RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1G

RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1G

These Solutions are part of RS Aggarwal Solutions Class 6. Here we have given RS Aggarwal Solutions Class 6 Chapter 1 Number System Ex 1G

Other Exercises

Question 1.
Solution:
(i) 2 = II
(ii) 8 = VIII
(iii) 14 = XIV
(iv) 29 = XXIX
(v) 36= XXXVI
(vi) 43 = XLIII
(vii) 54 = LIV
(viii) 61 = LXI
(ix) 73 = LXXIII
(x) 81 = LXXXI
(xi) 91 = XCI
(xii) 95 XCV
(xiii) 99= XCIX
(xiv) 105 CV
(xv) 114 = CXIV

Question 2.
Solution:
(i) 164 = CLXIV
(ii) 195 = CXCV
(iii) 226 = CCXXVI
(iv) 341 = CCCXLI
(v) 475 = CDLXXV
(vi) 596 = DXCVI
(vii) 611 = DCXI
(viii) 759 = DCCLIX

Question 3.
Solution:
(i) XXVII = 27
(ii) XXXIV = 34
(iii) XLV = 45
(iv) LIV = 54
(v) LXXIV = 74
(vi) XCI = 91
(vii) XCVI = 96
(viii) CXI = 111
(ix) CLIV = 154
(x) CCXXIV = 224
(xi) CCCLXV = 365
(xii) CDXIV = 414
(xiii) CDLXIV = 464
(xiv) DVI = 506
(xv) DCCLXVI = 766

Question 4.
Solution:
(i) V is never subtracted
∴ VC is wrong
(ii) I can be subtracted from V and X only
∴ IL is wrong
(iii) V, L, D are never repeated
∴ VVII is wrong
(iv) IX cannot occur to the left of X
∴ IXX is wrong

Hope given RS Aggarwal Solutions Class 6 Chapter 1 Number System Ex 1G are helpful to complete your math homework.

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RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1F

RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1F

These Solutions are part of RS Aggarwal Solutions Class 6. Here we have given RS Aggarwal Solutions Class 6 Chapter 1 Number System Ex 1F

Other Exercises

Find the estimated quotient for each of the following :

Question 1.
Solution:
87 ÷ 28
87 is estimated to the nearest ten = 90
28 is estimated to the nearest ten = 30
∴ 90 ÷ 30
= 3 Ans.

Question 2.
Solution:
83 ÷ 17
83 is estimated to the nearest ten = 80
17 is estimated to the nearest ten = 20
∴ 80 ÷ 20
= 4 Ans.

Question 3.
Solution:
75 ÷ 23
75 is estimated to the nearest ten = 80
23 is estimated to the nearest ten = 20
∴ 80 ÷ 20
= 4 Ans.

Question 4.
Solution:
193 ÷ 24
193 is estimated to the nearest ten = 200
24 is estimated to the nearest ten = 20
∴ 200 ÷ 20
= 10 Ans.

Question 5.
Solution:
725 ÷ 23
725 is estimated to the nearest hundred = 700
23 is estimated to the nearest ten = 20
∴700 ÷ 20
= 35 Ans.

Question 6.
Solution:
275 ÷ 25
275 is estimated to the nearest hundred = 300
25 is estimated to the nearest ten = 30
∴ 300 ÷ 30
= 10 Ans.

Question 7.
Solution:
633 ÷ 33
633 is estimated to the nearest hundred = 600
33 is estimated to the nearest ten = 30
∴ 600 ÷ 30
= 20 Ans.

Question 8.
Solution:
729 ÷ 29
729 is estimated to the nearest hundred = 700
29 is estimated to the nearest ten = 30
∴ 700 ÷ 30
= 70 ÷ 3
= 23 (approximately) Ans.

Question 9.
Solution:
858 ÷ 39
858 is estimated to the nearest hundred = 900
39 is estimated to the nearest ten = 40
∴ 900 ÷ 40
= 90 ÷ 4
= 23 (approximately) Ans

Question 10.
Solution:
868 ÷ 38
868 is estimated to the nearest hundred = 900
38 is estimated to the nearest ten = 40
∴ 900 ÷ 40
= 90 ÷ 4
= 23 (approximately) Ans.

Hope given RS Aggarwal Solutions Class 6 Chapter 1 Number System Ex 1F are helpful to complete your math homework.

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RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1E

RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1E

These Solutions are part of RS Aggarwal Solutions Class 6. Here we have given RS Aggarwal Solutions Class 6 Chapter 1 Number System Ex 1E

Other Exercises

Estimate each of the following products by rounding off each number to the nearest ten.

Question 1.
Solution:
(38 x 63)
38 estimated to the nearest ten = 40
63 estimated to the nearest ten = 60
∴ 40 x 60
= 2400 Ans.

Question 2.
Solution:
(54 x 47)
54 estimated to the nearest ten = 50
47 estimated to the nearest ten = 50
∴ 50 x 50
= 2500 Ans.

Question 3.
Solution:
(28 x 63)
28 estimated to the nearest ten = 30
63 estimated to the nearest ten = 60
∴ 30 x 60
= 1800 Ans.

Question 4.
Solution:
(42 x 75)
42 estimated to the nearest ten = 40
75 estimated to the nearest ten = 80
∴ 40 x 80
= 3200 Ans.

Question 5.
Solution:
(64 x 58)
64 estimated to the nearest ten = 60
58 estimated to the nearest ten = 60
∴ 60 x 60
= 3600 Ans.

Question 6.
Solution:
(15 x 34)
15 estimated to the nearest ten = 20
34 estimated to the nearest ten = 30
∴ 20 x 30
= 600 Ans.

Estimate each of the following products by rounding off each number to the nearest hundred :

Question 7.
Solution:
(376 x 123)
376 estimated to the nearest hundred = 400
123 estimated to the nearest hundred = 100
∴ 400 x 100
= 40000 Ans.

Question 8.
Solution:
(264 x 147)
264 estimated to the nearest hundred = 300
147 estimated to the nearest hundred = 100
∴ 300 x 100
= 30000 Ans.

Question 9.
Solution:
423 x 158)
423 estimated to the nearest hundred = 400
158 estimated to the nearest hundred = 200
∴ 400 x 200
= 80000 Ans.

