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Students can access the CBSE Sample Papers for Class 12 Applied Mathematics with Solutions and marking scheme Term 2 Set 6 will help students in understanding the difficulty level of the exam.

CBSE Sample Papers for Class 12 Applied Mathematics Term 2 Set 6 with Solutions

Maximum Marks : 40
Time : 2 Hours

Instructions:

• The question paper is divided into 3 sections-A, B and C
• Section A comprises of 6 questions of 2 marks each. Internal choice has been provided in two questions.
• Section B comprises of 4 questions of 3 marks each. Internal choice has been provided in one question.
• Section C comprises of 4 questions. It contains one case study based question. Internal choice has been provided in one question.

Section – A [12 Marks]

Question 1.
If the marginal cost function at x units of output is given by MC = \(\frac{p}{\sqrt{p x+q}}\), where p, q are constants and the fixed cost of production is zero, find the total cost function.
Or
Find the order and degree of differential equation \(\frac{d^{3} y}{d x^{3}}+\left(\frac{d y}{d x}\right)^{1 / 3}\) = \(x^{\frac{1}{3}}\).
Answer:
We have,
MC = \(\frac{p}{\sqrt{p x+q}}\)
⇒ \(\frac{d C}{d x}=\frac{p}{\sqrt{p x+q}}\) ⇒ dc = \(\frac{p}{\sqrt{p x+q}}\) dx
On integrating both sides, we get
⇒ C = ∫\(\frac{p}{\sqrt{p x+q}}\) dx + K
⇒ C = 2\(\sqrt{p x+q}\) + K …….(i)
where K is the constant of integration.
When x = 0, then fixed cost of production is zero,
i.e. C = 0
Putting x = 0 and C = 0 in Eq. (i), we get
0 = 2√q + K
⇒ K = – 2√q
Putting K = – 2√q in Eq. (i), we find that the total cost function is given by

Question 2.
Samples of two different types of bulbs were tested for length of life and the following data were obtained

Is the difference in mean life of two types of bulbs significant?
Answer:
Given, n₁ = 8, n₂ = 7, s₁ = 36, s₂ = 40, x̄₁ = 1234 and x̄₂ = 1136
Let us take the null hypothesis that there is no significant difference in the mean life of the two types of bulbs.
Test statistics,


From table with v = 8 + 7 – 2 =13, test statistics t_o.05 = 2.16. Since, the calculated value of t is greater than the tabulated value. Therefore, the null hypothesis is rejected.
Hence, there is a significant difference in the mean life of two types of bulbs.

Question 3.
A man borrowed some money and paid back in 3 equal installments of ₹ 2160 each. What sum did he borrow, if the rate of interest charged was 20% per annum compounded annually? Find also the total interest charged, [given, (1.20)^-3 = 0.5786]
Or
Find the present value of a sequence of payments of ₹ 2000 made at the end of every 6 months and continuing forever, if money is worth 10% per annum compounded semi-annually.
Answer:

Hence, the man borrowed ₹ 4551.12
In 3 yr the amount paid = ₹ (3 × 2160) = ₹ 6480
∴ Total interest charged = ₹ (6480 – 455L12)
= ₹ 1928.88
Or
Given, R = ₹ 2000, r = \(\frac{10}{2}\)% = 5% (per half)
So, i = 5 /100 = 0.05
∴ Present value,
P = \(\frac{R}{i}=\frac{2000}{0.05}\) = ₹ 40000

Question 4.
If Σ y = 91, n = 7, Σ x² – 28 and Σ xy = 33, then find the equation of the trend line.
Answer:
We know, a = \(\frac{\Sigma y}{n}\)
∴ a = \(\frac{91}{7}\) = 13 and b = \(\frac{\Sigma x y}{\Sigma x^{2}}=\frac{33}{28}\) = 1.179
∴ Equation of trend line,
y_t = a + bx = 13 + 1.179x.

Question 5.
Neera borrows a sum of ₹ 150000 at an interest rate of 10% (flat) for a tenure of 3 yr. Find her EMI.
Answer:
Given, principal = ₹ 150000
Interest (yearly) = 10% of ₹ 150000 = ₹ 15000
∴ Interest of 3 yr = ₹ 45000
∴ EMI = \(\frac{\text { Principal + Interest }}{\text { Period of months }}\)
= \(\frac{150000+45000}{3 \times 12}\) = \(\frac{195000}{36}\)
= ₹ 5416.67

Question 6.
A small firm manufactures necklaces and bracelets. The total number of necklaces and bracelets that it can handle per day is atmost 24. It takes one hour to make a bracelet and half an hour to make a necklace. The maximum number of hours available per day is 16. If the profit on a necklace is ₹ 100 and that on a bracelet is ₹ 300. Formulate on LPP, for finding how many of each should be produced daily to maximise the profit? It is being given that atleast one of each must be produced.
Answer:
Let number of necklaces and bracelets produced by firm per day be x and y, respectively.
Clearly, x ≥ 0 and y ≥ 0
∵ Total number of necklaces and bracelets that the firm can handle per day is atmost 24.
∴ x + y ≤ 24
Since, it takes one hour to make bracelet and half an hour to make a necklace and maximum number of hour available per day is 16.
∴ \(\frac{1}{2}\)x + y ≤ 16 ⇒ x + 2y ≤ 32
Let Z be the profit function.
Then, Z = 100x + 300y
∴ The given LPP reduces to
Maximise Z = 100x + 300y
Subject to constraints,
x + y ≤ 24
x + 2y ≤ 32
and x, y ≥ 0

Section – B [12 Marks]

Question 7.
Evaluate \(\frac{x^{2}-3 x+1}{\sqrt{1-x^{2}}}\).
Or

Answer:

Question 8.
Pramod invested ₹ 21000 in a mutual fund and the value of investment at the time of redemption was ₹ 35000. If CAGR for this investment is 7.55%. Calculate the time period for which the amount was invested?
[given log(1.667) = 0.2219 and log(1.0755) = 0.0316]
Answer:
Given, BV = ₹ 21000
EV = ₹ 35000 and CAGR = 7.55%

⇒ n = 7.022 = 7
Hence, the time period is 7 yr.

Question 9.
A random sample of size 16 has 53 as mean. The sum of squares of deviations from mean is 150. Can this sample be regard as taken from the population having 56 as mean? Level of significance is 5% (given t₁₅ (0.05) = 1.753)
Answer:
Consider: H₀: µ = 56
H_a: µ > 56
Here, n = 16, x̄ = 53 and Σ(x_i – x̄)² = 150
∴ S² = \(\frac{1}{n-1}\) Σ(x_i – x̄)² = \(\frac{150}{15}\) = 10 ⇒ S = √10 = 3.1622
Test statistics, t = \(\frac{\bar{x}-\mu}{(S / \sqrt{n})}=\frac{53-56}{3.1622 / \sqrt{16}}=\frac{(-3) \times 4}{3.1622}\) = – 3.795
Since, calculated value of |t| = 3.795 is greater than tabulated value, so H₀ can be rejected.

