Online Education for RD Sharma Class 10 Solutions Chapter 5 Arithmetic Progressions Ex 5.5

Online Education for RD Sharma Class 10 Solutions Chapter 5 Arithmetic Progressions Ex 5.5

These Solutions are part of Online Education RD Sharma Class 10 Solutions. Here we have given RD Sharma Class 10 Solutions Chapter 5 Arithmetic Progressions Ex 5.5

Other Exercises

Question 1.
Find the value of x for which (8x + 4), (6x – 2) and (2x + 7) are in A.P.
Solution:
(8x + 4), (6x – 2) and (2x + 7) are in A.P.
(6x – 2) – (8x + 4) = (2x + 7) – (6x – 2)
=> 6x – 2 – 8x – 4 = 2x + 7 – 6x + 2
=> -2x – 6 = -4x + 9
=> -2x + 4x = 9 + 6
=> 2x = 15
Hence x = \(\frac { 15 }{ 2 }\)

Question 2.
If x + 1, 3x and 4x + 2 are in A.P., find the value of x.
Solution:
x + 1, 3x and 4x + 2 are in A.P.
3x – x – 1 = 4x + 2 – 3x
=> 2x – 1 = x + 2
=> 2x – x = 2 + 1
=> x = 3
Hence x = 3

Question 3.
Show that (a – b)², (a² + b²) and (a + b)² are in A.P.
Solution:
(a – b)², (a² + b²) and (a + b)² are in A.P.
If 2 (a² + b²) = (a – b)² + (a + b)²
If 2 (a² + b²) = a² + b² – 2ab + a² + b² + 2ab
If 2 (a² + b²) = 2a² + 2b² = 2 (a² + b²)
Which is true
Hence proved.

Question 4.
The sum of three terms of an A.P. is 21 and the product of the first and the third terms exceeds the second term by 6, find three terms.
Solution:
Let the three terms of an A.P. be a – d, a, a + d
Sum of three terms = 21
=> a – d + a + a + d = 21
=> 3a = 21
=> a = 7
and product of the first and 3rd = 2nd term + 6
=> (a – d) (a + d) = a + 6
a² – d² = a + 6
=> (7 )² – d² = 7 + 6
=> 49 – d² = 13
=> d² = 49 – 13 = 36
=> d² = (6)²
=> d = 6
Terms are 7 – 6, 7, 7 + 6 => 1, 7, 13

Question 5.
Three numbers are in A.P. If the sum of these numbers be 27 and the product 648, find the numbers.
Solution:
Let the three numbers of an A.P. be a – d, a, a + d
According to the conditions,
Sum of these numbers = 27
a – d + a + a + d = 27
=> 3a = 27
RD Sharma Class 10 Solutions Chapter 5 Arithmetic Progressions Ex 5.5 1

Question 6.
Find the four numbers in A.P., whose sum is 50 and in which the greatest number is 4 times the least.
Solution:
Let the four terms of an A.P. be (a – 3d), (a – d), (a + d) and (a + 3d)
Now according to the condition,
Sum of these terms = 50
=> (a – 3d) + (a – d) + (a + d) + (a + 3d) = 50
=> a – 3d + a – d + a + d + a – 3d= 50
=> 4a = 50
=> a = \(\frac { 25 }{ 2 }\)
and greatest number = 4 x least number
=> a + 3d = 4 (a – 3d)
=> a + 3d = 4a – 12d
=> 4a – a = 3d + 12d
RD Sharma Class 10 Solutions Chapter 5 Arithmetic Progressions Ex 5.5 2

Question 7.
The sum of three numbers in A.P. is 12 and the sum of their cubes is 288. Find the numbers.
Solution:
RD Sharma Class 10 Solutions Chapter 5 Arithmetic Progressions Ex 5.5 3

Question 8.
Divide 56 in four parts in A.P. such that the ratio of the product of their extremes to the product of their means is 5 : 6. [CBSE 2016]
Solution:
RD Sharma Class 10 Solutions Chapter 5 Arithmetic Progressions Ex 5.5 4
RD Sharma Class 10 Solutions Chapter 5 Arithmetic Progressions Ex 5.5 5

Question 9.
The angles of a quadrilateral are in A.P. whose common difference is 10°. Find the angles.
Solution:
Let the four angles of a quadrilateral which are in A.P., be
a – 3d, a – d, a + d, a + 3d
Common difference = 10°
Now sum of angles of a quadrilateral = 360°
a – 3d + a – d + a + d + a + 3d = 360°
=> 4a = 360°
=> a = 90°
and common difference = (a – d) – (a – 3d) = a – d – a + 3d = 2d
2d = 10°
=> d = 5°
Angles will be
a – 3d = 90° – 3 x 5° = 90° – 15° = 75°
a – d= 90° – 5° = 85°
a + d = 90° + 5° = 95°
and a + 3d = 90° + 3 x 5° = 90° + 15°= 105°
Hence the angles of the quadrilateral will be
75°, 85°, 95° and 105°

Question 10.
Split 207 into three parts such that these are in A.P. and the product of the two smaller parts is 4623. [NCERT Exemplar]
Solution:
Let the three parts of the number 207 are (a – d), a and (a + d), which are in A.P.
Now, by given condition,
=> Sum of these parts = 207
=> a – d + a + a + d = 207
=> 3a = 207
a = 69
Given that, product of the two smaller parts = 4623
=> a (a – d) = 4623
=> 69 (69 – d) = 4623
=> 69 – d = 67
=> d = 69 – 67 = 2
So, first part = a – d = 69 – 2 = 67,
Second part = a = 69
and third part = a + d = 69 + 2 = 71
Hence, required three parts are 67, 69, 71.

Question 11.
The angles of a triangle are in A.P. The greatest angle is twice the least. Find all the angles. [NCERT Exemplar]
Solution:
Given that, the angles of a triangle are in A.P.
RD Sharma Class 10 Solutions Chapter 5 Arithmetic Progressions Ex 5.5 6

Question 12.
The sum of four consecutive numbers in A.P. is 32 and the ratio of the product of the first and last terms to the product of two middle terms is 7 : 15. Find the number. [NCERT Exemplar]
Solution:
RD Sharma Class 10 Solutions Chapter 5 Arithmetic Progressions Ex 5.5 7
or, d = ± 2
So, when a = 8, d = 2,
the numbers are 2, 6, 10, 14.

Hope given RD Sharma Class 10 Solutions Chapter 5 Arithmetic Progressions Ex 5.5 are helpful to complete your math homework.

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Circles Class 10 Extra Questions Maths Chapter 10 with Solutions Answers

Circles Class 10 Extra Questions Maths Chapter 10 with Solutions Answers

Here we are providing Online Education for Circles Class 10 Extra Questions Maths Chapter 10 with Answers Solutions, Extra Questions for Class 10 Maths was designed by subject expert teachers. https://ncertmcq.com/extra-questions-for-class-10-maths/

Online Education Extra Questions for Class 10 Maths Circles with Answers Solutions

Extra Questions for Class 10 Maths Chapter 10 Circles with Solutions Answers

Circles Class 10 Extra Questions Very Short Answer Type

Class 10 Circles Extra Questions Question 1.
If a point P is 17 cm from the centre of a circle of radius 8 cm, then find the length of the tangent drawn to the circle from point P.
Solution:
Circles Class 10 Extra Questions
OA ⊥ PA (∵ radius is ⊥ to tangent at point of contact)
∴ In ∆OAP, we have
PO2 = PA2 + AO2
⇒ (17)2 = (PA)2 + (8)2
(PA)2 = 289 – 64 = 225
⇒ PA = √225 = 15
Hence, the length of the tangent from point P is 15 cm.

Circle Class 10 Extra Questions With Solutions Question 2.
The length of the tangent to a circle from a point P, which is 25 cm away from the centre, is 24 cm. What is the radius of the circle?
Solution:
Class 10 Circles Extra Questions
∵ OQ ⊥ PQ
∴ PQ2 + QO2 = OP2
⇒ 252 = OQ2 + 242
or OQ = √625 – √576
= √49 = 7 cm

Circles Extra Questions Class 10 Question 3.
In Fig. 8.6, ABCD is a cyclic quadrilateral. If ∠BAC = 50° and ∠DBC = 60° then find ∠BCD.
Solution:
Circle Class 10 Extra Questions With Solutions
Here ∠BDC = ∠BAC = 50° (angles in same segment are equal)
In ABCD, we have
∠BCD = 180° – (∠BDC + ∠DBC)
= 180° – (50° + 60°)= 70°

Extra Questions Of Circles Class 10 Question 4.
In Fig. 8.7, the quadrilateral ABCD circumscribes a circle with centre O. If ∠AOB = 115°, then find ∠COD.
Solution:
Circles Extra Questions Class 10
∵ ∠AOB = ∠COD (vertically opposite angles)
∴ ∠COD = 115°

Extra Questions On Circles Class 10 Question 5.
In Fig. 8.8, AABC is circumscribing a circle. Find the length of BC.
Extra Questions Of Circles Class 10
Solution:
AN = AM = 3 cm [Tangents drawn from an external point]
BN = BL = 4 cm [Tangents drawn from an external point]
CL = CM = AC – AM = 9 – 3 = 6 cm
⇒ BC = BL + CL = 4 + 6 = 10 cm.

Extra Questions For Class 10 Maths Circles With Solutions Question 6.
In Fig. 8.9, O is the centre of a circle, PQ is a chord and the tangent PR at P makes an angle of 50° with PQ. Find ∠POQ.
Solution:
Extra Questions On Circles Class 10
∠OPQ = 90° – 50° = 40°
OP = OQ [Radii of a circle]
∠OPQ = ∠OQP = 40°
(Equal opposite sides have equal opposite angles)
∠POQ = 180° – ∠OPQ – ∠OQP
= 180° – 40° – 40° = 100°

Class 10 Maths Circles Extra Questions Question 7.
If two tangents inclined at an angle 60° are drawn to a circle of radius 3 cm, then find the length of each tangent.
Solution:
Extra Questions For Class 10 Maths Circles With Solutions
In Fig. 8.10
∆AOP ≅ ∆BOP (By SSS congruence criterion)
∠APO = ∠BPO = \(\frac{60°}{2}\) = 30°
In ∆AOP, OA ⊥ AP
∴ tan 30° = \(\frac{OA}{AP}\)
⇒ \(\frac{1}{\sqrt{3}}\) = \(\frac{3}{AP}\)
⇒ AP = 3√3 cm

Circles Class 10 Important Questions Question 8.
If radii of two concentric circles are 4 cm and 5 cm, then find the length of each chord of one circle which is tangent to the other circle.
Solution:
Class 10 Maths Circles Extra Questions
OA = 4 cm, OB = 5 cm
Also, OA ⊥ BC
∴ OB2 = OA2 + AB2
⇒ 52 = 42 + AB2
⇒ AB = √25 – √16 = 3 cm
⇒ BC = 2 AB = 2 × 3 = 6 cm

Class 10 Maths Chapter 10 Extra Questions Question 9.
PQ is a tangent drawn from a point P to a circle with centre O and QOR is a diameter of the circle such that ∠POR = 120° then find ∠OPQ.
Solution:
Circles Class 10 Important Questions
∠OQP = 90°
∠QOP = 180° – 120° = 60°
∠OPQ = 180° – ∠OQP – ∠QOP
= 180° – 90° – 60°
= 30°

Circle Extra Questions Class 10 Question 10.
From an external point P, tangents PA and PB are drawn to a circle with centre O. If ∠PAB = 50°, then find ∠AOB.
Class 10 Maths Chapter 10 Extra Questions
Solution:
∵ PA = PB ⇒ ∠BAP = ∠ABP = 50°
∴ ∠APB = 180° – 50° – 50° = 80°
∴ ∠AOB = 180° – 80° = 100°

Circles Chapter Class 10 Extra Questions Question 11.
In PQ is a tangent at a point C to a circle with centre O. If AB is a diameter and ∠CAB = 30°, find ∠PCA.
Solution:
Circle Extra Questions Class 10
∠ACB = 90° (Angle in the semicircle)
∠CAB = 30° (given)
In ∆ABC,
90° + 30° + ∠ABC = 180°
⇒ ∠ABC = 60°
Now, ∠PCA = ∠ABC (Angles in the alternate segment)
∴ ∠PCA = 60°
or
Construction: Join O to C.
∠PCO = 90° [∵ Line joining centre to point of contact is perpendicular to PQ]
In ∆AOC, OA = OC [Radii of circle]
∴ ∠OAC = ∠OCA = 30° [Equal sides have equal opp. angles]
Now, ∠PCA = ∠PCO – ∠ACO
= 90° – 30° = 60°

Extra Question Of Circle Class 10 Question 12.
In fig. 8.16, there are two concentric circles with centre O. PRT and PQS are tangents to the inner circle from a point P lying on the outer circle. If PR = 5 cm, find the length of PS.
Solution:
Circles Chapter Class 10 Extra Questions
PQ = PR = 5 cm [∵ Tangents drawn from external point are equal] PK
∴ PS = 2PQ = 10 cm [∵ Perpendicular drawn from centre to the chord bisects the chord]

Circles Class 10 Extra Questions Short Answer Type 1

State true or false for each of the following and justify your answer (Q. 1 to 3)

Circles Class 10 Extra Questions State Syllabus Question 1.
AB is a diameter of a circle and AC is its chord such that ∠BAC = 30°. If the tangent at C intersects AB extended at D, then BC = BD.
Solution:
Extra Question Of Circle Class 10
True, Join OC,
∠ACB = 90° (Angle in semi-circle)
∴ ∠OBC = 180o – (90° + 30°) = 60°
Since, OB = OC = radii of same circle [Fig. 8.16]
∴ ∠OBC = ∠OCB = 60°
Also, ∠OCD = 90°
⇒ ∠BCD = 90° – 60° = 30°
Now, ∠OBC = ∠BCD + ∠BDC (Exterior angle property)
⇒ 60° = 30° + ∠BDC
⇒ ∠BDC = 30°
∵ ∠BCD = ∠BDC = 30°
∴ BC = BD

Class 10 Circles Important Questions Question 2.
The length of tangent from an external point P on a circle with centre O is always less than OP.
Circles Class 10 Extra Questions State Syllabus
Solution:
True, let PQ be the tangent from the external point P.
Then ∆PQO is always a right angled triangle with OP as the hypotenuse. So, PQ is always less than OP.

Circles Class 10 Questions With Solutions Question 3.
If angle between two tangents drawn from a point P to a circle of radius ‘a’ and centre 0 is 90°, then OP = a√2.
Class 10 Circles Important Questions
Solution:
True, let PQ and PR be the tangents
Since ∠P = 90°, so ∠QOR = 90°
Also, OR = OQ = a
∴ PQOR is a square
Circles Class 10 Extra Questions Maths Chapter 10 with Solutions Answers 16

Extra Questions Of Chapter Circles Class 10 Question 4.
In Fig. 8.20, PA and PB are tangents to the circle drawn from an external point P. CD is the third tangent touching the circle at Q. If PA = 15 cm, find the perimeter of ∆PCD.
Circles Class 10 Questions With Solutions
Solution:
∵ PA and PB are tangent from same external point
∴ PA = PB = 15 cm
Now, Perimeter of ∆PCD = PC + CD + DP = PC + CQ + QD + DP
= PC + CA + DB + DP
= PA + PB = 15 + 15 = 30 cm

Chapter 10 Maths Class 10 Extra Questions Question 5.
In Fig. 8.21, PA and PB are tangents to the circle from an external point P. CD is another tangent touching the circle at Q. If PA = 12 cm, QC = QD = 3 cm, then find PC + PD.
Extra Questions Of Chapter Circles Class 10
Solution:
PA = PC + CA = PC + CQ [∵ CA = CQ (tangents drawn An from external point are equal)]
⇒ 12 = PC + 3 = PC = 9 cm
∵ PA = PB = PA – AC = PB – BD
⇒ PC = PD
∴ PD = 9 cm
Hence, PC + PD = 18 cm

Extra Questions Circles Class 10 Question 6.
Prove that the line segment joining the points of contact of two parallel tangents of a circle, passes through its centre.
Circles Class 10 Extra Questions Maths Chapter 10 with Solutions Answers 19
Solution:
Let the tangents to a circle with centre O be ABC and XYZ.
Construction : Join OB and OY.
Draw OP||AC
Since AB||PO
∠ABO + ∠POB = 180° (Adjacent interior angles)
∠ABO = 90° (A tangent to a circle is perpendicular to the radius through the point of contact)
90° + ∠POB = 180° = ∠POB = 90°
Similarly ∠POY = 90°
∠POB + ∠POY = 90° + 90° = 180°
Hence, BOY is a straight line passing through the centre of the circle.

Circles Class 10 Important Questions With Solutions Question 7.
If from an external point P of a circle with centre 0, two tangents PQ and PR are drawn such that QPR = 120°, prove that 2PQ = PO.
Circles Class 10 Extra Questions Maths Chapter 10 with Solutions Answers 20
Solution:
Given, ∠QPR = 120°
Radius is perpendicular to the tangent at the point of contact.
∠OQP = 90°
⇒ ∠QPO = 60°
(Tangents drawn to a circle from an external point are equally inclined to the segment, joining the centre to that point)
Circles Class 10 Extra Questions Maths Chapter 10 with Solutions Answers 21
2PQ = PO

Questions On Circles For Class 10 Question 8.
In Fig. 8.24, common tangents AB and CD to two circles with centres , and 0, intersect at E. Prove that AB = CD.
Circles Class 10 Extra Questions Maths Chapter 10 with Solutions Answers 22
Solution:
AE = CE and BE = ED [Tangents drawn from an external point are equal]
On addition, we get
AE + BE = CE + ED
∠QPO = 60°
⇒ AB = CD

Circles Class 10 Extra Questions Pdf Download Question 9.
The incircle of an isosceles triangle ABC, in which AB = AC, touches the sides BC, CA and AB at D, E and F respectively. Prove that BD = DC.
OR
In Fig. 8.25, if AB = AC, prove that BE = EC.
[Note: D, E, F replace by F, D, E]
Circles Class 10 Extra Questions Maths Chapter 10 with Solutions Answers 23
Solution:
Circles Class 10 Extra Questions Maths Chapter 10 with Solutions Answers 24
Given, AB = AC
We have, BF + AF = AE + CE ….(i)
AB, BC and CA are tangents to the circle at F, D and E respectively.
∴ BF = BD, AE = AF and CE = CD ….(ii)
From (i) and (ii)
BD + AE = AE + CD (∵ AF = AE)
⇒ BD = CD

Question 10.
In Fig. 8.27, XP and XQ are two tangents to the circle with centre O, drawn from an external point X. ARB is another tangent, touching the circle at R. Prove that XA + AR = XB + BR.
Circles Class 10 Extra Questions Maths Chapter 10 with Solutions Answers 25
Solution:
In the given figure,
AP = AR
BR = BQ
XP = XQ [Tangent to a circle from an external point are equal]
XA + AP = XB + BQ
XA + AR = XB + BR [AP = AR, BQ = BR]

Question 11.
In Fig. 8.28, a circle is inscribed in a AABC, such that it touches the sides AB, BC and CA at points D, E and F respectively. If the lengths of sides AB, BC and CA are 12 cm, 8 cm and 10 cm respectively, find the lengths of AD, BE and CF.
Circles Class 10 Extra Questions Maths Chapter 10 with Solutions Answers 26
Solution:
Let AD = AF = x
∴ DB = BE = 12 – x
and CF = CE = 10 – x
BC = BE + EC
⇒ 8 = 12 – x + 10 – x
⇒ x = 7
∴ AD = 7 cm, BE = 12 – 7 = 5 cm, CF = 10 – 7 = 3 cm

Question 12.
In Fig. 8.29, AP and BP are tangents to a circle with centre 0, such that AP = 5 cm and ∠APB = 60°. Find the length of chord AB.
Circles Class 10 Extra Questions Maths Chapter 10 with Solutions Answers 27
Solution:
PA = PB (Tangents from an external point are equal)
and ∠APB = 60°
⇒ ∠PAB = ∠PBA = 60°
∴ ∆PAB is an equilateral triangle.
Hence AB = PA = 5 cm.

Question 13.
In Fig. 8.30 from an external point P, two tangents PT and PS are drawn to a circle with centre 0 and radius r. If OP = 2r, show that ∠OTS = ∠OST = 30°.
Circles Class 10 Extra Questions Maths Chapter 10 with Solutions Answers 28
Solution:
Let ∠TOP = θ
∴ cos θ = \(\frac{OT}{OP}\) = \(\frac{r}{2r}\) =\(\frac{1}{2}\)
⇒ cos θ = cos 60°
⇒ θ = 60°
Hence, ∠TOS = 120°
In ∆OTS, OT = OS [Radii of circle]
⇒ ∠OTS = ∠OST = \(\frac{60^{\circ}}{2}\) = 30°

Question 14.
In Fig. 8.31, are two concentric circles of radii 6 cm and 4 cm with centre O. If AP is a tangent to the larger circle and BP to the smaller circle and length of AP is 8 cm, find the length of BP.
Circles Class 10 Extra Questions Maths Chapter 10 with Solutions Answers 29
Solution:
OA = 6 cm, OB = 4 cm, AP = 8 cm
OP2 = OA2 + AP2 = 36 + 64 = 100
⇒ OP = 10 cm
BP2 = OP2 – OB2 = 100 – 16 = 84
⇒ BP = 2√21 cm

Question 15.
In fig. 8.32, PQ is a tangent from an external point P to a circle with centre ( and OP cuts the circle at T and QOR is a diameter. If ∠POR = 130° and S is a point on the circle, find R 21 + 22.
Circles Class 10 Extra Questions Maths Chapter 10 with Solutions Answers 30
Solution:
∵ ∠POR = 130o = ∠ROT [∵ Angle subtended by an arc at the centre is double than the angle subtended by it at any part of circumference]
∠2 = \(\frac{1}{2}\) ∠ROT = \(\frac{1}{2}\) × 130° = 65°
∠POQ = 180° – 130° = 50° [Linear pair]
and ∠Q = 90°
∴ ∠1 = 40°[∵ Line drawn from centre to the point of contact is perpendicular to the tangent]
Hence ∠2 + ∠1 = 65° + 40° = 105° .

Circles Class 10 Extra Questions Short Answer Type 2

Question 1.
A tangent PQ at a point P of a circle of radius 5 cm meets a line through the centre 0 at a point so that OQ = 12 cm. Find the length of PQ.
Circles Class 10 Extra Questions Maths Chapter 10 with Solutions Answers 31
Solution:
We have, ∠OPQ = 90°
OQ = 12 cm and OP = 5 cm
∴ By Pythagoras Theorem
OQ2 = OP2 + QP2
⇒ 122 = 52 + QP2
⇒ QP2 = 144 – 25 = 119
= QP = √119 cm

Question 2.
From a point l, the length of the tangent to a circle is 24 cm and the distance of Q from the centre is 25 cm. Find the radius of the circle.
Solution:
Circles Class 10 Extra Questions Maths Chapter 10 with Solutions Answers 32
Let QT be the tangent and OT be the radius of circle. Therefore
OT ⊥ QT i.e., ∠OTQ = 90°
and OQ = 25 cm and QT = 24 cm
Now, by Pythagoras Theorem, we have
OQ2 = QT2 + OT2
⇒ 252 = 242 + OT2
⇒ OT2 = 252 – 242
⇒ 625 – 576
OT2 – 49
∴ OT = 7 cm

Question 3.
In Fig. 8.35, if TP and TQ are the two tangents to a circle with centre 0 so that ∠POQ = 110°, then find ∠PTQ.
Solution:
Circles Class 10 Extra Questions Maths Chapter 10 with Solutions Answers 33
Since TP and TQ are the tangents to the circle with centre O
So, OPIPT and OQ ⊥ QT
⇒ ∠OPT = 90°, ∠OQT = 90° and ∠POQ = 110°
So, in quadrilateral OPTQ, we have
∠POQ + ∠OPT + ∠PTQ + ∠TQO = 360°
⇒ 110° + 90° + ∠PTQ + 90° = 360°
⇒ ∠PTQ + 290° = 360°
∴ ∠PTQ = 360° – 290°
= ∠PTQ = 70°

Question 4.
Prove that the tangents drawn at the ends of a diameter of a circle are parallel.
Solution:
Circles Class 10 Extra Questions Maths Chapter 10 with Solutions Answers 34
Let AB be the diameter of the given circle with centre O, and two tangents PQ and LM are drawn at the end of diameter AB respectively.
Р. Now, since the tangent at a point to a circle is perpendicular to the radius through the point of contact.
Therefore, OA ⊥ PQ and OB ⊥ LM
i.e., AB ⊥ PQ and also AB ⊥ LM
⇒ ∠BAQ = ∠ABL (each 90°)
∴ PQ||LM (∵ ∠BAQ and ∠ABL are alternate angles)

Question 5.
If tangents PA and PB from a point P to a circle with centre O are inclined to each other at angle of 80°, then find ∠POA.
Solution:
Circles Class 10 Extra Questions Maths Chapter 10 with Solutions Answers 35
∵ PA and PB are tangents to a circle with centre O,
∴ OA ⊥ AP and OB ⊥ PB
i.e., ∠APB = 80°, ∠OAP = 90°, and ∠OBP = 90°
Now, in quadrilateral OAPB, we have
∠APB + ∠PBO + ∠BOA + ∠OAP = 360°
⇒ 80° + 90° + ∠BOA + 90o = 360°
⇒ 260° + ∠BOA = 360°
∴ ∠BOA = 360° – 260°
⇒ ∠BOA = 100°
Now, in ∆POA and APOB we have
OP = OP (Common)
ОА = ОВ (Radii of the same circle)
∠OAP = ∠OBP = 90°
∴ ∆POA ≅ APOB (RHS congruence condition)
⇒ ∠POA = ∠POB (CPCT)
Now, ∠POA = \(\frac{1}{2}\) = ∠BOA = \(\frac{1}{2}\) × 100 = 50°

Question 6.
The length of a tangent from a point A at distance 5 cm from the centre of the circle is 4 cm. Find the radius of the circle.
Circles Class 10 Extra Questions Maths Chapter 10 with Solutions Answers 36
Solution:
Let O be the centre and P be the point of contact.
Since tangent to a circle is perpendicular to the radius through the point of contact,
∴ ∠OPA = 90° Now, in right ∆OPA we have
OA2 = OP2 + PA2 [By Pythagoras Theorem]
52 = OP2 + 42
= 25 = OP2 + 16
⇒ OP2 = 25 – 16 = 9
∴ OP = 3cm
Hence, the radius of the circle is 3 cm.