Question 10.
Solution:
(509 x 179)
509 estimated to the nearest hundred = 500
179 estimated to the nearest hundred = 200
∴ 500 x 200
= 100000 Ans.

Question 11.
Solution:
(392 x 138)
392 estimated to the nearest hundred = 400
138 estimated to the nearest hundred = 100
∴ 400 x 100
= 40000 Ans.

Question 12.
Solution:
(271 x 339)
271 estimated to the nearest hundred = 300
339 estimated to the nearest hundred = 300
∴ 300 x 300
= 90000 Ans.

Estimate each of the following products by rounding off the first number upwards and the second number downwards:

Question 13.
Solution:
(183 x 154)
183 is rounded off upwards = 200
154 is rounded off downwards = 100
∴ 200 x 100
= 20000 Ans.

Question 14.
Solution:
(267 x 146)
267 is rounded off upwards = 300
146 is rounded off downwards = 100
∴ 300 x 100
= 30000 Ans.

Question 15.
Solution:
(359 x 76)
359 is rounded off upwards = 400
76 is rounded off downwards = 70
∴ 400 x 70
= 28000 Ans.

Question 16.
Solution:
(472 x 158)
472 is rounded off upwards = 500
158 is rounded off downwards = 100
∴ 500 x 100
= 50000 Ans.

Question 17.
Solution:
(680 x 164)
680 is rounded off upwards = 700
164 is rounded off downwards = 100
∴ 700 x 100
= 70000 Ans.

Question 18.
Solution:
(255 x 350)
255 is rounded off upwards = 300
350 is rounded off downwards = 300
∴ 300 x 300
= 90000 Ans.

Estimate each of the following products by rounding off the first number downwards and the second number upwards:

Question 19.
Solution:
(356 x 278)
356 is rounded off downwards = 300
278 is rounded off upwards = 300
∴ 300 x 300
= 90000 Ans.

Question 20.
Solution:
(472 x 76)
472 is rounded off downwards = 400
76 is rounded off upwards = 80
∴ 400 x 80
= 32000 Ans.

Question 21.
Solution:
(578 x 369)
578 is rounded off downwards = 500
369 is rounded off upwards = 400
∴ 500 x 400
= 200000 Ans.

Hope given RS Aggarwal Solutions Class 6 Chapter 1 Number System Ex 1E are helpful to complete your math homework.

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RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1D

RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1D

These Solutions are part of RS Aggarwal Solutions Class 6. Here we have given RS Aggarwal Solutions Class 6 Chapter 1 Number System Ex 1D

Other Exercises

Question 1.
Solution:
(a) 40
(b) 170
(c) 3870
(d) 16380

Question 2.
Solution:
(a) 800
(b) 1300
(c) 43100
(d) 98200

Question 3.
Solution:
(a) 1000
(b) 5000
(c) 17000
(d) 28000

Question 4.
Solution:
(a) 20000
(b) 30000
(c) 30000
(d) 270000

Estimate each sum to the nearest ten :

Question 5.
Solution:
(57 + 34)
57 estimated to the nearest ten = 60
34 estimated to the nearest ten = 30
Required sum = 60 + 30
= 90 Ans.

Question 6.
Solution:
(43 + 78)
43 estimated to the nearest ten = 40
78 estimated to the nearest ten = 80
Required sum = 40 + 80
= 120 Ans.

Question 7.
Solution:
(14 + 69)
14 estimated to the nearest ten = 10
69 estimated to the nearest ten = 70
Required sum = 10 + 70
= 80 Ans.

Question 8.
Solution:
(86 +19)
86 estimated to the nearest ten = 90
19 estimated to the nearest ten = 20
Required sum = 90 + 20
= 110 Ans.

Question 9.
Solution:
(95 + 58)
95 estimated to the nearest ten =100
58 estimated to the nearest ten = 60
Required sum = 100 + 60
= 160 Ans

Question 10.
Solution:
77 estimated to the nearest ten = 80
63 estimated to the nearest ten = 60
Required sum = 80 + 60
= 140 Ans.

Question 11.
Solution:
(356 + 275)
356 estimated to the nearest ten = 360
275 estimated to the nearest ten = 280
Required sum = 360 + 280
= 640 Ans.

Question 12.
Solution:
463 + 182
463 estimated to the nearest ten = 460
182 estimated to the nearest ten = 180
Required sum = 460 + 180
= 640 Ans.

Question 13.
Solution:
(538 + 276)
538 estimated to the nearest ten = 540
276 estimated to the nearest ten = 280
Required sum = 540 + 280
= 820 Ans.

Estimate each sum to the nearest hundred:

Question 14.
Solution:
(236 + 689)
236 estimated to the nearest hundred = 200
689 estimated to the nearest hundred = 700
Required sum = 200 + 700
= 900 Ans.

Question 15.
Solution:
(458 + 324)
458 estimated.to the nearest hundred = 500
324 estimated to the nearest hundred = 300
Required sum = 500 + 300
= 800 Ans.

Question 16.
Solution:
(170 + 395)
170 estimated to the nearest hundred = 200
395 estimated to the nearest hundred = 400
Required sum = 200 + 400
= 600 Ans.

Question 17.
Solution:
(3280 + 4395)
3280 estimated to the nearest hundred = 3300
4395 estimated to the nearest hundred = 4400
Required sum = 3300 + 4400
= 7700 Ans.

Question 18.
Solution:
(5130 + 1410)
5130 estimated to the nearest hundred = 5100
1410 estimated to the nearest hundred = 1400
Required sum = 5100 + 1400
= 6500 Ans.

Question 19.
Solution:
(10083 + 29380)
10083 estimated to the nearest hundred =10100
29380 estimated to the nearest hundred = 29400
Required sum = 10100 + 29400
= 39500 Ans.

Estimate each sum to the nearest thousand :

Question 20.
Solution:
(32836 + 16466)
32836 estimated to the nearest thousand = 33000
16466 estimated to the nearest thousand = 16000
Required sum = 33000 + 16000
= 49000 Ans.

Question 21.
Solution:
(46703 + 11375)
46703 estimated to the nearest thousand = 47000
11375 estimated to the nearest thousand = 11000
Required sum = 47000 + 11000
= 58000 Ans.

Question 22.
Solution:
54 balls + 79 balls
54 balls estimated to the nearest 10 = 50
79 balls estimated to the nearest 10 = 80
Required total number of balls = 50 + 80 + 130 Ans.