Question 10.
The number of letters (in hundred) received in a town on each day of a fortnight is given below

Calculate the 7-days moving average and display it on a graph.
Answer:
Given, table is shown below:

Let the moving average for 7 days is m, then

On the basis of above data we can draw the following graph for moving average

Section – C [16 Marks]

Question 11.
The demand and supply function are p = 25 – x² and p = 2x + 1, respectively. Find the
(i) the equilibrium point
(ii) the consumer’s surplus at the equilibrium points.
Answer:
Given, the demand function and supply are
p = D(x) = 25 – x² and p = S(x) = 2x +1
(i) At equilibrium point D(x) = S(x)
⇒ 25 – x²₀ = 2x₀ + 1
⇒ x²₀ +2x₀ – 24 = 0
⇒ (x₀ – 4) (x₀ + 6) = 0
⇒ x₀ = 4 [∵ x₀ = -6]
Now, putting x₀ = 4 in S(x), we get p₀ = 9
Hence, the equilibrium point (x₀, p₀) is (4,9)

(ii) The consumer’s surplus at the equilibrium point (4, 9) is given by

Question 12.
A firm anticipates on expenditure of ₹ 300000 for plant modernization at the end of 15 yr from now. How much should the company deposite at the end of each year into a sinking fund earning interest 6% per annum? [given, (1.06)¹⁵ = 23966 ]
Answer:
Given, A = ₹ 300000

⇒ R [(1.06)15 – 1] = 300000 × 0.06
⇒ R (2.3966 – 1) = 18000
⇒ R(1.3966) = 18000
⇒ R = \(\frac{18000}{1.3966}\)
= 12888.44
Hence, the company deposite at the end of each year into a sinking fund ₹ 12888.44.

Question 13.
A dietician wishes to mix two types of foods in such a way that the vitamin contents of mixture contains atleast 8 units of vitamin A and 10 units of vitamin C. Food I contains 2 units per kg of vitamin A and 1 unit per kg of vitamin C, while food II contains 1 unit per kg of vitamin A and 2 units per kg of vitamin C. It costs ₹ 5 per kg to purchase food I and ₹ 7 per kg to purchase food II. Find the minimum cost of such a mixture. Formulate above as an LPP and solve it graphically.
Or
Solve the following LPP graphically.
Maximise Z = 3x + 2y, subject to constraints are x + 2y ≤ 10, 3x + y ≤ 15 and x, y ≥ 0.
Also, determine the area of the feasible region.
Answer:
The given data can be put in the tabular form as follows

Suppose the diet contains x kg of food I and y kg of food II.
Then, the required LPP is minimise
Z = 5x + 7y
Subject to constraints 2x + y ≥ 8, x + 2y ≥ 10 and x ≥ 0, y ≥ 0
On considering the inequalities as equations,
we get
2x + y = 8 …… (i)
and x + 2y = 10 …… (ii)
Table for line 2x + y = 8 is

X	0	4
y	8	0

So, it passes through the points (0, 8) and (4, 0).
On putting (0,0) in the inequality 2x + y ≥ 8,
we get
0 ≥ 8 [which is false]
So, the half plane is away from the origin.
Table for line x + 2y = 10 is

X	10	0
y	0	5

So, it passes through the points (10,0) and (0, 5).
On putting (0,0) in the inequality x + 2y ≥ 10,
we get
0 ≥ 10 [which is false]
So, the half plane is away from the origin.
Also, x, y ≥ 0, so the feasible region lies in the first quadrant.
On solving Eq. (i) and Eq. (ii), we get
x = 2 and y = 4
So, these lines intersect at P(2, 4).
The graphical representation of the system of inequations given below

From the graph, the feasible region is BPC which is unbounded.
The values of Z at comer points are as follows

Corner points	Value of Z = 5x + 7y
C(10, 0)	Z = 5(10)+ 7(0) = 50
P{2, 4)	Z = 5(2)+7(4) = 10 + 28 =38 (minimum)
6(0. 8)	Z = 5(0)+ 7(8) = 0+ 56 = 56

From table, the minimum value of Z is 38 at P(2,4).
As the feasible region is unbounded, therefore 38 may or may not be the minimum value of Z. For this, we draw a dotted graph of the inequality 5 x + 7y < 38 and check whether the resulting half plane has point in common with the feasible region or not.
It can be seen that the feasible region has no common point with 5x + 7y < 38.
Hence, the minimum cost is ₹ 38, when x = 2 and y = 4.
Or
Our problem is to maximise Z = 3x + 2 y …(i) Subject to constraints,
x + 2y ≤ 10 …(ii)
3x + y ≤ 15 …(iii)
and x, y ≥ 0 …(iv)
Table for line x + 2y = 10 is

X	0	4
y	5	3

So, the line passes through the points (0, 5) and (4, 3).
On putting (0,0) in the inequality x + 2y ≤ 10, we get
0 + 2 × 0 ≤ 10
⇒ 0 ≤ 10, which is true.
So, the half plane is towards the origin.
Table for line 3x + y = 15 is

X	4	5
y	3	0

So, the line passes through the points (4, 3) and (5,0).
On putting (0,0) in the inequality 3x + y ≤ 15, we get
3 × 0 + 0 ≤ 15
⇒ 0 ≤ 15, which is true.
So, the half plane is towards the origin.
Also, x, y ≥ 0, so the region lies in the first quadrant.
On solving equations x + 2y = 10 and 3x + y = 15, we get x = 4 and y = 3
So, the intersection point is 6(4,3).
∴ Feasible region is OABCO

The corner points of the feasible region are 0(0,0), A(5,0), 6(4,3) and C(0,5).
The values of Z at the corner points are given below

Corner points	Value of Z = 3x + 2y
0(0, 0)	Z = 3 × 0 + 2 × 0 = 0
4(5, 0)	Z = 3 × 5 + 2 × 0 = 15
6(4, 3)	Z = 3 × 4 + 2 × 3 = 18 (Maximum)
C(0, 5)	Z = 3 × 0 +2 × 5 = 10

Therefore, the maximum value of Z is 18 at the point B(4, 3).
∴ Area of feasible region
= Area of ∆BOC + Area of ∆OAB
= \(\frac{1}{2}\) × OC × BD + \(\frac{1}{2}\) × OA × BE
= \(\frac{1}{2}\) × 5 × 4 + \(\frac{1}{2}\) × 5 × 3
= 10 + \(\frac{15}{2}\) = 10 + 7.5
= 17.5 sq units

Case Based/Data Based

Question 14.
An entertainment company has gained much popularity all over the countary. They buy a car to travel to their destination. The purchase price is ₹ 1000000. The car will be depreciated linearly over 10 yr and will have a scrap value of ₹ 500000.

On the basis of above information, answer the following questions.
(i) Find the rate of depreciation.
Answer:
∴ Rate of depreciation
= \(\frac{500000-1000000}{10-0}\)
= – \(\frac{500000}{10}\)
= – 50000
∴ Rate of depreciation is ₹ 50000

(ii) When will the car be worth ₹ 800000?
Answer:
According to the question,
800000 = – 500001 +1000000
⇒ – 200000 = -50000 t
⇒ t = 4 yr

Students can access the CBSE Sample Papers for Class 12 Applied Mathematics with Solutions and marking scheme Term 2 Set 7 will help students in understanding the difficulty level of the exam.

CBSE Sample Papers for Class 12 Applied Mathematics Term 2 Set 7 with Solutions

Maximum Marks : 40
Time : 2 Hours

Instructions:

• The question paper is divided into 3 sections-A, B and C
• Section A comprises of 6 questions of 2 marks each. Internal choice has been provided in two questions.
• Section B comprises of 4 questions of 3 marks each. Internal choice has been provided in one question.
• Section C comprises of 4 questions. It contains one case study based question. Internal choice has been provided in one question.