Question 7.
Two concentric circles are of radii 5 cm and 3 cm. Find the length of the chord of the larger circle which touches the smaller circle.
Solution:
Circles Class 10 Extra Questions Maths Chapter 10 with Solutions Answers 37
Let O be the common centre of two concentric circles and let AB be a chord of larger circle
touching the smaller circle at P. Join OP.
Since OP is the radius of the smaller circle and AB is tangent to this circle at P,
∴ OP ⊥ AB
We know that the perpendicular drawn from the centre of a circle to any chord of the circle bisects the chord.
Therefore, AP = BP
In right ∆APO we have
⇒ OA2 = AP2 + OP2
⇒ 52 = AP2 + 32
⇒ 25 – 9 = AP2
⇒ AP2 = 16
⇒ AP = 4
Now, AB = 2.AP = 2 × 4 = 8 [∵ AP = PB]
Hence, the length of the chord of the larger circle which touches the smaller circle is 8 cm.

Question 8.
Prove that the tangents drawn at the ends of a chord of circle make equal angles with the chord.
Solution:
Circles Class 10 Extra Questions Maths Chapter 10 with Solutions Answers 38
Given: A circle with centre O, PA and PB are tangents drawn at the ends A and B on chord AB.
To prove: ∠PAB = ∠PBA
Construction: Join OA and OB.
Proof: In ∆OAB we have
ОА = ОВ … (i) [Radii of the same circle]
∠2 = ∠1 … (ii) [Angles opposite to equal sides of a A]
Also (∠2 + ∠3 = ∠1 + 24) …(iii) [Both 90° as Radius ⊥ Tangent]
Subtracting (ii) from (iii), we have
∴ ∠3 = ∠4 = ∠PAB = ∠PBA

Question 9.
Prove that the perpendicular at the point of contact to the tangent to a circle passes through the centre.
Circles Class 10 Extra Questions Maths Chapter 10 with Solutions Answers 39
Solution:
Let LM be tangent drawn at the point P on the circle with centre O. Join OP. If possible, let PQ be perpendicular to LM, not passing through O.
Now, since tangent at a point to a circle is perpendicular to the radius through the point.
∴ OP ⊥ LM ⇒ ∠OPM = 90°
Also, ∠QPM = 90° (as assumed above)
∴ ∠OPM = ∠QPM,
which is possible only when points O and I coincide
Hence, the perpendicular at the point of contact to tangent to a circle passes through the centre.

Question 10.
A quadrilateral ABCD is drawn to circumscribe a circle (Fig. 8.42). Prove that AB + CD = AD + BC.
OR
A circle touches all the four sides of a quadrilateral ABCD. Prove that AB + CD = BC + DA
Circles Class 10 Extra Questions Maths Chapter 10 with Solutions Answers 40
Solution:
Since lengths of two tangents drawn from an external point of circle are equal,
Therefore, AP = AS, BP = BQ and DR = DS
CR = CQ (Where P, Q, R and S are the points of contact]
Adding all these, we have
(AP + BP) + (CR + RD) = (BQ + CQ) + (DS + AS)
⇒ AB + CD = BC + DA

Question 11.
A circle is touching the side BC of AABC at P and touching AB and AC produced at Q and R respectively. Prove that AQ = \(\frac{1}{2}\) (perimeter of ∆ABC).
Solution:
Circles Class 10 Extra Questions Maths Chapter 10 with Solutions Answers 41
Since tangents from an exterior point to a circle are equal in length.
∴ BP = BQ [Tangents from B] …(i)
CP = CR [Tangents from C] … (ii)
and, AQ = AR [Tangents from A] …(iii)
From (iii), we have
AQ = AR
⇒ AB + BQ = AC + CR
AB + BP
⇒ AC + CP (Using (i) and (ii)] …(iv)
Now, perimeter of AABC = AB + BC + AC
= AB + (BP.+ PC) + AC
= (AB + BP) + (AC + PC)
= 2(AB + BP) [Uisng (iv)]
= 2(AB + BQ) = 2AQ [Using (i)]
AQ = \(\frac{1}{2}\) (Perimeter of ∆ABC)

Question 12.
The difference between the radii of the smaller circle and the larger circle is 7 cm and the difference between the areas of the two circles is 1078 sq. cm. Find the radius of the smaller circle.
Solution:
Given: r2 – r1 = 7 (r2 > r1) …(i)
and π(r22 – r12) = 1078
π (r2 – r1) (r2 + r1) = 1078
π (r2 + r1) = 1078 [(From equation (i)]
⇒ r2 + r1 = \(\frac{1078 \times 7}{22 \times 7}\) = 49…(ii)
Adding (i) and (ii), we get
2r2 = 56
⇒ r2 = 28 cm
r1 = 21 cm [From equation (ii)]
∴ Radius of smaller circle = 21 cm.

Circles Class 10 Extra Questions Long Answer Type 1

Question 1.
Prove that the tangent to a circle is perpendicular to the radius through the point of contact.
Solution:
Given: A circle C(O,r) and a tangent AB at a point P.
To Prove: OP ⊥ AB.
Construction: Take any point l, other than P, on the tangent AB. Join OQ. Suppose OQ meets the circle at R.
Proof: We know that among all line segments joining the point to a point on AB, the shortest one is perpendicular to AB. So, to prove that OP ⊥ AB it is sufficient to prove that OP is shorter than any other segment joining O to any point of AB.
Circles Class 10 Extra Questions Maths Chapter 10 with Solutions Answers 42
Clearly, OP = OR [Radii of the same circle]
Now, OQ = OR + RQ
⇒ OQ > OR
⇒ OQ > OP [∵OP = OR]
Thus, OP is shorter than any other segment joining O to any point on AB.
Hence, OP ⊥ AB.

Question 2.
Prove that the lengths of two tangents drawn from an external point to a circle are equal.
Solution:
Circles Class 10 Extra Questions Maths Chapter 10 with Solutions Answers 43
Given: AP and AQ are two tangents from a point A to a circle C (O, r).
To Prove: AP = AQ
Construction: Join OP, OQ and OA.
Proof: In order to prove that AP = AQ, we shall first prove that ∆OPA ≅ ∆OQA.
Since a tangent at any point of a circle is perpendicular to the radius through the point of contact.
∴ OP ⊥ AP and OQ ⊥ AQ
⇒ ∠OPA = ∠OQA = 90°
Now, in right triangles OPA and OQA, we have
OP = OQ [Radii of a circle]
∠OPA = ∠OQA [Each 90°]
and OA = OA [Common]
So, by RHS-criterion of congruence, we get
∆OPA ≅ OQA
⇒ AP = AQ [CPCT]
Hence, lengths of two tangents from an external point are equal.

Question 3.
Prove that the parallelogram circumscribing a circle is a rhombus.
Solution:
Circles Class 10 Extra Questions Maths Chapter 10 with Solutions Answers 44
Let ABCD be a parallelogram such that its sides touch a circle with centre O.
We know that the tangents to a circle from an exterior point are equal in length.
Therefore, we have
AP = AS [Tangents from A]
BP = BQ [Tangents from B] …. (ii)
CR = CQ [Tangents from C] …. (iii)
And DR = DS [Tangents from D] …. (iv)
Adding (i), (ii), (iii) and (iv), we have
(AP + BP) + (CR + DR) = (AS + DS) + (BQ + CQ)
AB + CD = AD + BC
AB + AB = BC + BC [∵ ABCD is a parallelogram ∴ AB = CD, BC = DA]
2AB = 2BC ⇒ AB = BC
Thus, AB = BC = CD = AD
Hence, ABCD is a rhombus.

Question 4.
In Fig. 8.47, PQ is a chord of length 16 cm, of a circle of radius 10 cm. The tangents at P and Q intersect at a point T. Find the length of TP.
Solution:
Given: PQ = 16 cm
PO = 10 cm
Circles Class 10 Extra Questions Maths Chapter 10 with Solutions Answers 45

Question 5.
If PQ is a tangent drawn from an external point P to a circle with centre O and QOR is a diameter where length of QOR is 8 cm such that ∠POR = 120°, then find OP and PQ.
Solution:
Let O be the centre and QOR = 8 cm is diameter of a circle. PQ is tangent such that ∠POR = 120°
Circles Class 10 Extra Questions Maths Chapter 10 with Solutions Answers 46

Question 6.
In Fig. 8.49, two equal circles, with centres O and O’, touch each other at X.OO’ produced meets the circle with centre O’ at A. AC is tangent to the circle with centre 0, at the point C. O’D is perpendicular to AC. Find the value of \(\frac{DO’}{CO}\) .
Solution:
Circles Class 10 Extra Questions Maths Chapter 10 with Solutions Answers 47
AC is tangent to circle with centre O.
Thus ∠ACO = 90°
In ∆AO’D and ∆AOC
∠ADO’ = ∠ACO = 90°
∠A = ∠A (Common)
∴ ∆AO’D – ∠AOC (By AA similarity)
Circles Class 10 Extra Questions Maths Chapter 10 with Solutions Answers 48

Question 7.
In Fig. 8.50, O is the centre of a circle of radius 5 cm. T is a point such that OT = 13 cm and OT intersects circle at E. If AB is a tangent to the circle at E, find the length of AB, where TP and TQ are two tangents to the circle.
Circles Class 10 Extra Questions Maths Chapter 10 with Solutions Answers 49
Solution:
In right ∆POT
Circles Class 10 Extra Questions Maths Chapter 10 with Solutions Answers 50
TE = 8 cm
Let PA = AE = x
(Tangents from an external point to a circle are equal)
In right ∆AET
TA2 = TE2 + EA2
⇒ (12 – x)2 = 64 + x2
⇒ 144 + x2 – 24x = 64 + x2
⇒ x = \(\frac{80}{24}\)
⇒ x = 3.3 cm
Thus, AB = 6.6 cm

Circles Class 10 Extra Questions HOTS

Question 1.
Prove that opposite sides of a quadrilateral circumscribing a circle subtend supplementary angles at the centre of the circle.
Solution:
Circles Class 10 Extra Questions Maths Chapter 10 with Solutions Answers 51
Let a circle with centre O touches the sides AB, BC, CD and DA of a D quadrilateral ABCD at the points P, Q, R and S respectively. Then, we have to prove that
∠AOB + ∠COD = 180° and ∠AOD + ∠BOC = 180°
Now, Join OP, OQ, OR and OS.
Since the two tangents drawn from an external point to a circle subtend equal angles at the centre.
∴ ∠1 = ∠2, ∠3 = 24, 25 = 26 and 27 = 28 …(i)
Now, 21 + 22 +23 + 24 + 25 +26+ 27 + ∠8 = 360° … (ii)
[sum of all the angles subtended at a point is 360°]
⇒ 2(∠2 + ∠3 + ∠6 + ∠7) = 360° [using equation (i) and (ii)]
= (∠2 + ∠3) + (∠6 + ∠7) = 180°
∠AOB + ∠COD = 180°
again 2(∠1 + ∠8 +∠4 + ∠5) = 360° [from (i) and (ii)]
(∠1 + ∠8) + (∠4 + ∠5) = 180°
∠AOD + ∠BOC = 180°

Question 2.
A triangle ABC [Fig. 8.52] is drawn to circumscribe a circle of radius 4 cm such that the segments BD and DC into which BC is divided by the point of contact D are of lengths 8 cm and 6 cm respectively. Find the sides AB and AC.
Solution:
Circles Class 10 Extra Questions Maths Chapter 10 with Solutions Answers 52
Let ∆ABC be drawn to circumscribe a circle with centre O and radius 4 cm and circle touches the sides BC, CA and AB at D, E and 6 cm F respectively.
We have given that CD = 6 cm and BD = 8 cm
∴ BF = BD = 8 cm and CE = CD = 6 cm
{Length of two tangents drawn from an external point of circle are equal}
Now, let AF = AE = x cm
Then, AB = c = (x + 8) cm, BC = a = 14 cm, CA = b = (x + 6) cm
2s = (x + 8) + 14 + (x + 6) 25 = 2x + 28 or s = x + 14
s – a = (x + 14) – 14 = x
s – b = (x + 14) – (x + 6) = 8
s – c = (x + 14) – (x + 8) = 6
Circles Class 10 Extra Questions Maths Chapter 10 with Solutions Answers 53

Squaring both sides, we have
48x (x + 14) = 16(x + 14)2 = 48x (x + 14) – 16 (x + 14)2 = 0
16 (x + 14) (3x – (x + 14)] = 0
⇒ 16(x + 14)(2x – 14) = 0
either 16(x + 14) = 0 or 2x – 14 = 0
⇒ x = -14 or 2x = 14
⇒ x = -14 or x = 7
But x cannot be negative so x ≠ – 14 .
∴ x = 7 cm
Hence, the sides AB = x + 8 = 7 + 8 = 15 cm
AC = x + 6 = 7 + 6 = 13 cm.

Question 3.
In Fig. 8.53, XY and X’Y are two parallel tangents to a circle with centre O and another tangent AB with point of contact C intersecting XY at A and ∠X’Y at B. Prove that ∠AOB = 90°.
Solution:
Circles Class 10 Extra Questions Maths Chapter 10 with Solutions Answers 54
Join OC. In ∆APO and ∆ACO, we have
AP = AC (Tangents drawn from external point A)
AO = OA (Common)
PO = OC (Radii of the same circle)
∴ ∆APO ≅ ∆ACO (By SSS criterion of congruence)
∴∠PAO = ∠CAO (CPCT)
⇒ ∠PAC = 2∠CAO
Similarly, we can prove that
∆OQB ≅ ∆OCB
∴∠QBO = 2CBO
⇒ ∠CBQ = 22CBO
Now, ∠PAC + ∠CBQ = 180° [Sum of interior angles on the same side of transversal is 180°]
⇒ 2∠CAO + 2∠CBO = 180°
⇒ ∠CAO + ∠CBO = 90°
⇒ 180° – ∠AOB = 90°
[∵ ∠CAO + ∠CBO + ∠AOB = 180°]
⇒ 180° – 90° = ∠AOB
⇒ ∠AOB = 90°

Question 4.
Let A be one point of intersection of two intersecting circles with centres O and Q. The tangents at A to the two circles meet the circles again at B and C respectively. Let the point P be located so that AOPQ is a parallelogram. Prove that P is the circumcentre of the triangle ABC.
Solution:
Circles Class 10 Extra Questions Maths Chapter 10 with Solutions Answers 55
In order to prove that P is the circumcentre of ∆ABC it is sufficient to show that P is the point of intersection of perpendicular bisectors of the sides of AABC i.e., OP and PQ are perpendicular bisectors of sides AB and AC respectively. Now, AC is tangent at A to the circle with centre at 0 and OA is its radius.
∴ OA ⊥ AC
⇒ PQ ⊥ AC [∵ OAQP is a parallelogram so, OA ||PQ]
Also, Q is the centre of the circle
QP bisects AC [Perpendicular from the centre to the chord bisects the chord]
⇒ PQ is the perpendicular bisector of AC.
Similarly, BA is the tangent to the circle at A and AQ is its radius through A.
∴ BA ⊥ AQ [∵ AQPO is parallelogram]
BA ⊥ OP [∴ OP || AQ]
Also, OP bisects AB [∵ 0 is the centre of the circle]
⇒ OP is the perpendicular bisector of AB. Thus, P is the point of intersection of perpendicular bisectors PQ and PO of sides AC and AB respectively.
Hence, P is the circumcentre of ∆ABC.

Glimpses of India Extra Questions and Answers Class 10 English First Flight

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Online Education for Glimpses of India Extra Questions and Answers Class 10 English First Flight

Glimpses of India Extra Questions and Answers Very Short Answer Type

Glimpses Of India Extra Questions Question 1.
What are the elders in Goa nostalgic about?
Answer:
The elders in Goa are nostalgic about the Portuguese and their loaves of bread.

Glimpses Of India Class 10 Extra Questions Question 2.
How do they remember it?
Answer:
They remember about it fondly.

Class 10 English Glimpses Of India Extra Questions Question 3.
What equipments do the Goan people still own there?
Answer:
They still have amongst them the mixtures, the moulders and time-tested furnaces and those who bake the loaves.

Glimpses Of India Important Questions Question 4.
What are those bakers known in Goa?
Answer:
Those bakers are known as ‘pader’ in Goa.

Class 10 Glimpses Of India Extra Questions Question 5.
What does the thud and jingle of the traditional baker’s bamboo indicate?
Answer:
It indicates the announcement of the arrival of the baker in the morning.

Glimpses Of India Class 10 Important Questions Question 6.
What announces the arrival of the baker in Goa?
Answer:
The thud and jingle of the specially made bamboo staff announces the arrival of the traditional baker.

Extra Questions From Glimpses Of India Question 7.
How would the baker greet the lady of the house?
Answer:
The baker would greet the lady of the house with ‘good morning’.

Class 10 English First Flight Chapter 7 Extra Question Answer Question 8.
What did the children long to get from the baker?
Answer:
The children longed for to get bread-bangles from the baker.

Glimpses Of India Extra Question Answer Question 9.
What kind of fragrance does the author still recall?
Answer:
The author still recalls the typical fragrance of the baker’s loaves.

Glimpse Of India Extra Question Answer Question 10.
What kind of dress the lKabaV was?
Answer:
A single piece long frock reaching down to the knees.

Question 11.
When did the baker collect his bills?
Answer:
The baker collected his bills at the end of the month.

Question 12.
How were the monthly accounts of the baker recorded?
Answer:
The monthly accounts recorded on some wall in pencil.

Glimpses of India Extra Questions and Answers Short Answer Type

Question 1.
Why is the baker essential for the Goan people?
Answer:
Most of the celebrations and festivals need supply of bread so the baker’s furnace is essential for the Goan people.

Question 2.
Why did the baker and his family always look happy and prosperous?
Answer:
The baker used to collect his bills at the end of the month. Baking was indeed a profitable business in
the old days. The baker and his family never starved. Their plump physique was an open testimony that they were happy and prosperous.

Question 3.
Why would the children run to meet and greet the baker?
Answer:
The jingling thud of the baker’s bamboo would wake up the children from their sleep. They would run to meet and greet him to get bread bangles or sometimes sweet bread of special make.

Question 4.
What indicates the presence of the ‘patters’ still in Goa?
Answer:
The presence of the ‘paders’ in Goa even today is indicated by the fact that still there are mixers, the moulders and those who bake the loaves. Moreover, those age-old time-tested furnaces still exist.

Question 5.
What would the baker do after his musical entry?
Answer:
The baker would greet the lady of the house with ‘good morning’ and then place his basket on the bamboo after his musical entry.

Question 6.
How did the pader treat the kids who surrounded him?
Answer:
The pader treated the kids who surrounded him, very kindly he would push them aside with a mild rebuke.

Question 7.
Was baking a profitable profession?
Answer:
Yes, baking was really a profitable profession as the bread was an important part of the food of the Goan people. The bakers earned well and kept servants. Their families looked happy and prosperous. They never starved.

Question 8.
What are the elders in Goa nostalgic about?
Answer:
The elders in Goa are much fond of loaves of bread. Those were the Portuguese days and the people liked the breads of different types very much.

Question 9.
Is bread-making still popular in Goa? How do you know?
Answer:
Bread-making is still popular in Goa. We can see the mixers, the moulders and those who bake the loaves. Most of their festivals and other occasions will become meaningless without the loaves of the bread. The ladies of the house prepare sandwiches on the occasion of their daughter’s engagement.

Question 10.
What is the baker called?
Answer:
The baker is called ‘Pader’ in Goa. They wear special dresses.

Question 11.
When would the baker come everyday? Why did the children run to meet him?
Answer:
The baker would come at least twice a day. The morning was his selling round and he returned after selling them. Children ran to meet and greet him because they needed bread bangles from him. They also got sweet bread of special make.

Question 12.
Match the following. What is a must
(i) as marriage gifts? – cakes and bolinhas
(ii) for a party or a feast? – sweet bread called ‘bol’
(iii) for a daughter’s engagement? – bread
(iv) for Christmas? – sandwiches
Answer:
(i) As marriage gifts – sweet bread called ‘bol’
(ii) For a party or a feast – bread
(iii) For a daughter’s engagement – sandwiches
(iv) For Christmas – cake and bolinhas

Question 13.
What did the bakers wear?
(i) in the Portuguese days?
(ii) when the author was young?
Answer:
(i) The bakers wore a particular dress called ‘Kabai’. It was a single-piece long frock reaching down to the knees.
(ii) The bakers wore a shirt and trousers which were shorter than full length ones and longer than half pants.

Question 14.
Who invites the comment—‘he is dressed like a pader’? Why?
Answer:
The dress of Pader’ invites comments because it reaches just below the knees. It looks odd, funny and makes one’s figure like a joker.

Question 15.
Where were the monthly accounts of the baker recorded?
Answer:
The monthly accounts of the baker were recorded on a wall. It was written in pencil.

Question 16.
What does a ‘jackfruit’—like appearance’ mean?
Answer:
Any person with a ‘jackfruit—like appearance’ is easily compared to a baker.

Glimpses of India Extra Questions and Answers Long Answer Type

Question 1.
Describe the pen-portrait of a traditional Goan village baker.
Answer:
There is a deep impact of Portuguese culture on Goan life. The baker is also a part of this culture. They are known as paders in Goa. When author was a child, one could see the traditional baker in the village. He used to be friend of children. He visited the house twice a day. Children arose with the sound of thud and jingle of the bamboo in the morning. They would run to greet him. Children were fond of sweet bread and the bread bangles. The ladies of the house bought the bread. Bakers were professional and it was a family business. It was a profitable business and most of the bakers were plump. They had their peculiar traditional dress called Kabai.

Question 2.
“Not enough can be said to show now important a baker can be for a village”. How were the services of the baker required on various occasions?
OR
Why was the baker’s furnace essential in a traditional Goan village?
Answer:
A baker is very important and essential for a Goan village. He does not merely represent a profession but a highly admired Portuguese tradition. His breads are essential on each and every occasion. Marriage gifts are meaningless without the sweet bread known as the bol. Cakes and bolinhas are a must for Christmas as well as other festival. He enjoys respect and love of the people. The children consider him their friend, companion and guide. Thus, the presence of the baker’s furnace in the village is absolutely necessary.

Question 3.
Rodrigues describe his childhood and the bakers of Goa. What does he remember so fondly about these bakers?
OR
What, according to the author, do the elders of Goa think fondly about the past?
Answer:
Rodrigues describes his childhood and old Portuguese days and their famous loaves of bread. The bakers are known pader in Goa. The writer remembers a baker fondly. The baker would come at least twice a day for selling his bread. The jingling thud of his bamboo would wake the children and they would run to meet and greet him. The children longed for his visit for those bread-bangles or sometimes for sweet bread of special make. The baker would greet the lady of the house with ‘good morning’. Then he would place his basket on the vertical bamboo. He collected the bill at the end of the month.

Question 4.
Baking was considered an important and a profitable profession in a traditional Goan village. Explain.
OR
Bread and cakes were essential of Goan life in older days. Describe the memories that the author recollects about good old Portuguese days and their loaves of bread.
Answer:
In olden days, Goa was very much influenced by the Portuguese. Baking was considered an essential and profitable profession in a traditional Goan village. The Portuguese were famous for preparing the loaves of bread. Baking was the traditional family work. The villages were much fond of the sweet bread known as ‘bol’. The marriage gifts were meaningless without it. So the bakers furnaces were the most essential and ‘cakes and bolinhas’ formed an important item there. At various occasions like Christmas and other festivals the bakers would collect the bill at the end of month. Baking was a profitable profession in olden days.

Question 5.
Bread and cakes were an integral part of Goan life, in olden days. Based on your reading of the “A Baker from Goa”, describe the Goan cidture.
Answer:
Goa in west India, called golden Goa by the Portuguese, has an important Portuguese colony in Asia. The Portuguese were driven by their desire to spread their faith to the local population. Thus the culture of Goa is deeply influenced by Portuguese culture. Modem day Goa, a state of India, is a quaint blend of tradition, religion and modernity. Hindu temples are as much a part of Goa as are Christian monuments. The culture of Goa today is a synthesis of Portuguese and Indian cultures. It is one of the most attractive cultures in India. A Goan is said to be born with music in his blood and music literally accompanies him from the cradle to the grave. Musical traditions run in generations.

