## RS Aggarwal Class 6 Solutions Chapter 5 Fractions Ex 5F

These Solutions are part of RS Aggarwal Solutions Class 6. Here we have given RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5F.

Other Exercises

Find the difference:

Question 1.
Solution:
$$\frac { 5 }{ 8 } -\frac { 1 }{ 8 }$$
= $$\\ \frac { 5-1 }{ 8 }$$
= $$\frac { 4 }{ 8 }$$
= $$\frac { 4\div 4 }{ 8\div 4 }$$
= $$\frac { 1 }{ 2 }$$

Question 2.
Solution:
$$\frac { 7 }{ 12 } -\frac { 5 }{ 12 }$$

Question 3.
Solution:
$$4\frac { 3 }{ 7 } -2\frac { 4 }{ 7 }$$
= $$\frac { 31 }{ 7 } -\frac { 18 }{ 7 }$$

Question 4.
Solution:
$$\frac { 5 }{ 6 } -\frac { 4 }{ 9 }$$

Question 5.
Solution:
$$\frac { 1 }{ 2 } -\frac { 3 }{ 8 }$$

Question 6.
Solution:
$$\frac { 5 }{ 8 } -\frac { 7 }{ 12 }$$

Question 7.
Solution:
$$2\frac { 7 }{ 9 } -1\frac { 8 }{ 15 }$$
= $$\frac { 25 }{ 9 } -\frac { 23 }{ 15 }$$
(changing into improper fractions)

Question 8.
Solution:
$$3\frac { 5 }{ 8 } -2\frac { 5 }{ 12 }$$
= $$\frac { 29 }{ 8 } -\frac { 29 }{ 12 }$$

Question 9.
Solution:
$$2\frac { 3 }{ 10 } -1\frac { 7 }{ 15 }$$
= $$\frac { 23 }{ 10 } -\frac { 22 }{ 15 }$$

Question 10.
Solution:
$$6\frac { 2 }{ 3 } -3\frac { 3 }{ 4 }$$
= $$\frac { 20 }{ 3 } -\frac { 15 }{ 4 }$$

Question 11.
Solution:
$$7-5\frac { 2 }{ 3 }$$
= $$\frac { 7 }{ 1 } -\frac { 17 }{ 3 }$$
(changing into improper fractions)

Question 12.
Solution:
$$10-6\frac { 3 }{ 8 }$$
= $$\frac { 10 }{ 1 } -\frac { 51 }{ 8 }$$
(changing into improper fractions)

Simpilify

Question 13.
Solution:
$$\frac { 5 }{ 6 } -\frac { 4 }{ 9 } +\frac { 2 }{ 3 }$$

Question 14.
Solution:
$$\frac { 5 }{ 8 } +\frac { 3 }{ 4 } -\frac { 7 }{ 12 }$$

Question 15.
Solution:
$$2+\frac { 11 }{ 15 } -\frac { 5 }{ 9 }$$
= $$\frac { 90+33-25 }{ 45 }$$
(LCM of 15 and 9 = 45)

Question 16.
Solution:
$$5\frac { 3 }{ 4 } -4\frac { 5 }{ 12 } +3\frac { 1 }{ 6 }$$
= $$\frac { 23 }{ 4 } -\frac { 53 }{ 12 } +\frac { 19 }{ 6 }$$
(changing into improper fractions)

Question 17.
Solution:
$$2+5\frac { 7 }{ 10 } -3\frac { 14 }{ 15 }$$
= $$\frac { 2 }{ 1 } +\frac { 57 }{ 10 } -\frac { 59 }{ 15 }$$
(changing into improper fractions)

Question 18.
Solution:
$$8-3\frac { 1 }{ 2 } -2\frac { 1 }{ 4 }$$
= $$\frac { 8 }{ 1 } -\frac { 7 }{ 2 } -\frac { 9 }{ 4 }$$
(changing into improper fractions)

Question 19.
Solution:
$$8\frac { 5 }{ 6 } -3\frac { 3 }{ 8 } +2\frac { 7 }{ 12 }$$
= $$\frac { 53 }{ 6 } -\frac { 27 }{ 8 } +\frac { 31 }{ 12 }$$
(changing into improper fractions)

Question 20.
Solution:
$$6\frac { 1 }{ 6 } -5\frac { 1 }{ 5 } +3\frac { 1 }{ 3 }$$
= $$\frac { 37 }{ 6 } -\frac { 26 }{ 5 } +\frac { 10 }{ 3 }$$
(changing into improper fractions)

Question 21.
Solution:
$$3+1\frac { 1 }{ 5 } +\frac { 2 }{ 3 } -\frac { 7 }{ 15 }$$
= $$\frac { 3 }{ 1 } +\frac { 6 }{ 5 } +\frac { 2 }{ 3 } -\frac { 7 }{ 15 }$$

Question 22.
Solution:
By subtracting $$9 \frac { 2 }{ 3 }$$ from 19, we get the required number

Question 23.
Solution:
By subtracting $$6 \frac { 7 }{ 15 }$$ from $$8 \frac { 1 }{ 5 }$$ we get the required number

Question 24.
Solution:
Sum of $$3 \frac { 5 }{ 9 }$$ and $$3 \frac { 1 }{ 3 }$$
= $$\frac { 32 }{ 9 } +\frac { 10 }{ 3 }$$

Question 25.
Solution:
$$\\ \frac { 3 }{ 4 }$$, $$\\ \frac { 5 }{ 7 }$$

Question 26.
Solution:
Milk bought by Mrs. Soni = $$7 \frac { 1 }{ 2 }$$ litres
and milk consumed by here = $$5 \frac { 3 }{ 4 }$$ litres

Question 27.
Solution:
Total time of film show = $$3 \frac { 1 }{ 3 }$$ hours
Total spent on advertisement = $$1 \frac { 3 }{ 4 }$$ hours
Duration of the film

Question 28.
Solution:
On a day, rickshaw pullar earned

Question 29.
Solution:
Total length of wire =$$2 \frac { 3 }{ 4 }$$-metres
Length of one piece = $$\\ \frac { 5 }{ 8 }$$ metre
Length of the other piece

Hope given RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5F are helpful to complete your math homework.

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