Section – A [12 Marks]

Question 1.
A population grows at the rate of 5% per year. How long does it take for the population to double?
Answer:
Let P₀ be the initial population and the population after t yr be P.
According to given problem, we get
\(\frac{d P}{d t}=\left(\frac{5}{100}\right)\) × P = \(\frac{d P}{d t}=\frac{P}{20}\)
Now, separating the variables, we get
\(\frac{d P}{P}=\frac{d t}{20}\)
On integrating both sides, we get
l0gP = \(\frac{t}{20}\) + C₁
⇒ P = ^{et/20 + C₁} = e^t/20 – e^C₁ = Ce^t/20, where e^C₁ = C
∵ At t = 0, P = P₀, therefore we have P₀ = C.e⁰

Question 2.
The mean and variance of a random sample of 81 observations were computed as 200 and 144, respectively. Compute the 95% confidence limits for population mean.
Or
The mean weekly sales of mango candy in candy stores was 225.4 mango candy per store. After an advertising campaign the mean weekly sales in 25 stores for a typical week increased to 237.6 and showed a standard deviation of 21.3 was the advertising campaign successful? Level of confidence 5%. [given, t₂₄ (0.05) = 1.711]
Answer:
Given, n = 81, x̄ = 200 and σ² = 144 ⇒ σ = 12
∴ Confidence limits (95%) are
⇒ x̄ ± 1.96\(\left(\frac{\sigma}{\sqrt{n}}\right)\) = x̄ ± 1.96\(\left(\frac{12}{\sqrt{81}}\right)\)
= [200 – 1.96 \(\left(\frac{12}{9}\right)\),200 + 1.96 \(\left(\frac{12}{9}\right)\)]
= [200 – 2.61,200 + 2.61]
= [197.39,202.61]

Or

Given, n = 25, x̄ = 237.6, μ = 225.4 and S = 21.3
Consider, H₀ : μ = 225.4 and H₁ : μ > 225.4

Now, test statistics,
t = \(\frac{\bar{x}-\mu}{S / \sqrt{n}}\)
= \(\frac{237.6-225.4}{21.3 / \sqrt{25}}=\frac{12.2 \times 5}{21.3}\) = 2.86

Since, calculated value of t > tabulated value of t. Hence, H₀ can rejected
⇒ Advertising campaign was successful.

Question 3.
Anand Prasad borrows a sum of ₹ 225000 at an interest rate of 10% (flat) for a tenure of 5 yr. Calculate his EMI.
Or
A sum of ₹ 75000 invested at r% compounded quarterly will provide payments of ₹ 800 each at the end of 3 months. Find the value of r.
Answer:
Given, principal (P) = ₹ 225000
Interest (yearly) = 10% of 225000 = ₹ 22500
Interest for 5 yr = 5 × 22500 =112500
⇒ EMI = \(\frac{225000+112500}{5 \times 12}=\frac{337500}{60}\)
[∵ EMI = \(\frac{\text { Principal + Interest }}{n}\)]
= 5625
∴ Hence, EMI is 15625.

Or

Given, present value (P) = ₹ 75000
Let the rate of interest be r.
Since, interest compounded quarterly
∴ i = \(\frac{r}{4}\)
Periodic payment (R) = ? 800

We know that
P = \(\frac{R}{i}\)
⇒ 75000 = \(\frac{800}{i}\)
⇒ i = \(\frac{800}{75000}\)
⇒ i = 0.010
⇒ \(\frac{r}{4}\) = 0.010 4
⇒ r = 0.040
= 4% (approx.)

Question 4.
Calculate the 3-yearly moving averages of the following data.

Answer:
Calculation of 3-yearly moving averages.

Question 5.
What amount is recieved at the end of every 6 months forever, if ₹ 72000 kept in a bank earns 8% per annum compounded half-yearly.
Answer:
It is given that the present value of perpetuity of ₹ R payable at the end of each 6 months is ₹ 72000. If money is worth 8% compounded semi-annually. Thus,
We have, P = ₹ 72000
and i = \(\frac{8}{200}\) = 0.04
∵ P = \(\frac{R}{i}\)
⇒ R = Pi
⇒ R = 72000 × 0.04 = 2880
Hence, R is ₹ 2880

Question 6.
Find the maximum value of Z for the problem maximise Z = 2x + y subject to constraints are x + y ≤ 2, x ≥ 0, y ≥ 0 is
Answer:
We have, maximize Z = 2 x + y

Subject to constraints are
x + y ≤ 2, x ≥ 0, y ≥ 0

The shaded region shown in fig OAB is bounded and the coordinates of comer points O, A and B are (0, 0), (2,0) and (0, 2), respectively.

Comer points	Value of Z =2x+y
(0,0)	0
(2,0)	4 (Maximum)
(0, 2)	2

Section – B [12 Marks]

Question 7.
A product can be manufactured at a total cost C(x) = \(\frac{x^{2}}{100}\) + 100x + 40, where x is the number of units produced. The price at which each unit can be sold is given by p = (200 – \(\frac{x}{100}\)). Determine the production level x at which the profit is maximum. What is the price per unit and total profit at the level of production?
Answer:
Given, total cost C(x) = \(\frac{x^{2}}{100}\) + 100x + 40
Price of each unit can be sold
p = 200 – \(\frac{x}{100}\)

Price of x unit sold
R(x) = px = 200x – \(\frac{x^{2}}{400}\)

∴ Profit P(x) = R(x) – C(x)
= 200x – \(\frac{x^{2}}{400}-\frac{x^{2}}{100}\) – 100x – 40
⇒ P(x) = \(\frac{x^{2}}{80}\) + 100x – 40 ……..(i)

On differentiating both sides w.r.t. x, we get
P'(x) = \(\frac{2x}{80}\) + 100
= – \(\frac{x}{40}\) + 100

For maxima or minima, put P'(x) = 0
⇒ – \(\frac{x}{40}\) + 100 = 0
x = 4000
Now, P”(x) = – \(\frac{1}{40}\) < 0

Hence, P(x) is maximum when x = 4000.
Total profit at x = 4000, then
P(4000) = \(\frac{-(4000)^{2}}{80}\) + 100(4000) – 40 [from Eq. (i)]
= -200000 + 400000 – 40
= 199960
Hence, the total profit is ₹ 199960.

Question 8.
Ten oil tins are taken at random from an automatic filling machine. The mean weight of the tins is 17.2 kg and standard deviation is 0.62 kg. Does the sample mean differ significantly from the intended weight of 18 kg? [given, t₉(0.05) = 2.26]
Answer:
Given, n = 10, x̄ = 17.2, μ = 18 and S = 0.62
Consider, H₀: μ = 18
H₁: μ ≠ 18
t = \(\frac{\bar{x}-\mu}{S / \sqrt{n}}\)
= \(\frac{17.2-18}{0.62 / \sqrt{10}}\)
= –\(\frac{0.8 \times \sqrt{10}}{0.62}\) = -4.08

Since, calculated value of If |t| is greater than the tabulated value of t. So, H₀ is not accepted. Thus, the difference between sample mean weight and the intended weight is not insignificant.

Question 9.
Below are given the figures of production (in thousand tonnes) of a sugar factory.

Fit a straight line trend by the method of least squares and find trend value for year 2005.
Or
Consider the following data

Calculate 3-days moving average and display these and the original figures on the same graph.
Answer:
Here, n =7 (odd)
So, we shift the origin to the middle of the time period of the 2008.

Let the straight line trend of y on x be
y_t = a + bx …(i)

Now, construct the table as under.

Now, a = \(\frac{\Sigma y}{n}=\frac{785}{7}\) = 112.14
and b = \(\frac{\Sigma x y}{\Sigma x^{2}}=\frac{40}{28}\) = 1.43

So, the required equation of the straight line trend is
y_t = 112.14 + 1.43x

:. Trend value for year 2005,
y_t = 112.14 + 1.43(- 3)
= 112.14 – 4.29
= 107.85

Or

According to the question,
Let the 3-days moving average is m.


