्नों के उत्तर संस्कृत में लिखिए।)
वानरः – अरे! अरे! एवं वा (शीघ्रमेव गजस्यापि पुच्छं विधूय वृक्षोपरि आरोहति।)
(गजः तं वृक्षमेव स्वशुण्डेन आलोडयितुमिच्छति परं वानरस्तु कूर्दित्वा अन्यं वृक्षमारोहति। एवं गजं वृक्षांत् वृक्षं प्रति धावन्तं दृष्ट्वा सिंहः अपि हसति वदति च।)
सिंहः – भोः गज! मामप्येवमेवातुदन् एते वानराः।
वानरः – . एतस्मादेव तु कथयामि यदहमेव योग्यः वनराजपदाय येन विशालकायं पराक्रमिणं, भयंकरं चापि सिंह गजं वा पराजेतुं समर्था अस्माकं जातिः। अतः वन्यजन्तूनां रक्षायै वयमेव क्षमाः।
(अ) एकपदेन उत्तरत। (केवलं प्रश्न द्वयम्) (½ × 2 = 1)
(एक शब्द में उत्तर लिखिए) (केवल दो प्रश्न)
(i) गजस्य पुच्छं विधूय वानरः कुत्र आरोहति?
उत्तरः
वृक्षोपरि

(ii) स्वशुण्डेन कः वृक्षम् आलोडयितुम् इच्छति?
उत्तरः
गजः

(ii) वानराः कम् अपि आतुदन्?
उत्तरः
सिंहम्।

(आ) पूर्णवाक्येन उत्तरत। (केवलं प्रश्न द्वयम्) (1 × 2 = 2)
(पूर्ण वाक्य में उत्तर लिखिए।) (केवल दो प्रश्न)
(i) ‘वन्यजन्तूनां रक्षायै वयमेव क्षमाः इति कः कथयति?
उत्तरः
वानरः कथयति यत् वन्यजन्तूनां रक्षायै वयमेव क्षमाः।

(ii) यदा गजः स्वशुण्डेन आलोऽयितुम् इच्छति तदा _वानरः किं करोति?
उत्तरः
यदा गजः स्वशुण्डेन आलोऽयितुम् इच्छति तदा वानरः कूर्दित्वा अन्यं वृक्षमारोहति।

(iii) सिंहः कदा हसति वदति च।
उत्तरः
गजं वृक्षात् वृक्षं प्रति धावन्तं दृष्ट्वा सिंहः अपि हसति वदति च।

प्रश्न 8.
मञ्जूषातः समुचितपदानि चित्वा अधोलिखितश्लोकस्यः अन्वयं पूरयत- (½ × 4 = 2)
(मंजूषा से उचित पदों को चुनकर निम्नलिखित श्लोक का अन्वय को पूरा कीजिए।)
यत् प्रोक्तं येन केनापि तस्य तत्त्वार्थनिर्णयः।
कर्तुं शक्यो भवेद्येन सः विवेकः इतीरितः॥
अन्वयः-येन (i)…….. अपि यत् (ii)…… तस्य (iii)…… येन कर्तुं शक्यः भवेत् सः (iv)…….. इति ईतिरितः।
[मञ्जूषा-प्रोक्तं, केन, विवेकः, तत्त्वार्थनिर्णयः]
अथवा
मञ्जूषायाः साहाय्येन श्लोकस्य भावार्थे रिक्तस्थानानि पूरयित्वा पुनः लिखत।
(मंजूषा की सहायता से श्लोक के भावार्थ से रिक्तस्थानों को पूरा करके पुनः लिखिए।)
विचित्रे खलु संसारे नास्ति किञ्चिन्निरर्थकम्।
अश्वचेद् धावने वीरः भारस्य वहने खरः॥
भावार्थ:-अत्र जगतः (i) ……. वर्णयति कवि: यत् (ii) …….. संसारे किम् अपि न निरर्थकम् अर्थात् सर्व सार्थकम् अस्ति। यथा (iii) …… धावनाक्रियायां वीरः बलवान् वा तथैव खरः (iv) …….समर्थः।
[मञ्जूषा-अश्वः, अस्मिन्, भारवहने, वैचित्र्यम्]
उत्तरः
(i) केन
(ii) प्रोक्तं
(iii) तत्त्वार्थनिर्णयः
(iv) विवेकः
अथवा
(i) वैचित्र्यम्
(ii) अस्मिन्
(iii) अश्वः
(iv) भारवहने

प्रश्न 9.
अधोलिखित-कथांश समुचितक्रमेण लिखत (½ × 8 = 4)
(निम्नलिखित कथाशं को समुचित क्रम में लिखिए।)
(i) स भारवेदनया क्रन्दति स्म।
(ii) आदेशं प्राप्य उभौ प्राचलताम्।
(iii) भारवतः शवस्य स्कन्धेन वहनं दुष्करम् आसीत्।
(iv) आरक्षी सुपुष्टदेह आसीत्।।
(v) तस्य क्रन्दनं निशम्य आरक्षी तमुवाच।
(vi) अभियुक्तः अतीव कृशकायः आसीत्।
(vii) अस्मिन् चौर्याभियोगे त्वं वर्षत्रयस्य कारादण्डं लप्स्यसे।
(vi)त्वयाऽहं चोरिताया मञ्जूषाया ग्रहणाद् वारितः।
उत्तरः
(i) आदेशं प्राप्य उभौ प्राचलातम्।
(iv) आरक्षी सुपुष्टदेह आसीत्।
(vi) अभियुक्तः अतीव कृशकायः आसीत्।
(iii) भारवतः शवस्य स्कनधेन वहनं दुष्करम् आसीत्।
(i) स भारवेदनया क्रन्दति स्म।
(v) तस्य क्रन्दनं निशम्य आरक्षी तमुवाच।
(viii) त्वयाऽहं चोरिताया मञ्जूषाया ग्रहणात् वारितः।
(vii) अस्मिन् चौर्याभियोगे त्वं वर्षत्रयस्य कारादण्डं लप्स्यसे।

CBSE Sample Papers for Class 10 Maths Basic Term 2 Set 4 with Solutions

February 17, 2022

Students can access the CBSE Sample Papers for Class 10 Maths with Solutions and marking scheme Term 2 Set 2 will help students in understanding the difficulty level of the exam.

CBSE Sample Papers for Class 10 Maths BasicTerm 2 Set 2 with Solutions

Time allowed: 2 hours
Maximum Marks: 40

General Instructions:

The question paper consists of 14 questions divided into 3 sections A, B, C.
Section A comprises of 6 questions of 2 marks each. Internal choice has been provided in two questions.
Section B comprises of 4 questions of 3 marks each. Internal choice has been provided in one questions.
Section C comprises of 4 questions of 4 marks each. An internal choice has been provided in one questions. It contains two case study based questions.

Section – A (12 marks)

Question 1.
If the roots of the quadratic equation ax² + bx + c = 0 are sin α and cos α, then prove that a² + 2ac = b². (2)
Answer:
The roots of the equation ax² + bx + c = 0 are sin α and cos α.
∴ Sum of roots i.e.
⇒ sin α + cos α = \(\frac{-b}{a}\) ….. (i)
and products of roots
sin α + cos α = \(\frac{c}{a}\) ….. (ii)
From equation (i)
(sin α + cos α)² = \(\left(\frac{-b}{a}\right)^{2}\)
⇒ sin² α + cos² α + 2 sin α cos α
= \(\frac{b^{2}}{a^{2}}\)
⇒ 1 + 2 × \(\frac{c}{a}\) = \(\frac{b^{2}}{a^{2}}\) [from (ii)]
⇒ 1 + \(\frac{2c}{a}\) = \(\frac{b^{2}}{a^{2}}\)
⇒ a + 2c = \(\frac{b^{2}}{a}\)
⇒ a² + 2ac = b²

Question 2.
If in a cone, its height is tripled and radius is doubled, then by how much times does its volume increases ?
OR
If the total surface area of a solid hemisphere is 462 cm², then find its volume? [Take π = \(\frac{22}{7}\)] (2)
Answer:
Let, the height of cone be h and its radius be r units
Then, volume of cone = \(\frac{1}{3}\) ≠ r²h
If new height, H = 3h
New radius, R = 2r
Then,
New volume of cone = \(\frac{1}{3}\) ≠ R²h
= \(\frac{1}{3}\) ≠ (2r)² × 3h
= \(\frac{1}{3}\)(12 ≠ r²h)
= 12(\(\frac{1}{3}\)πr²h)
= 12 volume of initial cone
OR
Total surface area of hemisphere = 462 cm²
∴ 3πr²2 = 462
where r is the radius of the hemisphere
⇒ 3 × \(\frac{22}{7}\) × r² = 462
r² = \(\frac{462 \times 7}{3 \times 22}\) = 49
r = 7
(∵ Radius cannot be negative)
Volume of hemisphere = \(\frac{2}{3}\) ≠ r³
= \(\frac{2}{3}\) × \(\frac{22}{7}\) × 7 × 7 × 7
= \(\frac{2156}{3}\)
= 719 cm³ (approx)

Related Theory:
Hemisphere is the half of a sphere, which is obtained by cutting sphere into 2 halves

Question 3.
Write the relationship connecting three measures of central tendencies. Hence, find the median of the given data if mode is 24.5 and mean is 29.75. (2)
Answer:
According to the question,
Mode = 24.5
And Mean = 29.75
The relationship connecting the three measures of central tendency is:
3 Median = Mode + 2 × Mean
Now, mode = 24.5 and mean = 29.75
∴ 3 Median = 24.5 + 2 × 29.75
⇒ = 24.5 + 59.50
= 84.0 84
∴ Median = \(\frac{84}{3}\) = 28

Caution:
The correct empirical formula is important for calculating the value of the median.

