Selina Concise Mathematics Class 10 ICSE Solutions Chapter 24 Measures of Central Tendency Ex 24B

Selina Concise Mathematics Class 10 ICSE Solutions Chapter 24 Measures of Central Tendency (Mean, Median, Quartiles and Mode) Ex 24B

These Solutions are part of Selina Concise Mathematics Class 10 ICSE Solutions. Here we have given Chapter 24 Measures of Central Tendency (Mean, Median, Quartiles and Mode) Ex 24B.

Other Exercises

• Selina Concise Mathematics Class 10 ICSE Solutions Chapter 24 Measures of Central Tendency Ex 24A
• Selina Concise Mathematics Class 10 ICSE Solutions Chapter 24 Measures of Central Tendency Ex 24B
• Selina Concise Mathematics Class 10 ICSE Solutions Chapter 24 Measures of Central Tendency Ex 24C
• Selina Concise Mathematics Class 10 ICSE Solutions Chapter 24 Measures of Central Tendency Ex 24D
• Selina Concise Mathematics Class 10 ICSE Solutions Chapter 24 Measures of Central Tendency Ex 24E

Question 1.
The following table gives the ages of 50 students of a class. Find the arithmetic mean of their ages.

Solution:

Question 2.
The following table gives the weekly wages of workers in a factory.

Calculate the mean by using :
(i) Direct Method
(ii) Short-Cut Method
Solution:
(i) Direct Method:

(ii) Short cut method :

Question 3.
The following are the marks obtained by 70 boys in a class test :

Calculate the mean by :
(i) Short-Cut Method
(ii) Step-Deviation Method.
Solution:
(i) Short cut Method :

(ii) Step – Deviation Method:

Question 4.
Find mean by ‘step-deviation method :

Solution:

Question 5.
The mean of following frequency distribution is 21\(\frac { 1 }{ 7 }\) Find the value of ‘f ‘.

Solution:

Question 6.
Using step-deviation method, calculate the mean marks of the following distribution.

Solution:
Let Assumed mean = 72.5

Question 7.
Using the information given in the adjoining histogram; calculate the mean.
Solution:

Question 8.
If the mean of the following observations is 54, find the value of p.

Solution:
Mean = 54

⇒ 2106 + 54p = 2370 + 30p
⇒ 54p – 30p = 2370 – 2106 ⇒ 24p = 264
p = \(\frac { 264 }{ 24 }\) = 11
Hence p = 11

Question 9.
The mean of the following distribution is 62.8 and the sum of all the frequencies is 50. Find the missing frequencies f₁ and f₂.

Solution:
Mean = 62.8
and sum of frequencies = 50

Question 10.
Calculate the mean of the distribution given below using the short cut method.

Solution:

Question 11.
Calculate the mean of the following distribution :

Solution:

Hope given Selina Concise Mathematics Class 10 ICSE Solutions Chapter 24 Measures of Central Tendency Ex 24B are helpful to complete your math homework.

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