Question 6.
“The custom of baking bread is closely associated with Goan culture”. Explain/Discuss, with reference to the chapter ‘A baker from Goa’.
Answer:
Bread forms an essential part of the Goan culture. There is no party or festival without bread. Marriage gifts are meaningless without the sweet bread known as the bol. Any party or a feast loses its charm without bread. A baker is very important for a village. The lady of the house must prepare sandwiches on the occasion of her daughter’s engagement. Cakes and bolinhas are a must for Christmas as well as other festivals. Thus, the presence of the baker’s furnace in the village is absolutely essential. Loaves of bread are very popular in Goa and is a staple food even in remote villages. The bread has health benefits. There are still a few small bakeries left in some of the smaller towns.

Question 7.
Instead of enjoying their childhood the children today are keen to enter adulthood. After reading about all the joys that the author Lucio Rodrigues had in his childhood, do you think such a keenness on the part of children is desirable?
Answer:
Rodrigues describes his childhood. Those were good old Portuguese days, the Portuguese and their famous loaves of bread. The loaves were baked in the furnaces and one can see them even today. The baker visited the house twice a day. In the morning thud and jingle of the bamboo would awake people and children would run to greet him. It was their traditional family work. Those bakers are known as paders.in Goa. They have their peculiar dress. The maid servants purchased the loaves. The bakers also sold breads bangles, sweet bread of special make, cakes and bolinhas. He collected the bill at the end of the month.

Glimpses of India Extra Questions and Answers Reference to Context

Read the following passages and answer the questions that follow:

Question 1.
Our elders are often heard reminiscing nostalgically about those good old Portuguese days, the Portuguese and their famous loaves of bread. Those eaters of loaves might have vanished but the makers are still there. We still have amongst us the mixers, the moulders and those who bake the loaves. Those age-old, time-tested furnaces still exist. The fire in the furnaces has not yet been extinguished. The thud and – jingle of the traditional baker’s bamboo, heralding his arrival in the morning, can still be heard in some places. May be the father is not alive but the son still carries on the family profession. These bakers are, even today, known as pader in Goa.
(i) What are the elders nostalgic about?
(ii) How do they remember it?
(iii) How is a traditional baker recognised?
(iv) Pick out the word from the passage which means opposite to ‘Seldom”.
Answer:
(i) The elders are nostalgic about the Portuguese and their loaves of bread.
(ii) They remember about it fondly.
(iii) A traditional baker is recognised with the thud and jingle of his bamboo.
(iv) often.

Question 2.
During our childhood in Goa, the baker used to be our friend, companion and guide. He used to come at least twice a day. Once, when he set out in the morning on his selling round, and then again, when he returned after emptying his huge basket. The jingling thud of his bamboo woke us up from sleep and we ran to meet and greet him. Why was it so? Was it for the love of the loaf? Not at all. The loaves were bought by some Paskine or Bastine, the maid-servant of the house! What we longed for were those bread-bangles which we chose carefully. Sometimes it was sweet bread of special make.
(i) How do the children look upon the baker?
(ii) How did the children come to know about his arrival?
(iii) When did the baker come the second time?
(iv) Pick out word from the passage that means the same as—Desired.
Answer:
(i) The children look upon the bakers as friend, companion and guide.
(ii) The jingling thud of his bamboo woke up the children from their sleep. They at once ran towards him.
(iii) The baker came the second time after emptying his huge basket.
(iv) ‘longed for’

Question 3
The baker made his musical entry on the scene with the ‘jhang, jhang’ sound of his specially made bamboo staff. One hand supported the basket on his head and the other banged the bamboo on the ground. He would greet the lady of the house with “Go«4 Morning” and then place his basket on the vertical bamboo. We kids would be pushed aside with a mild rebuke and the loaves would be delivered to the servant. But we would not give up. We would climb a bench or the parapet and peep into the basket, somehow. I can still recall the typical fragrance of those loaves. Loaves for the elders and the bangles for the children. Then we did not even care to brush our teeth or wash our mouths properly.
(i) How did the baker make his entry?
(ii) How did he sell his loaves?
(iii) What were the types of loaves he had?
(iv) Pick out the word from the passage that means the same as—Stare into.
Answer:
(i) The baker made his musical entry on the scene with the ‘jhang, jhang’ sound of his specially made bamboo stick.
(ii) He sold his loaves. He would greet the ladies with good morning and then place his basket on the vertical bamboo.
(iii) He had loaves for elders and the bangles for the children.
(iv) peep into.

Question 4.
Marriage gifts are meaningless without the sweet bread known as the bol, just as a party or a feast loses its charm without bread. Not enough can be said to show how important a baker can be for a village. The lady of the house must prepare sandwiches on the occasion of her daughter’s engagement. Cakes and bolinhas are a must for Christmas as well as other festivals. Thus, the presence of the baker’s furnace in the village is absolutely essential.
(i) When are all the marriage gifts meaningless in Goa?
(ii) What was important at the daughter’s engagement?
(iii) What was in use for Christmas and other occasions?
(iv) Pick out the word from the passage that means the same as—‘Attraction’.
Answer:
(i) Marriage gifts are meaningless without the sweet bread in Goa. Preparation
(ii) of sandwiches is important at the daughter’s engagement. Cakes and bolinhas
(iii) were used for Christmas and other occasions.
(iv) charm.

Question 5.
The baker or bread-seller of those days had a peculiar dress known as the Kabai. It was a single piece long frock reaching down to the knees. In our childhood we saw bakers wearing a shirt and trousers which were shorter than full-length ones and longer than half pants. Even today, anyone who wears a half pant which reaches just below the knees invites the comment that he is dressed like a paderl
(i) What is the ‘Kabai’?
(ii) Describe the traditional dress of baker?
(iii) What did the narrator see in his childhood?
(iv) Pick out the word from the passage which means the same as—‘strange’.
Answer:
(i) ‘Kabai’ is the traditional dress of baker.
(ii) It is a single piece long frock reaching down to the knees.
(iii) The narrator saw in his childhood that the bakers wore a shirt and trousers which were shorter than full length ones and longer than half pants.
(iv) peculiar

Question 6.
The baker usually collected his bills at the end of the month. Monthly accounts used to be recorded on some wall in pencil. Baking was indeed a profitable profession in the old days. The baker and his family never starved. He, his family and his servants always looked happy and prosperous. Their plump physique was an open testimony to this. Even today any person with a jackfruit-like physical appearance is easily compared to a baker.
(i) When did the baker usually collect his bills?
(ii) How were the monthly accounts maintained?
(iii) Who is generally compared to a baker?
(iv) Pick out the word from the passage which means the same as—rich.
Answer:
(i) The bakers usually collected his bills at the end of the month.
(ii) The monthly accounts used to be recorded on some wall in pencil.
(iii) Any person with a jack fruit like physical appearance is easily compared to a baker.
(iv) prosperous.

Coorg

Glimpses of India Extra Questions and Answers Very Short Answer Type

Question 1.
Where is Coorg located?
Answer:
Coorg is situated between Mysore and the coastal town of Mangalore.

Question 2.
Which is the smallest district of Karnataka?
Answer:
Coorg is the smallest district of Karnataka.

Question 3.
Why is Coorg compared to heaven?
Answer:
Coorg is compared to heaven because of its natural beauty.

Question 4.
How much rain does the area receive during the monsoons?
Answer:
The area receives a heavy rainfall during monsoons.

Question 5.
Why do visitors keep away from the Coorg during the monsoon?
Answer:
Due to the heavy rainfall the visitors keep away from the Coorg during monsoon.

Question 6.
What is the nature of the people of Coorg?
Answer:
The nature of the people of Coorg is independent.

Question 7.
What is the possible descent of Coorg people?
Answer:
The people of Coorg are possibly of Greek or Arabic descent.

Question 8.
What are the people of Coorg known as?
Answer:
The people of Coorg are known as Kodavus.

Question 9.
What is the Kuppia?
Answer:
Kuppia is the long, black coat with an embroidered waist-belt worn by the Arabs and the Kurds.

Question 10.
What tradition do the Coorgi homes have?
Answer:
Coorgi homes have a tradition of hospitality.

Question 11.
Who was General Cariappa?
Answer:
General Cariappa, the first Chief of Indian Army was a Coorgi.

Question 12.
What is the source of water for the river Kavery?
Answer:
The source of water for the river Kaveri is the hills and forests of Coorg.

Question 13.
Where is Indian largest Tibetan colony?
Answer:
Bylakuppe in Coorg.

Glimpses of India Extra Questions and Answers Short Answer Type

Question 1.
Where is Coorg situated?
Answer:
Coorg is situated between Mysore and the coastal town of Mangalore in Karnataka state.

Question 2.
What is Coorg famous for?
Answer:
Coorg is famous for water sports, rock climbing, mountain biking and trekking.

Question 3.
Which story shows that Coorgis are of Greek descent?
Answer:
A story narrates that a part of Alexander’s Army moved south along the coast and settled at Coorg when their return became impractical. These people married the locals and became inhabitants of this place.

Question 4.
When can one visit Coorg?
Answer:
Coorg can be visited between September and March. It is the season of happiness during these months. One can enjoy different water sports like rafting, canoeing, rappelling rock climbing, etc.

Question 5.
How can one reach Coorg?
Answer:
One can reach Coorg either by road, air or rail. There are two routes from Bangalore. The route via Mysore is frequented one. The other route is Neelamangal, Kurigal and Chanrayanapatna.

Question 6.
What shows that Coorgis might be of Arabic descent?
Answer:
Kodavus wear the long, black coat with an embroidered waist belt, which is known as ‘Kuppia’. This coat resembles the Kuffia worn by the Arabs and the Kurds.

Question 7.
What are the various adventure sports available in Coorg?
Answer:
The various adventures sports available in Coorg to the tourists who visit Coorg are river rafting, canoeing, rappelling or going down a cliff by slidding down a rope, rock climbing, mountain biking and trekking.

Question 8.
Why is the climb to the Brahmagiri hills an important part of a visit to Coorg?
Answer:
The climb to the Brahmgiri hills offers the panoramic view of the entire misty landscape of Coorg. Besides, it leads to Nisargadhama and then, to Bylakuppe; the hidden surprises for the visitors. Thus, it is important to climb the Brahmagiri hills while visiting Coorg.

Question 9.
Write two characteristics of people of Coorg?
Answer:
The people of Coorg are fiercely independent and brave. Coorgi houses have a tradition of hospitality. The Coorg regiment is the most decorated one in the Indian Army. They feel proud sharing the courageous works of their sons and fathers.

Glimpses of India Extra Questions and Answers Long Answer Type

Question 1.
Write a brief description of Coorg with special reference to its beauty, people main crops, tourist seasons and speciality for army?
Answer:
Coorg is a small district of Karnataka state of India. This is a land of rolling hills inhabited by a proud race of martial men, beautiful women and wild creatures. It is famous for its coffee estates, evergreen rainforests and spices. Its thirty per cent area is covered with the evergreen rainforests. The people of Coorg are independent and brave. The Coorgi homes have a tradition of hospitality. The Coorgi regiment is one of the most decorated one in the Indian Army. The first Chief of the Indian Army, General Cariappa was a Coorgi. This place offers a variety of natural sciences which are liked by the tourists. The mountains offer various adventure games like river rafting, canoeing, rappelling, rock climbing and mountain biking. The best season to visit this place is from September to March.

Question 2.
What is the story prevalent about the Kodavus people’s descent?
OR
What is said about the descent of people of Coorg?
OR
What is the story behind Coorgi people’s descent that makes them so brave? *
Answer:
The people of Coorg are independent and brave. They are possibly of Greek or Arabic descent. There are two stories about their descent. According to one story, these people are the descendants of Greek. It is believed that a part of Alexander’s army moved south along the coast. When they found it difficult to return they settled there. They married among the locals and started their family life. According to another story, these people originated from Arabic people. This theory is supported by their dress which is known as kuppia. It resembles the kuffia worn by the Arabs and the Kurds.

Question 3.
The people of Coorg have a tradition of courage and bravery. How has it been recognised in modern India?
OR
“The people of Coorg are famous for their tradition of hospitality and valour in the army. Explain with reference to ‘Glimpses of India’.
Answer:
It is quite true that the people of Coorg are famous for their traditions of hospitality, love, respect and fellow-feeling. People visiting Coorg always feel at home there and enjoy the panoramic view of the whole landscape of Coorg. The visitors get pleasure in riding over the elephants and the fresh smell of coffee plantation. The residents are always eager to tell the tales of vigour, bravery and courage only. related to their sons and fathers. These people show utmost courage and exemplary bravery during the war period. It is a matter of great concern for all of us that Coorg Regiment is famous for its bravery. It is one of the most decorated in the Indian army. General Cariappa was a Coorgi. It is very rewarding for all of us. Even the government has allowed the Coorgi people to carry firearms with them. They can move in any part of the country without a licence.

Question 4.
Where is Coorg located? When should-one visit? Write an account of the life of the people of Coorg.
Answer:
Coorg is situated in the midway between Mysore and coastal town of Mangalore. It is the smallest district of Karnataka. It is a piece of heaven fallen from the kingdom of God. This is a land of rolling hills. There is the smell of coffee in the air. It has evergreen rainforests, spices and coffee plantations. The martial men and beautiful women of Coorg are of Greek or Arabic descent.

As per a story, a part of Alexander’s army moved south and settled here as return became difficult. The rites are different from that of Hindu mainstream. All of them wear a waist-belt called Kuppia. It resembles the Kuffia worn by the Arabs and Kurds. These Coorgs have many tales of bravery. They are very hospitable. Coorg soldiers are brave. They can carry firearms without any license. The Coorg Regiment is one of the most decorated regiments in the Indian Army.

Question 5.
Based on your reading of the chapter, write a paragraph describing ‘The people of Coorg’.
Answer:
It is said that Coorgis (Kodavus as they are locally known) are the ones easier to love than to like. One of the most hospitable people in India, the doors of their hQmes are always open to guests. Cosmopolitan in their outlook, they make friends easily. They are exceptionally brave. Coorg can be called a land of generals- Field Marshall Cariappa, the first general of free India and General Thimayya being the most well known of the lot. Almost every household has at least one person serving in the armed forces. The birth of male children as well as their death ceremonies are still celebrated with a gun salute.

Question 6.
The Coorgis are thousands of miles away from their origin, Greek or Arab. Yet they carry on their unique values, customs and practices. Does this make them appreciable to you?
OR
The people of Coorg are famous for their tradition of hospitality and valour in the Indian Army. Describe this statement with reference to the chapter what you have read.
Answer:
Coorg is situated midway between Mysore and the coastal town of Mangalore. It is the smallest district of the state of Karnataka. It is a piece of heaven fallen from the kingdom of God. We can find hills lull of greenary here. It has evergreen rainforests, spices and coffee plantations. It rains heavily here during the rainy season. There is the smell of coffee in the air. The people of Coorg are martial men. These people are of Greek or Arabic descent. According to a legend, a part of Alexander’s army stopped and settled here. They married amongst the locals.

Their culture is seen in the martial traditions, marriage and religious rites, they are different from the Hindu mainstream. These people wear a long black coat with an embroidered waist-belt. This is known as Kuppia and it resembles Kuffia that is worn by the Arabs and the Kurds. They love traditions of hospitality and this quality makes them unique.

Thinking about the Text

Question 1.
Where is Coorg?
Answer:
Coorg is situated in the midway between Mysore and the coastal town of Mangalore. It is the paradise on this earth. It must have been drifted from the kingdom of God.

Question 2.
What is the story about the Kodavu people’s descent?
Answer:
There are many stories about the Kodavu people’s descent. One of the stories tells that a part of Alexander’s army while moving south along the coast could not return. They settled there and got into marital relations with the local people. One can note the difference between their traditions and the other Hindu traditions. Thus these are from Greek or Arabic descent. The theory of Arab origin supports that the Kodagus wear long black coat with an embroidered waist belt known as Kuppia, it resembles the Kuffia worn by the Arabs and the Kurds.

Question 3.
What are some of the things you now know about:
(i) the people of Coorg?
(ii) the main crop of Coorg?
(iii) the sports it offers to tourists?
(iv) the animals you are likely to see in Coorg?
(v) its distance from Bangalore, and how to get there?
Answer:
(i) They are hospitable and friendly. They will tell the tales of bravery of their sons and fathers.
(ii) Coffee plantation is the main crop of Coorg.
(iii) These are river-rafting, canoeing rappelling, rock-climbing, mountain biking and the walking trails.
(iv) These are elephants, langurs and macaques.
(v) From Bangalore, it is around 250-260 km. By road there are two routes. The route via Mysore is often frequented one. The other route is via Neelamangal, Kunigal, Chanrayan^patna.

Question 4.
Here are six sentences with some words in italics. Find phrases from the text that have the same meaning. (Look in the paragraphs indicated).
(i) During monsoons it rains so heavily that tourists do not visit Coorg. (para 2)
(ii) Some people say that Alexander’s army moved south along the coast and settled there, (para 3)
(iii) The Coorg people are always ready to tell stories of their sons’ and fathers’ valour, (para 4)
(iv) Even people who normally lead an easy and slow life get smitten by the high-energy adventure
sports of Coorg.
(v) The theory of the Arab origin is supported by the long coat with embroidered waist-belt they wear,
(vi) Macaques, Malabar squirrels, observe you carefully from the tree canopy.
Answer:
(i) Keep away
(ii) A part of
(iii) Willing to
(iv) The most laidback individuals become converts to the life
(v) Draws support
(vi) Keep a watchful eye

Glimpses of India Extra Questions and Answers Reference to Context

Read the following passages and answer the questions that follow:

Question 1.
Midway between Mysore and the coastal town of Mangalore (now Mangaluru) sits a piece of heaven that must have drifted from the kingdom of god. This land of rolling hills is inhabited by a proud race of martial men, beautiful women and wild creatures.
(i) Where is Coorg located?
(ii) Why is Coorg compared to heaven?
(iii) What does the author mean by ‘drifted from the kingdom of god’?
(iv) Pick out the word from the passage that means the same as—‘separated’.
Answer:
(i) Coorg is situated between Mysore and the coastal town of Mangalore in Karnataka.
(ii) Coorg is compared to heaven because of its natural beauty.
(iii) The author means that Coorg had got separated from heaven, the kingdom of god.
(iv) drifted.

Question 2.
Coorg, or Kodagu, the smallest district of Karnataka, is home to evergreen rainforests, spices and coffee plantations. Evergreen rainforests cover thirty percent of this district. During the monsoons, it pours enough to keep many visitors away. The season of joy commences from September and continues till March. The weather is perfect, with some showers thrown in for good measure. The air breathes of invigorating coffee. Coffee estates and colonial bungalows stand tucked under trees canopies in prime comers. (Page 90)
(i) What is Coorg famous for?
(ii) Why do the visitors keep away from Coorg during the monsoons?
(iii) Which season is the best season for the tourists?
(iv) Pick out word from the passage that means the same as—‘Starts/begins’.
Answer:
(i) Coorg is famous for evergreen rainforests, spices and coffee plantations.
(ii) Due to the heavy rainfall the visitors keep away from Coorg during the monsoons.
(iii) September to March is the best season for tourists to visit Coorg.
(iv) ‘commences’

Question 3.
The fiercely independent people of Coorg are possibly of Greek or Arabic descent. As one story goes, a part of Alexander’s army moved south along the coast and settled here when return became impractical. These people married amongst the locals and their culture is apparent in the marital traditions, marriage and religious rites, which are distinct from the Hindu mainstream.
(i) What is the nature of the people of Coorg?
(ii) Whose descendents are the people of Coorg?
(iii) In which ways are culture of locals distinct from Hindu mainstream?
(iv) Pick out word from the passage that means the same as—“Origin”.
Answer:
(i) The people of Coorg are very independent.
(ii) People of Coorg are possible descendents of Greek or Arabic.
(iii) They and their culture are different in martial traditions and religious rites.
(iv) ‘Descent’.

Question 4.
Coorgi homes have a tradition of hospitality, and they are more than willing to recount numerous tales of valour related to their sons and fathers. The Coorg Regiment is one of the most decorated in the Indian Army, and the first Chief of the Indian Army, General Cariappa, was a Coorgi. Even now, Kodavus are the only people in India permitted to carry firearms without a licence. (Page 91)
(i) What are the Coorgi homes known for?
(ii) Which fact’ in the passages states that Coorgis are traditionally brave people?
(iii) Who was General Cariappa?
(iv) Pick out word from the passage that means the same as—‘bravery.
Ans.
(i) The Co.orgi homes are known for their hospitality and bravery.
(ii) They have numerous tales of valour related to their sons and fathers.
(iii) General Cariappa, the first Chief of the Indian Army was a Coorgi.
(iv) Valour’.

Question 5.
The river, Kaveri, obtains its water from the hills and forests of Coorg. Mahaseer—a large freshwater fish—abound in these waters. Kingfishers dive for their catch, while squirrels and langurs drop partially eaten fruit for the mischief of enjoying the splash and the ripple effect in the clear water. Elephants enjoy being bathed and scrubbed in the river by their mahouts.
(i) Where does the river Kaveri obtain the water from?
(ii) What is in abundance in the river?
(iii) How do the elephants enjoy?
(iv) Pick out the word from the passage that means*the same as—‘rubbed’.
Answer:
(i) The river Kaveri obtains the water from the hills and forests of Coorg.
(ii) Mahaseer, a large freshwater fish is in abundance in the river.
(iii) The elephants enjoy bathing and scrubbing in the river by their mahouts.
(iv) ‘scrubbed’.

Question 6.
The most laidback individuals become converts to the life of high-energy adventure with river rafting, canoeing, rappelling, rock climbing and mountain biking. Numerous walking trails in this region are a favourite with trekkers. Birds, bees and butterflies are there to give you company. Macaques, Malabar squirrels, langurs and slender loris keep a watchful eye from the tree canopy. I do, however, prefer to step aside for wild elephants.
(i) What adventure sports are available in Coorg?
(ii) How do the trekkers enjoy here?
(iii) Who accompanies the tourists?
(iv) Pick out the word form the passage that means the same as—relaxed.
Answer:
(i) Adventure sports available in Coorg are river rafting, canoeing, repelling, rock climbing, and mountain biking.
(ii) There are numerous walking trails which are favourite with trekkers.
(iii) Birds, bees and butterflies are there to accompany the tourists.
(iv) ‘laidback’.

Question 7.
The climb to the Brahmagiri hills brings you into a panoramic view of the entire misty landscape of Coorg. A walk across the rope bridge leads to the sixty-four-acre island of Nisargadhama. Running into Buddhist monks from India’s largest Tibetan settlement, at nearby Bylakuppe, is a bonus. The monks, in red, ochre and yellow robes, are amongst the many surprises that wait to be discovered by visitors searching for the heart and soul of India, right here in Coorg.
(i) What does a climb on Brahmagiri hills present?
(ii) What are others attractive places near Coorg?
(iii) Where is Indian’s largest Tibetan colony?
(iv) Pick out the word from the passage that means the same as—Buddhist priest.
Answer:
(i) A climb to Brahmagiri hills presents a panoramic view of the entire misty landscape of Coorg.
(ii) Nisargadhama and Bylakuppe are the other attraction places near Coorg.
(iii) India’s largest Tibetan colony is nearby Bylakuppe in Coorg.
(iv) ‘Monk’.

Tea from Assam

Glimpses of India Extra Questions and Answers Very Short Answer Type

Question 1.
What did Pranjol order for?
Answer:
Pranjol ordered for two cups of tea.

Question 2.
Where were both the boys going to?
Answer:
Both the boys were going to Assam.

Question 3.
What did Rajvir tell Pranjol?
Answer:
Rajvir told Pranjol that over eighty crore cups of tea are drunk everyday.

Question 4.
Where were the two boys?
Answer:
The two boys were in the train.

Question 5.
What was Pranjol doing?
Answer:
Pranjol was reading a detective book.

Question 6.
What was surprising for Rajvir?
Answer:
Rajvir had never seen such a greenery before.

Question 7.
What two crops did Rajvir see?
Answer:
Rajvir saw paddy fields and tea-bushes.

Question 8.
What was magnificent?
Answer:
The view of tea gardens was magnificent.

Question 9.
Who were the doll-like figures?
Answer:
The doll like figures were the women.

Question 10.
What is Rajvir telling Pranjol?
Answer:
Rajvir is telling Pranjol legends about the origin of tea.

Question 11.
Where was tea first drunk?
Answer:
The tea was first drunk in China.

Question 12.
When did tea come to Europe?
Answer:
In the sixteenth century.

Question 13.
How was tea used at that time?
Answer:
The tea was used as medicine rather than a beverage.

Question 14.
What did the ancient Buddhist ascetic do?
Answer:
An ancient Buddhist ascetic cut off his eyelids as he felt sleepy during meditations.

Question 15.
Which is the important junction of Assam?
Answer:
Mariani junction.

Question 16.
Where are the tea leaves collected?
Answer:
Tea leaves are collected in bamboo baskets by the women.

Question 17.
Which words are Chinese?
Answer:
‘Chai’ and ‘Chini’ are from Chinese.

Glimpses of India Extra Questions and Answers Short Answer Type

Question 1.
Which Chinese story did Rajvir tell about the discovery of tea?
Answer:
There was a Chinese story about tea. It was said that there was a Chinese emperor. He always drank boiled water. Once while boiling the water, some leaves of the burning twigs fell into the pot. The boiled water gave a delicious flavour. They were tea-leaves.