Estimate each difference to the nearest ten :

Question 23.
Solution:
(53 – 18)
53 estimated to the nearest ten = 50
18 estimated to the nearest ten = 20
Difference of 50 and 20
= 50 – 20
= 30 Ans.

Question 24.
Solution:
(97 – 38)
97 estimated to the nearest ten =100
38 estimated to the nearest ten = 40
Difference of 100 and 40
= 100 – 40
= 60 Ans.

Question 25.
Solution:
(409 – 148)
409 estimated to the nearest ten = 410
148 estimated to the nearest ten = 150
Difference of 410 and 150
= 410 – 150
= 260 Ans.

Estimate each difference to the nearest hundred :

Question 26.
Solution:
(678 – 215)
678 estimated to the nearest hundred = 700
215 estimated to the nearest hundred = 200
Difference between 700 and 200
= 700 – 200
= 500 Ans.

Question 27.
Solution:
(957 – 578)
957 estimated to the nearest hundred = 1000
578 estimated to the nearest hundred = 600
Difference between 1000 and 600
= 1000 – 600
= 400 Ans.

Question 28.
Solution:
(7258 – 2429)
7258 estimated to the nearest hundred = 7300
2429 estimated to the nearest hundred = 2400
Difference between 7300 and 2400
= 7300 – 2400
= 4900 Ans.

Question 29.
Solution:
5612 estimated to the nearest hundred = 5600
3095 estimated to the nearest hundred = 3100
Difference between 5600 and 3100
= 5600 – 3100
= 2500 Ans.

Estimate each difference to the nearest thousand :

Question 30.
Solution:
35863 estimated to the nearest thousand = 36000
27677 estimated to the nearest thousand = 28000
Difference between 36000 and 28000
= 36000 – 28000
= 8000 Ans.

Question 31.
Solution:
(47005 – 39488)
47005 estimated to the nearest thousand = 47000
39488 estimated to the nearest thousand = 39000
Difference between 47000 and 39000
= 47000 – 39000
= 8000 Ans.

Hope given RS Aggarwal Solutions Class 6 Chapter 1 Number System Ex 1D are helpful to complete your math homework.

If you have any doubts, please comment below. Learn Insta try to provide online math tutoring for you.

RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1C

RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1C

These Solutions are part of RS Aggarwal Solutions Class 6. Here we have given RS Aggarwal Solutions Class 6 Chapter 1 Number System Ex 1C

Other Exercises

Question 1.
Solution:
Number of persons in the first year = 13789509
Number of persons in the second year = 12976498
Total number of persons in the two years =13789509 +12976498
= 26766007 Ans.
RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1C 1.1

Question 2.
Solution:
Number of sugar bags in the first factory = 24809565
Number of sugar bags in the second factory = 18738576
Number of sugar bags in the third factory = 9564568
Total number of sugar bags in the three factories
= 24809565 + 18738576 + 9564568
= 53112709 bags Ans.
RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1C 2.1

Question 3.
Solution:
The given number = 37684955
The number which exceeds the given number by 3615045 will be
= 37684955 + 3615045
= 41300000 Ans.
RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1C 3.1

Question 4.
Solution:
Number of votes received by the first candidate = 687905
Number of votes received by the second candidate = 495086
Number of votes received by the third candidate = 93756
Number of invalid votes = 13849
Number of persons who did not vote = 25467
Total number of registered votes = 687905 + 495086 + 93756 + 13849 + 25467
= 1316063 Ans.
RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1C 4.1

Question 5.
Solution:
Number of people who got primary education = 1623546
Number of people who got secondary education = 9768678
Number of people who got higher education = 6837954
Number of illiterate people = 2684536
Number of children below the age of admission = 698781
Total population of the state = 1623546 + 9768678 + 6837954 + 2684536 + 698781
= 21613495 Ans.
RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1C 5.1

Question 6.
Solution:
In the first year, number of cycles produced = 8765435
In the second year, number of cycles produced = 8765435 + 1378689
= 10144124
The number of bicycles produced in the two years = 8765435 + 10144124
= 18909559 Ans.
RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1C 6.1

Question 7.
Solution:
Sale receipt during first year = Rs. 20956480
Sale receipt during the second year = Rs. 20956480 + Rs. 6709570
= Rs. 27666050
Total sale receipt during the two years = Rs. 20956480 + Rs.27666050
= Rs. 48622530 Ans
RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1C 7.1

Question 8.
Solution:
Total population of a city = 28756304
Number of males = 16987059
Number of females = 28756304 – 16987059
= 11769245 Ans.
RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1C 8.1

Question 9.
Solution:
The number 13246510 is larger than 4658642
= 13246510 – 4658642
= 8587868 Ans.
RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1C 9.1

Question 10.
Solution:
5643879 is smaller than one crore
= 10000000 – 5643879
= 4356121 Ans.
RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1C 10.1

Question 11.
Solution:
To, get the required number, we should subtract 2635967 from 11010101
= 11010101 – 2635967
= 8374134 Ans.
RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1C 11.1

Question 12.
Solution:
Sum of two numbers = 10750308
First number = 8967519
Second number = 10750308 – 8967519
= 1782789 Ans.
RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1C 12.1

Question 13.
Solution:
Total money, a man had = Rs 20000000
Amount spent on buying a school building = Rs. 13607085
Amount left with him
= Rs. 20000000 – Rs. 13607085
= Rs. 6392915 Ans.
RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1C 13.1

Question 14.
Solution:
The total requirement of a society = Rs. 18536000
Amount of fee collection = Rs. 7253840
Amount of loan taken = Rs. 5675450
Amount of donation = Rs. 2937680
Total amount collected = Rs. 7253840 + Rs. 5675450 + Rs. 2937680
= Rs. 15866970
Short amount
= Rs. 18536000 – Rs. 15866970
= Rs. 2669030 Ans.
RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1C 14.1

Question 15.
Solution:
Total amount a man had = Rs. 10672540
Amount given to his wife = Rs. 4836980
Amount given to his son = Rs 3964790
Total amount given to wife and son = Rs. 4836980 + Rs 3964790
= Rs. 8801770
RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1C 15.1
Balance amount given to his daughter
= Rs. 10672540 – Rs. 8801770
= Rs. 1870770 Ans.
RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1C 15.2