Question 4.
In the AP 31, 28, 25 ….. is 0 is its any term ?
OR
What is the sum of the odd numbers between 0 and 50? (2)
Answer:
Here, A.P. is 31, 28, 25…
Then a = 31,
d = 28 – 31 = – 3
Let, n^th term be 0
∴ 0 = 31 + (n – 1)(- 3)
– 31 = – 3n + 3
⇒ – 3n = – 34
n = \(\frac{34}{3}\)
which is not possible,
Therefore, 0 is not a term of the given A.P.
OR
Odd numbers between 0 and 50 be 1, 3, 5, 7 …49
Here, a = 1,
d = 3 – 1 = 2
a_n = 49
We have, a_n = a + (n – 1)d
1 + (n – 1) × 2 = 49
⇒ 2 (n – 1) = 48
⇒ n – 1 = 24
⇒ n = 25
Then, S₂₅ = \(\frac{n}{2}\)(a + l)
= \(\frac{n}{2}\)[a + a₂₅]
= \(\frac{25}{2}\) (1 + 49)
= \(\frac{25}{2}\) × 50
= 25 × 25
= 625

Question 5.
From the following distribution, what is the median class (2)

Cost of living index	No. of weeks
1400-1550	8
1550-1700	15
1700-1850	21
1850-2000	8

Answer:

Cost of living index	No. of week(f)	c.f.
1400-1550	8	8
1550-1700	15	23
1700-1850	21	44
1850-2000	8	52

Here, N = 52,
\(\frac{N}{2}\) = \(\frac{52}{2}\)
= 26
Hence, median class is 1700-1850.

Question 6.
In the given figure AB and CD are two common tangents to two touching circles. If DC = 4 cm, then calculate the length of AB. (2)
CBSE Sample Papers for Class 10 Maths Basic Term 2 Set 4 with solutions 1
Answer:
Here, AD and DC are tangents from point D.
∴ AD = DC ……(i)
(Since tangents from an external point are equal)
And DB and DC are also tangents from point D
∴ DB = DC ……. (ii)
On adding (i) and (ii), we get,
AD + BD = DC + DC
AB = 2DC
⇒ AB = 2 × 4
= 8 cm

Section – B (12 Marks)

Question 7.
What is the middle term of the sequence formed by all three digit numbers which leave a remainder 5 when divided by 7. Also, find the sum of all numbers on both sides of the middle term separately. (3)
Answer:
According to the condition, the sequence formed will be 103, 110, …….. 999
Since 999 = 103 + (n – 1) × 7
⇒ (n – 1) × 7 = 999 – 103
⇒ (n – 1) × 7 = 896
⇒ n – 1 = 128
⇒ n = 129
Therefore,
\(\frac{129+1}{2}\) = 65^th term is the middle term
Middle term a₆₅ = 103 + 64 × 7 = 551
Sum of first 64 terms = 32[2 × 103 + 63 × 7] = 20704
Sum of last 64 terms = 32[2 × 558 + 63 × 7] = 49824

Caution:
First evaluate the number of the terms in the series, to get the middle term.

Question 8.
In Gokuldham society, a rectangular park is needed to be designed such that, its breadth is 3m less than its length. Its area is to be 4 sq. m more than the area of the park that has already been made in the shape of an isosceles triangle with its base as the breadth of the rectangular park and of the altitude 12m. What is the length and breadth of the park.
OR
Vikram wants to make a show piece, in shape of a right angled ‘triangle’. For doing so, he took three rods together in the shape of a right – angled triangle. In this the hypotenuse is to be 2 cm longer than the base and 4 cm longer than the altitude. What should be the lengths of the rods? (3)
Answer:
Let, the Length of the park be ‘x’ m
Then, breadth of the park be (x – 3)m
Now, area of triangular park
= \(\frac{1}{2}\) × 12 × (x – 3)
= 6(x – 3)
And, area of rectangular park
= 6(x – 3) + 4
= 6x – 18 + 4
= 6x – 14
A.T.Q.
6x – 14 = x(x – 3)
⇒ 6x – 14 = x² – 3x
⇒ x² – 3x – 6x + 14 = 0
⇒ x² – 9x + 14 = 0
⇒ x² – 7x – 2x + 14 = 0
⇒ x(x – 7) – 2(x – 7) = 0
⇒ x = 7, 2
x = 2 is rejected
∴ x = 7 cm
Hence, length of park is 7 cm, and breadth is 4 cm.
OR
Let, the hypotenuse of the triangle be x cm.
A.T.Q.
Base of triangle = (x – 2) cm
Altitude of triangle = (x – 4) cm
By Pythagoras theorem,
x² = (x – 2)² + (x – 4)²
⇒ x² = x² + 4 – 4x + x² + 16 – 8x
⇒ x² – 12x + 20 = 0
⇒ x² – 10x – 2x + 20 = 0
⇒ x(x – 10) – 2(x – 10) = 0
⇒ (x – 2) (x – 10) = 0
⇒ x = 2, 10
Rejecting x = 2 we get, x = 10
Hypotenuse, x = 10 cm
Base = x – 2 = 10 – 2 = 8cm
Altitude = x – 4
= 10 – 4 = 6 cm.

Question 9.
In the adjoining figure, O is the centre of the circle. Then prove that ∠BAT = ∠ACB. (3)
CBSE Sample Papers for Class 10 Maths Basic Term 2 Set 4 with solutions 2
Answer:
Given: A circle with centre O. AC is its diameter.
AB and BC are two chords.
To prove: ∠BAT = ∠ACB

Proof:
∴ In ∆ABC,
∠ABC = 90° (Angle in a semicircle)
∴ ∠BAC = 90° – ∠ACB …… (i)
But ∠CAT = 90°
∴ ∠BAT = 90° – ∠CAB …… (ii)
From (i) and (ii)
∠BAT = 90° – (90° – ∠ACB)
∠BAT = ∠ACB
Hence proved.

Question 10.
From the top of a building 100 m high, the angle of depression of two objects are on the same side observed to be 45° and 60°. What is the distance between the objects. (3 )
Answer:
Here, AB is the building of height 100 m. Points P and Q are on the same side of the building, with angle of depression as 45° and 60°.
CBSE Sample Papers for Class 10 Maths Basic Term 2 Set 4 with solutions 3
Now, in ∆ABP

Section – C (16 marks)

Question 11.
A building is in the from of a cylinder surmounted by a hemispherical dome. The base diameter of the dome is equal to \(\frac{2}{3}\) of the total height of the building. Find the height of the building, if it contains 67\(\frac{1}{27}\) m³ of air.
OR
A 55 cm high cylindrical lamp – shade has small decorative mirror on its either ends upto a width of 10 cm and 50 mm thick wire wound around all over to cover the middle part. How many revolutions will the wire take to cover it ?
CBSE Sample Papers for Class 10 Maths Basic Term 2 Set 4 with solutions 5
Answer:
Let, the radius of the hemispherical dome be r meters and the total height of the building be h meters.

Since, the base diameter of the dome is equal to \(\frac{2}{3}\) of the total height, therefore
2r = \(\frac{2h}{3}\)
⇒ r = \(\frac{h}{3}\)m
Let, H metres be the height of the cylindrical portion.
Therefore, H = h – \(\frac{h}{3}\) = \(\frac{2h}{3}\)
Volume of the air inside the building = Volume of air inside the dome + Volume of air inside the cylinder
CBSE Sample Papers for Class 10 Maths Basic Term 2 Set 4 with solutions 7

Related Theory:
Cub/c units are the unit of volume. Square units are the unit area. So if air is given, it occupies space or volume of the dome.
OR
Here, height of cylinder in which wire is wound
= 55 – 10 – 10 = 35 cm
So, the portion need to be covered by wire =
2πR(35)
2πR (35) = 2πR × \(\frac{50}{10}\) cm × No. of revolutions
where, R is the radius of the cylinder
⇒ 35 = \(\frac{50}{10}\) × No. of revolution
⇒ No. of revolutions = 7

Question 12.
From the top of a tower h metres high, angle of depression of two objects which are in line with foot of the tower are α and β (β > α). Find the distance between the objects. (4)
Answer:
Let AB represent the tower of height h metres.
P and Q be the position of the two objects on the ground. We need to determine the distance PQ.
CBSE Sample Papers for Class 10 Maths Basic Term 2 Set 4 with solutions 8
From ∆QAB, we have
tan β = \(\frac{h}{\mathrm{QA}}\)
⇒ QA = h cot β …(i)
From ∆PAB, we have
tan α = \(\frac{A B}{P A}\)
= \(\frac{h}{P A}\)
⇒ PA = h cot a …(ii)
Further, PQ = PA – QA
= h cot α – h cot β (from (ii) and (iii))
= h (cot α – cot β)

Caution:
Since, β > α, then point of observation of angle p is closer to the tower than angle observation point of α.