Question 2.
Narrate the story of a Buddhists monk behind the discovery of tea?
Answer:
There was a Buddhist monk story about tea. A Buddhist ascetic was busy in his meditation for God. By chance he fell asleep and his meditation broke. He did not like it. In a state of anger, he cut his eyelids and threw them on the earth. There appeared tea plants out of these eyelids. Then these leaves were put in the hot water. When people drank the hot water, it banished their sleep. In the beginning it was drunk as a medicine rather than a beverage.

Question 3.
Where was Rajvir going? Why?
Answer:
Rajvir was going to Pranjol’s house in Assam. Pranjol has invited him to spend the summer vacations with him at his house. Moreover, Rajvir was interested to know about the tea gardens in Assam. So he was going to Assam.

Question 4.
What excited Rajvir? Why did Pranjol not share his excitement?
Answer:
Rajvir had never seen the tea garden before. So the sight of tea garden excited him. But Pranjol has been born and brought up in the tea plantations. He had seen them many times. So he did not share Rajvir’s excitement.

Question 5.
What are the various legends regarding the origin of tea?
Answer:
There was a Chinese story about tea. It was said that there was a Chinese emperor. He always drank boiled water. Once while boiling the water, some leaves of the burning twigs fell into the pot. The boiled water gave a delicious flavour. They were tea-leaves.

There was a Buddhist monk story about tea. A Buddhist ascetic was busy in his meditation for God. By chance he fell asleep and his meditation broke. He did not like it. In a state of anger, he cut his eyelids and threw them on the earth. There appeared tea plants out of these eyelids. Then these leaves were put in the hot water. When people drank the hot water, it banished their sleep. In the beginning it was drunk as a medicine rather than a beverage.

Glimpses of India Extra Questions and Answers Long Answer Type

Question 1.
What are the legends of the discovery of tea?
OR
What are the various legends regarding the origin of tea?
Answer:
There are two legends about the discovery of tea. According to one story, it was the Chinese emperor who discovered it accidentally. He always boiled water before drinking it. One day a few leaves of plants fell into the boiling water which gave it a delicious taste. It is said that they were tea leaves. The emperor started their use in boiling water. Another Indian legend says that an ancient Buddhist ascetic cut off his eyelids because he felt sleepy during meditation. Ten tea plants grew out of the eyelids. The leaves of these plants when put in hot water and drunk banished sleep. Thus, tea came into existence.

Question 2.
Based on your reading of the chapter “Tea From Assam”, write a paragraph on the topic “Importance of Tea in India”.
OR
You know that everybody drinks tea everyday in India. It banishes our sleep and makes us feel fresh. Describe the ‘importance of tea in India’.
Answer:
Today all people drink tea every day in India. But the quantity of tea differs from person to person. Life in an Indian house starts with a refreshing cup of tea. India has now surpassed China in tea production. India is one of the largest tea producers in the world. 70 per cent of its tea is consumed within India. Assam and Darjeeling produced world renowned tea. Tea became widely popular in India during 1950s Tea industry is the second largest employer in the country. It is grown in many states in India. Tea plants need shade to grow besides humid climate. It is a labour oriented industry. Tea has a number of medical and therapeutic properties.

Glimpses of India Extra Questions and Answers Reference to Context

Read the following passages and answer the questions that follow:

Question 1.
“CHAI-GARAM… garam chai,” a vendor called out in a high-pitched voice.
He came up to their window and asked, “Chai, sa’ab?”
“Give us two cups,” Pranjol said.
They sipped the steaming hot liquid. Almost everyone in their compartment was drinking tea too.
“Do you know that over eighty crore cups of tea are drunk every day throughout the world?” Rajvir said.
(i) Who was speaking in a high pitched voice and what?
(ii) What did Pranjol ask the tea vendor?
(iii) What did Rajvir tell Pranjol?
(iv) Pick out the word from the passage that means the same as “drank”.
Answer:
(i) A vendor was speaking in a high pitched voice for Chai-garam.
(ii) Pranjol asked the tea-vendor to give two cups of tea.
(iii) Rajvir told Pranjol that over eighty crore cups of tea are drunk every day throughout the world.
(iv) “sipped”.

Question 2.
“Whew!” exclaimed Pranjol. “Tea really is very popular.” The train pulled out of the station. Pranjol buried his nose in his detective book again. Rajvir too was an ardent fan of detective stories, but at the moment he was keener on looking at the beautiful scenery. It was green, green everywhere. Rajvir had never seen so much greenery before. Then the soft green paddy fields gave way to tea bushes.
(i) What was exclaimed by Pranjol?
(ii) What was Pranjol doing in the train?
(iii) What was surprising for Rajvir?
(iv) Pick out word from the passage that means the same as ‘firm’.
Answer:
(i) Pranjol exclaimed “Tea is really very popular”.
(ii) Pranjol was reading detective stories from a novel.
(iii) Rajvir was surprised to see the beautiful scenery.
(iv) ‘ardent’.

Question 3.
It was a magnificent view. Against the backdrop of densely wooded hills a sea of tea bushes stretched as far as the eye could see. Dwarfing the tiny tea plants were tall sturdy shade-trees and amidst the orderly rows of bushes busily moved doll-like figures. In the distance was an ugly building with smoke billowing out of tall chimneys. .“Hey, a tea garden!” Rajvir cried excitedly. Pranjol, who had been born and brought up on a plantation, didn’t share Rajvir’s excitement.
(i) Which view had been referred to above?
(ii) What had been compared with the tea plantation?
(iii) Why was Rajvir excited?
(iv) Pick out word from the passage that means the same as – ‘beautiful’.
Answer:
(i) The view of tea plantation was magnificent.
(ii) The tea garden had been compared with a vast sea.
(iii) Rajvir was excited after seeing the tea garden.
(iv) ‘magnificent’.

Question 4.
“Oh, this is tea country now, “he said. “Assam has the largest concentration of plantations in the world. You will see enough gardens to last you a lifetime!”
“I have been reading as much as I could about tea,” Rajvir said. “No one really knows who discovered tea but there are many legends.”
“What legends?”
“Well, there’s the one about the Chinese emperor who always boiled water before drinking it. One day a few leaves of the twigs burning under the pot fell into the water giving it a delicious flavour. It is said they were tea leaves.”
“Tell me another!” scoffed Pranjol,
“We have an Indian legend too. Bodhidharma, an ancient Buddhist ascetic, cut off his eyelids because he felt sleepy during meditations. Ten tea plants grew out of the eyelids. The leaves of these plants when put in hot water and drunk banished sleep.
(i) What did Rajvir say?
(ii) What was he telling him?
(iii) What was done by the Buddhist ascetic?
(iv) Pick out word from the passage that means the same as—‘tasty’.
Answer:
(i) Rajvir said that Assam had the largest concentration of plantations in the world.
(ii) He was telling him the legends about the origin of tea. There are many legends about the origin of tea.
(iii) The Buddhist monk cut off his eyelids and threw them away.
(iv) ‘delicious’.

Question 5.
“Tea was first drunk in China,” Rajvir added, “as far back as 2700 B.C! In fact words such as tea, ‘cha? and ‘chin? are from Chinese. Tea came to Europe only in the sixteenth century and was drunk more as medicine than as beverage.”
The train clattered into Mariani junction. The boys collected their luggage and pushed their way to the crowded platform.
Pranjol’s parents were waiting for them.
Soon they were driving towards Dhekiabari, the tea-garden managed by Pranjol’s father.
(i) Where was tea first drunk?
(ii) Which words are from Chinese?
(iii) When did tea come to Europe?
(iv) Pick out the word from the passage that means the same as—‘a period of hundred years’.
Answer:
(i) Tea was first drunk in China.
(ii) ‘Cha? and Chini words are from Chinese.
(iii) In the Sixteenth century, tea came to Europe.
(iv) ‘century’.

Question 6.
An hour later the car veered sharply off the mail*road. They crossed a cattle-bridge and entered Dhekiabari Tea Estate. On both sides of the gravel-road were acre upon acre of tea bushes, all neatly pruned to the same height. Groups of tea-pluckers, with bamboo baskets on their backs, wearing plastic aprons, were plucking the newly sprouted leaves. Pranjol’s father slowed down to allow a tractor, pulling a trailer-load of tea leaves, to pass.
“This is the second-flush or sprouting period, isn’t it, Mr Barua?” Rajvir asked. “It lasts from May to July and yields the best tea.”
(i) What was worn by the women?
(ii) What were they doing?
(iii) When is the best yield for tea?
(iv) Pick out the word from the passage that means the same as—‘clothes’.
Answer:
(i) The women wore plastic aprons.
(ii) They were plucking the newly sprouted leaves.
(iii) The best yield lasts from May to July.
(iv) ‘aprons’.

Amanda Extra Questions and Answers Class 10 English First Flight

Online Education for Amanda Extra Questions and Answers Class 10 English First Flight

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Online Education for Amanda Extra Questions and Answers Class 10 English First Flight

Amanda Extra Questions and Answers Short Answer Type

Amanda Class 10 Extra Question Answer Question 1.
What does the poet ask Amanda not to do in the poem” ‘Amanda’?
Answer:
The poet advises Amanda not to bite her nails, not to hunch her shoulders and not to eat chocolate. She advises her to sit straight and take care of her acne. She further advises her to keep herself clean.

Amanda Extra Questions Question 2.
In which way does Amanda imagine herself to be mermaid? .
Answer:
Mermaid is believed to be a creature with a woman’s head and body, and a fish’s tail instead of legs.
Amanda imagines herself or wishes to be free like a mermaid, which is moving slowly in a state of bliss in the sea, which is green like an emerald.

Amanda Extra Questions And Answers Question 3.
What instructions were given to Amanda about her homework, room and shoes?
Answer:
Amanda had been commanded or advised to finish her homework and keep her room neat and clean. She is also instructed to clean her shoes.

Amanda Poem Extra Questions Question 4.
How and why does Amanda say that she is an orphan?
Answer:
Amanda seems to be fed up with continuous instructions and naggings. She is feeling that her freedom is curtailed. So, she imagines herself to be an orphan street child who leaves imprints caused on the soft dust by her bare feet. She feels that silences is golden or precious and freedom is sweet.

Extra Questions Of Amanda Question 5.
What impression do you form about Amanda, after reading the poem ‘Ama ida’?
Answer:
Amanda feels suffocated because she is controlled and instructed not to do one thing or the other. She feels that her freedom is curtailed. But Amanda wishes to be free to live in her own world. She is a very sensitive girl who indulges in daydreaming quiet often. She highly values silence and freedom.

Amanda Class 10 Extra Questions Question 6.
What type of life does Amanda wish for?
Answer:
Amanda feels that her freedom has been curtailed. She is leading a controlled life under constant nagging. She wishes for a life free from all the restrictions. She wants to lead a life like a fairy, a mermaid or an orphan. Like a mermaid she wants to drifts blissfully. For, silence is golden and freedom is sweet.

Amanda Important Questions Question 7.
I am an orphan, roaming the street.
Is Amanda an orphan? If not, why does she say so?
Answer:
No, Amanda is not an orphan. There are many restrictions on her. She does not like this life. She wants freedom. She feels that there is no one to understand her feelings. She is all alone. This is the reason she says that she is an orphan.

Class 10 Amanda Extra Questions Question 8.
Don’t eat that chocolate Amanda!
Remember your acne, Amanda!
Why is Amanda forbidden to eat chocolate?
Answer:
Amanda is a little child who wants freedom from all restrictions of life. She loves to eat chocolate but she is forbidden to eat them as these will affect her health adversely. She is advised to take care of her acne.

Class 10 English Amanda Extra Questions Question 9.
Will you please look at me when I’m speaking to you,
Who do you think is speaking to Amanda?
Answer:
The poet is speaking to Amanda. She had put many restrictions on her. She advises her to take care of her health and acne. She is advised to follow a controlled and disciplined life.

Amanda Short Question Answer Question 10.
life in a tower is tranquil and rare;
I’ll certainly never let down my bright hair’.
Why does the poet say that life in a tower is tranquil and rare? Whose life is he talking about?
Answer:
The poet feels that life in a tower is peaceful and full of freedom because there is no one to nag you. She is talking about Rapunzel who lives in a peaceful tower.

Question 11.
Why does Amanda imagine to be
(i) a Mermaid (ii) an orphan, and (iii) Rapunzel,
What does it show about her?
Answer:
(i) Amanda imagines herself to be a mermaid so that she may drift in the silent sea and enjoy the loneliness and peace there. She yearns for freedom.

(ii) She wishes to be an orphan so that she may play bare feet in the dust without receiving several instructions or scolding. She wishes for her independence and freedom.

(iii) Amanda is fascinated by the lonely and tranquil life of Rapunzel in a closed tower. She wishes for such a life so that her nagging mother may not reach there. Here also, she yearns for her freedom from nagging.

Question 12.
“Don’t bite your nails, Amanda!
Don’t hunch your shoulders, Amanda!”
Amanda’s parents were over anxious about her. She often found their instructions very stifling. Reading the poem and based on Amanda’s experience, write a paragraph on the topic “Should parents be allowed to control children?”
Answer:
It goes without saying that no child can survive the early years of its life without the care and protection of its parents. But some parents are so over protective and over anxious about their children that they don’t let their children live in peace. They don’t allow them to explore and find out things on their own. Such parents kill the child’s initiative in learning. These parents always boss around and irritate their children.

They don’t trust their child’s capability to do things independently. However, the parents may control the children and guide them as long as it is necessary. Equipped with knowledge and confidence they will be able to face the world boldly. Gradually the child should be allowed to grow on its own and be responsible for its actions. When parents give freedom to their children they gain confidence and learn to do things in a better way.

Question 13.
If it fact that every person including a young child has his/her own individuality and personality. It is not necessary that the child will see the world according to the direction of his/her parents. Based on the reading the poem “Amanda” write a paragraph on: Should children be given freedom”.
Answer:
Growing up is a phase which requires a lot of space. A single child in his teens would feel more claustrophobic than four kids in the same family. The reason being parents of a single child tend to be more protective and possessive. What they fail to understand is that without sufficient space to grow the child will only end up disliking his/her parents. Freedom is necessary in any relationship.

A child should be allowed to choose his hobbies, to learn what he pleases, to play with kids of his age. In the present times, where nothing is safe and none can be trusted, jJarents are only dissuaded from sending their kids out to play. It is only through these activities can a child learn to socialize and understand values. Therefore, parents should give enough freedom for the child to grow but also make sure that the child is not led away by material needs.

Question 14.
Childhood blooms and bounces with the wind of innocence and fanciful fantasy. Any kind of outside or forceful restriction is completely unbearable to a child. If he is nagged or scolded, he may feel alienated and withdrawn. But nagging is not a good option. In the context of the poem “Amanda”, write a paragraph on “effects of parental nagging”.
Answer:
Nagging is never a good option. Parents have a tendency to nag their children, especially regarding their studies. But nagging never helps. When a parent keeps on ranting to the child to study, the child will only grow averse to studying. It will create resentment between the child and the parent.

After a while a point will be reached where the child will simply stop listening to the parent. It also makes the child feel controlled. Parents keep repeating what is to be done, how it is to be done, etc. over and over again, always supervising. This will create stress for the child and make him/her uncomfortable. Hence, parents should indulge in looking at the brighter side and praise their kids’ accomplishments and avoid pointing out the weaknesses.

Question 15.
It is said that excess of everything is bad. Excess of parental love may make a cjiild pampered , in the same way excess of nagging may throw a child into negativity. These statements are seen justified to some extent in the poem ‘Amanda’. Explain.
Answer:
None can refute the pious role of parents or elders or teachers in the proper grooming and holistic development of a child. Parent’s personality resonates and reflects through the behaviours and personality of a child. Parents do every possible thing, they can do, to shape the character and habits of their child. But sometimes, in course of nurturing the kid, the parents cross the limits unknowingly.

They became either overcaring or over protective or over anxious. They forget the fact that, when a matured mind cannot tolerate excess of do’s and don’ts, how can they expect it from a child who is totally unaware of the worries and cares of the world. To a child the world means a world of imagination fancy and fairy.

If being nagged repeatedly she may form negative opinions about his/her mother and father. The same thing we find in the poem ‘Amanda’. Amanda is a girl of around 8-11 year of age who lives in her own fairy land. She does not appreciate the constant scolding or nagging of her father/mother.

She feels that her freedom is punctuated. So, she instead of following the instructions, remains wandering in her own world of imagination. Excess of nagging has resulted into negativity as Amanda considers herself orphan. She sulks. She avoids eye to eye contact. Hence, parents must understand the line of boundary and act.

Question 16.
How old do you think Amanda is? How do you know this?
Answer:
Amanda is a teenager. This is the age when a child wants to have freedom. Teenagers do not like nagging and want to have free life. The poet advises Amanda to take care of her acne which commonly appears on the face of a teenager.

Question 17.
Who do you think is speaking to her?
Answer:
Her mother is speaking to her.

Question 18.
Why are stanzas—2, 4 and 6 given in parenthesis?
Answer:
The stanzas 2, 4 and 6 are given in parenthesis because they are the thoughts of the child in between the instructions that she is being given by her mother, which are given in stanzas! 3 and 5. The scolding by the mother and the child’s thoughts are placed in alternate stanzas by the poetess.

Question 19.
Who is speaker in stanzas 2, 4 and 6? Do you think this speaker is listening to speaker in stanza 1, 3, 5 and 7?
Answer:
In stanzas 2, 4 and 6, the speaker is the child Amanda?.No, she is not listening to her mother who is speaking in stanza 1, 3,5 and 7. She is lost in her own thoughts and does not listen to what is being said to her.

Question 20.
What could Amanda do if she were a mermaid?
Answer:
If Amanda were a mermaid, then she would drift slowly in a languid emerald sea. She would be the sole inhabitant of relaxed green sea and would move slowly on it.

Question 21.
Is Amanda an orphan? Why does she say so?
Answer:
No, Amanda is not an orphan. She says so because she wants to be alone and enjoy being herself she wants to roam around in the street alone and pattern dust with her barefeet. She finds silence ‘golden’ and freedom ‘sweet’. It is for this reason that she calls herself an orphan.

Question 22.
Do you know the story of Rapunzel? Why does she want to be Rapunzel?
Answer:
Rapunzel was a mythological figure, who was absolutely carefree, leading a calm and quiet life in tower, Amanda wishes to lead a carefree, calm and quiet life like Rapunzel.

Question 23.
What does the girl yearn for? What does this poem tell you about Amanda?
Answer:
The girl (Amanda) yearns for a life of freedom. The poem tells us that she is an imaginative girl who is constantly nagged by her unimaginative mother.

Question 24.
Read the last stanza. Do you think Amanda is sulking and is moody?
Answer:
No, Amanda is neither sulking, nor she is moody. She is simply longing for her freedom. She wants to go out and play wherever she likes.

Amanda Extra Questions and Answers Reference to Context

Read the following stanza and answer the questions that follow:

Question 1.
Don’t bite your nails, Amanda! ‘
Don’t hunch your shoulders, Amanda!
Stop that slouching and sit up straight,
Amanda!

(i) Name the poem and poet.
(ii) Who, do you think could be the speaker in the stanza?
(iii) What is the tone of the speaker towards Amanda?
(iv) Who is Amanda?
Answer:
(i) This stanza has been taken from the poem ‘Amanda’ composed by Robin Klein.
(ii) I, think the speaker could be either mother or the father.
(iii) The tone of the speaker towards Amanda is ‘ragging’ and ‘scolding’.
(iv) Amanda is a teenage girl.

Question 2.
(There is a languid, emerald sea,
where the sole inhabitant is me
a mermaid, drifting blissfully.)

(i) Who is the speaker?
(ii) What does the speaker wish?
(iii) Pick out the word from the stanza an antonym of‘energetic’.
(iv) Name the poem and poet.
Answer:
(i) Amanda is the speaker.
(ii) Amanda wishes to have freedom from constant nagging.
(iii) ‘languid’.
(iv) The poem “Amanda” composed by ‘Robin Klein’.

Question 3.
Did you finish your homework, Amanda?
Did you tidy your room, Amanda?
I thought I told you to clean your shoes, 
Amanda!

(i) Who speaks these lines and to whom?
(ii) What are the various works she has to do?
(iii) What does the parent think she asked Amanda to do?
(iv) Does Amanda like the advice of the speaker?
Answer:
(i) These lines are spoken by Amanda’s mother to Amanda.
(ii) She has to complete homework, clean her room and her shoes.
(iii) The parents think that she asked Amanda to clean her shoes.
(iv) No, she does not like the constant nagging by the poet. She wants to live without any restrictions.

Question 4.
(I am an orphan, roaming the street.
I pattern soft dust with my hushed, bare feet,
The silence is golden, the freedom is sweet.)

(i) Who is referred to as an orphan in the first line?
(ii) What does the speaker want to convey through this stanza?
(iii) Pick out the word from the stanza that means the same as—‘wandering’.
(iv) Name the poeip and poet.
Answer:
(i) Amanda.
(ii) She wants to roam in the street and make pattern on sands with her feet.
(iii) ‘roaming’
(iv) The poem “Amanda” written by ‘Robin Klein’.

Question 5.
Don’t eat that chocolate, Amanda!
Remember your acne, Amanda!
Will you please look at me when I’m speaking to you,
Amanda!

(i) Who is the speaker in these lines?
(ii) What does the speaker advise Amanda?
(iii) Which lines show that Amanda does not take interest in what the speaker says?
(iv) Name the poem and poet.
Answer:
(i) Robin Klein (poetess) is the speaker in these lines.
(ii) The speaker advised Amanda not to eat chocolate. She wants her to take care of her acne.
(iii) The line “will you please look at me… to you” shows that she is not interested in what the speaker says.
(iv) The poem “Amanda” composed by ‘Robin Klein’.

Question 6.
(I am Rapunzel, I have not a care;
life in a tower is tranquil and rare;
I’ll certainly never let down my bright hair!)

(i) Who is the speaker in the stanza?
(ii) What does the speaker wish to do?
(iii) What does the stanza promise?
Name the poem and poet.
Answer:
(i) Amanda is the speaker in this stanza.
(ii) The speaker wants to be like Rapunzel who lived peacefully in the tower.
(iii) The speaker promised herself that she would never let down her bright hair. (iv) The poem “Amanda” written by ‘Robin Klein’.

Question 7.
Stop that sulking at once, Amanda!
You’re always so moody, Amanda!
Anyone would think that I nagged at you,
Amanda! 

(i) Who is the speaker in the above stanza?
(ii) Who is being nagged and by whom in the above lines?
(iii) Do you think Amanda is moody?
(iv) Name the poem and poet.
Answer:
(i) Robin Klein is the speaker in this stanza.
(ii) Amanda is being nagged by the poet.
(iii) No, Amanda is not a moody girl. She is a normal girl who wants to get rid of constant nagging and live a peaceful life.
(iv) The poem “Amanda” written by “Robin Klein”.

The Necklace Extra Questions and Answers Class 10 English Footprints Without Feet

Online Education for The Necklace Extra Questions and Answers Class 10 English Footprints Without Feet

Here we are providing Online Education for The Necklace Extra Questions and Answers Class 10 English Footprints Without Feet, Extra Questions for Class 10 English was designed by subject expert teachers. https://ncertmcq.com/extra-questions-for-class-10-english/

Online Education for The Necklace Extra Questions and Answers Class 10 English Footprints Without Feet

The Necklace Extra Questions and Answers Short Answer Type

The Necklace Class 10 Extra Questions Question 1.
How did the Loisels react when they realised that the necklace had been lost?
Answer:
Matilda Loisel became very sad when they realised that the necklace had been lost. They were sure that the loss of necklace would make their life hell because Mr Loisel was only a petty clerk and it was very difficult for him to replace necklace of diamond.

The Necklace Extra Questions Question 2.
Why did Matilda not like to visit her rich friend?
Answer:
Matilda had inferiority complex. Whenever she visitedier rich friend she felt dejected and disappointed because of her poverty. She used to compare her lodgings to that of her friend’s. She did not have attractive dress and jewellery to adorn herself with. That is why, she did not like to visit her rich friend.

Necklace Extra Questions Question 3.
Why is Matilda unhappy with her life?
Answer:
Matilda is unhappy with her life because she ceaselessly, felt herself born for all delicacies and luxuries. The shabby walls, the worn chairs in her house tortured and angered her.

Necklace Class 10 Extra Questions Question 4.
Her husband is kind and loving. Do you agree? Give examples to support your answers.
Answer:
He wants her to be happy. He spends a huge savings that he had saved for years to buy a gun for his hobby for buying a pretty dress for his wife so that she could attend a big party and enjoy it. When the costly necklace is lost, he spends all his savings and even borrow to repay it. He works day and night but never creates any ruckus with his wife.

Extra Questions Of The Necklace Question 5.
What had Matilda’s husband saved the money for? Why did he then part with his savings?
Answer:
Matilda’s husband had saved a good amount of money to buy a gun for him. But when his wife refused to attend the party without a new dress, he had to give up buying the gun. He used the saved four hundred francs to buy her costume.

The Necklace Class 10 Extra Questions And Answers Question 6.
What was the cause of Matilda’s ruin? How could she have avoided it?
Answer:
Matilda’s aspiration and unrealistic dreams were the cause of her ruin. She paid due importance to materialistic things. She could have easily avoided if she had remained within her means. She was not a practical lady and had not understood her husband’s feelings.

The Necklace Important Questions Question 7.
What did Mme. Forestier tell Matilda about the reality of her Necklace?
Answer:
After having lost the borrowed necklace, Matilda replaced it with a diamond necklace bought for thirty-six thousand francs. But Mme Forestier told her that her necklace was false costing about 500 francs.