Question 16.
Solution:
Cost of one chair = Rs. 1485
Cost of 469 chairs = Rs. 1485 x 469
= Rs. 696465 Ans.
RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1C 16.1

Question 17.
Solution:
Collection from one student = Rs. 625
Collection from 1786 students = Rs. 1786 x 625
= Rs. 1116250 Ans.
RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1C 17.1

Question 18.
Solution:
Number of screws produced in one day = 6985
Number of screws produced in 358 days = 6985 x 358
= 2500630 Ans.
RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1C 18.1

Question 19.
Solution:
Number of months in one year = 12
Number of months in 13, years = 12 x 13
= 156
months Saving in one month = Rs. 8756
Saving in 156 months = Rs. 8756 x 156
= Rs. 1365936 Ans.
RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1C 19.1

Question 20.
Solution:
Cost of 1 scooter = Rs. 36725
Cost of 487 scooters = Rs. 36725 x 487
= Rs. 17885075 Ans.
RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1C 20.1

Question 21.
Solution:
Distance covered in 1 hour = 1485 km
Distance covered in 72 hours = 1485 x 72 km
= 106920 km Ans.
RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1C 21.1

Question 22.
Solution:
Product of two numbers = 13421408
First number = 364
Second number = 13421408 ÷ 364
= 36872 Ans.
RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1C 22.1

Question 23.
Solution:
Cost of 36 flats = Rs. 68251500
Cost of one flat
= Rs. 68251500 ÷ 36
= Rs. 1895875 Ans.
RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1C 23.1

Question 24.
Solution:
Mass of cylinder with gas = 30 kg 250 g and mass of empty cylinder = 14 kg 480 g
Mass of gas = 30 kg, 250 g – 14 kg, 480 g
= 15 kg, 770 g Ans.
RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1C 24.1

Question 25.
Solution:
Total length of cloth = 5 m
Length of piece cut off = 2 m 85 cm
Length of remaining piece of cloth = 5 m – 2 m 85 cm
= 2 m 15 cm Ans.
RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1C 25.1

Question 26.
Solution:
Cloth required for 1 shirt = 2 m 75 cm
Cloth required for 16 shirts = 2 m 75 cm x 16
= 44 m Ans.

Question 27.
Solution:
Total length of cloth for 8 trousers = 14 m 80 cm
Length of cloth for 1 trouser = 14 m 80 cm ÷ 8
= 1 m 85 cm Ans.
RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1C 27.1

Question 28.
Solution:
Mass of 1 brick = 2 kg 750 g
Total mass of 14 bricks = 2 kg 750 g x 14
= 38 kg 500 g Ans.
RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1C 28.1

Question 29.
Solution:
Total mass of 8 packets = 10 kg 600 g
Mass of one packet = 10 kg 600 ÷ 8
= 1 kg 325 g Ans.
RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1C 29.1

Question 30.
Solution:
Total length of rope = 10 m
No of pieces = 8
Length of each piece = 10 m ÷ 8
= 1 m 25 cm Ans.
RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1C 30.1

Hope given RS Aggarwal Solutions Class 6 Chapter 1 Number System Ex 1C are helpful to complete your math homework.

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RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1B

RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1B

These Solutions are part of RS Aggarwal Solutions Class 6. Here we have given RS Aggarwal Solutions Class 6 Chapter 1 Number System Ex 1B.

Other Exercises

Fill in each of the following boxes with the correct symbol > or < :

Question 1.
Solution:
RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1B 1.1

Question 2.
Solution:
RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1B 2.1

Question 3.
Solution:
RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1B 3.1

Question 4.
Solution:
RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1B 4.1

Question 5.
Solution:
RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1B 5.1

Question 6.
Solution:
RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1B 6.1

Arrange the following numbers in the descending order :

Question 7.
Solution:
102345680 > 63521047 > 63514759 > 7355014 > 7354206

Question 8.
Solution:
23794206 > 23756819 > 5032790 > 5032786 > 987876

Question 9.
Solution:
16060666 > 16007777 > 1808090 > 1808088 > 190909 > 181888

Question 10.
Solution:
1712040 > 1704382 > 1702497 > 201200 > 200175 > 199988.

Arrange the following numbers in the ascending order

Question 11.
Solution:
990357 < 9873426 < 9874012 < 24615019 < 24620010

Question 12.
Solution:
5694437 < 5695440 < 56943201 < 56943300 < 56944000

Question 13.
Solution:
700087 < 8014257 < 8014306 < 8015032 < 10012458

Question 14.
Solution:
893245 < 893425 < 980134 < 1020216 < 1020304 < 1021403

Hope given RS Aggarwal Solutions Class 6 Chapter 1 Number System Ex 1B are helpful to complete your math homework.

If you have any doubts, please comment below. Learn Insta try to provide online math tutoring for you.

RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1A

RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1A

These Solutions are part of RS Aggarwal Solutions Class 6. Here we have given RS Aggarwal Solutions Class 6 Chapter 1 Number System Ex 1A

Other Exercises

Question 1.
Solution:
(i) Nine thousand eighteen = 9,018.
(ii) Fifty four thousand seventy three = 54,073
(iii) Three lakh two thousand five hundred six = 3,02,506.
(iv) Twenty lakh ten thousand eight = 20,10,008.
(v) Six crore five lakh fifty-seven = 6,05,00,057.
(vi) Two crore two lakh two thousand two hundred two = 2,02,02,202.
(vii) Twelve crore twelve lakh twelve thousand twelve = 12,12,12,012.
(viii) Fifteen crore fifty lakh twenty thousand sixty-eight = 15,50,20,068.

Question 2.
Solution:
(i) 63,005 = Sixty three thousand five.
(ii)7,07,075 = Seven lakh, seven thousand seventy five.
(iii) 34,20,019 = Thirty-four lakh twenty thousand nineteen.
(iv) 3,05,09,0.12 = Three crore, five lakh, nine thousand twelve.
(v) 5,10,03,604 = Five crore ten lakh three thousand six hundred four.
(vi) 6,18,05,008 = Six crore eighteen lakh five thousand eight.
(vii) 19,09,09,900 = Nineteen crore nine lakh, nine thousand nine hundred.
(viii) 6,15.30,807 = Six crore fifteen lakh, thirty thousand eight hundred seven.
(ix) 6,60,60,060 = Six crore sixty lakh sixty thousand sixty. Ans.