Question 13.
Case Study-1
In new housing society, a park in the shape of a circle is made for children. The society member want to make a green zone around the park, by planting the trees around it in the form of tangent to the circle. Therd is a circular park of radius 24 m and there is a pole at a distance of 26 m from the centre of the park as shown in the figure. It is planned to enclose the park by planting trees along line segments PQ and PR tangential to the park.
CBSE Sample Papers for Class 10 Maths Basic Term 2 Set 4 with solutions 11
Answer:
(A) What is the length of PQ and PR (2)
Answer:

right angled triangle PRO,
We have,
PR = \(\sqrt{\mathrm{PO}^{2}-\mathrm{RO}^{2}}\)
= \(\sqrt{26^{2}-24^{2}}\)
= \(\sqrt{676-576}\)
= √100
= 10 m
⇒ PR = PQ = 10 m

(B) If six trees are planted along each tangential line segments at equal distances, find the distance between any two consecutive trees. (2)
Answer:
As six trees are to be planted along PQ and PR each,
CBSE Sample Papers for Class 10 Maths Basic Term 2 Set 4 with solutions 10
Let’s assume the distance between two consecutive trees is x.
Total trees are at 5 equal distances
Hence, 5x = 10
x = 2

Related Theory:
Here, the property of tangents that length drawn from a point outside the circle is equal in length.

Question 14.
Case Study-2
Bakery items like breads, buns, biscuits, cakes etc. have a definite life (in hours). They get stale very quickly, many microorganism persist on it, it not consumed timely. A bakery product manufacturer wants to know the lifetime of buns, pizza base and kulchas. For doing so, he tested the life time of 400 packets of pizza base.
CBSE Sample Papers for Class 10 Maths Basic Term 2 Set 4 with solutions 13

Life time (in hours)	No. of packets (c.f.)
150-200	14
200-250	60
250-300	130
300-350	211
350-400	300
400-450	360
450-500	400

(A) What is the frequency of the class interval 300 – 350? (2)
Answer:

Life time (in hours)	No. of packets (c.f.)	f
150-200	14	14
200-250	60	46
250-300	130	70
300-350	211	81
350-400	300	89
400-450	360	60
450-500	400	40

The frequency of class interval 300 – 350 is 81.

(B) What is average life time of a pizza base (2)
Answer:
CBSE Sample Papers for Class 10 Maths Basic Term 2 Set 4 with solutions 12
Then, x̄ = A + \(\frac{\Sigma f_{i} u_{i}}{\Sigma f_{i}}\)
= 325 + \(\frac{6250}{400}\)
= 325 + 15.625
= 340.625
= 341 hours

CBSE Sample Papers for Class 10 Maths Basic Term 2 Set 2 with Solutions

February 17, 2022

Students can access the CBSE Sample Papers for Class 10 Maths with Solutions and marking scheme Term 2 Set 2 will help students in understanding the difficulty level of the exam.

CBSE Sample Papers for Class 10 Maths BasicTerm 2 Set 2 with Solutions

Time allowed: 2 hours
Maximum Marks: 40

General Instructions:

The question paper consists of 14 questions divided into 3 sections A, B, C.
Section A comprises of 6 questions of 2 marks each. Internal choice has been provided in two questions.
Section B comprises of 4 questions of 3 marks each. Internal choice has been provided in one questions.
Section C comprises of 4 questions of 4 marks each. An internal choice has been provided in one questions. It contains two case study based questions.

Section – A (12 marks)

Question 1.
Solve the quadratic equation p²x² + (p² – q²) x – q² = 0, using quadratic formula.
OR
If α and β are the roots of a quadratic equation and α + β = 4 and α³ + β³ = 47, then form a quadratic equation in terms of x, having roots as α and β. (2)
Answer:
Given, p²x² + (p² – q²) x – q² = 0
On comparing it with standard equation We get
a = p², b = p² – q², c = – q²
∴ D = b² – 4ac
= (P² – q²)² – 4 × p² × (- q²)
= p⁴ – q⁴ – 2p²q² + 4p²q²
= p⁴ + q⁴ + 2 p²q²
= (p² + q²)² > 0
So, the equation has real roots,
CBSE Sample Papers for Class 10 Maths Basic Term 2 Set 2 with solutions 1
Hence, roots are \(\frac{q^{2}}{p^{2}}\) and – 1

Related Theory
This quadratic formula was given by Indian mathematician Sri Dharacharaya. Then for quadratic equation ax² + bx + c = 0, its roots are
\(\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}\)
OR
Here, α + β = 4 and
α³ + β³ = 44
⇒ (α + β)³ – 3 αβ(α + β) = 44
⇒ 4³ – 3 αβ (4) = 44
⇒ – 12αβ = 44 – 64
⇒ αβ = \(\frac{20}{12}\) = \(\frac{5}{3}\)
∴ Quadratic equation is:
x² – (α + β)x + αβ = 0
⇒ x² – 4x + \(\frac{5}{3}\) = 0
⇒ 3x² – 12x + 5 = 0, which is the required equation.

Related Theory:
If α and β are the roots of the quadratic equation, then quadratic equation can be formed as:
x² – (α + β)x + αβ = 0

Question 2.
In two APs, 60, 62, 64…. and – 10, – 3, 4, 11, for what value of n are terms equal ? (2)
Answer:
1^st A.P. is 60, 62, 64 …….
Here. a = 60,
d = 62 – 60 = 2
nth term of 1^st A.P. = a + (n – 1 )d
= 60 + (n – 1)2
= 58 + 2n ……. (i)
Terms of 2nd A.P. is – 10, – 3, 4, 11 ……..
Here, a = – 10,
d = – 3 + 10 = 7
∴ n^th term of 2^nd A.P. = a + (n – l)d
= – 10 + (n – 1)7
= – 17 + 7n …… (ii)
From (i) and (ii), we get
58 + 2n = – 17 + 7n
⇒ – 5n = – 75
⇒ n = \(\frac{75}{5}\) = 15
∴ 15th term of both A.P.s are equal.

Caution:
Equate the nth term of both the A.P. to the value of n.

Question 3.
The heights of students in a class are arranged in the tabular from. But some water drops get spilled on it, due to which few enteries got erased.
So, in the given distribution find the value of a, b, c, d. (2)

Height (in cm)	Frequency	Cumulative frequency
150-155	5	12
155-160	a	25
160-165	10	b
165-170	C	43
170-175	5	48
175-180	2	d

Answer:
From the table
12 + a = 25 ⇒ a = 25 – 12 = 13
25 + 10 = b ⇒ b = 35
b + c = 43
⇒ c = 43 – b
= 43 – 35 = 8
48 + 2 = d
⇒ d = 50

Related Theory:
The cumulative frequency can be calculated by adding the frequency of that class to the previous class and the c.f. of last class is equal to sum of all the frequency

Question 4.
Evaluate the sum of all natural numbers less than 100 which are divisible by 6.
OR
Show that the sequence defined as a_n = 2n² + 1 is not an A.P. (2)
Answer:
Natural numbers less than 100 and divisible by 6 are 6, 12, 18, ……….. 96,
a = 6,
d = 6,
and a_n = 96
∴ a + (n – 1)d = 96
6 + (n – 1)6 = 96
⇒ n – 1 = \(\frac{90}{6}\)
⇒ n – 1 = 15
⇒ n = 16 n.
∴ Sum = \(\frac{n}{2}\)[a + a_n]
= \(\frac{16}{2}\)[6 + 96]
= 8 × 102
= 816

Caution:
Use the appropriate formula, for calculating the sum, as number of terms in this A.P. is unknown.
OR
We have, a_n = 2n² + 1
Replacing n by (n + 1) in a_n, we obtain
a_{n + 1} = 2(n + 1)² + 1
= 2n² + 4n + 3
Now, a_{n + 1} – a_n = (2n² + 4n + 3) – (2n² + 1)
= 4n + 2
Clearly, a_{n + 1} – a_n is not independent of n and therefore not constant.
So, the given sequence is not an A.P.

Related Theory:
The common difference is the value between each successive number in an arithmetic sequence. Therefore, the formula for finding the common difference of an A.P. is d = a_n – a_{n – 1}, where an is the last term is the sequence and a_{n – 1} is the previous

Question 5.
The mean of the following data is 14 Then what is the value of k. (2)

X	frequency
5	7
10	k
15	8
20	4
25	5

Answer:
Table for the given data is:

x_i	f_i	x_if_i
5	7	35
10	k	10k
15	8	120
20	4	80
25	5	125
Total	Σf_i = k + 24	Σ x_if_i = 10 k + 360

Here, Mean = 14
Mean = \(\frac{\Sigma f_{i} x_{i}}{\Sigma f_{i}}\)
⇒ 14 = \(\frac{10 k+360}{k+24}\)
⇒ 14(k + 24 )= 10k + 360
⇒ 14k + 336 = 10k + 360
⇒ 14k – 10k = 360 – 336
⇒ 4k = 24
⇒ k = 6
Hence, the value of k is 6.