The Necklace Questions And Answers Question 8.
What changes came into the life of Loisels after the necklace was lost?
Answer:
They had to shift to a cheaper room and dismiss the servant. She did all the household works and shopping by herself. She fetched water, washed the floor, utensils and dirty clothes by herself. Matilda’s husband worked in the evening and late at night to pay back the debt.

The Necklace Extra Questions And Answers Question 9.
Why was Mme Forestier shocked to hear Matilda’s story?
Answer:
One Sunday, while walking, Matilda happened to see Mme Forestier. Matilda called her, but she could not recognise Matilda because she looked much older than her age. Mme Forestier was shocked to know that Matilda had suffered so much worrying about losing her necklace of real diamonds, whereas it was false.

The Necklace Class 10 Important Questions Question 10.
Do you think Matilda’s over-ambitious nature was the cause of her miseries?
Answer:
Yes, I do think that Matilda’s overambitious nature led to her avoidable miseries. Just to show herself a rich lady, she borrowed a necklace from her rich friend. Her miseries started when the necklace was lost by her.

The Necklace Extra Question Answer Question 11.
What kind of a person is Mme Loisel—why is she always unhappy?
Answer:
Mme. Loisel is a woman who lives in the world of dreams. She gives much value to her dreams and hence overlooks the realities of life. That is why she is always unhappy as dreams are a virtual reality and can’t be true.

Question 12.
What kind of a person is her husband?
Answer:
Her husband is a very simple and kind-hearted person. He is an ordinary man, who just like others, is caring and wants his wife to be happy.

Question 13.
What fresh problem now disturbs Mme Loisel?
Answer:
After buying a pretty dress, Mme Loisel was bothered by yet another problem. She had no jewels to adorn herself with. She said she would feel inferior and have a poverty-stricken look. Her husband -” suggested that she should wear some natural flowers. However, she refused and said that there was nothing more humiliating than to have a shabby air in the midst of rich women.

Question 14.
How is the problem solved?
Answer:
Mme Loisel’s husband solved this problem. He told his wife to request her friend, Mme Forestier, to lend her some jewels. When she went to Mme Forestier, the latter brought a jewel case for Mme Loisel so that she could choose whichever jewels she liked.

Question 15.
What do M. and Mme Loisel do next?
Answer:
When M. and Mme Loisel realized that the necklace was missing, they tried finding out where she could have possibly lost it. They concluded that it might have been dropped in the cab they were travelling in. But they did not remember its number. So, in an attempt to find the necklace, Loisel went over the track where they had walked.

When he found nothing, he went to the police and to the cab officers. He even put an advertisement in the newspapers, offering a reward. Meanwhile, he asked Matilda to write a letter to Mme Forestier, explaining that she had broken the clasp of the necklace and would get it repaired and return it soon. This gave them time to find the necklace. However, they eventually decided to replace the necklace with a new one.

Question 16.
How do they replace the Necklace?
Answer:
They decided to replace the necklace. They bought a new one for thirty-six thousand francs. Mr Loisel had eighteen thousand francs which his father left him. He borrowed the rest on a very high rate of interest.

Question 17.
What, was the cause of Matilda’s ruin? How could she have avoided it?
Answer:
The cause of Matilda’s ruin was her dissatisfaction with whatever life offered her. She was always unhappy. She felt that she was born for all the delicacies and luxuries of life. She disliked being in her current circumstances. She could have avoided this ruin by bringing content with whatever she had.

The Necklace Extra Questions and Answers Long Answer Type

Question 1.
A little confession would have changed the life of Matilda. Should we confess our mistakes courageously? Do you agree about above statement.
Answer:
Yes, a small mistake makes our life miserable and dark. People who are open-minded and speak the truth stay much happier. A little mistake made by Matilda changed her life completely. If Matilda had confessed that she had lost Madam Forestier’s necklace, her life would have been different. Confession could have brought peace of mind. Matilda would have at once come to know that necklace is not a real but it is an imitation. Hard work which Matilda put into repay the borrowed necklace could have been saved. We all get a very important message that we should not delay in admitting our mistake.

Question 2.
On inability to accept our circumstances may lead to an unhappy life. Explain with reference to the story “The Necklace”.
Answer:
We fail to recognise the situation in which we are placed but rather keep on grumbling. We become frustrated and want our life to be different. We should accept the life as it comes to us and should not keep on cribbing about unhappy circumstances. As we read the story The Necklace’ we find that Matilda is not at all happy with her husband. She had wished her life to be luxurious. It is this frustration of hers which puts her in a fix and spoils rest of her life. She does not work for solution but rather complicates the situation for her.

Question 3.
‘Love is blind’ is a phrase that was justified by Monsieur Loisel in the lesson ‘The Necklace’. Substantiate the answer from the story you have read in about 100 – 120 words.
Answer:
Monsieur Loisel’s acceptance and contentment differ considerably from Matilda’s emotional outbursts and constant dissatisfaction, and though he never fully understands his wife, he does his best to please her. When Monsieur Loisel tries to appease Matilda, he does it so blindly, wanting only to make her happy. When she declares that she cannot attend the party because she has nothing to wear, he gives her money to purchase a dress. When she complains that she has no proper jewellery, he urges her to visit Madame Forestier to borrow some.

Monsieur Loisel’s eagerness and willingness to please Matilda becomes his downfall when she loses the necklace. He is the one who devises a plan for purchasing a replacement necklace and orchestrates the loans and mortgages that help them pay for it. Although the decision costs him ten years of hard work, he does not complain or imagine an alternate fate. It is as if his desires do not even exist or, at the very least, his desires are meaningless if they stand in the way of Matilda’s.

Question 4.
‘The Necklace’ reveals that vanity is an evil. It may bring joy for short period but ultimately it leads to ruin. If you are placed in a situation similar to that of Matilda, what would you have done? Express your views.
Answer:
No doubt, Matilda was proud and self-loving. She was very beautiful and charming and she was proud of her beauty. Because of her beauty, she thought that she was born in a family of clerks through the error of destiny. She felt that she was born for all delicacies and luxuries. She also felt that she was made for expensive frocks, jewels and other such things.

Therefore, we can conclude that Matilda was very vain and proud because of her beauty. When we read the story, we find out that she suffered because of her vanity. If I were placed in a situation similar to that of Matilda, I would have valued the love of my husband. I would have not insisted on buying an expensive dress to wear to the party. There would be no question of borrowing an expensive necklace from my friend. I would have saved me and my husband from all hardships which the Loisels went through.

Question 5.
What changes came in the lifestyle of Matilda after she had lost the necklace?
Answer:
To return the borrowed money Mr and Mrs Loisel suffered for ten long years. First, they sent away the maid servant. Then they changed their lodging and rented some rooms. Now Matilda learnt heavy cares of household life, she had to do the difficult chores of her kitchen. She had to wash dishes, greasy pots and stew pans. She had to use her rosy nails to wash the greasy pots and the bottoms of the stew pans.

She had to wash dirty clothes and to hang them on the line to dry. Then each morning she had to take down the refuse to the street. She also had to bring up the water for daily use. She had to stop at each landing to catch her breath. She did not have much money so she haggled with the shopkeepers to get reduction in prices.

Once she was very beautiful and used to wear beautiful dresses. Now she seemed old. Now she looked like a common household woman. She had badly dressed hair and dirty dresses. Her hands were red and she spoke in a loud tone. She washed the floors with large pailg of water.

Question 6.
“At the end of the ten years, they had restored all”. What had Matilda and her husband restored and at what cost?
Answer:
Matilda lost the necklace borrowed from her wealthy friend Mme Forestier. They desperately tried to find out the necklace but in vain. Finally they decided to replace the necklace with a new one. M. Loisel spent his entire savings and even borrowed a loan to buy the? necklace.

To repay the debt, they cut down their expenses. They sent away the maid and reported some rooms in an attic. They cut down their expenses. M. Loisel worked evenings, putting the books of some merchants in order, and nights he often did copying at five sous a page. This life lasted for ten years. At the end of ten years, they had restored all.

Question 7.
Matilda would not have suffered much if she had confessed the loss of necklace. Do you think our mistakes become more serious if we try to cover them?
Answer:
Yes, a small mistake makes our life miserable and dark. People who are open-minded and speak the truth stay much happier. A little mistake made by Matilda changed her life completely. If Matilda had confessed that she had lost Madam Forestier’s necklace, her life would have been different.

Confession could have brought peace of mind. Matilda would have at once come to know that necklace is not a real but it is an imitation. Hard work which Matilda put into repay the borrowed necklace could have been saved. We all get a very important message that we should not delay in admitting our mistake.

Question 8.
Our inability to accept our limitations may lead to an unhappy life. Analyze with reference to the story ‘The Necklace’.
Answer:
We fail to recognise the situation in which we are placed but rather keep on grumbling. We become frustrated and want our life to be different. We should accept the life as it comes to us and should not keep on cribbing about unhappy circumstances. As we read the story The Necklace’ we find that Matilda is not at all happy with her husband. She had wished her life to be luxurious. It is this frustration of hers which puts her in a fix and spoils rest of her life. She does not work for solution but rather complicates the situation for her.

Question 9.
The course of the Loisels’ life changed due to the necklace. Comment.
Answer:
The course of the Loisel’s life changed due to the necklace. After replacing the lost necklace with a new one, they had to repay all the money that they had borrowed to buy the new necklace. They sent away the maid and changed their lodgings. They rented some rooms in an attic. Matilda learnt the odd work of the kitchen. She washed the dishes, soiled linen, their clothes and dishcloths.

She even took down the refuse to the street each morning and brought up the water, stopping at each landing to catch her breath. She went to the grocer’s, the butcher’s, and the fruitier’s, with a basket on her arm, shopping, haggling to save her money. Loisel worked in the evenings, putting the books of some merchants in order. At night, he did copy work at five sous a page. This lasted for ten years, and at the end of the said period, they were finally able to repay their lenders.

Question 10.
What would have happened to Matilda if she had confessed to her friend that she had lost her necklace?
Answer:
If Matilda would have confessed to her friend she had lost her necklace, she might have been in lesser trouble than what she had to face after having replaced the necklace. Her friend would have definitely been angry with her. Most likely, she would also have asked Matilda to replace it and given her the details from where she had bought the necklace and how much it had cost her. Matilda would have thus known that the jewels in the necklace were actually not real diamonds. It would have cost her a far lesser amount to replace it. Matilda would thus have saved herself and her husband of all the trouble they went through and life would have been much better and easier for them.

Question 11.
If you were caught in a situation like this, how would you have dealt with it?
Answer:
If I were caught in such a situation, I would have faced it boldly. I would have gone to Mrs Forestier and made a confession. Confessing one’s mistake needs courage and I would have generated that much courage to confess my mistake. It would have saved me from the sufferings that Matilda bore for such a long time. On my confessions, Forestier would have told me the reality of the necklace. Even if it were genuine diamond necklace, she being my friend and rich, would have forgiven me.

Question 12.
The characters in this story speak in English. Do you think this is their language? What clues are there in the story about the language its characters must be speaking in?
Answer:
The characters in this story speak in English. No, I think this is not their language. The names of the main characters are M and Mme Loisel, not Mr and Mrs Loisel. The currency used it Franc. It all suggests that their language is French.

Question 13.
Honesty is the best policy.
Answer:
It is true that honesty is the best policy. One should be honest in one’s work and deeds. Matilda tried to be honest by giving the necklace back to its owner. But her honesty would have proven to be the best policy, if she had admitted that she had lost the necklace. It would have saved her from ruining her life.

Question 14.
We should be content with what life gives us.
Answer:
Yes, we should be content with what life gives us. It is never ending desire which forces us to follow wrong path. Sometimes a person becomes dishonest to get more in life. The desire to have more makes a person unhappy. Matilda was a victim of such situation. Had she been content with what she had, she would not have ruined her life.

Electricity Class 10 Extra Questions with Answers Science Chapter 12

Electricity Class 10 Extra Questions with Answers Science Chapter 12

In this page, we are providing Online Education Electricity Class 10 Extra Questions and Answers Science Chapter 12 pdf download. NCERT Extra Questions for Class 10 Science Chapter 12 Electricity with Answers will help to score more marks in your CBSE Board Exams. https://ncertmcq.com/extra-questions-for-class-10-science/

Online Education for Class 10 Science Chapter 12 Extra Questions and Answers Electricity

Extra Questions for Class 10 Science Chapter 12 Electricity with Answers Solutions

Extra Questions for Class 10 Science Chapter 12 Very Short Answer Type

Electricity Class 10 Extra Questions Question 1.
Define the following terms:
(a) potential difference
(b) 1 volt
(c) electric current
(d) one ampere.
Answer:
Potential difference: The potential difference between two points in an electric circuit is the work done to move a unit charge from one point to the other. It is given by:
Electricity Class 10 Extra Questions

One volt/volt: The SI unit of potential difference is volt (V). One volt is the potential difference between two points in an electric circuit when one joule of work is done to move a charge of one coulomb from one point to the other.

Electric current: Electric current is the rate of flow of electric charges. It is denoted by I. It is given by:
Class 10 Electricity Extra Questions

One ampere/ampere: The SI unit of electric current is ampere (A). One ampere is the electric current when one coulomb of charge flows through a conductor in one second.

Class 10 Electricity Extra Questions Question 2.
What are resistors? Give some examples.
Answer:
Substances having comparatively high electrical resistance are called resistors. Some examples of resistors are alloys like nichrome, manganin, constantan, etc.

Extra Questions Of Electricity Class 10 Question 3.
Keeping the potential difference constant, the resistance of a circuit is doubled. By how much does the current change?
Answer:
V = IR
\(\frac{V}{I}\) = R
Since the resistance and the current are inversely proportional, the current will become half.

Electricity Class 10 Extra Questions Pdf Download Question 4.
How does the resistance of a wire change when:
(a) Its length is tripled?
(b) Its diameter is tripled?
(c) Its material is changed to one whose resistivity is three time?
Answer:
(a) The resistance is tripled.
(b) The resistance is reduced by 9 times.
(c) The resistance is tripled.

Electricity Class 10 Extra Questions Numerical Question 5.
If a wire is increased to 4 times its original length, by what factor does the resistivity change?
answer:
Since the resistivity depends only on the material of the wire, and not its length, it will remain the same.

Electricity Extra Questions Class 10 Question 6.
If the current passing through a conductor is doubled, what will be the change in the heat produced?
Answer:
Heat produced will increase by four times (H ∝ I2)

Extra Questions On Electricity Class 10 Question 7.
Name some devices which work on heating effect of electric current.
Answer:

  • Electric bulb
  • Electric iron
  • Electric geyser
  • Electric fuse

Class 10 Science Chapter 12 Extra Questions Question 8.
Why is an electric bulb filled with argon and nitrogen gas?
Answer:
An electric bulb is filled with argon and nitrogen gas because they do not react with the hot tungsten filament and hence, prolong the life of the filament of the electric bulb.

Electricity Class 10 Questions And Answers Question 9.
State the Joule’s law of heating.
Answer:
Joule’s law of heating states that the heat produced in a resistor is directly proportional to

  • Square of current (I2)
  • Resistance of the resistor (R) and
  • Time for which the current flows through the resistor.

H = I2Rt joules
From Ohm’s law, we get H = VIt joules = v2t/R joules

Class 10 Science Electricity Extra Questions Question 10.
How is heating effect of electric current used in an electric bulb?
Answer:
Electric bulb works on the principle of heating effect of electric current. When electric current passes through a very thin, high resistance tungsten filament of an electric bulb, the filament becomes white hot and emits light.

Class 10 Physics Electricity Extra Questions Question 11.
Explain why, the filaments of electric bulbs are made of tungsten.
Answer:
The filaments of electric bulbs are made of tungsten because it has a very high resistance. Due to its high resistance, heat produced is high and it becomes white-hot emitting light. Also due to its high melting point (3380° C), it can be kept white hot without melting.

Extra Questions For Electricity Class 10 Question 12.
How much work is done in moving a charge of magnitude 3 C across two points having a potential difference of 12 V?
Answer:
Given : Q = 3 C, V = 12 V
To find: W
V = \(\frac{W}{Q}\)
W = VQ = 12 × 3 = 36 J

Extra Questions Electricity Class 10 Question 13.
A current of 4 A flows through a 12V car headlight bulb for 10 minutes. How much energy transfer occurs during this time?
Answer:
Given : I = 4 A, V = 12 V, t = 10 min = 600 s
Energy transferred = VIt = 12 × 4 × 600 = 28800 J.

Chapter 12 Science Class 10 Extra Questions Question 14.
When a 12 V battery is connected across an unknown resistor, there is a current of 2.5 mA in the circuit. Find the value of the resistance of the resistor.
Answer:
Here, V = 12 V, I = 2.5 mA = 2.5 × 10-3 A
Resistance,
Extra Questions Of Electricity Class 10

Ch 12 Science Class 10 Extra Questions Question 15.
An electric current of 4.0 A flows through a 12 Ω resistor. What is the rate at which heat energy is produced in the resistor?
Answer:
Given: I = 4 A, R = 12 Ω
Rate of production of heat energy, P = I2R = 42 × 12 = 192 W.

Question 16.
A heating element is marked 210 V, 630 W. What is the current drawn by the element when connected to a 210 V D.C. mains? What is the resistance of the element?
Answer:
Given, P = 630 W, V = 210V
Current drawn, I = \(\frac{P}{V}=\frac{630}{210}\) = 3A

Question 17.
Calculate the energy transferred by a 5 A current flowing through a resistor of 2 Ω for 30 minutes.
Answer:
Here, I = 5 A, R = 2 Ω, t = 30 min = 1800 s
Energy transferred = I2Rt = (5)2 × 2 × 1800 = 9 × 104 J.

Question 18.
What does the slope of V – I graph at any point represent?
Answer:
Resistance.

Question 19.
What is the shape of the graph obtained by plotting potential difference applied across a conductor against the current flowing through it?
Answer:
Straight line.

Question 20.
Give reason why metals are good conductors, whereas non-metals are bad conductors of electricity.
Answer:

  • Metals contain free electrons which help in the conduction of electric charge and hence current
  • Resistivity of metals is higher

Question 21.
The electrical resistivity of silver is 1.60 × 10-6 Ω m. What will be the resistance of a silver wire of length 10 m and cross-sectional area 2 × 10-3 m2?
Answer:
Given: p = 1.60 × 10-6 Ω m, l = 10 m and A = 2 x 10-3 m2
Resistance,
Electricity Class 10 Extra Questions Pdf Download

Question 22.
Why are copper and aluminium wires usually employed for electricity transmission?
Answer:
Copper and aluminium have low resistivities. When electricity is transmitted through copper and aluminium wires, the power losses in the form of heat are very small.

Extra Questions for Class 10 Science Chapter 12 Short Answer Type I

Question 1.
Sketch a circuit diagram of an electric circuit consisting of a cell, an electric bulb, an ammeter, a voltmeter and a plug key.
Answer:
Electricity Class 10 Extra Questions Numerical

Question 2.
Differentiate between Resistance and Resistivity.
Answer:
Resistance:

  1. It is the opposition provided by the atoms of a conductor to the flow of electrons.
  2. SI unit of resistance is Ω (Ohm).
  3. Resistance depends on length, area of cross section, material and temperature of conductor.

Resistivity:

  1. It is the resistance of the conductor of that substance of unit length and unit area of cross section.
  2. SI unit of Resistivity of Ωm (Ohm-meter).
  3. Resistivity of substance depends only on the material of substance.

Question 3.
Distinguish between resistances in series and resistances in parallel.
Answer:
Resistances in series:

  1. If a number of resistances are connected in such a way that the same current flows through each resistance, then the arrangement is called resistances in series.
  2. The current across each resistance is same.
  3. The equivalent resistance in series combination is greater than the individual resistances.
  4. This combination decreases the current.in the circuit.

Resistances in parallel:

  1. If a number of resistances are connected between two common points in such a way that the potential differences across each of them is the same, then the arrangement is called resistances in parallel.
  2. The voltage across each resistance is same.
  3. The equivalent resistance in parallel combination is smaller than each of the individual resistances.
  4. This combination increases the current in the circuit.

Question 4.
Nichrome wire is used for making the Ideating elements of electrical appliances like iron, geyser, etc. Give reasons.
Answer:
Nichrome wire is used for making the heating elements of electrical appliances like iron, geyser, etc. because:

  • Nichrome has a very high resistance due to which it produces a lot of heat on passing current.
  • It does not undergo oxidation easily even at high temperature due to which it can be kept red hot.

Question 5.
A copper wire of resistivity 2.6 × 10-3 Ωm, has a cross sectional area of 30 × 10-4 cm3. Calculate the length of this wire required to make a 10 Ω coil.
Answer:
Given: R = 10Ω, ρ = 2.6 × 10-8 Ωm,
To find: l = ?
Formula: R = ρ\(\frac{l}{A}\)
Solution: R = ρ\(\frac{l}{A}\)
∴ ρl = RA
Electricity Extra Questions Class 10

Question 6.
Two coils of resistance R1 = 3Ω and R2 = 9Ω are connected in series across a battery of potential difference 14 V. Draw the circuit diagram. Find the electrical energy consumed in 1 min in each resistance.
Answer:
Given: R1 = 3Ω, R2 = 9Ω
Rs = R1 + R2 = 9 + 3 = 12 Ω
Extra Questions On Electricity Class 10
Now, I = \(\frac{V}{R}=\frac{14}{12}\) = 1.167 Amp. [I in series remains constant.]
Electric energy consumed in R1
H1 = I2R1t = (1.167)2 × 3 × 60 = 245.14 J
Electric energy consumed in R2
H2 = I2R2t = 735.42J

Question 7.
State the relation between work, charge and potential difference for an electric circuit.
Calculate the potential difference between the two terminals of a battery if 100 joules of work is required to transfer 20 coulombs of charge from one terminal of the battery to the other.
Answer:
V = \(\frac{W}{Q}\)
Here,
V = Potential difference,
W = Work done,
Q = Electric charge
W = 100 J
Q = 20 C
V = \(\frac{W}{Q}=\frac{100}{20}\) = 5V

Question 8.
What is an electric circuit? Distinguish between an open and a closed circuit.
Answer:
Electric circuit: A continuous and closed path of electric current is called an electric circuit.
Open circuit: A discontinuous circuit through which no current can flow.
Closed circuit: A circuit without interruption, providing a continuous path through which a current can flow.

Extra Questions for Class 10 Science Chapter 12 Short Answer Type II

Question 1.
With the help of a diagram, derive the formula for the equivalent resistance of three resistances connected in series.
Answer:
(i) If a number of resistances are connected in such a way that the same current flows through each resistance, then the arrangement is called ‘Resistances in Series’.
Class 10 Science Chapter 12 Extra Questions
(ii) Let R1, R2 and R3 be three resistances connected in a series combination and let R be their equivalent resistance.
Let V1, V2 and V3 be the potential difference across the resistances R1, R2 and R3 respectively. Let ‘V’ be the potential differences across the combination. Let ‘I’ be the current flowing through each resistance.

(iii) According to Ohm’s law,
V = IR
Hence, V1 = IR1; V2 = IR2; V3 = IR3
(iv) For series combination of resistances,
V = V1 + V2 + V3
IRs = IR1 + IR2 + IR3
IRs = I (R1 + R2 + R3)
Rs = R1 + R2 + R3
Hence, the equivalent resistance in series (Rs) is equal to the sum of the individual resistances.

Question 2.
With the help of a diagram, derive the formula for the equivalent resistance of three resistances connected in parallel.
1. If a number of resistances are connected between two common points in such a way that the potential difference across each resistance is same, then the arrangement is called ‘Resistances in Parallel’.

2. Let R1, R2 and R3 be the three resistances connected in parallel combination between points C and D and let Rp be their equivalent resistance.
Let I1, I2 and I3 be the currents flowing through resistances R1, R2 and R3 respectively.
Let I be the current flowing through the circuit and V be the potential difference of the cell.

3. According to Ohm’s law.
I = \(\frac{V}{R}\)
Therefore,
Electricity Class 10 Questions And Answers
Therefore, the reciprocal of the equivalent resistances in parallel combination is equal to the sum of the reciprocals of the individual resistances.

Question 3.
What is the better way of connecting lights and other electrical appliances in domestic wiring? Why?
Answer:
The better way of connecting lights and other electrical appliances in domestic wiring is parallel connection because of the following advantages:

  • In parallel circuit, if one appliance stops working due to some defect, then all other appliances keep working normally.
  • In parallel circuit, each electrical appliance has its own switch due to which it can be turned on or off, without affecting other appliances.
  • In parallel circuit, each electrical appliance gets the same voltage (220 V) as that of the power supply line.
  • In parallel circuit, the overall resistance of the domestic circuit is reduced due to which the current from the power supply is high.

Question 4.
An electric lamp, whose resistance is 20 Ω, and a conductor of 4 Ω resistance are connected to aft V battery (Fig.).
Calculate (a) the total resistance of the circuit, (b) the current through the circuit, and (c) the potential difference across the electric conductor.
Class 10 Science Electricity Extra Questions
Answer:
(a) Resistance of electric lamp, R1 = 20 W
Resistance of series conductor, R2 = 4 W
Total resistance in the circuit,
Rs = R1 + R2 = 20 Ω + 4 Ω = 24 Ω.