Question 3.
Solution:
(i) 15,768 = (1 x 10000) + (5 x 1000) + (7 x 100) + (6 x 10) + (8 x 1)
(ii) 3,08,927 = (3 x 100000) + (8 x 1000) + (9 x 100) +(2 x 10) +(7 x 1)
(iii) 24,05,609 = (2 x 1000000) + (4 x 100000) + (5 x 1000) + (6 x 100) + (9 x 1)
(iv) 5,36,18,493 = (5 x 10000000) + (3 x 1000000) + (6 x 100000) + (1 x 10000) + (8 x 1000) + (4 x 100) + (9 x 10) + (3 x 1)
(v) 6,06,06,006 = (6 x 10000000) + (6 x 100000) + (6 x 1000) + (6 x 1)
(vi) 9,10,10,510 = (9 x 10000000) + (1 x 1000000) + (1 x 10000) + (5 x 100) + (1 x 10) Ans,

Question 4.
Solution:
(i) 6 x 10000 + 2 x 1000 + 5 x 100 + 8 x 10 + 4 x 1
= 60000 + 2000 + 500 + 80 + 4
= 62,584.
(ii) 5 x 100000 + 8 x 10000 + 1 x 1000 + 6 x 100 + 2 x 10 + 3 x 1
= 500000 + 80000 + 1000 + 600 + 20 + 3
= 5,81,623
(iii) 2 x 10000000 + 5 x 100000 + 7 x 1000 + 9 x 100 + 5 x 1
= 20000000 + 500000 + 7000 + 900 + 5
= 2,05,07,905
(iv) 3 x 1000000 + 4 x 100000 + 6 x 1000 + 5 x 100 + 7 x 1
= 3000000 + 400000 + 6000 + 500 + 7
= 34,06,507 Ans.

Question 5.
Solution:
In 79520986
Value of first 9 = 9000000
and value of second 9 = 900
Difference = 9000000 – 900
= 89,99,100 Ans.

Question 6.
Solution:
In 27650934
place value of 7 = 7000000
and face value of 7 = 7
Difference = 7000000 – 7
= 6999993 Ans.

Question 7.
Solution:
There are 900000 6-digits numbers in all
i.e. 999999 – 99999
= 900000 Ans

Question 8.
Solution:
There are 9999999 – 999999
= 9000000 7-digits numbers in all.

Question 9.
Solution:
In 1,00,000, there are 100 thousands. Ans.

Question 10.
Solution:
In 10000,000, there are 10000 thousands.

Question 11.
Solution:
Given Number = 738
Reversing its digits = 837
Difference between 738 and 837
= 837 – 738
= 99 Ans.

Question 12.
Solution:
Numbers after 9547999
= 9547999 + 1
= 9548000 Ans.

Question 13.
Solution:
Number first before 9900000
= 9900000 – 1
= 9899999 Ans.

Question 14.
Solution:
Number first before 10000000
= 10000000 – 1
= 9999999 Ans.

Question 15.
Solution:
3-digits numbers using 2, 3, 4 taking each digit only once will be
234, 243, 324, 342, 423, 432 Ans.

Question 16.
Solution:
The smallest number by using different digits 3, 1, 0, 5 and 7 will be
= 10357 Ans.

Question 17.
Solution:
The largest number formed by using different digits 2, 4, 0, 3, 6 and 9 will be
= 964320. Ans.

Question 18.
Solution:
RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1A 18.1
(i) Seven hundred thirty five thousand eight hundred twenty-one.
(ii) Six million fifty seven thousand eight hundred ninety-four.
(iii) Fifty-six million nine hundred forty-three thousand eight hundred twenty-one.
(iv) Thirty-seven million five hundred two thousand ninety-three.
(v) Eighty-nine million three hundred fifty thousand sixty-four.
(vi) Ninety million seven hundred three thousand and six. Ans.

Question 19.
Solution:
RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1A 19.1

OBJECTIVE QUESTIONS
Tick the correct answer in each of the following :

Question 20.
Solution:
(c) Because 6 is at lakh place.

Question 21.
Solution:
(a) Because face value is always same.

Question 22.
Solution:
(b) Because place value and face value of 5 in 87653421 are 50000 and 5.
difference
= 50000 – 5
= 49995.

Question 23.
Solution:
(b) Smallest counting number or natural number is 1.

Question 24.
Solution:
(b) Number of 4-digits numbers
= 9999 – 999 (i.e. these are 1000 to 9999)
= 9000

Question 25.
Solution:
(b) Number of 7-digit numbers (from 1000000 to 9999999)
= 9999999 – 999999
= 9000000

Question 26.
Solution:
(c) Numbers of 8-digit numbers (from 10000000 to 99999999)
= 99999999 – 9999999
= 90000000

Question 27.
Solution:
(b) Because 1000000 – 1
= 999999 Ans.

Hope given RS Aggarwal Solutions Class 6 Chapter 1 Number System Ex 1A are helpful to complete your math homework.

If you have any doubts, please comment below. Learn Insta try to provide online math tutoring for you.

RS Aggarwal Class 6 Solutions Chapter 2 Factors and Multiples Ex 2C

RS Aggarwal Class 6 Solutions Chapter 2 Factors and Multiples Ex 2C

These Solutions are part of RS Aggarwal Solutions Class 6. Here we have given RS Aggarwal Solutions Class 6 Chapter 2 Factors and Multiples Ex 2C.

Other Exercises

Give the prime factorization of each of the following numbers.

Question 1.
Solution:
We have
RS Aggarwal Class 6 Solutions Chapter 2 Factors and Multiples Ex 2C 1.1
∴12 = 2 x 2 x 3 = 22 x 3.

Question 2.
Solution:
We have
RS Aggarwal Class 6 Solutions Chapter 2 Factors and Multiples Ex 2C 2.1
∴18 = 2 x 3 x 3 = 2 x 32

Question 3.
Solution:
We have
RS Aggarwal Class 6 Solutions Chapter 2 Factors and Multiples Ex 2C 3.1
∴ 48 = 2 x 2 x 2 x 2 x 3
= 24 x 3.