On the basis of above data we can draw the following graph:

Question 10.
Mr. Narayan Sankar has invested ₹ 150000 in a financial plan whose compound annual growth rate (CAGR) is 8.5% and he received a final value of ₹ 300000.
Find the period (completed) for which he has invested the amount. [given, log 2 = 0.3010 and log(1.09) = 0.0374]
Answer:
10. Given, EV = ₹ 300000
BV = ₹ 150000 and CAGR = 8.5%

We know that
CAGR = [\(\left(\frac{\mathrm{EV}}{\mathrm{BV}}\right)^{1 / n}\) – 1] × 100
⇒ 8.5 = [\(\left(\frac{300000}{150000}\right)^{1 / n}\) – 1] × 100
⇒ 8.5 = [(2)^1/n – 1] × 100
⇒ 8.5 = (2)^1/n × 100 – 100
⇒ 8.5 + 100 = (2)^1/n × 100
⇒ 108.5 = (2)^1/n × 100
⇒ (2)^1/n = \(\frac{108.5}{100}\) = 1.085
⇒ \(\frac{1}{n}\) log2 = log(1.09)
⇒ n = \(\frac{\log 2}{\log (1.09)}\)
⇒ n = \(\frac{0.3010}{0.0374}\)
⇒ n = 8.0481
⇒ n = 8
∴ The period for which he has invested the amount is 8 yr.

Section – C [16 Marks]

Question 11.
A machine is bought for ₹ 320000. Its effective life is 8 yr, after which its salvage value would be ₹ 25000. It is decided to create a sinking fund to replace this machine at the end of its effective life by making half yearly payments that will earn an interest of 8% per annum compounded half yearly. If it is known that the cost of machine increases by 5% per annum. Calculate the amount of each payment to the sinking fund. [given (1.04)¹⁶ =1.8730 and (1.05)⁸ =1.4774]
Or
A bond has face value of ₹ 10000 and maturity period of 10 yr. The nominal interest rate is 6% per annum. What should be the price of the bond to yield an effective interest of 8%? [given (1.08)^-0 = 0.4631]
Answer:
Let each semi-annually deposit in the sinking fund of ₹ R. Since, the cost of new machine is increases by 5% per annum the cost of present.
Cost of machine at present = ₹ 320000
Cost of machine after increasing 5% per annum after 8 yr
= 32000o\(\left(1+\frac{5}{100}\right)^{8}\)
= 32000 (1.05)⁸
= 320000 × 1.4774
= ₹ 472768
Salvage value of present machine = ₹ 25000
So, net amount required at the end of 8 yr to purchase the new model is ₹ (472768 – 25000) = ₹ 447768

We know that R = \(\frac{i \times S}{(1+i)^{n}-1}\)
Here, S = ₹ 447768, n = 8 × 2 = 16 yr
i = \(\frac{8}{200}\) = 0.04
∴ R = \(\frac{(0.04) \times(447768)}{(1+0.04)^{16}-1}\)
= \(\frac{17910.72}{(1.04)^{16}-1}\)
= \(\frac{17910.72}{18730-1}\)
= \(\frac{17910.72}{0.8730}\) = 20516.28
Thus, ₹ 20516.28 deposited half yearly out of the profit to purchase the new model of the machine.

Or

We have, F = Face value of bond = ₹ 10000
N = Number of period = 10
C = Coupon payment = Annual dividend × 10000
= \(\frac{6}{100}\) × 10000 = 1600
F = Maturity value = Face value = ₹ 10000

Let PV be the price of the bond.

Hence, the price of bond is ₹ 8657.75.

Question 12.
The supply function of a producer is given by p = \(\frac{2}{5}\) e^2x, where x denotes thousand units. Find producer’s surplus when sales are 2000 units.
Answer:
The supply functions is p = \(\frac{2}{5}\) e^2x
When sales are 2000 units i.e., x₀ =2, we get

Question 13.
Anil wants to invest atmost ₹ 12000 in bonds A and B. According to the rules, he has to invest atleast ₹ 2000 in bond A and atleast ₹ 4000 in bond B. If the rate of interest in bond A is 8% per annum and on bond B is 10% per annum, then to maximise the interest, then find the investment in bond A and B.
Answer:
Let the investment in bond A and B are x and y respectively.
Then, our problem is to Maximise Z = 0.08x + 0.10y
Subject to constraints are
x + y ≤ 12000, x ≥ 2000
y ≥ 4000 and x, y ≥ 0

The graph of the above inequality is given by

In the above graph shaded region is the feasible bounded region ABC.
Now, the values of Z at the comer points are given by

Corner point	Value of Z = 0.08x + 0.10 y
(2000, 4000)	560
(8000, 4000)	1040
(2000, 10000)	1160 (Maximum)

From the above table, we see that the maximum value of Z is 1160 which occurs at the point (2000,10000).
Hence, to maximise the interest ₹ 2000 and ₹ 10000 must be invested in bond A and B, respectively.

Case Based/Data Based

Question 14.
EMI is a part of equally divided monthly outgoes to clear off an outstanding loan within a stipulated time frame. For a fixed interest rate loan, the EMI remain fixed for the entire tenure of the loan, provided there is no default or part payment in between. The EMI is used off both the principal and interest components of an outstanding loan, The first EMI has the highest interest component and the lowest principal component.

Rajesh purchased a house from a company for ₹ 2500000 and made a down payment of ₹ 500000. He repays the balance in 25 yr by monthly installments at the rate of 9% per annum compounded monthly, (given (1.0075)_300 = 0.1062)
(i) What are the monthly payment?
(ii) What is the total interest payment?
Answer:
Cost of house = ₹ 2500000
Down payment = ₹ 500000
Principal amount = ₹ (2500000 – 500000)
= ₹ 2000000,
n = 25 × 12 = 300
and i = \(\frac{9}{1200}\) = 0.0075

(i) We know that

Hence, monthly payment is ₹ 16782.27

(ii) We have, EMI = ₹ 16782.27
n = 300 and P = ₹ 2000000
Total interest = n × EMI – P
= 300 × 16782.27 – 2000000
= 5034681 – 2000000
= 3034681
Hence, total interest is ₹ 3034681.

Students can access the CBSE Sample Papers for Class 12 Accountancy with Solutions and marking scheme Term 2 Set 3 will help students in understanding the difficulty level of the exam.

CBSE Sample Papers for Class 12 Accountancy Standard Term 2 Set 4 with Solutions

Time Allowed: 2 Hours
Maximum Marks: 40

General Instructions:

• This question paper comprises two Parts – A and B. There are 12 questions in the question paper. Alt1 questions are compulsory.
• Part-A is compulsory for all candidates.
• Part-B has two options i.e., (i) Analysis of Financial Statements and (ii) Computerized Accounting. Students must attempt only one. of the given options.
• There is no overall choice. However, an internal choice has been provided in 3 questions of three marks and 1 question of five marks.

 PART-A
(Accounting for Not-for-Profit Organisations, Partnership Firms, and Companies)

Question 1.
How are the following dealt with while preparing Income and Expenditure Account for the year ended 31st March 2021? (2)
Receipts and Payments Account (An Extract)

Answer:
Income and Expenditure Account (An Extract) For the year ended 31st March, 2021

Question 2.
Differentiate between ‘Dissolution of Partnership’ and ‘Dissolution of Partnership Firm’ on the basis of:
(A) Court’s intervention
(B) Closure of Books (2)
Answer:
Difference between Dissolution of Partnership and Dissolution of Partnership Firm

Basis of Difference	Dissolution of Partnership	Dissolution of Partnership Firm
(A) Court’s Intervention	There is no intervention by the court.	Dissolution of partnership firm may be done with the given permission of court.
(B) Closure of Books	Books of accounts are not closed. It is continued by the remaining partners.	Books of accounts are dosed, as the business is discontinued.