(b) Total potential difference, V = 6 V
By Ohm’s law, the current through the circuit is
Class 10 Physics Electricity Extra Questions

(c) Potential difference across the electric lamp,
V1 = IR1 = 0.25 A × 20 Ω = 5 V.
Potential difference across the conductor is
V2 = IR2 = 0.25 A × 4 Ω = 1 V.

Question 5.
A wire has a resistance of 10Ω. It is melted and drawn into a wire of half of its length. Calculate the resistance of the new wire. What is the percentage change in its resistance?
Answer:
Given: R1 = 10 Ω, l2 = \(\frac{l_{1}}{2}\)
To find: (a) R2
(b) Percentage change in the resistance (ΔR%).
If volume of the wire remains same in both the cases.
Extra Questions For Electricity Class 10
Dividing eq. (iii) by (ii), we get
Extra Questions Electricity Class 10

Question 6.
If, in Figure R1 = 10 ohms, R2 = 40 ohms, R3, = 30 ohms, R4 = 20 ohms, Rg = 60 ohms and a 12 volt battery is connected to the arrangement, calculate: (a) the total resistance and (b) the total current flowing in the circuit.
Chapter 12 Science Class 10 Extra Questions
Answer:
(a) Let R’ be the equivalent resistance of R1 and R2. Then,
Ch 12 Science Class 10 Extra Questions
R’ = 8Ω
Let R” be the equivalent resistance of R3, R4 and R5. Then,
Electricity Chapter Class 10 Extra Questions
R” = 10 Ω
Total Resistance, R = R’ + R” = 8 + 10 = 18 Ω

(b) Current,
Extra Question Of Electricity Class 10

Question 7.
Two lamps, one rated 60 W at 220 V and other 40 W a 220 V, are connected in parallel to an electric supply at 220 V. [CBSE 2016]
(a) Draw the circuit diagram to show the connections.
(b) Calculate the current drawn from the electric supply.
(c) Calculate the total energy consumed by the two lamp together when they operate for one hour.
Answer:
(a) The required circuit diagram is shown below:
Electricity Class 10 Extra Questions with Answers Science Chapter 12, 18

(b) Total power of the two lamps = 60 + 40 = 100 W
Applied Voltage, V = 220 V
Current drawn from the electric supply,
Electricity Class 10 Extra Questions with Answers Science Chapter 12, 19
(c) Total energy consumed by the lamp in one hour = 60W × 1h + 40W × 1h = 100 Wh = 0.1 kWh.

Question 8.
A household uses the following electric appliances:
(i) Refrigerator of rating 400 W for ten hours each day.
(ii) Two electric fans of rating 80 W each for twelve hours each day.
(iii) Six electric tubes of rating 18 W each for 6 hours each day.
Calculate the electricity bill of the household for the month of June if the cost per unit of electric energy is ₹ 3.00.
Answer:
Energy consumed by refrigerator of rating 400 W for ten hours each day
= P × t = 400 W × 10 Aw = \(\frac{400}{1000}\) kW × 10 h = 4.0 kWh
Energy consumed by two electric fans of rating 80 W each for twelve hours each day
= 2 × P × t = 2 × 80W × 12h = \(\frac{160}{1000}\) kW × 12 h = 1.92 kWh
Energy consumed by six electric tubes of rating 18 W each for 6 hours each day
= 6 × P × t = 6 × 18W × 6h = \(\frac{108}{1000}\) W × 6 h = 0.648 kWh
Total energy consumed in the month of June (30 days)
= (4.0 + 1.92 + 0.648) × 30 kWh = 6.568 × 30 = 197.04 kWh
Electricity bill for the month of June
= ₹ 197.04 × 3 = ₹ 591.12 = ₹ 591 (approx.)

Extra Questions for Class 10 Science Chapter 12 Long Answer Type

Question 1.
(a) Two resistors R1 and R2 may form (i) a series combination or (ii) a parallel combination, and the combination may be connected to a battery of six volts. In which combination will the potential difference across R1 and across R2 be the same and in which combination will the current through R1 and through R2 be the same?
(b) For the circuit, shown in this diagram,
Electricity Class 10 Extra Questions with Answers Science Chapter 12, 20
Calculate
(i) the resultant resistance
(ii) the total current
(iii) the voltage across 7 Ω resistor
Answer:
(a)
Electricity Class 10 Extra Questions with Answers Science Chapter 12, 21
Electricity Class 10 Extra Questions with Answers Science Chapter 12, 22
In series combination, the current through R1 and R2 is same.
In parallel combination, the potential difference across R1 and R2 is same.

(b) (i) Here 5Ω and 10Ω resistors are connected in parallel.
Electricity Class 10 Extra Questions with Answers Science Chapter 12, 23
Now circuit becomes
Electricity Class 10 Extra Questions with Answers Science Chapter 12, 24
Equivalent resistance,
Req = \(\frac{10}{3}\)Ω + 7Ω = \(\frac{31}{3}\)Ω = 10.33Ω
(ii)
Electricity Class 10 Extra Questions with Answers Science Chapter 12, 25
(iii) Voltage across 7Ω resistor
V = IR ⇒ V = \(\frac{18}{31}\) × 7 = 4.06A

Question 2.
(a) List the factors on which the resistance of a conductor depends.
(b) A 4 kW heater is connected to a 220 V source of power. Calculate
(i) the electric current passing through the heater.
(ii) the resistance of the heater.
(iii) the electric energy consumed in 2 hour use of the heater.
Answer:
(a) Resistance of a conductor depends on
(i) length of conductor (l)
(ii) Area of cross-section (A)
(iii) Resistivity of material (ρ)
Relation of resistance is given by, R = ρ\(\frac{l}{A}\)

(b) Given, P = 4 kW = 4000 W and V = 220 V
(i) P = VI or I = \(\frac{P}{A}\)
Hence, I = \(\frac{4000}{220}\) = 18.18 A

(ii) V = IR or R = \(\frac{V}{I}\)
R = \(\frac{220}{18.18}\) = 12.1Ω

(iii) Energy consumed, E = P × t
E = 4000 W × 2h = 8000Wh = 8 kWh = 8 unit.

Question 3.
(a) State Ohm’s law.
(b) Give the circuit diagram to establish relation between potential difference (V) and current (I) through a given wire.
(c) Draw a graph between V and I.
Answer:
(a) Ohm’s law:
According to Ohm’s law, the potential difference, v, across the ends of a given metallic wire in an electric circuit is directly proportional to the current flowing through it, provided its temperature remains same.
V ∝ I ⇒ \(\frac{V}{I}\) = constant
\(\frac{V}{I}\) = R (R = constant) ⇒ V = IR
Here, R is constant for a given metallic wire at a given temperature and is called resistance.
V-I graph of Ohm’s law and its experimental setup:

(b) Circuit diagram
Electricity Class 10 Extra Questions with Answers Science Chapter 12, 26

(c) Variation of current with potential difference
Electricity Class 10 Extra Questions with Answers Science Chapter 12, 27

Electricity HOTS Questions With Answers

Question 1.
Two students perform experiments on series and parallel combinations of two given resistors R1 and R2 and plot the following V-I graphs.
Electricity Class 10 Extra Questions with Answers Science Chapter 12, 28
Which of the graphs is (are) correctly labeled in terms of the words ‘Series and parallel’? justify your answer.
Answer:
In case of series combination, the effective resistance = R1 + R2 is more, hence slope of V – I graph will be more. It is otherwise in case of I – V graph. So, series and parallel are correctly marked in graph (ii).

Question 2.
You are given three resistors of 10 Ω, 10 Ω, 20 Ω to a battery of emf 2.5 V, a key, an ammeter and a voltmeter. Draw a circuit diagram showing the correct connections of given components such that the voltmeter gives a reading of 2.0 V.
Answer:
Electricity Class 10 Extra Questions with Answers Science Chapter 12, 29

Question 3.
The electrical resistivity of few material is given below in ohm-metre. Which of these materials can be used for making elements of a heating device.
A 6.84 × 10-8 Ωm
B 1.60 × 10-8 Ωm
C 1.00 × 10-4 Ωm
D 2.50 × 1012 Ωm
E 4.40 × 10-5 Ωm
F 2.30 × 1017 Ωm
Answer:
A material having highest value of resistivity is used for making element of heating devices; therefore, material C will be used. D and F are insulators since they have very high values of resistivity.

Question 4.
Two electric bulbs A and B are marked 220 V, 60 W and 220 V, 100 W respectively. Which one of the two has greater resistance?
Answer:
The resistance of a bulb is given by the expression R = V2/P. For the voltage, the bulb having a smaller power has more resistance. Therefore, the 60W, 220 V bulb has a greater resistance.

Question 5.
A potential difference V is applied across a conductor of length l and diameter D. How is the resistance R of the conductor affected, when (i) V is halved (ii) l is halved and (iii) D is doubled. Justify your answer in each case.
Answer:
The table below gives the variation:
Electricity Class 10 Extra Questions with Answers Science Chapter 12, 30

Question 6.
The applied potential difference across a given resistor is altered so that the heat produced per second increases by a factor of 16. By what factor the applied potential difference change.
Answer:
The heat produced across a resistor is given by R = V2/P. It is proportional to the square of potential.
Therefore, if the heat becomes 16 times the voltage must have been increased 4 times.

Question 7.
The I – V graphs of two resistors, and their series combination, are shown below. Which one of these graphs represents the series combination of the other two? Give reasons for your answer.
Electricity Class 10 Extra Questions with Answers Science Chapter 12, 31
Answer:
Draw a vertical line from any point on the V axis such as to cut the graphs 1, 2 and 3 at points P, Q and R as shown in the graph below.
Electricity Class 10 Extra Questions with Answers Science Chapter 12, 32

For the same potential, the current in each is different (I1 < I2 < I3). Hence \(\frac{V}{I_{1}}\) will be greatest for graph 1.
Therefore, graph 1 represents the series combination of the other two resistances.

Question 8.
The values of current I flowing in a given resistor for the corresponding values of potential difference V across the resistor are given below:

I (amperes) 0.5 1.0 2.0 3.0 4.0
V (volts) 1.6 3.4 6.7 10.2 13.2

Plot a graph between V and I and calculate the resistance of the resistor.
Answer:
The graph between V and I for the given data is shown below:
Electricity Class 10 Extra Questions with Answers Science Chapter 12, 33
Resistance of the resistor,
Electricity Class 10 Extra Questions with Answers Science Chapter 12, 34

Question 9.
A piece of wire having resistance ‘R’ is cut into four equal parts.
(a) How does the resistance of each part compare with the original resistance?
(b) If the four parts are placed in parallel, how will be the resistance of the combination compare with the resistance of the original wire?
Answer:
(a) As R ∝ l, when the wire is cut into four equal pieces, the resistance of each part is \(\frac{R}{4}\)
(b) When they are connected in parallel.
Electricity Class 10 Extra Questions with Answers Science Chapter 12, 35
Electricity Class 10 Extra Questions with Answers Science Chapter 12, 36

Question 10.
Two resistance when connected in parallel give resultant value of 2 Ω. When connected in series, the value becomes 9 Ω. Calculate the value of each resistance.
Answer:
Let R1 and R2 be the two resistances,
R1 + R2 = 9Ω  …….(1)
When connected in parallel
Electricity Class 10 Extra Questions with Answers Science Chapter 12, 37
Now (a – b)2 = (a + b)2 – 4ab
(R1 – R2)2 = (R1 + R2)2 – 4 R1R2 = 9 × 9 – 4 × 18
(R1 – R2)2 = 81 – 72 = 9 or R1 – R2 = 3
∴ R1 – R2 = 3  ………(2)
Solving eq. (i) and (ii), we gets
R1 + R2 = 9 or R1 – R2 = 3
2R1 = 12
∴ R1 = 6Ω
Putting the value of R1 in eq. (i), we get
R1 + R2 = 9 or R2 = 9 – R1 = 9 – 6
R2 = 3Ω

Question 11.
If length of a resistance wire become half and cross-section area becomes twice, then find the relation between old resistance and new resistance.
Answer:
Electricity Class 10 Extra Questions with Answers Science Chapter 12, 38
Dividing (ii) by (i), we get R’ = \(\frac{R}{4}\)
Resistance becomes one fourth.

Extra Questions for Class 10 Science Chapter 12 Value Based Questions

Question 1.
Raman always switched off lights, fans and electric gadgets when not in use. Her electricity bill had cut down to half.
(a) What is commercial unit of electric energy?
(b) Suggest any two methods of saving electricity,
(c) What values does Raman show?
Answer:
(a) The commercial unit of electric energy is kWh.
(b) Using LED’s and efficient devices.
(c) Self-discipline and responsible behavior.

Question 2.
Raghav wants to connect electrical devices in series with the battery. But his friend advised him to connect these devices in parallel.
(a) What are the advantages of connecting electrical devices in parallel instead of connecting them in series?
(b) Which value is shown by Shivam’s friend?
Answer:
(a) (i) Potential difference across each device remain same whereas in series connections, it gets distributed.
(ii) If one device is switched off, it does not affect the other device.

(b) Intelligent and helping.

Statistics Class 9 Extra Questions Maths Chapter 14 with Solutions Answers

Statistics Class 10 Extra Questions Maths Chapter 14 with Solutions Answers

Here we are providing Online Education Statistics Class 10 Extra Questions Maths Chapter 14 with Answers Solutions, Extra Questions for Class 10 Maths was designed by subject expert teachers. https://ncertmcq.com/extra-questions-for-class-10-maths/

Online Education Extra Questions for Class 10 Maths Statistics with Answers Solutions

Extra Questions for Class 10 Maths Chapter 14 Statistics with Solutions Answers

Statistics Class 10 Extra Questions Very Short Answer Type

Statistics Class 10 Extra Questions Question 1.
Find the class mark of the class 10 – 25.
Solution:
Statistics Class 10 Extra Questions

Class 10 Statistics Extra Questions Question 2.
Find the mean of the first five natural numbers.
Solution:
Class 10 Statistics Extra Questions

Statistics Extra Questions Class 10 Question 3.
A data has 13 observations arranged in descending order. Which observation represents the median of data?
Solution:
Total no. of observations = 13, which is odd
Statistics Extra Questions Class 10
i.e., 7th term will be the median.

Extra Questions Of Statistics Class 10 Question 4.
If the mode of a distribution is 8 and its mean is also 8, then find median.
Solution:
Mode = 8; Mean = 8; Median = ?
Relation among mean, median and mode is
3 median = mode + 2 mean
3 × median = 8 + 2 × 8
Median = \(\frac{8+16}{3}\) = \(\frac{24}{3}\) = 8

Statistics Class 10 Extra Questions With Answers Pdf Question 5.
In an arranged señes of an even number of 2n terms which term is median?
Solution:
No. of terms = 2n which are even
Extra Questions Of Statistics Class 10
i.e., the mean of nth and (n + 1)th term will be the median.

Extra Questions On Statistics Class 10 Question 6.
What does the abscissa of the point of intersection of the less than type and of the more than type cumulative frequency curves of a grouped data represent?
Solution:
The abscissa of the point of intersection of the less than type and of the more than type cumulative frequency curves of a grouped data gives its median.

Class 10 Maths Chapter 14 Extra Questions With Solutions Question 7.
Name the graphical representation from which the mode of a frequency distribution is obtained.
Solution:
The mode of frequency distribution is determined graphically from Histogram.

Class 10 Maths Statistics Extra Questions Question 8.
A student draws a cumulative frequency curve for the marks obtained by 60 students of a class as shown below. Find the median marks obtained by the students of the class.
Statistics Class 10 Extra Questions With Answers Pdf
Solution:
Here n = 60
\(\frac{n}{2}\) = 30
Corresponding to 30 on y-axis, the marks on x-axis is 40.
∴ Median marks = 40.

Statistics Class 10 Extra Questions With Answers Question 9.
Write the modal class for the following frequency distribution:
Extra Questions On Statistics Class 10
Solution:
Maximum frequency, i.e., 65 corresponds to the class 30 – 40
∴ Modal class is 30 – 40.

Statistics Class 10 Extra Questions Short Answer Type 1

Extra Questions Of Chapter 14 Class 10 Maths Question 1.
If xi‘s are the mid-points of the class intervals of a grouped data. fi‘s are the corresponding frequencies and is the mean, then find Σfi (xi – \(\bar{x}\)).
Solution:
Class 10 Maths Chapter 14 Extra Questions With Solutions

Class 10 Statistics Important Questions Question 2.
Consider the following frequency distribution.
Class 10 Maths Statistics Extra Questions
Solution:
Classes are not continuous, hence make them continuous by adding 0.5 to the upper limits and subtracting 0.5 from the lower limits.
Statistics Class 10 Extra Questions With Answers
Class interval can’t be negative hence the first CI is starting from 0.
Now to find median class we calculate \(\frac{\Sigma f}{2}\) = \(\frac{57}{2}\) = 28.5
∴ Median class = 11.5 – 17.5.
So, the upper limit is 17.5

Class 10 Maths Ch 14 Extra Questions Question 3.
Find the median class of the following distribution:
Extra Questions Of Chapter 14 Class 10 Maths
Solution:
First we find the cumulative frequency
Class 10 Statistics Important Questions
Class 10 Maths Ch 14 Extra Questions
Here, \(\frac{n}{2}\) = \(\frac{50}{2}\)
∴ Median class = 30 – 40.

Ch 14 Maths Class 10 Extra Questions Question 4.
Find the class marks of classes 15.5 – 18.5 and 50 – 75.
Solution:
Ch 14 Maths Class 10 Extra Questions

Statistics Class 10 Extra Questions Short Answer Type 2

Extra Sums Of Statistics Class 10 Question 1.
If the mean of the following distribution is 6, find the value of p.
Extra Sums Of Statistics Class 10
Solution:
Calculation of mean
Chapter 14 Maths Class 10 Extra Questions

Chapter 14 Maths Class 10 Extra Questions Question 2.
Find the mean of the following distribution:
Questions On Statistics Class 10
Solution:
Calculation of arithmetic mean
Extra Questions For Class 10 Maths Statistics

Questions On Statistics Class 10 Question 3.
The following data gives the information on the observed lifetimes (in hours) of 225 electrical components:

Class 10th Statistics Extra Questions
Determine the modal lifetimes of the components.
Solution:
Here, the maximum class frequency is 61 and the class corresponding to this frequency is 60 – 80.
So, the modal class is 60 – 80.
Statistics Class 10 Extra Questions Maths Chapter 14 with Solutions Answers 19
Hence, modal lifetime of the components is 65.625 hours.

Extra Questions For Class 10 Maths Statistics Question 4.
The distribution below gives the weights of 30 students of a class. Find the median weight of the students.
Statistics Class 10 Extra Questions Maths Chapter 14 with Solutions Answers 20
Solution:
Calculation of median
Statistics Class 10 Extra Questions Maths Chapter 14 with Solutions Answers 21
The cumulative frequency just greater than \(\frac{n}{2}\) = 15 is 19, and the corresponding class is 55 – 60.
∴ 55 – 60 is the median class.
Statistics Class 10 Extra Questions Maths Chapter 14 with Solutions Answers 22
Hence, median weight is 56.67 kg.

Class 10th Statistics Extra Questions Question 5.
The lengths of 40 leaves of a plant are measured correctly to the nearest millimetre, and the data obtained is represented in the following table:
Statistics Class 10 Extra Questions Maths Chapter 14 with Solutions Answers 23
Find the median length of the leaves.
Solution:
Here, the classes are not in inclusive form. So, we first convert them in inclusive form by subtracting \(\frac{h}{2}\) from the lower limit and adding \(\frac{h}{2}\) to the upper limit of each class, where h is the difference between the lower limit of a class and the upper limit of preceding class.
Now, we have
Statistics Class 10 Extra Questions Maths Chapter 14 with Solutions Answers 24
We have, n = 40
⇒ \(\frac{n}{2}\) = 20 .
And, the cumulative frequency just greater than \(\frac{n}{2}\) is 29 and corresponding class is 144.5 – 153.5.
So median class is 144.5 – 153.5.
Statistics Class 10 Extra Questions Maths Chapter 14 with Solutions Answers 25
Hence, the median length of the leaves is 146.75 mm.

Statistics Class 10 Extra Questions Long Answer Type

Question 1.
The following table gives the literacy rate (in percentage) of 35 cities. Find the mean literacy rate.
Statistics Class 10 Extra Questions Maths Chapter 14 with Solutions Answers 26
Solution:
Here, we use step deviation method to find mean.
Let assumed mean A = 70 and class size h = 10
So, ui = \(\frac{x_{i}-70}{10}\)
Now, we have
Statistics Class 10 Extra Questions Maths Chapter 14 with Solutions Answers 27

Question 2.
The following distribution shows the daily pocket allowance of children of a locality. The mean pocket allowance is ₹ 18. Find the missing frequency f.
Statistics Class 10 Extra Questions Maths Chapter 14 with Solutions Answers 28
Solution:
Let the assumed mean A = 16 and class size h = 2, here we apply step deviation method.
Statistics Class 10 Extra Questions Maths Chapter 14 with Solutions Answers 1.3
Now, we have,
Statistics Class 10 Extra Questions Maths Chapter 14 with Solutions Answers 29
Statistics Class 10 Extra Questions Maths Chapter 14 with Solutions Answers 30
Hence, the missing frequency is 20.

Question 3.
The mean of the following frequency distribution is 62.8. Find the missing frequency x.
Statistics Class 10 Extra Questions Maths Chapter 14 with Solutions Answers 31
Solution:
We have
Statistics Class 10 Extra Questions Maths Chapter 14 with Solutions Answers 32
⇒ 2512 + 62.8x = 2640 + 50x
⇒ 62.8x – 50x = 2640 – 2512
⇒ 12.8x = 128
∴ x = \(\frac{128}{12.8}\) = 10
Hence, the missing frequency is 10.

Question 4.
The distribution below gives the marks of 100 students of a class.
Statistics Class 10 Extra Questions Maths Chapter 14 with Solutions Answers 33
Draw a less than type and a more than type ogive from the given data. Hence, obtain the median marks from the graph.
Solution:
Statistics Class 10 Extra Questions Maths Chapter 14 with Solutions Answers 34
Statistics Class 10 Extra Questions Maths Chapter 14 with Solutions Answers 35
Hence, median marks = 24

Question 5.
During the medical check-up of 35 students of a class, their weights were recorded as follows:
Statistics Class 10 Extra Questions Maths Chapter 14 with Solutions Answers 36
Draw a less than type ogive for the given data. Hence, obtain the median weight from the graph and verify the result by using the formula.
Solution:
To represent the data in the table graphically, we mark the upper limits of the class interval on x-axis and their corresponding cumulative frequency on y-axis choosing a convenient scale. Now, let us plot the points corresponding to the ordered pair given by (38,0), (40,3), (42,5), (44, 9), (46, 14), (48, 28), (50, 32) and (52, 35) on a graph paper and join them by a freehand smooth curve.
Thus, the curve obtained is the less than type ogive.
Statistics Class 10 Extra Questions Maths Chapter 14 with Solutions Answers 37
Now, locate \(\frac{n}{2}\) = \(\frac{35}{2}\) = 17.5 on the y-axis,
We draw a line from this point parallel to x-axis cutting the curve at a point. From this point, draw a perpendicular line to the x-axis. The point of intersection of this perpendicular with the x-axis gives the median of the data. Here it is 46.5.
Let us make the following table in order to find median by using formula.
Statistics Class 10 Extra Questions Maths Chapter 14 with Solutions Answers 38
Here, n = 35, \(\frac{n}{2}\) = \(\frac{35}{2}\) = 17.5, cumulative frequency greater than \(\frac{n}{2}\) = 17.5 is 28 and corresponding class is 46 – 48. So median class is 46 – 48.
Now, we have l = 46, \(\frac{n}{2}\) = 17.5, cf = 14, f = 14, h = 2
Statistics Class 10 Extra Questions Maths Chapter 14 with Solutions Answers 39
Hence, median is verified.

Question 6.
A survey was conducted by a group of students as a part of their environment awareness programme, in which they collected the following data regarding the number of plants in 20 housesin a locality. Find the mean number of plants per house.
Statistics Class 10 Extra Questions Maths Chapter 14 with Solutions Answers 40
Which method did you use for finding the mean and why?
Solution:
Calculation of mean number of plants per house.
Statistics Class 10 Extra Questions Maths Chapter 14 with Solutions Answers 41
Here, we used direct method to find mean because numerical values of x; and fi are small.

Question 7.
A life insurance agent found the following data for distribution of ages of 100 policy holders. Calculate the median age, if policies are given only to persons having age 18 years onwards but less than 60 years.
Statistics Class 10 Extra Questions Maths Chapter 14 with Solutions Answers 42
Solution:
We are given the cumulative frequency distribution. So, we first construct a frequency table from the given cumulative frequency distribution and then we will make necessary computations to compute median.
Statistics Class 10 Extra Questions Maths Chapter 14 with Solutions Answers 43
Here, n = 100
⇒ \(\frac{n}{2}\) = 50

And, cumulative frequency just greater than \(\frac{n}{2}\) 50 is 78 and the corresponding class is 35 – 40.
So 35 – 40 is the median class.
Statistics Class 10 Extra Questions Maths Chapter 14 with Solutions Answers 44
Hence, the median age is 35.76 years.

