RS Aggarwal Class 6 Solutions Chapter 5 Fractions Ex 5A

These Solutions are part of RS Aggarwal Solutions Class 6. Here we have given RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5A.

Other Exercises

Question 1.
Solution:
(i) \(\\ \frac { 3 }{ 4 } \)
(ii) \(\\ \frac { 1 }{ 4 } \)
(iii) \(\\ \frac { 2 }{ 3 } \)
(iv) \(\\ \frac { 3 }{ 10 } \)
(v) \(\\ \frac { 4 }{ 9 } \)
(vi) \(\\ \frac { 3 }{ 8 } \)

Question 2.
Solution:
In the figure, \(\\ \frac { 4 }{ 9 } \) is shaded
RS Aggarwal Class 6 Solutions Chapter 5 Fractions Ex 5A 2.1

Question 3.
Solution:
In the figure, whole rectangle is not divided into four equal parts.

Question 4.
Solution:
(i) Three-fourths = \(\\ \frac { 3 }{ 4 } \)
(ii) Four-sevenths = \(\\ \frac { 4 }{ 7 } \)
(iii) Two-fifths = \(\\ \frac { 2 }{ 5 } \)
(iv) Three-tenths = \(\\ \frac { 3 }{ 10 } \)
(v) One-eighth = \(\\ \frac { 1 }{ 8 } \)
(vi) three-tenths = \(\\ \frac { 5 }{ 6 } \)
(vii) five-sixths = \(\\ \frac { 8 }{ 9 } \)
(vii) seven-twelfths = \(\\ \frac { 7 }{ 12 } \)

Question 5.
Solution:
(i) In \(\\ \frac { 4 }{ 9 } \), numerator is 4 and denominator is 9.
(ii) In \(\\ \frac { 6 }{ 11 } \), numerator is 6 and denominator is 11.
(iii) In \(\\ \frac { 8 }{ 15 } \), numerator is 8 and denominator is 15.
(iv) In \(\\ \frac { 12 }{ 17 } \), numerator is 12 and denominator is 17.
(v) \(\\ \frac { 5 }{ 1 } \) , numerator is 5 and denominator is 1.

Question 6.
Solution:
(z) Numerator = 3, Denominator = 8, then fraction = \(\\ \frac { 3 }{ 8 } \).
(ii) Numerator = 5, Denominator = 12, then fraction = \(\\ \frac { 5 }{ 12 } \)
(iii) Numerator = 7, Denominator = 16, then fraction = \(\\ \frac { 7 }{ 16 } \).
(iv) Numerator = 8, Denominator = 15, then fraction = \(\\ \frac { 8 }{ 15 } \)

Question 7.
Solution:
(i) \(\\ \frac { 2 }{ 3 } \) = two-thirds
(ii) \(\\ \frac { 4 }{ 9 } \) = four-ninths
(iii) \(\\ \frac { 2 }{ 5 } \) = two-fifths
(iv) \(\\ \frac { 7 }{ 10 } \) = seven-tenths
(v) \(\\ \frac { 1 }{ 3 } \) = one-thirds
(vi) \(\\ \frac { 3 }{ 4 } \) = three-fourth
(vii) \(\\ \frac { 3 }{ 8 } \) = three-eighths
(viii) \(\\ \frac { 9 }{ 14 } \) = nine-fourteenths
(ix) \(\\ \frac { 5 }{ 11 } \) = five-elevanths
(x) \(\\ \frac { 6 }{ 15 } \) = six-fifteenths

Question 8.
Solution:
24 minutes is the fraction of 1 hour i.e.,
60 minutes = \(\\ \frac { 24 }{ 60 } \)

Question 9.
Solution:
Natural number between 2 to 10 are 2, 3, 4, 5, 6, 7, 8, 9, 10 = 9
Out of these prime number are 2, 3, 5, 7 = 4
Fraction = \(\\ \frac { 4 }{ 9 } \)

Question 10.
Solution:
(i) \(\\ \frac { 2 }{ 3 } \) of 15 pens = \(\\ \frac { 2 }{ 3 } \) x 15 = 2 x 5 = 10 pens.
(ii) \(\\ \frac { 2 }{ 3 } \) of 27 balls = \(\\ \frac { 2 }{ 3 } \) x 27 = 2 x 9 = 18 balls.
(iii) \(\\ \frac { 2 }{ 3 } \) of 36 balloons = \(\\ \frac { 2 }{ 3 } \) x 36 = 2 x 12 = 24 balloons. Ans.

Question 11.
Solution:
(i) \(\\ \frac { 3 }{ 4 } \) of 16 cups = \(\\ \frac { 3 }{ 4 } \) x 16 = 3 x 4
= 12 cups.
(ii) \(\\ \frac { 3 }{ 4 } \) of 28 rackets = \(\\ \frac { 3 }{ 4 } \) x 28 = 3 x 7
= 21 rackets.
(iii) \(\\ \frac { 3 }{ 4 } \) of 32 books = \(\\ \frac { 3 }{ 4 } \) x 32 = 3 x 8
= 24 books. Ans.

Question 12.
Solution:
Total number of pencils Neelam has = 25
No. of pencils given to Meena
= \(\\ \frac { 4 }{ 5 } \) of 25
= \(\\ \frac { 4 }{ 5 } \) x 25 – 20
No. of pencils left with Neelam = 25 – 20 = 5

Question 13.
Solution:
(i) \(\\ \frac { 3 }{ 8 } \)
Take a line segment OA = one unit of length
Divide it into 8 equal parts and take 3 parts at P, then P represents \(\\ \frac { 3 }{ 8 } \).
RS Aggarwal Class 6 Solutions Chapter 5 Fractions Ex 5A 13.1
(ii) \(\\ \frac { 5 }{ 9 } \)
(a) Take a line segment OA = one unit of length.
(b) Divide it into nine equal parts and take 5 parts at P, then P represents \(\\ \frac { 5 }{ 9 } \).

(iii) \(\\ \frac { 4 }{ 7 } \)
(a) Take a line segment OA = one unit of length.
(b) Divide it into 7 equal parts and take 4 parts at P then P represents \(\\ \frac { 4 }{ 7 } \).
RS Aggarwal Class 6 Solutions Chapter 5 Fractions Ex 5A 13.3
(iv) \(\\ \frac { 2 }{ 5 } \)
(a) Take a line segment OA = 1 unit of length.
(b) Divide it with 5 equal parts and take 2 parts and P then P represents \(\\ \frac { 2 }{ 5 } \).

(v) \(\\ \frac { 1 }{ 4 } \)
(a) Take a line segment OA = 1 unit of length.
(b) Divide it with 4 equal parts and take 1 parts and P then P represents \(\\ \frac { 1 }{ 4 } \).
RS Aggarwal Class 6 Solutions Chapter 5 Fractions Ex 5A 13.5