Question 4.
Solution:
We have
RS Aggarwal Class 6 Solutions Chapter 2 Factors and Multiples Ex 2C 4.1
∴ 56 = 2 x 2 x 2 x 7
= 23 x 7.

Question 5.
Solution:
We have
RS Aggarwal Class 6 Solutions Chapter 2 Factors and Multiples Ex 2C 5.1
∴ 90 = 2 x 3 x 3 x 5
= 2 x 32 x 5.

Question 6.
Solution:
We have
RS Aggarwal Class 6 Solutions Chapter 2 Factors and Multiples Ex 2C 6.1
136 = 2 x 2 x 2 x 17
= 23 x 17.

Question 7.
Solution:
We have
RS Aggarwal Class 6 Solutions Chapter 2 Factors and Multiples Ex 2C 7.1
∴ 252 = 2 x 2 x 3 x 3 x 7
= 22 x 32 x 7.

Question 8.
Solution:
We have
RS Aggarwal Class 6 Solutions Chapter 2 Factors and Multiples Ex 2C 8.1
∴ 420 = 2 x 2 x 3 x 5 x 7
= 22 x 3 x 5 x 7.

Question 9.
Solution:
We have
RS Aggarwal Class 6 Solutions Chapter 2 Factors and Multiples Ex 2C 9.1
∴ 637 = 7 x 7 x 13
= 72 x 13.

Question 10.
Solution:
We have
RS Aggarwal Class 6 Solutions Chapter 2 Factors and Multiples Ex 2C 10.1
∴ 945 = 3 x 3 x 3 x 5 x 7
= 33 x 5 x 7.

Question 11.
Solution:
We have
RS Aggarwal Class 6 Solutions Chapter 2 Factors and Multiples Ex 2C 11.1
∴ 1224 = 2 x 2 x 2 x 3 x 3 x 17
= 23 x 32 x 17.

Question 12.
Solution:
We have
RS Aggarwal Class 6 Solutions Chapter 2 Factors and Multiples Ex 2C 12.1
∴ 1323 = 3 x 3 x 3 x 7 x 7
= 33 x 72

Question 13.
Solution:
We have
RS Aggarwal Class 6 Solutions Chapter 2 Factors and Multiples Ex 2C 13.1
∴ 8712 = 2 x 2 x 2 x 3 x 3 x 11 x 11
= 23 x 32 x 112.

Question 14.
Solution:
We have
RS Aggarwal Class 6 Solutions Chapter 2 Factors and Multiples Ex 2C 14.1
∴9317 = 7 x 11 x 11 x 11
= 7 x 113

Question 15.
Solution:
We have
RS Aggarwal Class 6 Solutions Chapter 2 Factors and Multiples Ex 2C 15.1
∴ 1035 = 3 x 3 x 5 x 23
= 32 x 5 x 23

Question 16.
Solution:
We have
RS Aggarwal Class 6 Solutions Chapter 2 Factors and Multiples Ex 2C 16.1
∴ 1197 = 3 x 3 x 7 x 19
= 32 x 7 x 19

Question 17.
Solution:
We have
RS Aggarwal Class 6 Solutions Chapter 2 Factors and Multiples Ex 2C 17.1
∴ 4641 = 3 x 7 x 13 x 17.

Question 18.
Solution:
We have
RS Aggarwal Class 6 Solutions Chapter 2 Factors and Multiples Ex 2C 18.1
∴ 4335 = 3 x 5 x 17 x 17
= 3 x 5 x 172

Question 19.
Solution:
We have
RS Aggarwal Class 6 Solutions Chapter 2 Factors and Multiples Ex 2C 19.1
∴ 2907 = 3 x 3 x 17 x 19
= 32 x 17 x 19.

Question 20.
Solution:
We have
RS Aggarwal Class 6 Solutions Chapter 2 Factors and Multiples Ex 2C 20.1
∴ 13915 = 5 x 11 x 11 x 23 = 5 x 112 x 23

Hope given RS Aggarwal Solutions Class 6 Chapter 2 Factors and Multiples Ex 2C are helpful to complete your math homework.

If you have any doubts, please comment below. Learn Insta try to provide online math tutoring for you.

Class 6 Geography Chapter 4 Extra Questions and Answers Maps

Online Education for Class 6 Geography Chapter 4 Extra Questions and Answers Maps

Here we are providing Online Education for Class 6 Geography Chapter 4 Extra Questions and Answers Maps was designed by subject expert teachers. https://ncertmcq.com/extra-questions-for-class-6-social-science/

Online Education for Maps Class 6 Extra Questions Geography Chapter 4

Class 6 Geography Chapter 4 Extra Questions Question 1.
What are political maps?
Answer:
Maps showing different countries and states of the world with their boundaries are called political maps.

Maps Class 6 Extra Questions Question 2.
Who was the first to represent the earth as a sphere?
Answer:
An Egyptian geographer was the first who represented: the earth as a sphere.

Class 6 Geography Chapter 4 Worksheet Question 3.
How do we draw maps in present times?
Answer:
Nowadays, maps are drawn on computers. These maps are very accurate.

Ncert Class 6 Geography Chapter 4 Extra Questions Question 4.
What are the limitations of a globe?
Answer:
When we want to study only a part of the earth, or about the states, districts, towns or villages of our country, globes are of little help. They only help us to study about the earth as a whole.

Class 6 Geography Chapter 4 Extra Questions and Answers Maps

Class 6 Geography Chapter 4 Questions And Answers Question 5.
What are physical maps?
Answer:
Maps which show natural features of the earth, such as mountains, plateaus, plains, rivers and oceans, are called physical maps.

Class 6 Geography Chapter 4 Question 6.
What are the components of a map? Write about each of them.
Answer:
The three components of a map are distance, direction and symbol.

1.Distance: Maps are drawings which reduce the entire world or a part of it to fit on a sheet of paper. This reduction is done very carefully so that distances between the places are kept true. It is possible only when a small distance on the map represents a large distance on the ground.

Therefore that scale is chosen, which is a ratio between the actual distance on the ground and the distance shown on the map, eg. suppose the distance between your home and school is 10 km and on the map you show it as 2 cm. Therefore, the scale of your drawing will be 1 cm – 5 km.