Question 8.
The following distribution gives the daily income of 50 workers of a factory.
Statistics Class 10 Extra Questions Maths Chapter 14 with Solutions Answers 45
Convert the distribution above to a less than type cumulative frequency distribution, and draw its ogive.
Solution:
Converting given distribution to a less than type cumulative frequency distribution, we have,
Statistics Class 10 Extra Questions Maths Chapter 14 with Solutions Answers 46
Now, let us plot the points corresponding to the ordered pairs (120, 12), (140, 26), (160, 34), (180, 40), (200, 50) on a graph paper and join them by a freehand smooth curve.
Statistics Class 10 Extra Questions Maths Chapter 14 with Solutions Answers 47
Thus, obtained curve is called the less than type ogive.

Question 9.
Find the mean of the following frequency distribution:
Statistics Class 10 Extra Questions Maths Chapter 14 with Solutions Answers 48
Solution:
Calculation of mean
Statistics Class 10 Extra Questions Maths Chapter 14 with Solutions Answers 49

Statistics Class 10 Extra Questions HOTS

Question 1.
The mean of the following frequency table is 50. But the frequencies f1 and f2 in class 20 – 40 and 60 – 80 respectively are missing. Find the missing frequencies.
Statistics Class 10 Extra Questions Maths Chapter 14 with Solutions Answers 50
Solution:
Let the assumed mean A = 50 and h = 20.
Calculation of mean
Statistics Class 10 Extra Questions Maths Chapter 14 with Solutions Answers 51
Putting the value of f1 in equation (i), we get
28 + f2 = 52
⇒ f2 = 24
Hence, the missing frequencies f1 is 28 and f2 is 24.

Question 2.
If the median of the distribution given below is 28.5, find the values of x and y.
Statistics Class 10 Extra Questions Maths Chapter 14 with Solutions Answers 52
Solution:
Here, median = 28.5 and n = 60
Now, we have
Statistics Class 10 Extra Questions Maths Chapter 14 with Solutions Answers 53

Online Education for RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6

Online Education for RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6

These Solutions are part of Online Education RD Sharma Class 10 Solutions. Here we have given RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6. You must go through NCERT Solutions for Class 10 Maths to get better score in CBSE Board exams along with RS Aggarwal Class 10 Solutions.

Other Exercises

Question 1.
Determine the nature of the roots of following quadratic equations :
(i) 2x² – 3x + 5 = 0 [NCERT]
(ii) 2x² – 6x + 3 = 0 [NCERT]
(iii) \(\frac { 3 }{ 5 }\) x² – \(\frac { 2 }{ 3 }\) x + 1 = 0
(iv) 3x² – 4√3 x + 4 = 0 [NCERT]
(v) 3x² – 2√6 x + 2 = 0
Solution:
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 1
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 2

Question 2.
Find the values of k for which the roots are real and equal in each of the following equations :
(i) kx² + 4x + 1 = 0
(ii) kx² – 2√5 x + 4 = 0
(iii) 3x² – 5x + 2k = 0
(iv) 4x²+ kx + 9 = 0
(v) 2kx² – 40x + 25 = 0
(vi) 9x² – 24x + k = 0
(vii) 4x² – 3kx +1 = 0
(viii) x² – 2 (5 + 2k) x + 3 (7 + 10k) = 0
(ix) (3k + 1) x² + 2(k + 1) x + k = 0
(x) kx² + kx + 1 = – 4x² – x
(xi) (k + 1) x² + 2 (k + 3) x + (k + 8) = 0
(xii) x² – 2kx + 7k – 12 = 0
(xiii) (k + 1) x² – 2 (3k + 1) x + 8k + 1 = 0
(xiv) 5x² – 4x + 2 + k (4x² – 2x – 1) = 0
(xv) (4 – k) x² + (2k + 4) x (8k + 1) = 0
(xvi) (2k + 1) x² + 2 (k + 3) x (k + 5) = 0
(xvii) 4x² – 2 (k + 1) x + (k + 4) = 0
(xviii) 4x² (k + 1) x + (k + 1) = 0
Solution:
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 3
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 4
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 5
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 6
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 7
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 8
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 9
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 10
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 11
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 12
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 13
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 14
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 15
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 16

Question 3.
In the following, determine the set of values of k for which the given quadratic equation has real roots :
(i) 2x² + 3x + k = 0
(ii) 2x² + x + k = 0
(iii) 2x² – 5x – k = 0
(iv) kx² + 6x + 1 = 0
(v) 3x² + 2x + k = 0
Solution:
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 17
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 18
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 19

Question 4.
Find the values of k for which the following equations have real and equal roots :
(i) x²- 2(k + 1) x + k² = 0 [CBSE 2001C, 2013]
(ii) k²x² – 2 (2k – 1) x + 4 = 0 [CBSE 2001C]
(iii) (k + 1) x² – 2(k – 1) x + 1 = 0 [CBSE 2002C]
(iv) x² + k(2x + k – 1) + 2 = 0 [CBSE 2017]
Solution:
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 20
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 21
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 22

Question 5.
Find the values of k for which the following equations have real roots
(i) 2x² + kx + 3 = 0 [NCERT]
(ii) kx (x – 2) + 6 = 0 [NCERT]
(iii) x² – 4kx + k = 0 [CBSE 2012]
(iv) kx(x – 2√5 ) + 10 = 0 [CBSE 2013]
(v) kx (x – 3) + 9 = 0 [CBSE 2014]
(vi) 4x² + kx + 3 = 0 [CBSE 2014]
Solution:
(i) 2x² + kx + 3 = 0
Here a = 2, b = k, c = 3
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 23
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 24
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 25

Question 6.
Find the values of k for which the given quadratic equation has real and distinct roots :
(i) kx² + 2x + 1 = 0
(ii) kx² + 6x + 1 = 0
Solution:
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 26

Question 7.
For what value of k, (4 – k) x² + (2k + 4) x + (8k + 1) = 0, is a perfect square.
Solution:
(4 – k) x² + (2k + 4) x + (8k + 1) = 0
Here, a = 4 – k, b = 2k + 4, c = 8k + 1
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 27

Question 8.
Find the least positive value of k for which the equation x² + kx + 4 = 0 has real roots.
Solution:
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 28

Question 9.
Find the value of k for which the quadratic equation (3k + 1) x² + 2(k + 1) x + 1 = 0 has equal roots. Also, find the roots.
[CBSE 2014]
Solution:
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 29
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 30

Question 10.
Find the values of p for which the quadratic equation (2p + 1) x² – (7p + 2) x + (7p – 3) = 0 has equal roots. Also, find these roots.
Solution:
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 31
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 32

Question 11.
If – 5 is a root of the quadratic equation 2x² + px – 15 = 0 and the quadratic equation p(x² + x) + k = 0 has equal-roots, find the value of k. [CBSE 2014]
Solution:
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 33
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 34

Question 12.
If 2 is a root of the quadratic equation 3x² + px – 8 = 0 and the quadratic equation 4x² – 2px + k = 0 has equal roots, find the value of k. [CBSE 2014]
Solution:
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 35
=> 16k = 16
k = 16

Question 13.
If 1 is a root of the quadratic equation 3x² + ax – 2 = 0 and the quadratic equation a(x² + 6x) – b=0 has equal roots, find the value of b.
Solution:
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 36

Question 14.
Find the value of p for which the quadratic equation (p + 1) x² – 6 (p + 1) x + 3 (p + q) = 0, p ≠ -1 has equal roots. Hence, find the roots of the equation. [CBSE 2015]
Solution:
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 37
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 38

Question 15.
Determine the nature of the roots of following quadratic equations :
(i) (x – 2a) (x – 2b) = 4ab
(ii) 9a²b²x² – 24abcdx + 16c²d² = 0, a ≠ 0, b ≠ 0
(iii) 2 (a² + b²) x² + 2 (a + b) x + 1 = 0
(iv) (b + c) x² – (a + b + c) x + a = 0
Solution:
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 39
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 40

Question 16.
Determine the set of values of k for which the given following quadratic equation has real roots :
(i) x² – kx + 9 = 0
(ii) 2x² + kx + 2 = 0
(iii) 4x² – 3kx +1=0
(iv) 2x² + kx – 4 = 0
Solution:
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 41
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 42

Question 17.
If the roots of the equation (b – c) x² + (c – a) x + (a – b) = 0 are equal, then prove that 2b = a + c. [CBSE 2002C]
Solution:
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 43
=> a + c = 2b
=> 2b = a + c
Hence proved.

Question 18.
If the roots of the equation (a² + b²) x² – 2 (ac + bd) x + (c² + d²) = 0 are equal. prove that \(\frac { a }{ b }\) = \(\frac { c }{ d }\)
Solution:
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 44

Question 19.
If the roots of the equations ax² + 2bx + c = 0 and bx² – 2√ac x + b = 0 are simultaneously real, then prove that b² = ac
Solution:
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 45
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 46

Question 20.
If p, q are real and p ≠ q, then show that the roots of the equation (p – q) x² + 5(p + q) x – 2(p – q) = 0 are real and unequal.
Solution:
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 47

Question 21.
If the roots of the equation (c² – ab) x² – 2 (a² – bc) x + b² – ac = 0 are equal, prove that either a = 0 or a3 + b3 + c3 = 3abc.
Solution:
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 48

Question 22.
Show that the equation 2 (a² + b²) x² + 2 (a + b) x + 1 = 0 has no real roots, when a ≠ b.
Solution:
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 49

Question 23.
Prove that both the roots of the equation (x – a) (x – b) + (x – b) (x – c) + (x – c) (x – a) = 0 are real but they are equal only when a = b = c.
Solution:
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 50

Question 24.
If a, b, c are real numbers such that ac ≠ 0, then show that at least one of the equations ax² + bx + c = 0 and – ax² + bx + c = 0 has real roots.
Solution:
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 51

Question 25.
If the equation (1 + m²) x² + 2mcx + (c² – a²) = 0 has equal roots, prove that c² = a² (1 + m²). (C.B.S.E. 1999)
Solution:
RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 52

Hope given RD Sharma Class 10 Solutions Chapter 4 Quadratic Equations Ex 4.6 are helpful to complete your math homework.

If you have any doubts, please comment below. Learn Insta try to provide online math tutoring for you.

The Tale of Custard the Dragon Extra Questions and Answers Class 10 English First Flight

The Tale of Custard the Dragon Extra Questions and Answers Class 10 English First Flight

Here we are providing Online Education for The Tale of Custard the Dragon Extra Questions and Answers Class 10 English First Flight, Extra Questions for Class 10 English was designed by subject expert teachers. https://ncertmcq.com/extra-questions-for-class-10-english/

Online Education for The Tale of Custard the Dragon Extra Questions and Answers Class 10 English First Flight

The Tale of Custard the Dragon Extra Questions and Answers Short Answer Type

The Tale Of Custard The Dragon Extra Questions Question 1.
What were the names of Belinda’s pets?
Answer:
The names of Belinda’s pets were Ink, a little black kitten; Mustard, a little yellow dog; Blink, a little grey mouse and a dragon whose name was Custard.

The Tale Of Custard The Dragon Extra Question Answer Question 2.
How did the pirate look?
Answer:
The pirate held a pistol in his left hand and another pistol in his right hand. He had black beard and his one leg was of wood. He held a bright cutlass in his teeth. It was clear that his intentions were not good.

The Tale Of Custard The Dragon Question Answer Question 3.
Why did the Belinda cry for help?
Answer:
Belinda was scared to see the pirate who had pistols in his hands and had a bright cutlass in his teeth. There was something bad in his appearance and intention. Therefore Belinda was afraid of the pirate and cried for help.

Tale Of Custard The Dragon Extra Questions Question 4.
What did the custard do at last?
Answer:
Custard saved Belinda and the other pets from the pirate. He showed his braver side and attacked the pirate and gobbled him up. Finally, Custard showed that he was not as coward as others.

The Tale Of Custard The Dragon Class 10 Extra Questions Question 5.
Why did the Custard, the dragon cry for a nice, safe cage?
Answer:
Custard, in fact, was very brave but still he kept asking for a nice, safe cage. It made people think him to be cowardly. He might be crying for a nice, safe cage so that he might not harm anyone when in anger or he might be proving that a little safety cage averts a disaster. The others thought that he cried for a cage as he was a coward.

The Tale Of Custard The Dragon Short Question Answer Question 6.
What did Belinda and her pets hear?
Answer:
Belinda and her pets heard a nasty sound made by the pirate breaking in through the window. Belinda and her pets except Custard were terrified and cried for help. Ink, Blink and Mustard fled away cowardly. Custard fought with him bravely and killed him.

Extra Questions Of The Tale Of Custard The Dragon Question 7.
What terrified the pirate? Who killed him and how?
Answer:
Custard, the dragon, jumped up, snorting and clashing his tail. He was making a lot of clatter and clankering and he was squirming. He attacked the pirate. It terrified the pirate. He fired at Custard and missed. Custard killed him by swallowing him up. It shows that he was brave.

The Tale Of Custard The Dragon Important Questions Question 8.
Write the poetic aspect of the poem “The Tale of Custard the Dragon”.
Answer:
The poem “The Tale of Custard the Dragon” is a light-hearted story, written in the ballad style. It is written in a four-lined stanza format with the rhyming scheme of aabb. It takes it near to the heroic couplet. The poem offers many similes. The stanzas vary in size. The lines are prosaic and long. The first two stanzas act as refrain to indicate continuity. The words are simple.

The Tale Of Custard The Dragon Extra Questions And Answers Question 9.
When the pirate attacked Belinda, ail of her brave friends—Ink, Blink and Mustard ran away. Only Custard fought with the enemy. Based on your reading of the poem, write a paragraph on the topic: ‘A friend in Need is a Friend Indeed’.
Answer:
Man is a social animal and we all have survived throughout the civilization through the process of socialization. The beginning of any friendship is when one tries to socialize with the other. But not all socializations result in friendship. Some people walk past us in the journey of life, and some stay back and see us grow. The ones, who walk away when the clouds are cast, are the ones who will never stick around when we need them the most.

A true friend is the one who always sticks around irrespective of how good or bad the situation is. Therefore it is rightly said that those who survive the test of friendship i.e., those who stand by us in our most trying times are the real friends. Truly, a friend in need is a friend indeed.

Question 10.
Everyone believed that the Custard was a coward; but when an opportunity came he showed exemplary courage. Based on y our reading of the poem, write a paragraph on the topic: ‘Courage is a Mind, not of Muscle’.
Answer:
Mark Twain once said that ‘Courage is resistance to fear, mastery of fear—not absence of fear’. Courage is not merely a show of power but the ability to overcome fear and not allow it to paralyze our minds. Most of us tend to generalize and call people who shy away from a physical show of power as being cowards.

But the truth lies in the fact that those who indulge in physical aggression are the ones who are the most insecure. David was barely one-fourth of Goliath, the giant. Yet David succeeded, in killing him. He had used his presence of mind and stood successful over an entire army. Thus, we must remember that courage is a matter of mind, not muscle.

Question 11.
The dragon Custard was considered a coward. The humble dragon proved his bravery in adversity. Analyses that certain qualities like bravery and courage are situation and spontaneous. Explain with reference to the poem “The Tale of Custard the Dragon”.
Answer:
The pirate held a pistol in his left hand and another pistol in his right hand. He had black beard and his one leg was of wood. He held a bright cutlass in his teeth. It was clear that his intentions were not good.

Question 12.
Who are the characters in this poem? List them with their pet names.
Answer:
The characters in this poem are Belinda, a little black kitten, a little grey mouse, a little yellow dog, a little pet dragon and a pirate.

Character Pet name
Kitten Ink
Mouse Blink
Dog Mustard
Dragon Custard

Question 13.
Why did Custard cry for a nice, safe cage? Why is the dragon called “cowardly dragon”?
Answer:
Custard cried for a nice, safe cage because it was a coward. It is called a ‘cowardly dragon’ because everybody else in the house was brave. Belinda was as brave as a barrel of bears. Ink and blink are described as so brave they chased lions down the stairs and Mustard was as brave as a tiger in rage. Compared to them, Custard cried asking for a nice and safe cage, which is why it is called a coward.

Question 14.
“Belinda tickled him, she tickled him unmerciful…” Why?
Answer:
Belinda tickled the dragon unmercifully because it was very scared and cried for a safe cage. They all laughed at it as it was a coward.

Question 15.
The poet has employed many poetic devices in the poem. For example: “Clashed his tail like iron in a dungeon”—the poetic device here is a simile. Can you, with your partner, list some more such poetic devices used in the poem?
Answer:
In the entire poem, the poet has made extensive use of similes. Apart from simile, another poetic device that has been used is repetition. For example, the repetitive use of the word ‘little’ in the first stanza to emphasize how everything from the house to Belinda to her pets were all little. Also, in the seventh stanza, the poet has made use of incorrect spelling as a poetic device to maintain the rhyme scheme of the poem.

He has chosen to write ‘winda’ instead of ‘window’ as ‘winda’ rhymes with ‘Belinda’, whereas ‘window’ does not. He has also used alliteration in the poem. For example, in the tenth stanza, ‘custard’ has ‘clashed’ his tail with a ‘clatter’ and a ‘clank’. Similarly, in stanza eleven, the pirate ‘gaped’ at the dragon and ‘gulped’ some ‘grog”.

Question 16.
Read the stanza three again to know how the poet describes the appearance of the dragon.
Answer:
The teeth of the dragon, Custard were having fine edges or points. There were spikes with sharp points on the top of his body and beneath his body had scales or hard body. His mouth looked like a fireplace or hearth and his nose was like a chimney. And there were short pointed daggers like sharp points on his toes.

Question 17.
Can you find out the rhyme scheme of two or three stanzas of the poem?
Answer:
The rhyme scheme of each stanza of this poem is ‘aabb’.

Question 18.
Writers use words to give us a picture or image without actually saying what they mean. Can you trace some images used in the poem?
Answer:
Some such images used in the poem are ‘mouth like a fireplace’, ‘chimney for a nose’, ‘brave as a barrel full of bears’, ‘brave as a tiger in a rage’, ‘went at the pirate like a robin at a worm’, etc.

Question 19.
Do you find The Tale of Custard the Dragon to be a serious or a light-hearted poem? Give reasons to support your answer.
Answer:
The Tale of Custard the Dragon is a light-hearted poem. It is almost a parody. The names of the pets of Belinda are all rhyming and funny. Belinda has been compared to a barrel full of bears. The kitten and mouse, both little, could chase lions down the stairs. The little yellow dog was as brave as a tiger, while the dragon was a coward and they all teased him. However,when the pirate came to their little house, all of them were engulfed in fear and had hidden themselves.

Ironically, the ‘cowardly’ dragon came to their rescue and jumped snorting like an engine. It clashed its tail and charged at the pirate like a robin at a worm and ate him up. Even as everybody became happy to see the bravery of the dragon, they again came back to glorifying themselves that they could have been twice or thrice braver than the dragon. Finally, at the end of the poem, the situation again came back to the other pets being brave and the dragon being the coward.

Question 20.
This poem, in ballad form, tells a story. Have you come across any such modern song or lyric that tells a story? If you know one, tell it to the class. Collect such songs as a project.
Answer:
‘Light of Asia’ is an epic that has been read. It tells us a story in verse. In it we get the story of Prince Siddhartha, the son of king Sudhodhana. We get from it the complete story of his life, how he was brought-up and how he got married and how he became a saint.

The Tale of Custard the Dragon Extra Questions and Answers Reference to Context

Read the following stanza and answer the questions that follow:

Question 1.
Belinda lived in a little white house,
With a little black kitten and a little grey mouse,
And a little yellow dog and little red wagon,
And a realio, trulio, little pet dragon.

(i) Name the poem and poet.
(ii) Who was Belinda?
(iii) Where did Belinda live?
(iv) Who were her companions?
Answer:
(i) This stanza has been taken from the poem “The Tale of Custard the Dragon” composed by Ogden Nash.
(ii) Belinda was a little girl.
(iii) Belinda lived in a little white house.
(iv) Belinda had four pets—a little black kitten, a little grey mouse, a little yellow dog and a little red wagon.

Question 2.
Now the name of the little black kitten was Ink,
And the little grey mouse, she called him Blink,
And the little yellow dog was sharp as Mustard,
But the dragon was a coward, and she called him Custard.

(i) What were the names of her pets?
(ii) Who was the sharpest of them?
(iii) Who was a coward?
(iv) Name the poem and poet.
Answer:
(i) Kitten was Ink, mouse was Blink, the dog was Mustard and the dragon was called Custard.
(ii) Mustard, the dog was the sharpest of them.
(iii) The dragon, Custard was a coward.
(iv) The poem “The Tale of Custard the Dragon” and composed by “Ogden Nash”.

Question 3.
Custard the dragon had big sharp teeth,
And spikes on top of him and scales underneath
Mouth like a fireplace, Chimney for a nose,
And realio, trulio daggers on his toes.

(i) Who was Custard?
(ii) What were on his top?
(iii) How did his mouth and nose look like?
(iv) Name the poem and poet.
Answer:
(i) Custard was the pet dragon of Belinda.
(ii) There were spikes on his top.
(iii) His mouth looked like a fireplace and his nose was like a chimney.
(iv) The poem “The Tale of Custard the Dragon” and composed by “Ogden Nash”.

Question 4.
Belinda was as brave as a barrel full of bears,
And Ink and Blink chased lions down the stairs,
Mustard was as brave as a tiger in a rage,
But Custard cried for a nice safe cage.

(i) What type of a girl was Belinda?
(ii) Who was Ink and Blink?
(iii) Who was Mustard? What was his quality?
(iv) Name the poem and poet.
Answer:
(i) Belinda was as brave as a barrel full of bears.
(ii) The kitten was Ink and the mouse was Blink.
(iii) Mustard was the name of her pet dog. He was as brave as a tiger.
(iv) The poem “The Tale of Custard the Dragon” and composed by “Ogden Nash”.

Question 5.
Belinda tickled him, she tickled him unmerciful,
Ink, Blink and Mustard, they rudely called him Percival,
They all sat laughing in the little red wagon
At the realio, trulio, cowardly dragon.

(i) Who did Belinda tickle?
(ii) What did other pets call him?
(iii) Why did they laugh at him?
(iv) Name the poem and poet.
Answer:
(i) Belinda tickled the Dragon.
(ii) The other pets called him Percival.
(iii) They laughed at him because he was coward.
(iv) The poem “The Tale of Custard the Dragon” and composed by “Ogden Nash”.

Question 6.
Belinda giggled till she shook the house,
And Blink said Weeck! which is giggling for a mouse,
Ink and Mustard rudely asked his age,
When Custard cried for a nice safe cage.

(i) On whom did Belinda giggle?
(ii) How did Ink and Mustard trouble Custard?
(iii) What did Custard cry for?
(iv) Name the poem and poet.
Answer:
(i) Belinda giggled and made fun of him when Custard cried for a nice safe cage.
(ii) Ink and Mustard made fun of Custard and rudely asked his age.
(iii) Custard cried for a nice safe place.
(iv) The poem “The Tale of Custard the Dragon” and composed by “Ogden Nash”.

Question 7.
Suddenly, suddenly they heard a nasty sound,
And Mustard growled, and they all looked around.
Meowch! qried Ink, and ooh! cried Belinda,
For there was a pirate, climbing in the winda.

(i) Who are ‘they here?
(ii) What did they hear?
(iii) How did they react?
(iv) Name the poem and poet.
Answer:
(i) ‘They’ are Belinda and her pets.
(ii) They heard a nasty sound.
(iii) All of them were afraid.
(iv) The poem “The Tale of Custard the Dragon” and composed by “Ogden Nash”.

Question 8.
Pistol in his left hand, pistol in his right,
And he held in his teeth a cutlass bright,
His beard was black, one leg was wood;
It was clear that the pirate meant no good.

(i) Who is ‘He’in this stanza?
(ii) What did he look like?
(iii) What was his intention?
(iv) Name the poem and poet.
Answer:
(i) ‘He’ is the pirate in this stanza, who had entered to their house.
(ii) His beard was black. He had one wooden leg. He looked scary.
(iii) He did not have good intention.
(iv) The poem “The Tale of Custard the Dragon” and composed by “Ogden Nash”.

Question 9.
Belinda paled, and she cried Help! Help!
But Mustard fled with a terrified yelp,
Ink trickled down to the bottom of the household,
And little mouse Blink strategically mouseholed.

(i) Why did Belinda become pale?
(ii) How did Mustard react?
(iii) What did Ink do? Why?
(iv) Name the poem and poet.
Answer:
(i) Belinda paled when a pirate attacked her.
(ii) Mustard fled with a terrified yelp.
(iii) Ink was so terrified that she trickled down to the bottom of the household.
(iv) The poem “The Tale of Custard the Dragon” and composed by “Ogden Nash”.

Question 10.
The pirate gaped at Belinda’s dragon
And gulped some grog from his pocket flagon,
He fired two bullets, but they didn’t hit,
And Custard gobbled him, every bit.

(i) What did the pirate do?
(ii) What did he drink?
(iii) What did Custard do?
(iv) Name the poem and poet.
Answer:
(i) The pirate gaped at Belinda’s dragon (Custard).
(ii) He drank some wine from his vessel.
(iii) Custard gobbled pirate slowly and slowly.
(iv) The poem “The Tale of Custard the Dragon” and composed by “Ogden Nash”.

Two Gentlemen of Verona Extra Questions and Answers Class 10 English Literature

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Two Gentlemen of Verona Extra Questions and Answers Short Answer Type

Two Gentlemen Of Verona Questions And Answers Class 10 Question 1.
Justify the title Two Gentlemen of Verona.
Answer:
The title is absolutely justified as the story is about two young boys, who despite their youth, were already true gentlemen. They were dignified, conscientious, sincere and hardworking. They shouldered the responsibility of looking after their sister Lucia and paid her hospital bills by working hard without expecting any help from anyone. They lived with dignity and pride.