Question 3.
Star and Moon are two partners sharing profits in the ratio of 2 :1. Give the journal entry at the time of dissolution in the following cases.
(A) Deferred revenue advertising expenditure appered at ₹ 90,000
(B) Profit and Loss A/c was appearing on the assets side of balance sheet at ₹ 1,80,000.
(C) An unrecorded investment realized at ₹ 18,000.
(D) Partner moon paid to a creditor ₹ 60,000 (2)
Answer:

Question 4.
How will you deal with the Entrance Fees while preparing the final accounts for the year ended 31st March, 2021, in each of the following cases:
(A) During the year 2020-21, Entrance Fees received ₹ 2,50,000. It is the policy of the club to treat the Entrance Fees as capital receipts.
(B) During the year 2020-21, Entrance Fees received ₹ 2,50,000. According to the policy of the club, 40% of the Entrance Fees is to be capitalized.
OR
From the following information provided by Moonlight Club, calculate the amount of subscriptions which will be treated as income for the year ended 31st March 2019:
(i) Subscriptions received during the year ended 31st March, 2019 amounted to ₹ 80,000.
(ii) Subscriptions outstanding in the beginning of the year ended 31st March 2019 amounted to ₹ 5,000.
(iii) Subscriptions not yet collected for the year ended 31st March 2019 amounted to ₹ 8,000.
(iv) Subscriptions received in advance for the year ended 31st March, 2020 amounted to ₹ 2,000. (3)
Answer:

Question 5.
In a partnership firm, Abhi, Shiva, and Vishnu were partners sharing profits and losses is the ratio of 5 :3: 2. The balance sheet of the firm as at 31st March 2020 is as under:

On 1st April 2020, Shiva retires from the firm and the new profit sharing ratio decided between Abhi and Vishnu is 3 :1. Following adjustments are agreed:
(i) Land and Building be written up by ₹ 88,000.
(ii) Plant and Machinery be reduced by ₹ 88,000.
(iii) Stock be written down by ₹ 8,440.
(iv) An amount of ₹ 8,800 included is Sundry debtors be written off as it is no longer receivable.
(v) A provision for doubtful debts be maintained at 5%.
(vi) There was an outstanding amount of Repairs of ₹ 4,800.
(vii) An amount of ₹ 5,600 included in sundry creditors be written back as no longer payable,
(viii) An old furniture written-afF previously was sold for ₹ 16,000 as scrap.
You are required to prepare the Revaluation Account of the firm, to give effect to the above adjustment. (3)
Answer:

Question 6.
On 9th April, 2021, Sunshine Ltd. issued 500, 10% Debentures of ₹ 1,000 each credited as fully paid-up to the promoters for their services to incorporate the company. On 18th May, 2021, the company issued 100, 10% Debentures of ₹ 1,000 each credited as fully paid-up to the underwriters towards their commission.
Pass necessary journal entries in the books of the company.
OR
Suhana Limited purchased machinery from Vikrant Manufacturers Limited. The company paid the vendors by issue of some equity shares and debentures and the balance through Bill payable on acceptance in their favour payable after three months. The accountant of the company, while journalizing the above-mentioned transactions left some items blank. You are required to fill in the blanks. (3)

Answer:

Question 7.
Following is the Balance Sheet of A and B as at 31st March, 2021:

The firm was dissolved on the above date under the following arrangement:
(i) A promised to pay off Mrs. A’s Loan and took Stock at ₹ 12,000.
(ii) B took half the Investments @ 10% discount.
(iii) Book Debts realised ₹ 57,000.
(iv) Trade Creditors and Bills Payable were due on average basis of one month after 31st March, but were paid immediately on 31st March @ 2% discount per annum.
(v) Plant realised ₹ 75,000; Building ₹ 1,20,000; Goodwill ₹ 18,000 and remaining Investments ₹ 13,500.
(vi) An old typewriter, written off completely from the firm’s books, now estimated to realise f 900. It was taken by B at this estimated price.
(vii) Realisation expenses were ₹ 3,000.
Prepare Realisation Account and Capital Accounts of Partners.
OR
Amit, Balan and Chander were partners in a firm sharing profits and losses in the proportion of \(\frac{1}{2}, \frac{1}{3} \text { and } \frac{1}{6}\) respectively. Chander retired on 31st March 2022. The Balance Sheet of the firm on the date of Chander’s retirement was as follows:
Balance Sheet
as on 31st March 2022

It was agreed that:
(i) Goodwill will be valued at ₹ 27,000.
(ii) Depreciation of 10% was to be provided on Machinery.
(iii) Patents were to be reduced by 20%.
(iv) Liability on account of Provident Fund was estimated at ₹ 2,400.
(v) Chander took over Investments for ₹ 15,800.
(vi) Amit and Balan decided to adjust their capitals in proportion of their profit sharing ratio by opening Current Accounts.
Prepare Revaluation Account and Partners’ Capital Accounts on Chander’s retirement. (5)
Answer:


Working Notes:
(1) Value of Investments taken over by B:
Book Value of Investments taken over by B = 50% of Total Investments
= \(\frac{50}{100} \times ₹ 30,000\)
= ₹ 15,000

Value of Investments taken over by B = Book Value of Investments taken over x \(\frac{90}{100}\)
=15,000x \(\frac{90}{100}\)
= ₹ 13,500
[Since Investment is taken over by B at a discount of 10%]

(2) Calculation of Amount paid to Creditors:
Amount paid to Creditors = Amount to be paid to Credftors – 2% Discount for 1 month
= ₹ 90,000- \(\left(₹ 90,000 \times \frac{2}{100} \times \frac{1}{12}\right)\)
= ₹ 90.000 – ₹ 150
= ₹ 89,850

(3) Calculation of Amount paid to BillS Payable:
Amount paid to Bills Pagable = Amount to be paid to Bills Payable – 2% Discount for 1 month
= ₹ 24,000 – \(\left(₹ 24,000 \times \frac{2}{100} \times \frac{1}{12}\right)\)
= ₹ 24,000 – ₹ 4O
= ₹ 23,960

Working Notes:
(1) Adjustment of Goodwill:
Goodwill of Firm = ₹ 27,000
Chander’s share of Goodwill = ₹ 27,000 x \(\frac{1}{6}\) = ₹ 4,500
which will be compensated by Amit and Balan in their Gaining Ratio. i.e, 3 : 2
Amit will compensate = ₹ 4,500 x \(\frac{3}{5}\) = ₹ 2,700
Balan wilL compensate = ₹ 4,500 x \(\frac{2}{5} \) = ₹ 1,800

(2) Adjustment of CapitoL:
Adjusted Old Capitol of Amit = ₹ 40,000 + ₹ 300 + ₹ 4, 500 – ₹ 2,700
= ₹ 42,100
Adjusted Old Capital of Batan = ₹ 36,500 + ₹ 200 + ₹ 3,000 — ₹ 1,800
= ₹ 37,900
Total Adjusted Capital of Amit and Batan = ₹ 42,100 + ₹ 37,900 = ₹ 80,000
New Profit Shoring Ratio of Amit and Batan = 3: 2
Amit’s New Capital = ₹ 80,000 x \(\frac{3}{5}\) = ₹ 48,000
BaLan’s New Capital = ₹ 80,000 x \(\frac{2}{5}\) = ₹ 32,000
Note: Since, here no information is given regarding the share acquired by Amit and Batan, therefore, their gaining ratio is same as their new profit sharing ratio, i.e 3: 2

Question 8.
Goel Iron Casts Industries engaged in production of Iron rods having registered office in Chandigarh was incorporated on 1st April 2016. To expand their business, company purchased a Plant from Faujdar Metal Limited to increase the production of iron rods. Goel Iron Casts Industries paid the amount to Faujdar Metal Limited as follows:
(i) By issuing 16,000,12% Debentures of ₹ 100 each at a discount of 10%.
(ii) By issuing 80,000, Equity Shares of ₹ 100 each at a premium of 10%.
(iii) Balance by accepting a bill of exchange of ₹ 4,00,000 payable after two months.