2. Direction: Most maps contain an arrow marked with the letter ‘N at the upper right. It is called the north line and the arrow show’s the north direction. With the help of this line, we can find the other directions – south, east and west.

3. Symbols: We cannot draw the actual size and shape of different features like buildings, railway lines etc on the map, so they are shown with different symbols. The symbols give much information in a limited space. With the use of these symbols, maps can be easily drawn and are simple to read. The symbols can be read by all. Sometimes colours are used on the maps for the same pin-pose, e.g. blue colour represents water bodies.

Class 6 Geography Chapter 4 Extra Questions and Answers Maps

Multiple Choice Questions

1. Which one of the following statements is true about a map?
(а) It is a true model of the earth
(b) A map is used to show various features of the earth
(c) It is a representation of the earth’s surface or a part of it drawn on a flat surface with the help of a scale
(d) It is used to show a small area.
Answer:
(c) It is a representation of the earth’s surface or a part of it drawn on a flat surface with the help of a scale

2. Which one of the following is used to show the natural features (land, river, etc.) of the earth?
(a) Thematic map
(b) Physical -map
(c) Political map
(d) Road map
Answer:
(b) Physical -map

3. Cities, towns, etc. are shown on which one of the following maps?
(a) Political maps
(b) Weather maps
(c) Road maps
(d) City maps
Answer:
(a) Political maps

4. Which one of the following maps focuses on specific information?
(a) Physical map
(b) Political map
(c) Weather map
(d) Thematic map
Answer:
(d) Thematic map

Class 6 Geography Chapter 4 Extra Questions and Answers Maps

5. Which one of the following is different from the other three, with reference to the components of maps?
(a) Distance
(b) Title
(c) Direction
(d) Symbol
Answer:
(b) Title

6. Which one of the following terms is used for the ratio between the actual distance on the ground and the distance shown on the map?
(a) Direction
(b) Plan
(c) Scale
(d) Sketch
Answer:
(c) Scale

7. On which one of the following maps, the large areas like continents, etc. are shown with the help of a small scale?
(a) Small scale map
(b) Large scale map
(c) Globe
(d) Sketch
Answer:
(a) Small scale map

8. Which one of the following statements is true about the large scale map?
(а) It shows continents, countries, oceans, etc.
(b) It shows small areas (village or town) by using large scale
(c) It shows less information
(d) It is drawn on a small piece of paper
Answer:
(b) It shows small areas (village or town) by using large scale.

Important Definitions/ Words:

→ Map: It is a representation of the earth’s surface or a part of it on a flat surface.

→ Atlas: It is a collection of maps bound into a volume. Generally, these maps are drawn on a small scale.

→ Cartography; It is the science of map-making.

Class 6 Geography Chapter 4 Extra Questions and Answers Maps

→ Scale: It is the ratio between the actual distance on the ground and the distance shown on the map.

→ Cardinal points: The four major directions North, South, East and West are called Cardinal points.

→ Symbols: It is not possible to draw on the map the actual shape and size of different features. So they are shown by symbols. Symbols give information in a limited space.

→ Conventional symbols: There is an international agreement regarding the use of symbols.

→ Sketch: It is a drawing mainly based on memory and not to scale.

→ Plan: It is a drawing of a small area on a large scale.

Extra Questions for Class 6 Social Science

Online Education The Living Organisms and Their Surroundings Class 6 Notes Science Chapter 9

On this page, you will find Online Education for The Living Organisms and Their Surroundings Class 6 Notes Science Chapter 9 Pdf free download. CBSE NCERT Class 6 Science Notes Chapter 9 The Living Organisms and Their Surroundings will seemingly help them to revise the important concepts in less time.

Online Education CBSE Class 6 Science Chapter 9 Notes The Living Organisms and Their Surroundings

The Living Organisms and Their Surroundings Class 6 Notes Understanding the Lesson

1. Various types of things in the environment can be divided into two parts, e.g, living things and non­living things.

2. Animals, plants and microorganisms together constitute biotic components or living things.

3. Air, water, light, temperature, soil, etc., are abiotic components or non-living things.

4. The living things are called organims

5. Characteristics of living things are given below:

(a) Living things need food, air and water.
(b) Living things can grow.
(c) Living things respire.
(d) Living things excrete.
(e) Living things reproduce their own kind.
(f) Living things move.
(g) Living things respond to stimuli.

6. All the living things grow from a ‘single-cell’.

7. Animals move from one place to another

  • in search of food.
  • to protect themselves from their enemies.
  • to escape from natural calamities or natural hazards.

8. The movement of a part of the plant towards light is called

9. The change in surroundings to which living things respond are called

10. All living things take food. They use this food to obtain energy to grow, move, heal and stay alive.

11. The removal of waste substances from the body of living organism is called

12. The process by which living organisms produce new members of their species is called

13. All the living things start their life when they are born as babies or hatched from eggs.

14. The time period for which a living thing remains alive is called its lifespan.

15. The place or surroundings where a plant or animal lives is called their habitat.

16. There are two types of habitats:

(i) Terrestrial habitat
(ii) Aquatic habitat

17. Deserts, mountain and grassland are some terrestrial habitat.

18. Desert has a harsh environment with high temperature and low rainfall.

19. Desert animals live deep in burrows and come out only during the night to avoid intense heat.

20. Desert plants have deep roots and leaves reduced to spines.

21. Mountain region has very cold and windy climate.

22. Animals living in the mountain region have thick skin, fur, long hair to protect from snow.

23. Trees in mountain region are cone-shaped for easy sliding of snow falling on them.

24. Climate of forest or grassland is favourable for animals and plants living there. So it is densly populated.

25. Animals living in grassland have strong legs, long ears, and colour of their body similar to their surroundings to hide or mix up with them.

26. Aquatic habitat is broadly classified into saline water and freshwater.

27. Aquatic animals have streamlined body, gills or blowholes to survive and move in water.

28. Aquatic plants have reduced root system, hollow stem, floating leaves, etc.

29. There are different kinds of habitats having entirely different environmental conditions, such as temperature and amount of water.

30. The presence of specific body features or certain habits which enable a plant or animal to live in a particular habitat is called adaptation.

Class 6 Science Chapter 9 Notes Important Terms

Adaptation: The presence of specific body features or certain habits which enable a plant or an animals to live in a particular habitat is called adaptation.

