RS Aggarwal Class 6 Solutions Chapter 5 Fractions Ex 5F
These Solutions are part of RS Aggarwal Solutions Class 6. Here we have given RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5F.
Other Exercises
- RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5A
- RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5B
- RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5C
- RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5D
- RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5E
- RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5F
- RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5G
Find the difference:
Question 1.
Solution:
\frac { 5 }{ 8 } -\frac { 1 }{ 8 }
= \\ \frac { 5-1 }{ 8 }
= \frac { 4 }{ 8 }
= \frac { 4\div 4 }{ 8\div 4 }
= \frac { 1 }{ 2 }
Question 2.
Solution:
\frac { 7 }{ 12 } -\frac { 5 }{ 12 }
Question 3.
Solution:
4\frac { 3 }{ 7 } -2\frac { 4 }{ 7 }
= \frac { 31 }{ 7 } -\frac { 18 }{ 7 }
Question 4.
Solution:
\frac { 5 }{ 6 } -\frac { 4 }{ 9 }
Question 5.
Solution:
\frac { 1 }{ 2 } -\frac { 3 }{ 8 }
Question 6.
Solution:
\frac { 5 }{ 8 } -\frac { 7 }{ 12 }
Question 7.
Solution:
2\frac { 7 }{ 9 } -1\frac { 8 }{ 15 }
= \frac { 25 }{ 9 } -\frac { 23 }{ 15 }
(changing into improper fractions)
Question 8.
Solution:
3\frac { 5 }{ 8 } -2\frac { 5 }{ 12 }
= \frac { 29 }{ 8 } -\frac { 29 }{ 12 }
Question 9.
Solution:
2\frac { 3 }{ 10 } -1\frac { 7 }{ 15 }
= \frac { 23 }{ 10 } -\frac { 22 }{ 15 }
Question 10.
Solution:
6\frac { 2 }{ 3 } -3\frac { 3 }{ 4 }
= \frac { 20 }{ 3 } -\frac { 15 }{ 4 }
Question 11.
Solution:
7-5\frac { 2 }{ 3 }
= \frac { 7 }{ 1 } -\frac { 17 }{ 3 }
(changing into improper fractions)
Question 12.
Solution:
10-6\frac { 3 }{ 8 }
= \frac { 10 }{ 1 } -\frac { 51 }{ 8 }
(changing into improper fractions)
Simpilify
Question 13.
Solution:
\frac { 5 }{ 6 } -\frac { 4 }{ 9 } +\frac { 2 }{ 3 }
Question 14.
Solution:
\frac { 5 }{ 8 } +\frac { 3 }{ 4 } -\frac { 7 }{ 12 }
Question 15.
Solution:
2+\frac { 11 }{ 15 } -\frac { 5 }{ 9 }
= \frac { 90+33-25 }{ 45 }
(LCM of 15 and 9 = 45)
Question 16.
Solution:
5\frac { 3 }{ 4 } -4\frac { 5 }{ 12 } +3\frac { 1 }{ 6 }
= \frac { 23 }{ 4 } -\frac { 53 }{ 12 } +\frac { 19 }{ 6 }
(changing into improper fractions)
Question 17.
Solution:
2+5\frac { 7 }{ 10 } -3\frac { 14 }{ 15 }
= \frac { 2 }{ 1 } +\frac { 57 }{ 10 } -\frac { 59 }{ 15 }
(changing into improper fractions)
Question 18.
Solution:
8-3\frac { 1 }{ 2 } -2\frac { 1 }{ 4 }
= \frac { 8 }{ 1 } -\frac { 7 }{ 2 } -\frac { 9 }{ 4 }
(changing into improper fractions)
Question 19.
Solution:
8\frac { 5 }{ 6 } -3\frac { 3 }{ 8 } +2\frac { 7 }{ 12 }
= \frac { 53 }{ 6 } -\frac { 27 }{ 8 } +\frac { 31 }{ 12 }
(changing into improper fractions)
Question 20.
Solution:
6\frac { 1 }{ 6 } -5\frac { 1 }{ 5 } +3\frac { 1 }{ 3 }
= \frac { 37 }{ 6 } -\frac { 26 }{ 5 } +\frac { 10 }{ 3 }
(changing into improper fractions)
Question 21.
Solution:
3+1\frac { 1 }{ 5 } +\frac { 2 }{ 3 } -\frac { 7 }{ 15 }
= \frac { 3 }{ 1 } +\frac { 6 }{ 5 } +\frac { 2 }{ 3 } -\frac { 7 }{ 15 }
Question 22.
Solution:
By subtracting 9 \frac { 2 }{ 3 } from 19, we get the required number
Question 23.
Solution:
By subtracting 6 \frac { 7 }{ 15 } from 8 \frac { 1 }{ 5 } we get the required number
Question 24.
Solution:
Sum of 3 \frac { 5 }{ 9 } and 3 \frac { 1 }{ 3 }
= \frac { 32 }{ 9 } +\frac { 10 }{ 3 }
Question 25.
Solution:
\\ \frac { 3 }{ 4 } , \\ \frac { 5 }{ 7 }
Question 26.
Solution:
Milk bought by Mrs. Soni = 7 \frac { 1 }{ 2 } litres
and milk consumed by here = 5 \frac { 3 }{ 4 } litres
Question 27.
Solution:
Total time of film show = 3 \frac { 1 }{ 3 } hours
Total spent on advertisement = 1 \frac { 3 }{ 4 } hours
Duration of the film
Question 28.
Solution:
On a day, rickshaw pullar earned
Question 29.
Solution:
Total length of wire =2 \frac { 3 }{ 4 } -metres
Length of one piece = \\ \frac { 5 }{ 8 } metre
Length of the other piece
Hope given RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5F are helpful to complete your math homework.
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