You are required to answer the following questions:
(A) Calculate the amount Goel Iron Casts Industries paid to Faujdar Metal Limited by issuing 12% Debentures.
(B) Calculate the purchase price of Plant.
(C) Calculate the amount of annual fixed obligation associated with debentures.
(D) Pass journal entry which will be passed at the time of purchase of Plant in the books of Goel Iron Casts Industries.
(E) Pass journal entry for the allotment of debentures. (5)
Answer:
(A) Amount Paid to Faujdar Metal limited by Issue of 12% Debentures
= 16,000 x [₹ 100 – (10% of ₹ 100)]
= 16,000 x ₹ 90 = ₹ 14,40,000

(B) Purchase Price of Plant = Amount Paid by Issue of Debentures + Amount Paid by Issue of Equity
Shares + Amount Paid by Bill of Exchange
= {16.000 x [₹ 100 – (10% of ₹ 100)J} + { 80,000 x [₹ 100 + (10% of ₹ 100)1} + ₹ 4,00,000
= (16.000 x ₹ 90) + (80,000 x ₹ 110) +₹ 4,00,000
= ₹ 14,40,000 +₹ 88,00.000 + ₹ 4,00,000
= ₹ 1,06,40,000

(C) Interest on 12% Debentures = ₹ 16,00,000 x \(\frac{12}{100}\) =₹ 1,92,000

(D) In the Books of Goel Iron Casts Industries Journal

Question 9.
Receipts and Payments Account of Sunderban Society Club for the year ended 31st March 2021 is as follows:
Receipts and Payments Account

Additional Information:

Particulars	31st March 2020 (₹ )	31st March 2021 (₹ )
Outstanding Subscriptions	7,000	5,600
Subscriptions Received in Advance	2,000	2,500
Salaries Outstanding	1,200	1,800
Furniture	10,000	–
Sports Equipment	20,000	–

Depreciate furniture by 20% and Sports Equipment by 30%.
You are required to prepare an Income and Expenditure Account for the year ended 31st March, 2021 and ascertain the Capital Fund on 31st March, 2020. (5)
Answer:
In the Books of Sunderban Society Club
Balance Sheet
as on 31st March. 2020

PART-B
Option-1
(Analysis of Financial Statements)

Question 10.
State which of the following transactions would result in inflow, outflow or no flow of Cash and Cash Equivalents:
(A) Decrease in Cash Credit.
(B) Sale of Current Investments. (2)
Answer:
(A) Decrease in Cash Credit wilt results in outflow of Cash and Cash Equivalents.
(B) Sale of Current Investments wilt result in no fLow of Cash and Cash Equivalents.

Question 11.
From the following Statement of Profit and Loss of Gokulnath Traders Limited as at 31st March 2020 and 2021, you are required to prepare Comparative Statement of Profit and Loss as at 31st March 2020 and 2021:

OR
You are provided with the Common Size Balance Sheet of Sushiksha Limited as at 31st March, 2022 with missing information. You are required to fill in the blanks:
In the Books of Sushiksha Limited
Common Size Balance Sheet
as at 31st March 2022 (3)

Answer:
Gotuknath Traders limited
Comparative Statement of Profit and Loss
for the years ended 31 March 2020 and 2021

OR
In the Books of Sushikshci Limited
Common Size BaLance Sheet
as at 31 March 2022

Question 12.
From the following Balance Sheet of Tamalika Limited as at 31st March 2019 and additional information, prepare Cash Flow Statement for the year ended 31st March 2019:
Statement of Profit and Loss
for the year ended 31st March 2019

Notes to Accounts:

Additional Information:
(i) During the year, Machinery costing ₹ 1,40,000 (accumulated depreciation provided thereon ₹ 1,10,000) was sold for ₹ 20,000.
(ii) During the year, Non-Current Investments costing ₹ 80,000 were sold at a profit of ₹ 16,000.
(iii) Additional debentures were issued on 31st March, 2019. (5)

Answer:
Tamatikci Limited Cash Flow Statement
for the year ended 31s March, 2021

Students can access the CBSE Sample Papers for Class 12 Accountancy with Solutions and marking scheme Term 2 Set 7 will help students in understanding the difficulty level of the exam.

CBSE Sample Papers for Class 12 Accountancy Standard Term 2 Set 7 with Solutions

Time Allowed: 2 Hours
Maximum Marks: 40

General Instructions:

• This question paper comprises two Parts – A and B. There are 12 questions in the question paper. Alt1 questions are compulsory.
• Part-A is compulsory for all candidates.
• Part-B has two options i.e., (i) Analysis of Financial Statements and (ii) Computerized Accounting. Students must attempt only one. of the given options.
• There is no overall choice. However, an internal choice has been provided in 3 questions of three marks and 1 question of five marks.

PART-A
(Accounting for Not-for-Profit Organisations, Partnership Firms and Companies)

Question 1.
Calculate the amount to be posted to the Income and Expenditure Account of Sangan Sports Academy for the year ended 31^st March, 2021 from the information given:
Stock of Sports Materials on 1^st April, 2020 – ₹ 60,000
Creditors for Sports Materials on 1^st April, 2020 – ₹ 40,000
Amount paid for Sports Materials during the year – ₹ 2,16,000
Stock of Sports Materials on 31^st March, 2021 – ₹ 10,000 (2)
Answer:

Question 2.
Differentiate between ‘Dissolution of Partnership’ and ‘Dissolution of Partnership Firm’ on the basis of:
(A) Economic Relationship
(B) Closure of Books (2)
Answer:
Difference between Dissolution of Partnership and Dissolution of Partnership Firm

Basis of Difference	Dissolution of Partnership	Dissolution of Partnership Firm
(A) Economic Relationship	Economic relationship changes between or among the partners.	Economic relationship between or among the partners comes to an end.
(B) Closure of Books	Books of accounts are not closed. It is continued by the remaining partners.	Books of accounts are closed, as the business is discontinued.

Question 3.
Pass journal entries for following transactions on the dissolution of a firm of partners X and Y, after various assets (other than cash) and outside liabilities have been transferred to Realisation Account?
(A) ‘X’ took 50% of the stock at a discount of 20%. Remaining stock was sold at a profit of 30% on csot (Book value of stock given in the Balance Sheet before dissolution was ₹ 8,00,000).
(B) Debtors ₹ 5,28,000. Provision for Doubtful Debts. ₹ 48,000, ₹ 96,000 of the book debts proved
bad. (2)
Answer:

Question 4.
From the following information given by Giani Sports Club, calculate the amount of Subscription received during the year 2020-21.
(i) Subscription credited to Income and Expenditure Account for the year ending 31^st March, 2021 amounted to ₹ 12,00,000. Each member of the club is required to pay an annual subscription of ₹ 12,000.
(ii) During the year 2019-20,12 members paid the subscription amount for the year 2020-21.
(iii) Subscription in arrears as on 1^st April, 2020 amounted to ₹ 64,000.
(iv) During the year 2020-21, 10 members made partial payment of ₹ 1,04,000 towards subscription, 8 members failed to pay the subscription amount and 5 members paid the subscription amount for the year 2021-22.
OR
Following is the Receipts and Payments Account of South Literary Club for the year ended 31^st March, 2021:

Additional Information:
(i) Subscriptions outstanding as on 31^st March, 2020 were ₹ 2,000 and on 31^st March, 2021 were ₹ 2,500.
(ii) On 31^st March, 2021 salary outstanding was ₹ 600 and rent outstanding was ₹ 1,200.
(iii) On 31^st March, 2020 the club owned Furniture of ₹ 15,000 and Books of ₹ 7,000.
You are required to prepare Income and Expenditure Account of South Literary Club for the year ended 31^st March, 2021. (3)
Answer:

Note: Subscription outstanding on 31-03-2021 is ₹ 2,500 which includes the subscription outstanding for the year 2019-20 ₹ 800 (i.e., ₹ 2,000 – ₹ 1,200 received during 2020-21). Hence, the subscription outstanding for the year 2020-21 is ₹ 1,700 (i.e. ₹ 2,500 – ₹ 800). it should be noted that there is a difference between subscription outstanding on 31-03-2021 and subscription outstanding for 2020-21 (which indicates that subscription outstanding only for 2020-21).

