## RS Aggarwal Class 6 Solutions Chapter 2 Factors and Multiples Ex 2F

These Solutions are part of RS Aggarwal Solutions Class 6. Here we have given RS Aggarwal Solutions Class 6 Chapter 2 Factors and Multiples Ex 2F.

**Other Exercises**

- RS Aggarwal Solutions Class 6 Chapter 2 Factors and Multiples Ex 2A
- RS Aggarwal Solutions Class 6 Chapter 2 Factors and Multiples Ex 2B
- RS Aggarwal Solutions Class 6 Chapter 2 Factors and Multiples Ex 2C
- RS Aggarwal Solutions Class 6 Chapter 2 Factors and Multiples Ex 2D
- RS Aggarwal Solutions Class 6 Chapter 2 Factors and Multiples Ex 2E
- RS Aggarwal Solutions Class 6 Chapter 2 Factors and Multiples Ex 2F

**Objective Questions**

**Tick the correct answer in each of the following :**

**Question 1.**

**Solution:**

(c) Because sum of its digits is 8 + 3 + 4 + 7 + 9 + 5 + 6 + 0 = 42 which is divisible by 3.

**Question 2.**

**Solution:**

(a) Because sum of its digits is 8 + 5 + 7 + 6 + 9 + 0 + 1 = 36 which is divisible by 9.

**Question 3.**

**Solution:**

(d) Because the number formed by tens and ones digits is divisible by 4 i.e. 32 ÷ 4 = 8.

**Question 4.**

**Solution:**

(b) Because the number formed by hundred, tens and ones digits is divisible by 8 i.e. 176 ÷ 8 = 22.

**Question 5.**

**Solution:**

(a) Because its one digit is divisible by 2 and sum of its digits is 8 + 7 + 9 + 0 + 4 + 3 + 2 = 33,

which is divisible by 3. Hence it is divisible by 6.

**Question 6.**

**Solution:**

(c) Because the difference of the sums of its odd places digits and of its even places digits is (2 + 2 + 2 + 2) – (2 + 2 + 2 + 2) i.e. 8 – 8 = 0, which is zero and is divisible by 11.

**Question 7.**

**Solution:**

(d) Because 97 has no factors other than 1 and itself.

**Question 8.**

**Solution:**

(c) Because 179 has no factors other than 1 and itself.

**Question 9.**

**Solution:**

(c) Because 263 has no factors other than 1 and itself.

**Question 10.**

**Solution:**

(a), (b) Because the common factors of 9 and 10 are none but 1.

**Question 11.**

**Solution:**

(c) Because 32 has factors which are 2, 2, 2, 2, 2.

**Question 12.**

**Solution:**

(d) Because 18 is the highest common factor of 144 and 198.

**Question 13.**

**Solution:**

(a) Because 12 is the highest common factors of these numbers 144, 180 and 192.

**Question 14.**

**Solution:**

(b) Because 161 and 192 have no common factor other than 1, i.e., HCF of 161 and 192 is 1.

**Question 15.**

**Solution:**

(d) Because HCF of 289 and 391 is 289

and \(\frac { 289\div 17 }{ 391\div 17 } \) = \(\\ \frac { 17 }{ 23 } \)

**Question 16.**

**Solution:**

(d) Because dividing 134 and 167 by 33 remainder is 2 in each case.

**Question 17.**

**Solution:**

(c) Because 360 is the least multiple of 24, 36 and 40.

**Question 18.**

**Solution:**

(d) Because 540 is the least multiple of 12, 15, 20 and 27

**Question 19.**

**Solution:**

(c) Because 1263 – 3 = 1260 is divisible by 14, 28, 36 and 45.

**Question 20.**

**Solution:**

(c) Because HCF of two co-prime number is always 1.

**Question 21.**

**Solution:**

(c) Because HCF of a and b, two co-primes is 1.

LCM = a x b = ab.

**Question 22.**

**Solution:**

(c) Because LCM of two numbers = Product of these number ÷ their HCF i.e 2160 ÷ 12 = 180.

**Question 23.**

**Solution:**

(b) Because second number

= \( \frac { LCM\times HCF }{ 1st\quad number } \)

i.e., \(\\ \frac { 145\times 2175 }{ 725 } \)

= 435

**Question 24.**

**Solution:**

(c) Because LCM of 15, 20, 24. 32 and 36 = 1440.

**Question 25.**

**Solution:**

(d) Because LCM of 9, 12, 15 is 180. 180

180 minutes = \(\\ \frac { 180 }{ 60 } \)

= 3 hours.

Hope given RS Aggarwal Solutions Class 6 Chapter 2 Factors and Multiples Ex 2F are helpful to complete your math homework.

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