Question 6.
A solid wooden toy is in the shape of a right circular cone mounted on a hemisphere of radius 4.2 cm. The total height of the toy is 10.2 cm. What is the volume of the toy? [use π = \(\frac{22}{7}\)] (2)
Answer:
From the figure, we have radius of the base of the cone = 4.2 cm and height = 10.2 – 4.2 = 6 cm
CBSE Sample Papers for Class 10 Maths Basic Term 2 Set 2 with solutions 2
So, volume of the toy = Volume of cone + Volume of hemisphere
= \(\frac{1}{3}\)π(4.2)²6 + \(\frac{2}{3}\)π(4.2)³
= 776.16 + 155.232
= 931.392 cm³

Section – B (12 marks)

Question 7.
Draw a circle of radius 2.2 cm. Take a point P on the circle. From the point P, construct a tangent to the circle.
OR
Draw a line segment of length 6.4 cm. Divide AB in the ratio of 3 : 5. Measure the two parts. (3)
Answer:
CBSE Sample Papers for Class 10 Maths Basic Term 2 Set 2 with solutions 3
Steps of construction:

Draw a circle of radius 2.2 cm with centre O.
Draw a circle of radius 2.2 cm, intersecting circle at P.
From P, draw a perpendicular.
Extend BP.
Now, BPA is the required tangent.

Related Theory:
Tangent to a circle is always perpendicular to the radius.
OR
CBSE Sample Papers for Class 10 Maths Basic Term 2 Set 2 with solutions 4

Steps of construction:

Draw a line segment of length 6.4 cm.
Draw an acute angle ZBAX.
Make eight equal marks on ray AX.
Join A8B.
Draw a line from A3 parallel to A8B.
P is the required point of intersection on AB

Here, P divide AB in the ratio of 3 : 5
∴ AP = 3.9 cm
PB = 2.5 cm

Caution:
The number of divisions, in which acute angle line is to be divided is the sum of the ratios i.e. 3 + 5 = 8

Question 8.
The top of a broken tree has its top touching the ground at a distance 15 m from the bottom, the angle made by the broken end with the ground is 30°. Then what is the length of the broken part? (3)
Answer:
Here, BAP is a tree and it gets broken at the point A and touches the ground at point C.
CBSE Sample Papers for Class 10 Maths Basic Term 2 Set 2 with solutions 5
So, AC is the broken part.
In ∆ABC,
cos 30° = \(\frac{B C}{A C}\)
cos 30° = \(\frac{15}{A C}\)
⇒ \(\frac{\sqrt{3}}{2}\) = \(\frac{15}{A C}\)
⇒ AC = \(\frac{30}{\sqrt{3}} \times \frac{\sqrt{3}}{\sqrt{3}}\)
= 10√3 m
= 10 × 1.732 m
= 17.32 m

Caution:
The three main functions in trigonometry are sine, cosine and tangent.
sine function : sin θ = \(\frac{\text { Oppositeside }}{\text { Hypotenuse }}\)
cosine function : cos θ = \(\frac{\text { Adjacent side }}{\text { Hypotenuse }}\)
tangent function : tan θ = \(\frac{\text { Opposite side }}{\text { Adjocent side }}\)

Question 9.
In the given figure, the diameters, of two wheels have measures 4 cm and 2 cm. Determine the lengths of the belts AD and BC that pass around the wheels if it is given that belts cross each other at right angles. (3)
CBSE Sample Papers for Class 10 Maths Basic Term 2 Set 2 with solutions 6
Answer:
Here, circle with centre O has radius 4 cm and circle with centre O’ has radius 2 cm.
In ∆OAP and ∆OCP
AP = PC [Tangent to a circle from same point]
OP = OP
OA = OC [radii of a circle]
∴ ∆OAP ≅ ∆OPB
∵ ∠APO = ∠CPO [By c.p.c.t]
But ∠APC = 90° [Given]
∴ ∠APO = 45°
In right ∆OAP = \(\frac{\mathrm{AP}}{\mathrm{OP}}\) = cot 45°
∴ AP = OP = 2 cm
Similarly, PD = 1 cm,
AD = AP + PD
= 1 + 2 = 3 cm
Now, AD = BC = 3 cm

Related Theory:
Congruency of two triangles and properties of trigonometric ratios are used to find the required side.

Question 10.
Prove that: The tangent at any point of a circle is perpendicular to the radius through the point of contact (O). At the point of contact the angle between radius and tangent to a circle is 90°. (3)
Answer:
Given: A circle (0, r) with centre 0. AB is a tangent to the circle at point P.
To Prove: OP ⊥ AB
Construction: Take any point Q an AB other than P and join OQ.
CBSE Sample Papers for Class 10 Maths Basic Term 2 Set 2 with solutions 7
OQ > OR (i) (∵ greater than radii)
Similarly, OR>OP …(ii)
Thus, we find that among all such Line segments the line segment OP is the shortest, which is only possible when OP is perpendicular to AB
Hence, OP ⊥ AB

Caution:
Here, do the necessary construction to prove the desired result.

Section – C (16 marks)

Question 11.
The angle of depression of the top and bottom of building 50 m high as observed from the top of a tower are 30° and 60° respectively. Find the height of the tower and also the horizontal distances between the building and the tower. (4)
Answer:
CBSE Sample Papers for Class 10 Maths Basic Term 2 Set 2 with solutions 8
From right ∆BDQ,

⇒ \(\frac{50 \times 3}{2}\)
= 25 × 3
= 75 m
Thus, the height of the tower is 75 m.
From equation (i), we have,
AP = BD = \(\frac{\mathrm{PQ}}{\sqrt{3}}\) = \(\frac{75}{\sqrt{3}}\)
= 25√3
= 25 × 1.732
= 43:25 m

Question 12.
If h, C and v respectively represent the height, curved surface area and volume of a cone, prove that
C² = \(\frac{3 \pi v h^{3}+9 v^{2}}{h^{2}}\)
h2
OR
To maintain the beauty of a monument, the students of a school cleaned and painted the dome of the monument. The monument is in the form of a hemisphere. From inside, it was whitewashed by the students whose area is 249.48 m².
Find the volume of the air inside the dome. If white washing costs ₹ 2/m², how much does it costs ? (4)
Answer:
CBSE Sample Papers for Class 10 Maths Basic Term 2 Set 2 with solutions 10

Here,
Volume of the cone, V = \(\frac{1}{3}\)πr² h
Curved surface area of cone (C)
= πrl
= πr\(\sqrt{h^{2}+r^{2}}\)
C² = π²r² (h² + r²) …(i)
So, 3πVh³ + 9V²
= 3π(\(\frac{1}{3}\)πr²h)h³ + 9(\(\frac{1}{9}\)π²r⁴h²)
= π²r²h⁴ + π²r⁴h²
= π²r²h² (h² + r²)
or \(\frac{3 \pi \mathrm{Vh}^{3}+9 \mathrm{~V}^{2}}{h^{2}}\) = π²r² (h² + r²) = C² [from (i)]

Related Theory:
Curved surface area of cone is calculated by using the slant height. And slant height (l) of the cone is
given by \(\sqrt{h^{2}+r^{2}}\)
OR
Here, dome of the monument is hemispherical in shape, which has to be whitewashed by the students.
Now, total area to be whitewashed = 249.48 m²
cost of white washing = ₹ 2/m²
∴ Total cost of white washing
= ₹ 2 × 249.48
= ₹ 498.96
Also, 2πr² = 249.48
r² = \(\frac{249.48}{2 \times 22}\) × 7
r = √158.76 = 12.6 m
Volume of air inside the dome = Volume of hemisphere
= \(\frac{2}{3}\) ≠ r³
= \(\frac{2}{3}\) × \(\frac{22}{7}\) × 12.6 × 12.6 × 12.6
= 4191.264 m³

Question 13.
Case Study-1
A wax museum or waxworks usually consists of a collection of wax sculptures representing famous people from history and contemporary personalities exhibited in lifelike poses, wearing real clothes. A beautiful wax museum was built in taj city. Many people are visiting that museum on daily basis. A group of 71 people visited that museum on a particular day. The manager of the store want to make some calculation regarding the data of the number of peoples collected.
CBSE Sample Papers for Class 10 Maths Basic Term 2 Set 2 with solutions 11
The table below shows the categorization on the basis of their ages.

Age (in years)	No. of persons
Less than 10	3
Less than 20	12
Less than 30	20
Less than 40	44
Less than 50	50
Less than 60	71

Now, answer the following questions:
(A) If true class limits are made, then what will be the last class interval. (2)
Answer:
Explanation: Here class interval formed

C.I.	f	cf
0-10	3	3
10-20	9	12
20-30	8	20
30-40	24	44
40-50	6	50
50-60	21	71

Then, last class interval is 50 – 60

(B) What is the median of the given data? (2)
Answer:

C.I.	f	cf
0-10	3	3
10-20	9	12
20-30	8	20
30-40	24	44
40-50	6	50
50-60	21	71
	71

Here, \(\frac{N}{2}\) = \(\frac{71}{2}\) = 35.2
Then, median class is 30 – 40
Median = l + \(\frac{\frac{N}{2}-c f}{f}\) × h
= 30 + \(\frac{35.2-20}{24}\) × 10
= 30 + \(\frac{15.2}{24}\)
= 30 + 6.33
= 36.33.

