## RS Aggarwal Class 6 Solutions Chapter 5 Fractions Ex 5C

These Solutions are part of RS Aggarwal Solutions Class 6. Here we have given RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5C.

**Other Exercises**

- RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5A
- RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5B
- RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5C
- RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5D
- RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5E
- RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5F
- RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5G

**Question 1.**

**Solution:**

(i) \(\\ \frac { 2 }{ 3 } \)

= \(\\ \frac { 2X2 }{ 3X2 } \)

= \(\\ \frac { 4 }{ 6 } \)

**Question 2.**

**Solution:**

(i) In \(\\ \frac { 5 }{ 6 } \) and \(\\ \frac { 20 }{ 24 } \)

\(\\ \frac { 5 }{ 6 } \) = \(\\ \frac { 20 }{ 24 } \)

**Question 3.**

**Solution:**

Equivalent fraction of \(\\ \frac { 3 }{ 5 } \) having

(i) Denominator = 30 and 30 = 5 x 6

**Question 4.**

**Solution:**

(i) Denominator = 54, and 54 = 9 x 6

**Question 5.**

**Solution:**

Equivalent fraction of \(\\ \frac { 6 }{ 11 } \) having

(i) Denominator = 77 and 77 = 11 = 7

\(\\ \frac { 6 }{ 11 } \)

= \(\\ \frac { 6X7 }{ 11X7 } \)

= \(\\ \frac { 42 }{ 77 } \)

(ii) Numerator = 60 and 60 = 6 x 10

\(\\ \frac { 6 }{ 11 } \)

= \(\\ \frac { 6X10 }{ 11X10 } \)

= \(\\ \frac { 60 }{ 110 } \)

**Question 6.**

**Solution:**

Let \(\\ \frac { 24 }{ 30 } \) = \(\\ \frac { 4 }{ x } \)

In order to get 4, divide 24 by 6,

**Question 7.**

**Solution:**

Equivalent fraction of \(\\ \frac { 36 }{ 48 } \), with

(i) Numerator 9 and 9 = 36 + 4

\(\frac { 36 }{ 48 } =\frac { 36\div 4 }{ 48\div 4 } =\frac { 9 }{ 12 } \)

(ii) Denominator = 4 and 4 = 48 ÷ 12

\(\frac { 36 }{ 48 } =\frac { 36\div 12 }{ 48\div 12 } =\frac { 3 }{ 4 } \)

**Question 8.**

**Solution:**

Equivalent fraction of \(\\ \frac { 56 }{ 70 } \) with

(i) Numerator 4 and = 56 ÷ 14

\(\frac { 56 }{ 70 } =\frac { 56\div 14 }{ 70\div 14 } =\frac { 4 }{ 5 } \)

(ii) Denominator =10 and 10 = 70 ÷ 7

\(\frac { 56 }{ 70 } =\frac { 56\div 7 }{ 70\div 7 } =\frac { 8 }{ 10 } \)

**Question 9.**

**Solution:**

(i) In \(\\ \frac { 9 }{ 15 } \), HCF of 9 and 15 = 3

Now, dividing each term by 3, we get:

\(\frac { 9 }{ 15 } =\frac { 9\div 3 }{ 15\div 3 } =\frac { 3 }{ 5 } \)

**Question 10.**

**Solution:**

We know that a fraction is in its simplest form if its HCF of numerator and denominator is 1.

**Question 11.**

**Solution:**

Hope given RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5C are helpful to complete your math homework.

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