Question 5.
Arun, Bimal and Chandan were partners sharing profits in the ratio of 2 : 2 : 1. They decided to dissolve their firm on 31^st March, 2019 when the Balance Sheet was:

Following transactions took place:
(i) Arun took over Stock at ₹ 36,000. He also took over his wife’s loan.
(ii) Bimal took over half of Debtors at ₹ 28,000.
(iii) Chandan took over Investments at ₹ 54,000 and half of Creditors at their book value.
(iv) Remaining Debtors realised 60% of their book value. Furniture sold for ₹ 30,000; Machinery ₹ 82,000 and Land ₹ 1,20,000.
(v) An unrecorded asset was sold for ₹ 22,000.
(vi) Realisation expenses amounted to ₹ 4,000.
Prepare Realisation Account. (3)
Answer:

Question 6.
Pass the necessary journal entries for the issue of debentures for the following transactions:
(A) Renuka Traders Limited took over Plant and Machinery of ₹ 16,00,000 and liabilities of ₹ 6,00,000 from Unnati Limited for a purchase consideration of ₹ 12,00,000. The payment was made by issue of 12% Debentures of ₹ 100 each at 20% premium.

(B) On 1st April, 2021, Surya Limited issued 1,600, 12% Debentures of ₹ 500 each at a premium of 20%, to Chandani Limited for Plant purchased from them costing ₹ 9,60,000.
OR
Akanksha Limited issued 8% Debentures of the face value of ₹ 20,00,000 at a discount of 6% on 1st April, 2016. These debentures are redeemable by annual drawings of ₹ 4,00,000 made on 31^st March each year. The directors decided to write off discount based on the debentures outstanding each year.

Prepare Discount on Issue of Debentures Account of Akanksha Limited for five years. (3)
Answer:

Working Note:

= \(\frac{₹ 12,00,000}{₹(100+20)}\)
= 10,000

OR
Total Discount on the Issue of Debentures = ₹ 20,00,000 × \(\frac{6}{10}\) = ₹ 1,20,000
Since debentures are redeemable by annual drawings of ₹ 4,00,000, the amount of discount written off from Statement of Profit and Loss is determined as follows:

*Ratio has been obtained by dividing Debentures Outstanding by ? 4,00,000.

Question 7.
Aman, Jay and Kant are partners in firm ‘Ajaka Limited’ sharing profits and losses in the ratio of 3 : 2 : 1. They decided to dissolve their firm on 31^st March, 2020, the date on which their Balance Sheet stood as:

The following additional information is given:
(i) The Investments are taken by Aman for ₹ 5,000 in settlement of his loan.
(ii) Assets were realised as follows:
Stock – ₹ 17,500
Debtors – ₹ 14,500
Furniture – ₹ 6,800
Machinery – ₹ 30,300

(iii) Expenses on realisation amounted to ₹ 2,000.
Prepare Realisation Account and Partners’ Capital Account at the time of dissolution of the partnership firm ‘Ajaka Limited’.
OR
On 31^st March, 2022, the Balance Sheet of Pooja, Qureshi and Ross, who were partners in Pukaro Limited was as under:

Qureshi died on 1^st July, 2022. The profit sharing ratio of the partners was 2 : 1 : 1. On the death of a partner, the partnership deed provided for the following:

(i) His share in the profits of the firm till the date of his death will be calculated on the basis of average profits of last three completed years.

(ii) Goodwill of the firm will be calculated on the basis of total profit of last two years.

(iii) Interest on loan given by the firm to a partner will be charged at the rate of 6% p.a. or ₹ 4,000, whichever is more.

(iv) Profits for the last three years 2019-20, 2020-21 and 2021-22 were ₹ 45,000, ₹ 48,000 and ? 33,000 respectively.

You are required to prepare Qureshi’s Capital Account to be rendered to his executors. Also show the working notes clearly. (5)
Answer:

OR

Working Notes:
(1) Calculation of Profit Sharing Ratio:
Old Profit Sharing Ratio of Pooja, Qureshi and Ross = 2 : 1 : 1
New Profit Sharing Ratio of Pooja and Ross = 2 : 1 and
Gaining Ratio of Pooja and Ross = 2 : 1

(2) Calculation of Qureshi’s Share of Goodwill:
Goodwill of Firm = ₹ 48,000 + ₹ 33,000 = ₹ 81,000
Qureshi’s Share of Goodwill = ₹ 81,000 × \(\frac{1}{4}\) = ₹ 20,250
This share of Goodwill will be contributed by Pooja and Ross in their gaining ratio, i.e, 2 : 1.
Pooja will contribute = ₹ 20,250 × \(\frac{2}{3}\) ₹ 13,500
Ross will contribute = ₹ 20,250 × \(\frac{1}{3}\) = ₹ 6,750

(3) Calculation of Qureshi’s Share of Profit till the date of his death:
Average prifit of last three years = \(\frac{45,000+48,000+33,000}{3}\) = ₹ 42,000
Qureshi’s Share of Profit till the date of his death
= Previous year’s Profit × Qureshi’s Share ×
= ₹ 42,000 × \(\frac{1}{4} \times \frac{3}{12}\) = ₹ 2,625

(4) Calculation of Qureshi’s Share in Reserve Fund:
Qureshi’s Share in Reserve Fund = ₹ 2,00,000 × \(\frac{1}{4}\) = ₹ 50,000

(5) Calculation of Amount due on account of Loan given to Qureshi:
Loan given to Qureshi by firm = ₹ 1,00,000
Amount of Interest till 1st July, 2022 = ₹ 1,00,000 × \(\frac{6}{100} \times \frac{3}{12}\) = ₹ 1,500

Total Amount due to firm on 1^st July = Loan given to Qureshi by firm + Amount of Interest
= ₹ 1,00,000 + ₹ 4,000 [As ₹ 4,000 > Amount of Interest]
= ₹ 1,04,000

Question 8.
Pacific Foods Limited, a FMCG company has an equity share capital of ₹ 20,00,000. The company earns a return on investment of 15% on its capital. The company needed funds for diversification. The finance manager had the following two options:
(i) Borrow ₹ 10,00,000 @ 15% p.a. from a bank payable in four equal quarterly instalments starting from the end of the fifth year.
(ii) Issue ₹ 10,00,000, 9% Debentures of ? 100 each to the public at par, redeemable after five years at a premium of 10%.

After all deliberations, on 1st April, 2021, the board of directors of the company opted for option (ii), to increase the return to the shareholders. The Balance Sheet of the company on 1^st April, 2021 shows a balance of ₹ 3,00,000 in Capital Reserve which the company decided to use for writing off the discount on issue of debentures.
You are required to answer the following questions:
(A) Pass journal entry for receipt of application money of debentures.
(B) Pass journal entry to be passed at the time of allotment of debentures.
(C) Pass journal entry to write ofFloss on issue of debentures.
(D) Prepare Loss on Issue of Debentures Account.
(E) Calculate the amount of annual fixed obligation associated with debentures. (5)
Answer:


(E) Interest on 9% Debentures = ₹ 10,00,000 × \(\frac{9}{100}\) = ₹ 90,000

Question 9.
Following is the Receipts and Payments Account of Jalandhar Sports Club for the year ending 31^st March, 2021:

Additional Information:
(i) Subscriptions outstanding was ₹ 1,200 on March 31, 2020 and ₹ 3,200 on March 31, 2021.
(ii) Locker rent outstanding on March 31, 2021 was ₹ 250.
(iii) Salary outstanding on March 31, 2021 was ₹1,000.
(iv) Fixed Deposit was made on 1st January, 2021 @10% p.a.
(v) On April 1, 2020, club has following assets: Building ₹ 36,000, Furniture ₹ 12,000, and Sports Equipments ₹ 17,500. Depreciation on these items is to be charged at 10% (including purchase).
You are required to prepare Income and Expenditure Account for the year ending 31^st March, 2021 and also ascertain the Capital Fund as on 31st March, 2020. (5)
Answer:

PART-B
Option-1
(Ana Lysis of Financial Statements)

Question 10.
Classify the following transactions as Operating Activities for a financial company and a Non- Financial Company:
(A) Payment of Interest
(B) Royalty received (2)
Answer:
(A) Payment of Interest – Financial Company
(B) Royalty received – Non-Financial Company

Question 11.
Prepare Comparative Statement of Profit and Loss from the following information:

Particulars	31st March, 2021	31st March, 2020
Revenue from Operations	₹ 75,00,000	₹ 50,00,000
Other Income	₹ 9,00,000	₹ 10,00,000
Cost of Materials Consumed	₹ 45,00,000	₹ 25,00,000
Other Expenses	₹ 7,50,000	₹ 5,00,000
Tax Rate	50%	50%

OR
You are required to prepare Common Size Balance Sheet of Revati Trading Limited as at 31^st March, 2020 and 2021.