Question 14.
Case Study-2
A busy area is there in the shopping market of Gwalior. It was decided to make some parking lots to resolved the parking issues in the market.
CBSE Sample Papers for Class 10 Maths Basic Term 2 Set 2 with solutions 12
As shown in the above figure, there are two squares. These of them are the spaces needed to be given to the parking area of cars near a mall in the market. The first square i.e. ABCD has side ‘a’ and another square PQRS has side ‘P’
The sum of the areas of two squares is 640 m2 and difference in their perimeter be 64 m.
Answer the following questions:
(A) What is length of the side of small parking area? (2)
Answer:
8 m
Explanation: A.T.Q. the side of square ABCD is a cm.
∴ Its area = a²
Similarly, for second square, PQRS, whose side is p cm, area = p²
∴ a² + p² = 640
or p² = 640 – a² …… (i)
And 4p – 4a = 64
⇒ p – a = 16 …(ii)
(Using (i) and (ii), we get
⇒ (16 + a)² = 164 – a²
⇒ 256 + a² + 32a = 640 – a²
⇒ 2a²+ 32a – 384 = 0
⇒ a² + 16a – 192 = 0
⇒ a² + 24a – 8a – 192 =0
⇒ a(a + 24) – 8(a + 24) = 0
⇒ a = 8, – 24
∴ a = 8 m

(B) What is the total area available for the parking lot in the form of big square? (2)
Answer:
Since, p – a =16
p = 16 + a
= 16 + 8 [from (i)]
= 24 m
Area of square PQRS = p × p
= 24 × 24 = 574 m²

Tansen Extra Questions and Answers Class 6 English A Pact with the Sun

January 17, 2022

Here we are providing Tansen Extra Questions and Answers Class 6 English A Pact with the Sun, Extra Questions for Class 6 English was designed by subject expert teachers. https://ncertmcq.com/extra-questions-for-class-6-english/

Tansen Extra Questions and Answers Class 6 English A Pact with the Sun

Tansen Extra Questions and Answers Short Answer Type

Tansen Class 6 Extra Questions And Answers Question 1.
Who was Tansen?
Answer:
Tansen was famous for his singing talent. He was the greatest musician India has ever produced.

Tansen Extra Questions And Answers Question 2.
What were the distinctive qualities of Tansen as a child?
Answer:
Tansen as a child, used to play in the forest. He learnt to copy the calls of birds and animals. Once he frightened Swami Haridas and his pupils by his producing the roar of a tiger.

Tansen Extra Questions Class 6 Question 3.
How did Tansen’s life change?
Answer:
Tansen was born to Mukandan Misra and his wife in Gwalior. His talent was spotted by Swami Haridas. He lived with his guru for eleven years. He joined Mohammad Ghaus who took him to the court of Rani Mrignaini. Tansen married Hussaini. He impressed Emperor Akbar with music.

Tansen Short Question And Answer Class 6 Question 4.
What trap was laid by the jealous courtiers?
Answer:
Shaukat Mian had a bright idea. The courtiers made Tansen sing Raga Deepak. If the Raga was sung properly, it made the air hot and even burnt the singer to ashes.

Tansen Questions And Answers Extra Class 6 Question 5.
Why was Tansen worried when he was asked to sing raga Deepak?
Answer:
Tansen was a famous singer. But his fear was that the song would give off a lot of heat. It would set the lamps alight and would also burn him to ashes.

Extra Questions Of Tansen Class 6 Question 6.
How did the jealous courtiers plan to harm Tansen? How did the great musician save his honour as well as official position?
Answer:
Tansen was a talented musician. He came to the notice of Emperor Akbar. Tansen was honored with a place in Akbar’s court. The jealous courtiers decided to ruin him. They demanded that Tansen should sing Raga Deepak. They knew that the Raga would burn him to ashes. However, Tansen accepted the challenge. He trained two girls to sing Raga Megh to bring rain and put out the fire. Tansen was thus saved wisely.

Tansen Extra Questions and Answers Long Answer Type

Extra Questions On Tansen Class 6 Question 1.
Discuss ‘nature is a perfect teacher’ for a child.
Answer:
Tansen was a legendary singer. He observed nature so closely and learnt various sounds in the forest. He imitated them so perfectly that he scared Swami Haridas and his disciple. The experience laid foundation stone of his successful career. He prepared his daughters to sing Raga Megha to counter the burning impact of Raga Deepak and they became his savior. Therefore we can say that co-existence, peaceful mind and wisdom can be earned when a person lives close to the nature.

Tansen Questions And Answers Class 6 Question 2.
Tansen’s patience and perseverance saved his life. How?
Answer:
Tansen presented himself as a man who was passionate about his music. He didn’t fight with anyone. His status grew in the eyes of Emperor Akbar. His patience made him win in every situation. The promptness and wisdom saved him from evil plans. His works in the field of music are admired till date. No one has ever equalled in his brilliance and perseverance.

Question 3.
Why did Swami Haridas say Tansen was ‘talented’?
Answer:
Swami Haridas said Tansen was ‘talented’ because he frightened the little group by roaring exactly like a tiger and even Swami Haridas was not able to differentiate between the sound.

Question 4.
Why did Akbar ask Tansen to join his court?
Answer:
Tansen learnt music from Swami Haridas for eleven years. He himself became a famous singer. Sometimes he sang before Emperor Akbar. Akbar was so impressed that he asked Tansen to join his court in 1556.

Question 5.
How do we know that Akbar was fond of Tansen? Give two reasons.
Answer:
Akbar was fond of Tansen is clear as
(i) Akbar would call upon Tansen to sing at any time.
(ii) Often Akbar went to Tansen’s house to hear him practice.

Question 6.
What did the other courtiers feel about Tansen?
Answer:
The other courtiers felt jealous of Tansen. They became his enemies. They had made up their mind to ruin Tansen.

Question 7.
(i) What happens if Raga Deepak is sung properly?
(ii) Why did Tansen’s enemies want him to sing the raga?
Answer:
(i) If Raga Deepak is sung properly, the air becomes so hot that the lamps are lighted. The heat bums the singer also to ashes.
(ii) Tansen’s enemies were jealous of him. Therefore, they wanted him to sing the Raga and die of heat.

Question 8.
Why did the Tansen agree to sing Raga Deepak?
Answer:
Tansen agreed to sing Raga Deepak because he could not disobey Emperor Akbar.

Question 9.
(i) What steps did he take to save himself?
(ii) Did his plan work? How?
Answer:
(i) Tansen was a little worried as well as afraid. He took two steps for his safety. He requested the king to give him some time. Next, he taught his daughter and her friend to sing Raga Megh.
(ii) Yes, Tansen’s plan worked. His singing made the environment hot. Flames shot up and lighted the lamps. Just then, the two girls started singing Raga Megh. The rains came down suddenly and saved Tansen’s life?

Question 10.
Are you interested in music? Do you like classical music? Name a few distinguished Indian musicians.
Answer:
Yes, I am very much interested in classical music. We own the legacy of many Indian musicians who
have contributed to the music and have excelled in their field. Few of them are Ravi Shankar, Zakir Hussain, Bhimsen Joshi, Amjad Ali Khan, Vilayut Khan and Pandit Jasraj.

The Wonder Called Sleep Extra Questions and Answers Class 6 English A Pact with the Sun

January 17, 2022

Here we are providing The Wonder Called Sleep Extra Questions and Answers Class 6 English A Pact with the Sun, Extra Questions for Class 6 English was designed by subject expert teachers. https://ncertmcq.com/extra-questions-for-class-6-english/

The Wonder Called Sleep Extra Questions and Answers Class 6 English A Pact with the Sun

The Wonder Called Sleep Extra Questions and Answers Short Answer Type

The Wonder Called Sleep Extra Questions Class 6 Question 1.
What is sleep? Why is it necessary to enjoy sound sleep?
Answer:
Sleep is a state of rest. Sleep gives rest to our tired body. After a good sleep we feel fresh, alert and active.

Extra Questions Of The Wonder Called Sleep Class 6 Question 2.
What happens to our body when we are asleep?
Answer:
Our body starts relaxing. Our muscles relax and our body temperatures falls. Our heartbeat becomes slower. The ever-active brain also slows down.

The Wonder Called Sleep Class 6 Extra Questions And Answers Question 3.
What is a dream?
Answer:
Dream is an activity of the mind that takes place only when we are asleep. It helps in having sound sleep.

The Wonder Called Sleep Class 6 Question 4.
Why we tend to forget dreams?
Answer:
Some dreams are probable. It means that many of the things that happen in dreams could happen when we are awake. But other dreams are improbable.

The Wonder Called Sleep Question Answer Class 6 Question 5.
What is a myth about dreams?
Answer:
The myth about dreams is that it tell the future.

Question 6.
What have certain doctors found about dreams?
Answer:
Certain doctors think that our dreams can provide a key to the solution of problems.

Question 7.
Why does the author call sleep a wonder?
Answer:
The body and brain recover from weariness after a good sleep. Sleep is a state of rest. When we wake up, we feel fresh. We also become alert and ready for the normal activities of the day.

Question 8.
Why having a dream is significant?
Answer:
Dreams are important because they help us to sleep even through noise. Some doctors say that one’s dreams can suggest solutions to one’s problem or tell the future.

The Wonder Called Sleep Extra Questions and Answers Long Answer Type

Question 1.
‘Nature is a great healer’ Elaborate.
Answer:
When one sleeps, he relaxes his body and mind. To rejuvenate, sleep plays a major role. Everything in nature happens for a cause. If everything happens naturally it is understood properly, lot of issues and problem will be settled automatically. Thus, nature is .a teacher and a great healer.

Question 2.
‘The lullaby of grandmother helps in deep sleep’. How does it helps in personality development?
Answer:
Sleep relaxes body and muscle. Lullaby’s of mother and grandmother comforts a child with music to the extent they goes into sleep. Children who listen to the lullaby’s have stronger personalities. The discipline and virtue of respect in relationships grows with time in these children.