Two Gentlemen Of Verona One Mark Questions Class 10 Question 2.
Where did the narrator meet the two boys for the first time? What were they doing?
Answer:
The narrator met the boys for the first time as he was driving towards Verona on the foothills of the Alps. The boys were selling baskets of strawberries and they stopped his car to sell him some too.

The Two Gentlemen Of Verona Question Answer Class 10 Question 3.
Why did the narrator say that what struck one most was their willingness to work?
Answer:
Though the boys were fairly young, they were extremely hard-working. Even when they were tired, they ‘ worked without complaint. They did many jobs and worked willingly and cheerfully.

Two Gentlemen Of Verona Class 10 Extra Questions With Answers Question 4.
Why was the square deserted?
Answer:
The square was deserted because it was very late at night. People had returned home.

The Two Gentlemen Of Verona Question Answer Class 10 Question 5.
Were the boys quite happy to work? Which sentence tells -you this?
Answer:
Yes, we know that the boys were happy to work as the narrator observes, “What struck one most was their willingness to work.”

Two Gentlemen Of Verona Question Answers Class 10 Question 6.
What made the narrator think that they were earning much?
Answer:
The narrator saw the boys doing multiple jobs. They shined shoes, sold fruit, hawked newspapers, conducted tourists round the town and ran errands. Therefore, the narrator thought they were earning a good amount of money.

Two Gentlemen Of Verona Question Answers Pdf Class 10 Question 7.
The narrator feels that the boys worked very hard but spent very little. What impression has he formed of their character?
Answer:
The narrator saw that the boys worked very hard at many jobs. He also noticed that despite their earnings, they spent nothing on clothes and ate very frugal meals. He assumes that the boys were hoarding money to emigrate to the United States.

Question 8.
Where did the boys go every Sunday? Why did they do so?
Answer:
Every Sunday, the boys went to the hospital in Poleta to meet their sister Lucia who was admitted there. Lucia was suffering from tuberculosis of the spine.

Question 9.
Do you think the boys looked after Lucia willingly? Explain.
Answer:
Undoubtedly the boys looked after Lucia willingly. They worked at various jobs and performed errands for people cheerfully, spending little on themselves. They neither looked to others for help nor for sympathy. They could have easily taken help from the narrator and other people, but they preferred to look after their sister themselves.

Question 10.
How does the story of the Two Gentlemen of Verona give promise of greater hope for human society?
Answer:
The two boys—one 13 and the other 12—shouldered responsibility for their ailing sister without complaints. They worked hard and tirelessly, not looking for help or pity. They did not shirk from their duty towards their family or country. They were the embodiment of selflessness, nobility and gentleness. The two boys prove that hope, faith, positive thinking and hard work can help overcome all troubles in life.

Question 11.
Why did the boys work so hard?
Answer:
The boys worked hard because their sister was suffering from tuberculosis of the spine and was hospitalized.
They had to take care of her hospital bills as they were orphans with no other family. Also, they were proud, wanting neither help nor pity.

Question 12.
What had happened to their parents?
Answer:
The boys had lost their mother very early in life. Their father had been killed during the war.

Question 13.
Who is Lucia?
Answer:
Lucia was the elder sister of Nicola and Jacopo. She was suffering from tuberculosis of the spine and was in hospital for treatment.

Question 14.
What were Nicola’s feelings when the narrator commented on his frugal lifestyle?
Answer:
When the narrator commented on the fact that the boys worked hard and probably earned a good deal of money yet lived very frugally, Nicola was embarrassed and he did not say anything, just looked down.

Question 15.
Why did the narrator follow the boys to the villa? Why did he not meet Lucia?
Answer:
The narrator was curious about why the boys had gone to the villa. He wanted to find out more about them, so he followed them to the villa. He did not go in to meet Lucia as he did not wish to embarrass the boys.

Question 16.
What were the narrator’s feelings about the two boys at first? What change did they undergo and why?
Answer:
At first the narrator was impressed by the hard work the boys put in. He became fond of them as they were friendly and ran errands for him. But when he saw them with Lucia and realised that they were working hard to shoulder the responsibility of an ailing elder sister, he was filled with admiration and respect for them.

Question 17.
Did the boys try to prevent the narrator from finding out the real purpose of their visit to Poleta? Did they succeed?
Answer:
The boys tried to prevent the narrator from finding out the real purpose of their visit. They jumped out of the car as soon as it stopped and rushed off after telling the narrator that they would meet him in an hour’s time. They did not succeed because the narrator, fired by curiosity, went inside later and found out the truth.

Question 18.
How did the war affect the boys’ family?
Answer:
The boys’ father was killed shortly after the war started. Subsequently, a bomb destroyed their home and the three children were thrown out into the streets. They suffered horribly from near starvation and exposure to the cold winter. During the German occupation, the boys joined the resistance movement. The hardships and suffering led to the sister developing tuberculosis of the spine.

Question 19.
“Just plans, sir….” Why does Nicola say it in a low voice? Does he want to hide anything?
Answer:
Nicola is embarrassed by the narrator’s observation on their frugal spending and shabby clothing despite them and his brother earning what must be a considerable amount. Nicola also wanted to hide the real reason behind their saving money from the narrator.

Two Gentlemen of Verona Extra Questions and Answers Long Answer Type

Question 1.
Write a paragraph on the early life of the two boys during the war.
Answer:
The father of the two boys was a well-known singer and a widower. He was killed in war and a bomb blast had destroyed their home. As a result, the boys and their sister were left on the streets. They suffered starvation and exposure to cold winter and barely managed to keep themselves alive. They built a shelter with their own hands amid the rubble. The boys had joined the resistance movement. During this time, their sister developed tuberculosis of the spine.

Question 2.
Give a brief character sketch of Nicola and Jacopo.
Answer:
Nicola and Jacopo endured immense suffering. They were motherless and had lost their father in the war. A bomb blast had destroyed their house but their spirit was not broken. They were a resourceful duo and had made their own shelter. They were hard-working and willing to do any job to pay for their sister’s stay in the hospital.

They were devoted to their sister and did not spend money on themselves. They were dignified and conscientious and also patriotic as they had joined the Resistance movement against Germans, though they were mere children. They were proud and did not want sympathy from anyone.

Question 3.
Give a brief character sketch of Nicola.
Answer:
He was a brave and spirited boy. Despite enduring immense suffering in the absence of his mother and father, his spirit was not broken. He was the stronger of the two brothers and was extremely resourceful. He even made his own shelter. He was hard-working and willing to do any job. He was devoted to his sister and was willing to do any kind of hard work to pay for her stay in the hospital. He did not spend money on himself. He was patriotic by nature and had joined the Resistance movement against Germans though was very young. He was proud and did not want sympathy from any one for his plight. He was also childish and innocent.

Question 4.
In what way is Jacopo different from his elder brother?
Answer:
He was a brave and spirited boy and the terrible hardships that he had to endure had not broken his spirit. He was the younger of the two brothers. He was childish and innocent and was naughty as a squirrel.

Question 5.
“Yet in both these boyish faces there was a seriousness which was far beyond their years.” Does this sentence signal anything to you?
Answer:
The boys had imbibed a sense of responsibility at a very young age. They were ready to do any job and were extremely hard-working. Their selfless action and devotion to their sister’s treatment is remarkable. Their hard-earned money was spent shouldering responsibility far beyond their years.

Question 6.
Justify the title Two Gentlemen of Verona.
Answer:
A ‘gentleman’ is a person who is gentle and considerate and respects the feelings of others while treating them. He adheres to high standards of behaviour and responsibility and is mindful of his duty. The two boys are gentlemen as they are hardworking and conscientious as well as imbued with a sense of duty towards their country. They are also aware of their responsibility towards their sister Lucia.

Question 7.
The journey to Poleta changed the narrator’s previous impression about the boys. He was deeply moved by their story. He could not sleep that night. He wrote about them in his diary. Write the diary of the narrator.
Answer:
Dear Diary,
I have met two very hard working boys. I saw them doing a number of jobs. They had a frugal nature that reflected in their appearance as well food habits. I presumed that they were saving to emigrate. One day I accompanied them to Poleta and followed them to a villa. I learnt of their hard life. I came to know about the loss of their father and how their home was destroyed. I came to know about the extreme hard work that they were doing to pay for their sister’s hospital bills and I was mighty impressed by their sense of responsibility. I admired the pride that the two boys had, as they refused to be looked upon with pity by others.

Question 8.
The nurse in the hospital told Lucia that she had completely recovered from the illness and she could go home the next day. Lucia became very happy and that day she wrote a diary. What would that diary entry be?
Answer:
Dear Diary,
I have recovered from my illness after staying in the hospital for ,many months. My brothers have endured immense hardships to pay the hospital fees. I have tremendous admiration for their resourcefulness and their sense of duty. I will work as a singer and try to give them a good life.

Question 9.
Two Gentlemen of Verona deals with the importance of family relationships. Comment.
Answer:
The values revealed by the two boys are selflessness, devotion to duty, willingness to work hard and cheerfulness in adverse circumstances. It gives us promise of a greater hope for society. The war had destroyed everything Nicola and Jacopo had. Moreover, their sister Lucia was suffering from tuberculosis of the spine and had to be hospitalized. However, it did not fill them with despair. They resolved to start a new life for themselves after the war. They got Lucia admitted to a hospital and worked very hard to pay for her treatment.

Question 10.
How does the story Two Gentlemen of Verona by A.J. Cronin promise hope for society?
Answer:
The story stresses the importance of relationships and one’s duty towards society and country. The boys’ father was killed in the war and their home was destroyed. Nicola and Jacopo worked at numerous jobs and ran errands to earn money to pay for their sister’s treatment.

The destruction caused by the war could not break the spirit of the two boys. Rather it filled them with a new energy to rebuild from what was left after the war. In this world, where values are eroding, these boys and their work promise a new hope for society. Their selflessness, devotion to duty, willingness to work hard and cheerfulness in adverse circumstances give us promise of a greater hope for society.

Two Gentlemen of Verona Extra Questions and Answers Reference to Context

Read the following passages taken from Two Gentlemen of Verona and answer the questions:

Question 1.
“One boy had on a worn jersey and cut-off khaki pants; the other a shortened army tunic gathered in loose folds about his skinny frame. Yet, gazing at the two little figures, with their brown skins, tangled hair and dark earnest eyes, we felt ourselves strangely attracted. ”

(a) What quality of the boys attracted the narrator?
Answer:
The narrator was attracted by the honesty in the boys’ eyes.

(b) How did the narrator help the boys?
Answer:
The narrator helped the boys by buying the strawberries they were selling.

(c) How do we know that the boys were poor?
Answer:
We know that the boys were poor as they were wearing tom and oversized clothes.

Question 2.
“Next morning, coining out of our hotel, we saw our friends bent over shoeshine boxes beside the fountain in the public square, doing a brisk business. We watched for a few moments; then as trade slackened we went over. They greeted us with friendly faces. ”

(a) Whom does the narrator refer to as ‘our friends’?
Answer:
The narrator refers to Nicola and Jacopo as ‘our friends’.

(b) What were the ‘friends’ doing?
Answer:
The boys were shining shoes in the town square.

(c) What does the phrase ‘trade slackened’ mean?
Answer:
The phrase means that the boys’ business of shining shoes had slowed down. They were not very busy.

Question 3.
“As we made the rounds, my interest was again provoked by their remarkable demeanour. ”

(a) What does the phrase ‘making the rounds’ mean?
Answer:
The phrase means to go around from one place to another. The narrator means he was sightseeing in the town of Verona. ’

(b) What did the narrator notice about their ‘demeanour’?
Answer:
The narrator noticed that the boys were very serious.

(c) Why was it ‘remarkable’?
Answer:
It was remarkable because the boys were rather young. The seriousness did not go well with their age.

Question 4.
“The following afternoon we drove to the tiny village set high upon the hillside. ”

(a) Who went on the trip to the tiny village?
Answer:
The narrator and the two brothers, Nicola and Jacopo went on the trip.

(b) What was the name of the village they had driven to?
Answer:
The narrator and the boys had driven to the village called Poleta.

(c) Why was the narrator surprised when Jacopo directed him as to where he should stop?
Answer:
The narrator was surprised as he had thought they would stop at some humble dwelling, but Jacopo guided him to a large villa.

Question 5.
“The boys grew to hate the Germans. When the resistance movement began to form they were among the first to join. ”

(a) Who are the ‘boys’?
Answer:
The ‘boys’ are Nicola and Jacopo.

(b) Why did the boys grow to hate the Germans?
Answer:
The boys hated the Germans as not only they had lost their father early in the war but a German bomb had also destroyed their beautiful home.

Magnetic Effects of Electric Current Class 10 Extra Questions with Answers Science Chapter 13

Magnetic Effects of Electric Current Class 10 Extra Questions with Answers Science Chapter 13

In this page, we are providing Online Education for Magnetic Effects of Electric Current Class 10 Extra Questions and Answers Science Chapter 13 pdf download. NCERT Extra Questions for Class 10 Science Chapter 13 Magnetic Effects of Electric Current with Answers will help to score more marks in your CBSE Board Exams. https://ncertmcq.com/extra-questions-for-class-10-science/

Online Education for Class 10 Science Chapter 13 Extra Questions and Answers Magnetic Effects of Electric Current

Extra Questions for Class 10 Science Chapter 13 Magnetic Effects of Electric Current with Answers Solutions

Extra Questions for Class 10 Science Chapter 13 Very Short Answer Type

Magnetic Effect Of Electric Current Class 10 Extra Questions And Answers Question 1.
Define magnetic effect of electric current.
Answer:
The production of magnetic field around a conductor when electric current is passed through it.

Magnetic Effect Of Electric Current Extra Questions Question 2.
What is fuse?
Answer:
Fuse is the most important safety device, used for protecting the circuits due to short-circuiting or overloading of the circuits.

Extra Questions Of Magnetic Effect Of Electric Current Question 3.
What is the pattern of magnetic field around a current carrying conductor?
Answer:
The magnetic field around a current carrying conductors forms a pattern of concentric circles.

Magnetic Effects Of Electric Current Class 10 Extra Questions Question 4.
Draw an appropriate schematic diagram showing common domestic circuits and discuss the importance of fuse.
Answer:
Magnetic Effect Of Electric Current Class 10 Extra Questions And Answers

Extra Questions for Class 10 Science Chapter 13 Short Answer Type

Class 10 Science Chapter 13 Extra Questions Question 1.
What is electric motor? Write down its principle of working.
Answer:
Electric motor: An electric motor is a rotating device that converts electrical energy to mechanical energy.
Principle: A current-carrying conductor when placed in a magnetic field experiences a force.

Magnetic Effects Of Electric Current Extra Questions Question 2.
What is galvanometer?
Answer:
A galvanometer is an instrument that can detect the presence of a current in a circuit.
The pointer remains at zero (the centre of the scale) for zero current flowing through it.
It can deflect either to the left or to the right of the zero mark depending on the direction of current.
Magnetic Effect Of Electric Current Extra Questions

Class 10 Magnetic Effect Of Electric Current Extra Questions Question 3.
Describe domestic electric circuits.
Domestic Electric circuits: In our houses, we receive AC electric power of 220 V with a frequency of 50 Hz. One of the wires in this supply is with red insulation, called live wire. The other one is of black insulation, which is a neutral wire. The potential difference between the two is 220 V.

The third is the earth wire that has green insulation and this is connected to a metallic body deep inside the earth. It is used as a safety measure to ensure that any leakage of current to a metallic body of an appliance does not give any severe shock to the user.

Ch 13 Science Class 10 Extra Questions Question 4.
What will happen if a current carrying conductor is placed in magnetic field? How can the direction of magnetic field be found out?
Answer:
A current-carrying conductor when placed in a magnetic field experiences a force.
If the direction of the field and that of the current are mutually perpendicular to each other, then the force acting on the conductor will be perpendicular to both as given by Fleming’s left-hand rule.

Magnetic Effect Of Electric Current Class 10 Extra Questions Question 5.
What does the direction of thumb indicate in the right-hand thumb rule? In what ways this rule is different from Fleming’s left-hand rule?
Answer:
The thumb indicates the direction of current in the straight conductor held by curled fingers, whereas Fleming’s left-hand rule gives the direction of force experienced by current carrying conductor placed in an external magnetic field.

Extra Questions Of Chapter 13 Class 10 Science Question 6.
What is the difference between a direct current and an alternating current? How many times does AC used in India change direction in one second?
Answer:
Direct current always flows in one direction but the alternating current reverses its direction periodically. The frequency of AC in India is 50 Hz and in each cycle it alters direction twice. Therefore, AC changes direction 2 × 50 = 100 times in one second.

Class 10 Magnetic Effects Of Electric Current Extra Questions Question 7.
What is the role of fuse, used in series with any electrical appliance? Why should a fuse with defined rating not be replaced by one with larger rating?
Answer:
Fuse is used for protecting appliances due to short-circuiting or overloading. The fuse is rated for a certain maximum current and blows off when a current more than the rated value flows through it. If a fuse is replaced by one with larger ratings, the appliances may get damaged while the protecting fuse does not burn off. This practice of using fuse of improper rating should always be avoided.

Chapter 13 Science Class 10 Extra Questions Question 8.
On which factors does the magnetic field produced by a current carrying conductor at a given point depend?
Answer:
The magnetic field produced by a given current decreases as the distance from it increases.
The magnitude of the magnetic field produced at a given point increases as the current through the wire increases.

Extra Questions Of Magnetic Effect Of Electric Current Class 10 Question 9.
What is electric generator? Write down its principle of working.
Answer:
Electric Generator: A generator converts mechanical energy into electrical energy.
Principle: It works on the basis of electromagnetic induction. AC generator produces AC current and DC generator produces DC current.

Extra Questions On Magnetic Effect Of Electric Current Question 10.
What is difference between AC and DC? Write down advantage of AC over DC?
Answer:
The difference between the direct and alternating currents is that the direct current always flows in one direction, whereas the alternating current reverses its direction periodically.

In India, the AC changes direction after every 1/100 second, that is, the frequency of AC is 50 Hz. An important advantage of AC over DC is that electric power can be transmitted over long distances without much loss of energy.

Class 10 Chapter 13 Science Extra Questions Question 11.
With the help of a labelled circuit diagram illustrate the pattern of field lines of the magnetic field around a current carrying straight long conducting wire. How is the right hand thumb rule useful to find direction of magnetic field associated with a current carrying conductor?
Answer:
Right hand thumb rule states that if a current carrying straight conductor is held in the right hand with the thumb pointing towards the direction of current, then the fingers will wrap around the conductor in the direction of the field lines of the magnetic field.
Extra Questions Of Magnetic Effect Of Electric Current

Extra Question Of Magnetic Effect Of Electric Current Question 12.
Describe the activity that shows that a current-carrying conductor experiences a force perpendicular to its length and the external magnetic field. How does Fleming’s left-hand rule help us to find the direction of the force acting on the current carrying conductor?
Answer:

  • Take a small aluminium rod AB (of about 5 cm). Using two connecting wires, suspend it horizontally from a stand.
  • Place a strong horse-shoe magnet in such a way that the rod lies between the two poles with the magnetic field directed upwards. For this put the north pole of the magnet vertically below and south pole vertically above the aluminium rod.
  • Connect the aluminium rod in series with a battery, a key and a rheostat.
  • Now pass a current through the aluminium rod from end B to end A.
  • It is observed that the rod is displaced towards the left. You will notice that the rod gets displaced.
  • Reverse the direction of current flowing through the rod and observe the direction of its displacement. It is now towards the right.

The displacement of the rod in the above activity suggests that a force is exerted on the current-carrying aluminium rod when it is placed in a magnetic field. According to Fleming’s left hand rule stretch the thumb, forefinger and central finger of your left hand such that they are mutually perpendicular.

If the forefinger points in the direction of magnetic field and the central in the direction of current, then the thumb will point in the direction of motion or force acting on the conductor.
Magnetic Effects Of Electric Current Class 10 Extra Questions

Extra Questions for Class 10 Science Chapter 13 Long Answer Type

Class 10 Science Ch 13 Extra Questions Question 1.
Write down a short note on magnetic field produced by a solenoid.
Answer:
Magnetic field due to a solenoid
Solenoid: A coil of many circular turns of insulated copper wire wrapped closely in the shape of a cylinder is called a solenoid.

  • The pattern of the magnetic field around a current carrying solenoid is same as that of a bar magnet. One end of the solenoid behaves as a magnetic North pole, while the other behaves as a South pole.
  • The field lines inside the solenoid are in the form of parallel straight lines.
  • The field is uniform inside the solenoid.
  • A strong magnetic field produced inside a solenoid can be used to magnetise a piece of magnetic material, like soft iron, when placed inside the coil. The magnet so formed is called an electromagnet.

Class 10 Science Chapter 13 Extra Questions
Field lines of the magnetic field through and around a current carrying solenoid
Magnetic Effects Of Electric Current Extra Questions
A current-carrying solenoid coil is used to magnetise steel rod inside it-an electromagnet

Extra Questions On Magnetic Effects Of Electric Current Class 10 Question 2.
Describe the magnetic field produced due to current-carrying circular loop.
Magnetic field due to current-carrying circular loop
Answer:

  • At the centre of the current carrying loop the magnetic field appears to be a straight line.
  • The magnetic field produced by a current carrying wire at a given point depends directly on current passing through it.

Class 10 Magnetic Effect Of Electric Current Extra Questions
Magnetic field lines of the field produced by a current-carrying circular loop

Question 3.
Define electromagnetic induction. Explain the ways by which magnetic field linked through a coil can be changed.
Answer:
Electromagnetic Induction: The phenomenon of electromagnetic induction is the production of induced current in a coil placed in a region where the magnetic field changes with time.

1. The magnetic field may change due to relative motion between the coil and the magnet.
Ch 13 Science Class 10 Extra Questions
Moving a magnet towards a coil sets up a current in the coil circuit, as indicated by deflection in the galvanometer needle

2. If the coil is placed near a current carrying conductor, the magnetic field may change either due to change in the current through the conductor or due to the relative motion between the coil and the conductor.
Magnetic Effect Of Electric Current Class 10 Extra Questions
current is included in coil – 2 when current in coil – 1 changed

Question 4.
Define magnetic field and magnetic field lines. Write down the properties of magnetic field lines.
Answer:
Magnetic field:
The region surrounding a magnet, in which the force of the magnet can be detected, is said to have a magnetic field.

Magnetic field lines:
Magnetic field lines are the imaginary lines drawn in a magnetic field along which a north magnetic pole would move.

Properties of magnetic field line:

  • Magnetic field lines are closed curves.
  • The relative strength of the magnetic field is shown by degree of closeness of the field lines.
  • No two field lines can cross each other as at the point of intersection the compass needle would point towards two directions, which is not possible.

Extra Questions Of Chapter 13 Class 10 Science

Magnetic Effects of Electric Current HOTS Questions With Answers

Question 1.
AB is a current carrying conductor in the plane of the paper as shown in the Figure. What are the directions of magnetic fields produced by it at points P and Q? Given r1 > r2, where will the strength of the magnetic field be larger?
Answer:
Into the plane of paper at P and out of it at Q. The strength of the magnetic field is larger at the point located closer i.e., at Q.
Class 10 Magnetic Effects Of Electric Current Extra Questions

Question 2.
Under what conditions permanent electromagnet is obtained if a current carrying solenoid is used? Support your answer with the help of a labelled circuit diagram.  [NCERT Exemplar]
Answer:

  1. The current through the solenoid should be direct current.
  2. The rod inside is made of a magnetic material such as steel.

Chapter 13 Science Class 10 Extra Questions

Question 3.
A magnetic compass shows a deflection when placed near a current carrying wire. How will the deflection of the compass get affected if the current in the wire is increased? Support your answer with a reason.
Answer:
The deflection increases. The strength of magnetic field is directly proportional to the magnitude of current passing through the straight conductor.

Question 4.
It is established that an electric current through a metallic conductor produces a magnetic field around it. Is there a similar magnetic field produced around a thin beam of moving (i) alpha particles, (ii) neutrons? Justify your answer.
Answer:
(i) Yes, Alpha particles being positively charged constitute a current in the direction of motion.
(ii) No, the neutrons being electrically neutral does not constitute any current.

Question 5.
Why does a magnetic compass needle pointing North and South in the absence of a nearby magnet get deflected when a bar magnet or a current carrying loop is brought near it. Describe some salient features of magnetic lines of field concept.
Answer:
Current carrying loops behave like bar magnets and both have their associated lines of field. This modifies the already existing earth’s magnetic field and a deflection results. Magnetic field has both direction and magnitude. Magnetic field lines emerge from N – pole and enter S – pole. The magnetic field strength is represented diagrammatically by the degree of closeness of the field lines.

Field lines cannot cross each other as two values of net field at a single point cannot exist. Only one value, a unique net value, can exist. If in a given region, lines of field are shown to be parallel and equispaced, the field is understood to be uniform.

Extra Questions for Class 10 Science Chapter 13 Value Based Questions

Question 1.
Ravi took his grandma for MRI test. His younger sister asked some questions and Ravi answered?
(i) What is basic concept behind MRI?
(ii) Write down values shown by Ravi.
Answer:
(i) MRI or Magnetic Resonance Imaging is based on magnetic effect of electric current.
(ii) Ravi is a knowledgeble and caring too.