RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1C

RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1C

These Solutions are part of RS Aggarwal Solutions Class 8. Here we have given RS Aggarwal Solutions Class 8 Chapter 1 Rational Numbers Ex 1C.

Other Exercises

Question 1.
Solution:
(i) \(\\ \frac { -2 }{ 5 } \) + \(\\ \frac { 4 }{ 5 } \)
= \(\\ \frac { -2+4 }{ 5 } \) = \(\\ \frac { 2 }{ 5 } \)
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1C 1

Question 2.
Solution:
(i) \(\frac { 3 }{ 4 } +\left( \frac { -3 }{ 5 } \right) \)
\(\frac { 15+\left( -12 \right) }{ 20 } =\frac { 15-12 }{ 20 } =\frac { 3 }{ 20 } \)
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1C 2
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1C 3
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1C 4

Question 3.
Solution:
(i) L.H.S = \(\\ \frac { -12 }{ 5 } \) + \(\\ \frac { 2 }{ 7 } \)
= \(\\ \frac { -84+10 }{ 35 } \) = \(\\ \frac { -74 }{ 35 } \)
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1C 5
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1C 6
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1C 7

Question 4.
Solution:
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1C 8
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1C 9
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1C 10
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1C 11
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1C 12

Question 5.
Solution:
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1C 13
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1C 14

Question 6.
Solution:
We know that additive inverse of \(\\ \frac { a }{ b } \) is \(\\ \frac { -a }{ b } \) and of \(\\ \frac { -a }{ b } \) is \(\\ \frac { a }{ b } \).
Therefore Additive inverse of
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1C 15
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1C 16

Question 7.
Solution:
(i) \(\\ \frac { 3 }{ 4 } \) from \(\\ \frac { 1 }{ 3 } \) or \(\\ \frac { 1 }{ 3 } \) – \(\\ \frac { 3 }{ 4 } \)
= \(\\ \frac { 4-9 }{ 12 } \) = \(\\ \frac { -5 }{ 12 } \)
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1C 17
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1C 18
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1C 19
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1C 20

Question 8.
Solution:
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1C 21
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1C 22
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1C 23

Question 9.
Solution:
Sum of two numbers = – 2
one number = \(\\ \frac { -14 }{ 5 } \)
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1C 24

Question 10.
Solution:
Sum of two numbers = \(\\ \frac { -1 }{ 2 } \)
One number = \(\\ \frac { 5 }{ 6 } \)
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1C 25

Question 11.
Solution:
Sum of two numbers = \(\\ \frac { -3 }{ 2 } \)
one number = \(\\ \frac { -5 }{ 8 } \)
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1C 26

Question 12.
Solution:
Sum of two numbers = \(\\ \frac { 5 }{ 7 } \)
One number = – 1
Second number = \(\\ \frac { 5 }{ 7 } \) – ( – 1)
= \(\\ \frac { 5 }{ 7 } \) + \(\\ \frac { 1 }{ 1 } \)
\(\\ \frac { 5+7 }{ 7 } \) = \(\\ \frac { 12 }{ 7 } \)

Question 13.
Solution:
Difference of two numbers = \(\\ \frac { -1 }{ 6 } \)
One number = \(\\ \frac { -2 }{ 3 } \)
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1C 27

Question 14.
Solution:
(i) 0 is the rational number.
(ii) Yes, the difference of two rational numbers is also rational.
(iii) Yes, addition is commutative.
(iv) Yes, addition associative.
(v) No, subtraction is not commutative.
(vi) No, subtraction is not associative.
(vii) The number itself.

Hope given RS Aggarwal Solutions Class 8 Chapter 1 Rational Numbers Ex 1C are helpful to complete your math homework.

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RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1B

RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1B

These Solutions are part of RS Aggarwal Solutions Class 8. Here we have given RS Aggarwal Solutions Class 8 Chapter 1 Rational Numbers Ex 1B.

Other Exercises

Question 1.
Solution:
(i) \(\\ \frac { 1 }{ 3 } \)
Draw a line and take a point O on it.
Let it represent 0.
From O, set off unit OA, AB to right side of O, representing integers 1, 2 respectively.
Now, divide OA into 3 equal parts and take one part OR Which is \(\\ \frac { 1 }{ 3 } \) as shown below on the line.
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1B 1
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1B 2
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1B 3
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1B 4
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1B 5
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1B 6
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1B 7

Question 2.
Solution:
(i) \(\\ \frac { -1 }{ 3 } \)
Draw a line and take a point O on it.
Let it represent O.
Now, from O, take OA, AB to the left of O, representing integers – 1, – 2 respectively. Divide OA into three equal parts and take one part.
Then OP = \(\\ \frac { -1 }{ 3 } \) which is shown on the number line as given below :
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1B 8
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1B 9
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1B 10
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1B 11
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1B 12
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1B 13
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1B 14

Question 3.
Solution:
(i) True, as the numbers left of O are negative.
(ii) False, as the numbers right of O are positive and \(\\ \frac { -12 }{ 7 } \) is negative.
(iii) True, as \(\\ \frac { 1 }{ 3 } \) is positive and \(\\ \frac { -5 }{ 2 } \) is negative.
(iv) False \(\\ \frac { -18 }{ -13 } \) = \(\\ \frac { 18 }{ 13 } \) which is positive and positive numbers lie on the right of O.