Question 3.
What is the most obvious advantage of sleep?
Answer:
The most obvious advantage of sleep is that it gives rest to our tired body. After a good sleep we become alert and active again for the day’s work.

Question 4.
What happens to our body when we sleep?
Answer:

Our muscles, relax.
Our heart beat become slower.
Our temperature and blood pressure go down.
The activity of the brain slows down.

Question 3.
Define a dream in your own words.
Answer:
A dream is an activity of the mind that takes place when we are asleep.

Question 4.
Why are dreams important? Mention two reasons.
Answer:

Dream help us to sleep through noise or other disturbances.
It can provide a key to the solution of those problems.

Question 5.
Why has sleep been called a wonder?
Answer:
Sleep recovers us from fatigue. It refreshes us from the day’s work. Dreams which we see in sleep help us in many ways.

Question 6.
Describe briefly to the class an importable dream you have ever had.
Answer:
Do yourself.

Question 7.
Grandmother and mothers sing nice little songs while rocking little ones to sleep. Such a song is called a ‘lullaby’. Do you remember a lullaby in your own language? Tell the class in ‘ English what the lullaby says.
Answer:
Do yourself.

The Shepherds Treasure Extra Questions and Answers Class 6 English A Pact with the Sun

January 17, 2022

Here we are providing The Shepherds Treasure Extra Questions and Answers Class 6 English A Pact with the Sun, Extra Questions for Class 6 English was designed by subject expert teachers. https://ncertmcq.com/extra-questions-for-class-6-english/

The Shepherds Treasure Extra Questions and Answers Class 6 English A Pact with the Sun

The Shepherds Treasure Extra Questions and Answers Short Answer Type

The Shepherd’s Treasure Extra Question Answer Class 6 Question 1.
How was the shepherd?
Answer:
The shepherd was poor and uneducated. But he was wise and friendly. He lived in a cave.

The Shepherds Treasure Extra Question Answer Class 6 Question 2.
Why did the king go to the cave?
Answer:
The stories of the wisdom and friendly nature of the shepherd led the king of Iron to visit his cave.

Extra Questions Of The Shepherd’s Treasure Class 6 Question 3.
What quality of shepherd impressed the king?
Answer:
The king was greatly impressed by the shepherd’s hospitality and generosity.

Shepherd’s Treasure Extra Questions Class 6 Question 4.
What reward did the shepherd get for his qualities?
Answer:
The king was greatly pleased with the shepherd’s gentleness and intelligence. So he appointed him the governor of a small district. Later on the king rewarded the shepherd for his honesty, humility and wisdom. He made the shepherd, a governor of a much bigger district.

The Shepherd’s Treasure Extra Questions Class 6 Question 5.
What was the shepherd carrying in the iron chest?
Answer:
The old blanket was the shepherd’s oldest and the best friend. It could protect him when the king wished to take away his position, power and cloaks.

The Shepherd’s Treasure Summary Class 6 Questions And Answers Question 6.
What is the moral/message of the story?
Answer:
The moral of the story is that honesty, humility and wisdom are great virtues.

Question 7.
How did the other governor try to humiliate the shepherd?
Answer:
The king was pleased with the shepherd’s wisdom and appointed him as a governor. The envious governors poisoned the king’s ear against him. The king agreed to see for himself the jewels in the iron- box. But he found only an old and ordinary blanket. That was his only treasure. This incident enhanced shepherd’s dignity. The other governors felt embarrassed.

The Shepherds Treasure Extra Questions and Answers Long Answer Type

Question 1.
The story of shepherd teaches humanitarian values. Do you agree?
Answer:
The shepherd was an embodiment of wisdom and kindness. He earned the honor bestowed upon him by the king. The king decided to meet him when he heard about the courage and common sense.

The king went in a disguise to him, who greeted him. The shepherd bade him farewell by calling him ‘Your Majesty’. This surprised the king. He made him the governor of a small state. When false accusation was laid on him he gave a reply with poise and dignity.The values that can be learnt from him are honesty, wisdom and compassion.

Question 2.
If you were shepherd, should you be discouraged for having negative people or give a befitting reply. Comment?
Answer:
The popularity of the new governor made the other governors jealous and insecure. They tried to defame him but his truthfulness and honesty helped him in embarking the success.
If I were the shepherd. I would have led an exemplary life like him. I won’t give up before the negative approach of others. One should have ideals in life.

Question 3.
The shepherd hadn’t been to school because
(i) he was very poor.
(ii) there were very few schools in those days.
(iii) he wasn’t interested in studies.
Choose the right answer.
(ii) there were very few schools in those days.

Question 4.
Who visited the shepherd one day, and why?
Answer:
The king of a country visited the shepherd one day because he was famous for his wisdom and friendly nature. The king heard about him, and thought of meeting him to know the truth.

Question 5.
Why did the other governors grow jealous of the shepherd?
Answer:
The common shepherd was appointed as the governor of a small district. He was loved and honoured by the people. His fame spread far and wide. So the governors of other provinces grew jealous of him.

Question 6.
Why was the new governor called to the palace?
Answer:
The jealous governors reported that the new governor was dishonest, and he always carried his treasure in an iron chest. So the new governor was called to the palace because the king wanted to know the secret of the iron chest.

Question 7.
Why was everyone delighted to see the iron chest on the camel’s back?
Answer:
Everyone was delighted to see the iron chest fastened securely behind him on the camel’s back. The councillors had warned the king that he was dishonest and stored all the treasures that he collected in the iron chest. They were convinced that he had brought the iron chest with him it would be opened and his dishonestly would be revealed to the king.

Question 8.
(i) What did the iron chest contain?
(ii) Why did the shepherd always carry it?
(iii) Is it an example of the shepherd’s humility or wisdom or both?
Answer:
(i) The iron chest contained an old blanket.
(ii) The shepherd always carried it because it was his oldest friend and it could always protect him even when king took away his new cloaks.
(iii) It is an example of both shepherd’s humility and wisdom.

Question 9.
How did the king reward the new governor?
Answer:
The king was highly pleased with the new governor’s humility and honesty. He rewarded him with a promotion. He made him the governor of a much bigger province the same day.

The Old-Clock Shop Extra Questions and Answers Class 6 English A Pact with the Sun

January 17, 2022

Here we are providing The Old-Clock Shop Extra Questions and Answers Class 6 English A Pact with the Sun, Extra Questions for Class 6 English was designed by subject expert teachers. https://ncertmcq.com/extra-questions-for-class-6-english/

The Old-Clock Shop Extra Questions and Answers Class 6 English A Pact with the Sun

The Old-Clock Shop Extra Questions and Answers Short Answer Type

The Old Clock Shop Extra Questions Class 6 Question 1.
Ray was a handicapped, how was he managing his customers?
Answer:
Ray was the owner of an old clock shop. He was deaf and dumb. He communicated with his customers by writing on a notepad.

The Old-Clock Shop Extra Questions Class 6 Question 2.
Who came to the shop at the time of closing?
Answer:
The two persons came to Ray’s shop just before the shop closed. One was young and the other was older one was nearly fifty. They had an evil plan to, rob Ray of his cash.’’

The Old Clock Shop Extra Question Answer Class 6 Question 3.
What was the intention of the intruders?
Answer:
The two persons visiting Ray’s shop were in dire need of money. They were ready to take away Ray’s cash by force.

The Old-Clock Shop Questions And Answers Class 6 Question 4.
How did Ray handle the two shoppers?
Answer:
Ray observed that two men hadn’t come to buy anything. Ray hide his growing fear and he kept cool. He paid fifty dollars in exchange for an old watch. That pleased the man. He said ‘Merry Christmas’ to Ray before he walked out of the shop.

Extra Questions Of The Old Clock Shop Class 6 Question 5.
What message did the old clocks impart?
Answer:
The old clocks and timepieces in Ray’s shop chimed all together. They spread the message of peace on earth and goodwill towards all.

The Old-Clock Shop Pdf Questions And Answers Class 6 Question 6.
‘Ray was an inspiration’. How?
Answer:
Ray was an old and deaf owner of an old clock shop. He repaired and sold old clocks. He communicated with his customers using pen and paper. He was wise, generous and helpful also. He overpaid his visitors in need. He sent away the unfriendly visitors quite happy.

The Old Clock Shop Question Answer Class 6 Question 7.
How did the old clock give a timeless message through Ray?
Answer:
Ray was an old and deaf dealer in old clocks. He also used to pay to the needy customers against the security of their old clocks. Two visitors came to his shop when he was going to pull the shutter down. He doubted their intentions. But he kept his cool. He offered them fifty dollars for an old clock. He did so as a gesture of goodwill and peace. The timepiece rang out a musical message filled with hope. All the three persons who stood in the shop heard the timeless message of peace on earth and goodwill towards all.

The Old-Clock Shop Extra Questions and Answers Long Answer Type

The Old Clock Shop Class 6 Extra Questions And Answers Question 1.
“A single person can bring change in life”. Discuss in light of the lesson.
Answer:
Although Ray was deaf, his observation was impeccable. He understood the purpose of his customers and was scared. Yet, he managed to hold his fear and responded in a friendly manner. He was generous, understanding, congenial in nature. These habits enabled him to win over the unfriendly customers. His warmth melted the hearts of the two men. So a good person makes an everlasting impression on minds of many.