Aquatic habitat: When organisms live in water, their place of living is known as aquatic habitat.

Biotic component: Living things of a habitat form its biotic component.

Excretion: The removal of nitrogenous waste substances from the body of a living being is called excretion.

Growth: Increase in size and total weight of the living organism is called growth.

Habitat: The place where an organism survives, flourish and reproduces is called habitat.

Living: These are the things which need water, air and nutrients for their survival.

Reproduction: The process of a living things to produce of its own kind is called reproduction.

Respiration: Respiration is a process in which air taken by an organism combines with the reserve food, undergoes oxidation and releases energy.

Stimulus: The factors like food, water, light, touch, gravitational force, etc., are stimuli to which plants and animals respond.

The Monkey and the Crocodile Extra Questions and Answers Class 6 English A Pact with the Sun

Online Education for The Monkey and the Crocodile Extra Questions and Answers Class 6 English A Pact with the Sun

Here we are providing Online Education for The Monkey and the Crocodile Extra Questions and Answers Class 6 English A Pact with the Sun, Extra Questions for Class 6 English was designed by subject expert teachers. https://ncertmcq.com/extra-questions-for-class-6-english/

Online Education for The Monkey and the Crocodile Extra Questions and Answers Class 6 English A Pact with the Sun

The Monkey and the Crocodile Extra Questions and Answers Short Answer Type

The Monkey And The Crocodile Extra Questions Class 6 Question 1.
Why had the monkey welcomed the crocodile?
Answer:
The monkey was happy to have a friend. He welcomed the crocodile because he had plenty of sweet fruits to eat. Earlier he had no friend to talk to and share the fruits with.

The Monkey And The Crocodile Extra Question Answer Class 6 Question 2.
How did the monkey and the crocodile become good friends?
Answer:
The monkey and the crocodile were lonely, secondly the monkey had lots of tasty fruits to give to the crocodile.

Extra Questions Of The Monkey And The Crocodile Class 6 Question 3.
What was the plan pf crocodile’s wife?
Answer:
The crocodile’s wife was annoyed with him for spending a lot of time with the monkey. She was fed up with managing the young ones alone. So she planned to get rid of the monkey once for all.

Monkey And The Crocodile Extra Questions Class 6 Question 4.
Whom did the crocodile choose to betray?
Answer:
The crocodile loved his wife. He was also very fond of his friend, the monkey. He, finally decided to betray his friend and please his life partner.

The Monkey And The Crocodile Class 6 Extra Questions Question 5.
How was the monkey taken to crocodile’s home?
Answer:
The monkey readily agreed to go with his friend. But he was not a swimmer. He rode on the crocodile’s back. And they set out.

The Monkey And The Crocodile Question Answer Class 6 Question 6.
‘The monkey was scared and depressed’. Why?
Answer:
The monkey realised the danger to his life. He could not jump into the river as he could not swim. The thought of his sure death made him sad and seared.

Class 6 English The Monkey And The Crocodile Extra Questions Question 7.
What did the monkey do as he reached the tree?
Answer:
The clever monkey climbed the tree. He offered some fruit to his friend. He declared that they won’t meet again.

The Monkey And The Crocodile Comprehension Questions Class 6 Question 8.
‘The monkey was nice and clever’. How?
Answer:
The crocodile was a good friend of the monkey who gave him lot of fruits for him as well as for his wife. One day the crocodile returned home late. The wife was annoyed. She wanted him to break up with his friend. So she wished to eat the monkey’s heart. The crocodile carried his friend on his back. In midstream he disclosed his wife’s plan. The monkey was clever enough to save his life. He said he had left his heart behind on the tree. As the two came back to the tree, the monkey climbed up.

Question 9.
The monkey was happy living in the fruit tree, but his happiness was not complete. What did he miss?
Answer:
The monkey was happy in his fruit tree home. He had plenty to eat, but he had no company. He felt lonely. He needed a companion to talk to and also to share his fruits.

Question 10.
What did the two friends generally talk about?
Answer:
The two friends talked about birds, animals, nearby villages and villager’s difficulties.

Question 11.
Why was the crocodile’s wife annoyed with her husband one day?
Answer:
The crocodile’s wife was annoyed of waiting for the crocodile to come home and in managing the little crocodiles that had just been hatched.

Question 12.
Why was the crocodile unwilling to invite his friend home?
Answer:
The crocodile’s wife desired to eat heart of the monkey. She ordered him to bring the monkey. He could* not betray his friend. Therefore, he was unwilling to invite his friend (the monkey) home.

Question 13.
What did the crocodile tell the monkey midstream?
Answer:
The crocodile told the monkey that his wife wanted to eat his heart.

Question 14.
How did the monkey save himself?
Answer:
The monkey was very clever. He told crocodile that he would gladly give away his heart to his friend’s wife, but he forgot his heart on the tree. He asked the crocodile to swim back to bring the heart from there. The crocodile could not understand monkey’s plan he swam back up to the tree. The monkey jumped on a branch and saved himself.

Question 15.
What does the last sentence of the story suggest? What would the crocodile tell his wife?
Answer:
The last sentence of the story suggests that the crocodile had learnt a lesson. He realised that he had lost a good friend because of his wife’s stupid desire. So it seems that the crocodile would rebuke his wife for her greed.

The Monkey and the Crocodile Extra Questions and Answers Long Answer Type

Question 1.
What do you learn from the lesson about friendship?
Answer:
Friendship grows among individual for their common interests and mutual respect. The bond grows if they sincerely make an effort to make it successful. However, if anyone of them betrays then his act is unforgivable, the bond is snapped. It can’t be taken any further. Monkey welcomed the crocodile to be his friend. But he was stabbed at the back. However, he managed to save his life.

Question 2.
‘The trust and faith is the foundation stone of friendship’. Justify your answer.
Answer:
The monkey was living on a tree. To avoid the loneliness of the monkey, crocodile was happily invited by him. He was offered fruits and they spent time together. But when his wife wanted to eat the monkey, the crocodile could not defy the wish of his wife. He broke the trust of his friend. However, the monkey was clever and came out of the situation.

The bond could have been saved. The fact is that crocodile could have convinced his wife and his friendship would have gone further. He could have enjoyed fruits for a longer time period. So when the crocodile lost faith and trust of his Mend, he lost his Mend forever.