Hope given RS Aggarwal Solutions Class 8 Chapter 1 Rational Numbers Ex 1B are helpful to complete your math homework.

If you have any doubts, please comment below. Learn Insta try to provide online math tutoring for you.

Online Education for RS Aggarwal Class 8 Solutions Chapter 11 Compound Interest Ex 11C

Online Education for RS Aggarwal Class 8 Solutions Chapter 11 Compound Interest Ex 11C

These Solutions are part of Online Education RS Aggarwal Solutions Class 8. Here we have given RS Aggarwal Solutions Class 8 Chapter 11 Compound Interest Ex 11C.

Other Exercises

Question 1.
Solution:
Principal (P) = Rs. 8000
Rate (R) = 10% p.a. or 5% half yearly
Period (n) = 1 year or 2 half years
RS Aggarwal Class 8 Solutions Chapter 11 Compound Interest Ex 11C 1.1

You can also Download NCERT Solutions for Class 8 Maths to help you to revise complete Syllabus and score more marks in your examinations.

Question 2.
Solution:
Principal (P) = Rs. 31250
Rate (R) = 8% p.a. or 4% half yearly
Period (n) = \(1\frac { 1 }{ 2 } \) years or 3 half years
RS Aggarwal Class 8 Solutions Chapter 11 Compound Interest Ex 11C 2.1
= Rs 3902

Question 3.
Solution:
Principal (P) = Rs 12800
Rate (R) = \(7\frac { 1 }{ 2 } \)% p.a. = \(\\ \frac { 15 }{ 2 } \)% half yearly
Period (n) = 1 year or 2 half years
RS Aggarwal Class 8 Solutions Chapter 11 Compound Interest Ex 11C 3.1

Question 4.
Solution:
Principal (P) = Rs. 160000
Rate (R) = 10% p.a. or 5% half yearly
Period (n) = 2 years or 4 half years
RS Aggarwal Class 8 Solutions Chapter 11 Compound Interest Ex 11C 4.1

Question 5.
Solution:
Principal (P) = Rs. 40960
Rate (R) = \(12\frac { 1 }{ 2 } \) = \(\\ \frac { 25 }{ 2 } \)% p.a. or \(\\ \frac { 25 }{ 4 } \) % half yearly
RS Aggarwal Class 8 Solutions Chapter 11 Compound Interest Ex 11C 5.1

Question 6.
Solution:
Loan received for the cost of the house (P) = Rs. 125000
Rate of interest (R) = 12% p.a. or 6% half yearly
RS Aggarwal Class 8 Solutions Chapter 11 Compound Interest Ex 11C 6.1

Question 7.
Solution:
Amount deposit in the bank = Rs. 20000
Rate of interest (R) = 6% p.a. or 3% half-yearly
Period (n) = 1 year or 2 half years
Amount received after 1 year
= \({ \left( 1+\frac { R }{ 100 } \right) }^{ n }\)
RS Aggarwal Class 8 Solutions Chapter 11 Compound Interest Ex 11C 7.1

Question 8.
Solution:
Amount of loan = Rs. 65536
Rate of interest (R) = 12 \(12\frac { 1 }{ 2 } \) % = \(\\ \frac { 25 }{ 2 } \)%
RS Aggarwal Class 8 Solutions Chapter 11 Compound Interest Ex 11C 8.1
RS Aggarwal Class 8 Solutions Chapter 11 Compound Interest Ex 11C 8.2

Question 9.
Solution:
Amount deposit in the bank (P)
= Rs. 32000
Rate of interest (R) = 5% p.a.
RS Aggarwal Class 8 Solutions Chapter 11 Compound Interest Ex 11C 9.1

Question 10.
Solution:
Amount taken from finance company (P) = Rs. 390625
Rate of interest (R) = 16% p.a.
RS Aggarwal Class 8 Solutions Chapter 11 Compound Interest Ex 11C 10.1

Hope given RS Aggarwal Solutions Class 8 Chapter 11 Compound Interest Ex 11C are helpful to complete your math homework.

If you have any doubts, please comment below. Learn Insta try to provide online math tutoring for you.