Question Answer Of The Old Clock Shop Class 6 Question 2.
What is more important in life to be rich – or helping humanity? Give your opinion.
Answer:
A person can accumulate wealth through various means. But if he is not a good person, fall of his character can be very obvious and then he won’t get support of anybody. Moreover, he would be deserted by his own people. Whereas, a person who contributes to the goodwill and welfare of humanity, He may not be rich in monetary terms becomes rich in winning hearts. So in my opinion, a person should work for common good.

Question 3.
What made Ray think the visitor was not really a shopper?
Answer:
Ray’s old, wise eyes told him that visitor was not a shopper because there was no sign of friendliness in his eyes and his other friend remained at the door.

Question 4.
Why did visitors come to the shop?
Answer:
The visitor had not come to the shop to buy anything. Perhaps his intention was to loot the owner of his cash. He was in dire need of money.

Question 5.
How did Ray communicate with him?
Answer:
Ray was deaf. So he used notepad and a pencil. He wrote on the notepad. The visitor also wrote his reply on paper.

Question 6.
What do you think the man said to his friend who waited at the door?
Answer:
The man must have communicated to his friend what Ray had communicated to him by shaking his head and pointing to his ears. So the man perhaps told his friend that the owner of that shop was deaf and dumb.

Question 7.
Ray was not a pawnbroker. Why then did he lend money to people in exchange for their old watches and clocks?
Answer:
Ray was not a pawnbroker, a person who lends money on security of some item. He did not lend money on interest. He was, however, kind and helpful. He couldn’t say ‘No’ to the needy people.

Question 8.
“The watch was nothing special and yet had great powers”. In what sense did it have ‘great powers’?
Answer:
The watch was ordinary. But it had the power to pull a person out of difficult situation. The stranger got money he needed and Ray the shopkeeper also escaped from any injury. So in this sense the watch had great powers.

Question 9.
Do you think the man would ever come back to pick up the watch?
Answer:
Yes, I think that the man would return to pick up the watch. Before leaving the shop, he himself wrote that he would return to pick up the watch and also he was grateful to Mr Ray and must be touched by his kindness.

Question 10.
When did “the unfriendly face” of the visitor turn truly friendly?
Answer:
The unfriendly face of the visitor turn truly friendly when Ray gave fifty dollar note for his ordinary watch which was not worth that much. Also he was surprised to know that Mr Ray was deaf and dumb and ready to help him.

The Friendly Mongoose Extra Questions and Answers Class 6 English A Pact with the Sun

January 17, 2022

Here we are providing The Friendly Mongoose Extra Questions and Answers Class 6 English A Pact with the Sun, Extra Questions for Class 6 English was designed by subject expert teachers. https://ncertmcq.com/extra-questions-for-class-6-english/

The Friendly Mongoose Extra Questions and Answers Class 6 English A Pact with the Sun

The Friendly Mongoose Extra Questions and Answers Short Answer Type

The Friendly Mongoose Extra Question Answer Question 1.
What was the farmer’s reason of having a pet?
Answer:
The farmer wanted the boy to have a companion when he grow up. So he decided to bring home a pet to give his son company.

The Friendly Mongoose Question Answer Question 2.
How was the farmer’s child saved by the mongoose?
Answer:
The mongoose saved the life of the farmer’s son from a deadly cobra. He killed the snake. He sacrificed his life.

Extra Questions Of The Friendly Mongoose Question 3.
What did the mongoose do when someone comes home?
Answer:
The mongoose used to ran to the door to welcome the farmer’s wife when she returned home. He sat outside the house waiting for her. It was customary.

The Friendly Mongoose Class 6 Extra Questions And Answers Question 4.
Why was farmer’s wife angry?
Answer:
The sight of blood on the face and paws of the mongoose made the farmer’s wife mad with anger. She took it for granted that the mongooses had killed her son.

The Friendly Mongoose Extra Questions Question 5.
What made the farmer’s wife to repent?
Answer:
The farmer’s wife had gone to the market. She left the baby to the care of her pet, the friendly mongoose. She came back home and saw blood on the face of the pet. Blind with anger, she killed the mongoose. Soon she discovered that her baby was all right and the mongoose had killed a snake and thus saved the baby’s life. She repented and wept. But it was too late.

The Friendly Mongoose Extra Questions and Answers Long Answer Type

The Friendly Mongoose Class 6 Questions And Answers Question 1.
Hasty decision leads to regret’. Comment in the light of the story ‘The friendly Mongoose’.
Answer:
The farmer’s wife has a preconceived notion that the mongoose would not be trusted. Whereas, it saved the child from snake, when farmer’s wife left for market she did not trust her husband’s words. Even though he assured her that mongoose is a sweet friend to their child. But without giving a second thought she acted in haste and killed it. Her imaginary fear and whims had taken a life of an innocent animal. Impulsive action leads to loss of something valuable. So one should think twice before taking an action.

Friendly Mongoose Questions And Answers Question 2.
Animals are more loyal and faithful than human beings. Do you agree?
Answer:
It is considered that human being is intelligent of all animals. However their actions do not justify this statement. Their rash act often leads to accidents. No one think of consequences for their irresponsible and atrocious behaviour. Mongoose in His story performed, his duty and saved the innocent child but it was punished because it failed to convince or change the heart of the lady. One should learn honesty, integrity and loyalty from animals like mongoose.

The Friendly Mongoose Question Answers Question 3.
Why did the farmer bring a baby mongoose into the house?
Answer:
The farmer brought a baby mongoose into his house because they needed a pet so that their son had a companion when he grew up. The baby mongoose can be a pet to their son in the future.

Extra Questions Of Friendly Mongoose Question 4.
Why didn’t the farmer’s wife want to leave the baby alone with the mongoose?
Answer:
The farmer’s wife didn’t want to leave the baby alone with the mongoose because she was afraid that the mongoose would harm him.

The Friendly Mongoose Question And Answer Question 5.
What was the farmer’s comment on his wife’s fears?
Answer:
The farmer understood why his wife was afraid of leaving the baby alone with the mongoose. Therefore, he tried to remove her fear. He said that the mongoose was a friendly animal, as sweet and gentle as their own baby.

Friendly Mongoose Extra Question Answer Question 6.
Why did the farmer’s wife strike the mongoose with her basket?
Answer:
The farmer’s wife strikes the mongoose with her basket because she thought that the mongoose had killed her son.

The Friendly Mongoose Questions And Answers Question 7.
Did she repent her hasty action? How does she show her repentance?
Answer:
She repented her hasty action a great deal. She touched the dead mongoose and cried, “Oh! what have I done? I killed you who had saved my son!” She stared for long at the dead mongoose and sobbed. Do you have a pet a cat or a dog? If not, would you like one? How would you look after it? Are you for or against keeping birds in a cage as pets? I like to have pet animals. I have a dog and I love to play with it. I am against keeping birds in cages as pets.

The Quarrel Extra Questions and Answers Class 6 English Honeysuckle

January 17, 2022

Here we are providing The Quarrel Extra Questions and Answers Class 6 English Honeysuckle, Extra Questions for Class 6 English was designed by subject expert teachers. https://ncertmcq.com/extra-questions-for-class-6-english/

The Quarrel Extra Questions and Answers Class 6 English Honeysuckle

The Quarrel Extra Questions and Answers Short Answer Type

The Quarrel Poem Questions And Answers Class 6 Question 1.
With your partner try to guess the meaning of the underlined phrases.
(i) And somehow we fell out.
(ii) The afternoon turned black.
Answer:
(i) fell out – Quarrelled.
(ii) turned black-was spoiled due to our tense mood.

The Quarrel Poem Extract Questions And Answers Class 6 Question 2.
Read these lines from the poem:
(i) One thing led to another
(ii) The start of it was slight
(iii) The end of it was strong
(iv) The afternoon turned black
(v) Thumped me on the back.
Discuss with your partner what these lines mean.
Answer:
(i) They brother and sister went on arguing.
(ii) The quarrel was started on small issue.
(iii) The quarrel ended bitter note and it turned into a big fight.
(iv) The quarrel spoiled their mood. The afternoon became very sad.
(v) He (brother) patted on her back in a friends manner.

The Quarrel Poem Extra Questions And Answers Class 6 Question 3.
Describe a recent quarrel that you have had with your brother, sister or friend. How did it start? What did you quarrel about? How did it end?
Answer:
After finishing our homework, me and my brother love to watch initial few minutes our fight starts over possessing the remote. It ends when our mother scold us and back us in our room.
Internal Assessment

The Quarrel Extra Questions and Answers Reference of Context

The Quarrel Question Answer Class 6 Question 1.
I quarrelled with my brother
I don’t know what about
One thing led to another
And somehow we fell out.

The start of it was slight
The end of it was strong
He said he was right
I knew he was wrong!

Explanation
The poet writes about the quarrels between her and her brother. The poetess did not know the reason behind their fights. The arguments turn soar. It starts over petty things. He extorts his dominance. The poet rather

Questions
(i) What is the name of the poem and the poet?
(ii) Does the poet know about the reasons of quarrel?
(iii) Give the meaning of‘fell out’.
(iv) Why did it end bitterly?
(v) What kind of relationship siblings share generally?
Answer:
(i) Eleanor Farjeon wrote the poem “The Quarrel’.
(ii) No, the poet does not know the reason of their fight.
(iii) Fight.
(iv) Because both of them think that they are right.
(v) The siblings generally fight with each other.

Class 6 English The Quarrel Questions And Answers Question 2.
I quarrelled with my brother
We hated one another.
The afternoon turned black.
Then suddenly my brother
Thumped me on the back,

And said, “Oh, come along!
We can’t go on all night—
I was in the wrong.”
So he was in the right

Explanation
Both of them even hate each other. One day when the weather was not good, her brother patted her at the back as he decided to give up fight with her. He said that there is no point in having a bitter relationship with her. And the poet agreed to her brother when he took the responsibility of his wrong doings.

Questions
(i) What kind of relationship do they share?
(ii) Why did the brother patted on her back?
(iii) What was the intention of her brother?
(iv) Give the meaning of ‘thumped’.
(v) Why does it ‘turn black’?
Answer:
(i) They both hate each other.
(ii) The brother patted at her back to talk to her.
(iii) He wanted to ‘patch up’ with his sister.
(iv) Hit heavily.
(v) It means that their fight turned soar.

The Wonderful Words Extra Questions and Answers Class 6 English Honeysuckle

January 17, 2022

Here we are providing The Wonderful Words Extra Questions and Answers Class 6 English Honeysuckle, Extra Questions for Class 6 English was designed by subject expert teachers. https://ncertmcq.com/extra-questions-for-class-6-english/

The Wonderful Words Extra Questions and Answers Class 6 English Honeysuckle

The Wonderful Words Extra Questions and Answers Short Answer Type

In groups of four discuss the following lines and their meanings.

The Wonderful Words Extra Questions And Answers Question 1.
All that you-do is match the words
To the brightest thoughts in your head
Answer:
You need to find the accurate words which seem to translate your best thoughts.

The Wonderful Words Poem Extra Questions And Answers Question 2.
For many of the loveliest things
Have never yet been said
Answer:
The poet encourage readers to convert their thoughts into words and speak them as there are loveliest things that never yet been said.

The Wonderful Words Poem Questions And Answers Question 3.
And everyone’s longing today to hear
Some fresh and beautiful thing
Answer:
If you want to express your thought, you will find many eager listeners. Everyone is very eager to hear something new and beautiful.

The Wonderful Words Class 6 Extra Questions Question 4.
But only words can free a thought
From its prison behind your eyes
Answer:
You have thoughts in your mind but its in prison behind your eyes. You need to free your thoughts from the prison by giving them word.

The Wonderful Words Extra Questions and Answers Reference to Context

Wonderful Words Extra Questions Question 1.
All that you do is match the words
To the brightest thoughts in your head
So that they come out clear and true
And handsomely groomed and fed
For many of the loveliest things
Have never yet been said.

Explanation
One’s actions must match with the bright thought that flashes in one’s mind, expressing that idea or thought. The proper usage of words decorates that idea masses. A lot more is needed to be done and expressed. There is always a scope spheres. Which is yet untouched and undiscovered.

(i) How brightest thought’ can be expressed?
(ii) What can come out ‘clear and true’?
(iii) Why is that the thought needs to be groomed?
(iv) Explain ‘Have never yet been said’.
(v) Change the word ‘handsome’ to adverb.
Answer:
(i) The thought can come out clear and true.
(ii) The thought can come out clear and true.
(iii) The thought needs to be groomed for better understanding.
(iv) The poet explains that a lot of thoughts did not come out as they were not expressed in language
(v) Handsomely.

The Wonderful World Poem Questions And Answers Question 2.
Words are the food and dress of thought
They give it its body and swing
And everyone’s longing today to hear
Some fresh and beautiful thing;
But only words can free a thought
From its prison behind your eyes
May be your mind is holding now
A marvellous new surprise!

Explanation
Words are the food for thought and decorates one’s thought. Proper shapes are given to ideas. Everyone wish to hear new and interesting things that are appealing and soothes to the ears of the listeners. The poet emphasized on the importance of expression through words. New and innovative ideas keep coming and may prove to be fruitful for humanity in general.

(i) How can be words the ‘food and dress’?
(ii) What do everyone wish for?
(iii) What is imprisoned behind the eyes?
(iv) What does the poet pray for?
(v) Find out the antonym of‘Marvellous’.
Answer:
(i) The words are food and dress as they feed and decorate one’s thought.
(ii) Everyone wish to hear something about fresh and beautiful things.
(iii) A thought is imprisoned behind the eyes.
(iv) The poet prays for expression of some surprise idea.
(v) ‘Ordinary’.

Beauty Extra Questions and Answers Class 6 English Honeysuckle

January 17, 2022

Here we are providing Beauty Extra Questions and Answers Class 6 English Honeysuckle, Extra Questions for Class 6 English was designed by subject expert teachers. https://ncertmcq.com/extra-questions-for-class-6-english/

Beauty Extra Questions and Answers Class 6 English Honeysuckle

Beauty Extra Questions and Answers Short Answer Type

Beauty Poem Class 6 Questions And Answers Question 1.
The poet says, “Beauty is heard in …”
Can you hear beauty? Add a sound that you think is beautiful to the sounds the poet thinks are beautiful. –
The poet, Keats, said:
Heard melodies are sweet,
But those unheard are sweeter.
What, do you think this means? Have you ever ‘heard’ a song in your head, long after the song was sung or played?
Answer:
The sound of a child’s laughter is also beautiful.
Keats means that poems that one keeps on chanting in his mind are a greater source of happiness than the one which is heard from someone.
Yes, it is true we often keep on hearing a beautiful song long after the singer has stopped singing.

Beauty Poem Class 6 Extra Questions And Answers Question 2.
Read the first and second stanzas of the poem again. Note the following phrases, corn growing, people working or dancing, wind sighing, rain falling, a singer chanting These could be written as
• corn that is growing
• people who are working or dancing
Can you rewrite the other phrases like this? Why do you think the poet uses the shorter phrases?
Answer:
Wind that is sighing
rain that is falling
a singer who is chanting
The poet uses the shorter phrases to enhance its beauty and for creating musical effect.

Class 6 English Poem Beauty Extra Question Answer Question 3.
Find pictures of beautiful things you have seen or heard of.
Answer:
Please find those pictures yourself.

Beauty Poem Extra Questions And Answers Question 4.
Write a paragraph about beauty. Use your own ideas along with the ideas in the poem. (You may discuss ideas with your partner)
Answer:
A beautiful thing brings smile in face of every one that sees or feels it. A beautiful blessing of nature or lap of mother, cuddling of sibling, reading about great people give happiness and endless immortal feel. In the nature everyone has different kind of beauty. It depends on one’s perspective that how he or she see takes it.

Beauty Extra Questions and Answers Reference of Context

Beauty Poem Questions And Answers Class 6 Question 1.
Beauty is seen
In the sunlight,
The trees, the birds,
Corn growing and people working
Or dancing for their harvest.

Explanation
Beauty is all around us it can be felt and seen in the ‘natures’ gifts like , trees, birds etc. growing of com, blooming of a fruit laden plant from a seed, and in tilling the harvest make them to dance to show their messiest.

(i) Where can beauty be seen?
(ii) What are the beautiful things?
(iii) What is the reason of dancing in the poem?
(iv) What is the noun form of ‘grow’?
(v) What is the meaning of “harvest’?
Answer:
(i) Beauty can be seen in daylight, trees, birds etc.
(ii) The beautiful things are trees, birds, harvest and dancing of workers that worked hard.
(iii) The harvest is the yield of tiresome end over of the workers. So they dance in happiness.
(iv) Growth.
(v) Cut and collect crop.

Beauty Poem Class 6 Question 2.
Beauty is heard
In the night,
Wind sighing, rain falling,
Or a singer chanting
Anything in earnest.

Explanation
Beauty can be witnessed and experienced at night also blowing of breeze, falling of rain drops. Anything done with a sincere endeavour can be noticed at the night. Lyrical singers get attention and soothes the soul at night.

(i) What does the poet mean by ‘beauty heard in the night’?
(ii) What can be heard at night?
(iii) Why is it so that one can listen clearly at night?
(iv) What is the impact of the sounds?
(v) What is the antonym of‘earnest’?
Answer:
(i) The poet says that as one cannot see at night, yet the sounds can be heard.
(ii) Melodious sound of wind sighing, falling of rain drop and singing of songs can be heard at night.
(iii) Because most of the activities takes place in the day, comes at halt. So it is easy to listen to the sounds.
(iv) The sounds brings peace and are harmonious to the nature.
(v) Insincere.

Beauty Extra Questions Class 6 Question 3.
Beauty is in yourself.
Good deeds, happy thoughts
That repeat themselves
In your dreams,
In your work,
And even in your rest.

Explanation
The poet affirms that beauty lies in eyes of beholders. Great works and happiness done with good intention stays in mind. Their impact is impeccable. It reflects through ones action.
A person can have good and comfortable sleep when he is satisfied in life.

(i) What do you understand by ‘Beauty is in yourself?
(ii) How do ‘Good deeds’ repeat in dream?
(iii) What is the meaning of‘deeds’?
(iv) What is the name of the poem?
(v) Write the name of the poet.
Answer:
(i) Beauty is deep within a person. It is reflected through his action and thoughts.
(ii) A person’s action and its impacts stay in his thoughts. So dream reflect what he perceives.
(iii) ‘A conscious effort’.
(iv) The name of the poem is ‘Beauty’.
(v) The poet name is ‘E-Yeh-Shure’.