You are required to prepare Common Size Balance Sheet of Revati Trading Limited as at 31^st March, 2020 and 2021. (3)
Answer:

OR

Question 12.
Prepare Cash Flow Statement for the year ended 31st March, 2020 from the following Balance Sheet of Sanskar Limited as at 31^st March, 2020 and additional information provided:

Notes to Accounts:

Additional Information:
(i) An old machinery having book value of? 50,000 was sold for ₹ 60,000.
(ii) Depreciation provided on Plant and Machinery during the year was ₹ 30,000. (5)
Answer:

Working Notes:

Students can access the CBSE Sample Papers for Class 12 Applied Mathematics with Solutions and marking scheme Term 2 Set 5 will help students in understanding the difficulty level of the exam.

CBSE Sample Papers for Class 12 Applied Mathematics Term 2 Set 5 with Solutions

Maximum Marks : 40
Time : 2 Hours

Instructions:

• The question paper is divided into 3 sections-A, B and C
• Section A comprises of 6 questions of 2 marks each. Internal choice has been provided in two questions.
• Section B comprises of 4 questions of 3 marks each. Internal choice has been provided in one question.
• Section C comprises of 4 questions. It contains one case study based question. Internal choice has been provided in one question.

Section – A [12 Marks]

Question 1.
Evaluate

Or
The marginal cost function of producing x units of a product is given by
MC = \(\frac{x}{\sqrt{x^{2}+3600}}\). Find the total cost function and the average cost function, if the fixed cost is ₹ 1000.
Answer:

Question 2.
Calculate the 3-yearly moving average of the following data.

Answer:

∴ 3-Yearly moving averages are 3.67,5.33,6.67, 8.33 and 10.33.

Question 3.
Find the effective rate of interest corresponding to 10% nominal rate compounded quarterly, [given (1.025) =1.1038]
Or
Find the present value of a sequence of payments of ₹ 4500 made at the end of every 6 months continuing, if money is worth 8% converted half-yearly.
Answer:
Given, nominal rate of interest,
r = 10% = 0.10
Since, interest is compounded quarterly.
∴ Number of conversion per year (m) = 4
We know that effective rate of interest
r_e = (1 + \(\frac{r}{m}\))^m – 1
= (1 + \(\frac{0.10}{4}\))⁴ – 1
= (1 + 0025)⁴ – 1
= (1025)⁴ – 1
= 1.1038 – 1
= 0.1038
= 10.38%

Or

Given, R = ₹ 4500
and rate of interest (r) = 8% = 0.08
Since, interest is compounded semi-annually.
∴ i = \(\frac{r}{2}=\frac{0.08}{2}\) = 0.04
Present value of an immediate perpetuity is
P = \(\frac{R}{i}\) ⇒ P = \(\frac{4500}{0.04}\)
= ₹ 112500

Question 4.
What sum of money invested now would establish a scholarship of ₹ 12000 to be awarded at the starting of each year to a deserving student, if money is worth 5% compounded annually?
Answer:
Given, R = ₹ 12000
i = \(\frac{5}{100}\) = 0.05

∴ Present value of a perpetuity due,
P = R(1 + i)
= 12000(1 + \(\frac{1}{0.05}\)
= 12000(1 + 20)= 12000 × 21= 252000
∴ Amount to be invested is ₹ 252000.

Question 5.
A random sample of size 25 has 60 as mean. The sum of squares of deviations from mean is 168, can this sample be regard as taken from the population having 64 as mean? Level of significance is 5%.
Answer:
Consider, H₀: µ = 64
H₁: µ > 64
n = 25, x̄ = 60, µ = M
and Σ(x_i – x̄)² = 168

Degree of freedom =25- 1=24
∴ Tabulated value of t = 1.711
Since, calculated value |t| = 7.55 is greater than
the tabulated value, so H₀ is rejected.

Question 6.
Two tailors A and B earn ₹ 300 and ₹ 400 per day, respectively. A can stitch 6 shirts and 4 pairs of trousers while B can stitch 10 shirts and 4 pairs of trousers per day.
To find how many days should each of them work and if it is desired to produced at least 60 shirts and 32 pairs of trousers at a minimum labour cost. Formulate this problem as on LPP.
Answer:
Suppose, tailor A works for x days and tailor B works for y days.

The given data can be written in the tabulor form as follows

Required linear programming problem is Min Z = 300x + 400y
Subject to constraints are 6x + 10y ≥ 60,
4x + 4y ≥ 32 ⇒ x + y ≥ 8 and
x,y ≥ 0

Section – B [12 Marks]

Question 7.
Mr. Amit have set up a sinking fund in order to have ₹ 40000 in 12 yr for his son’s higher education. What amount he has to set aside at the end of every month into the fund paying 6% per annum compounded monthly? [given, (1.005)¹⁴⁴ = 205]
Answer:
Given, A = ₹ 40000
i = \(\frac{r}{12 \times 100}=\frac{6}{12 \times 100}\)
= 0.005
n = 12 × 12 = 144 months

∴ The monthly periodic payments,

Question 8.
Find the f-test value for the following two samples from a population.
Set-I 6, 8, 5, 7
Set-II 4, 6, 5, 8
Answer:
x̄ = \(\frac{6+8+5+7}{4}=\frac{26}{4}\) = 6.5
and ȳ = \(\frac{4+6+5+8}{4}=\frac{23}{4}\) = 5.75

∴ S² = \(\frac{1}{n_{1}+n_{2}-2}\)[Σ(x – x̄)² + Σ(x – ȳ)²]
= \(\frac{1}{6}\)[5 + 8.9325]

Here, Σ(x – x̄)² = (-0.5)² + (1.5)²
+ (-1.5 )² + (0.5 )² = 0.25 + 2.25 + 2.25 + 0.25 = 5
and Σ(x – ȳ)² = (-1.75)² + (0.5)² + (- 0.75)² + (2.25 )²
= 306 + 0.25 + 0.5625 + 5.06 = 8.9325
⇒ S² = \(\frac{1}{6}\) (13.9325) = 2.3220 ⇒ S = 1.52

Question 9.
Consider the following data

Calculate 3-days moving average and display these and the original figures on the same graph.
Answer:
Given, table is shown below:

Dates in April	Number of unit sold
12	2
13	5
14	0
15	12
16	13
17	25
18	45
19	13
20	31
21	18
22	11
23	2
24	3
25	1

On the basis of above data, we can draw the following graph.

Question 10.
The demand function of a product is p = 10e^-x. Find the consumer’s surplus, when the market price at p₀ = 1. [given, log₁₀ e = 0.4343]
Or
The demand and supply functions for a commodity are p = x² – 6x +16 and p = \(\frac{x^{2}}{3}+\frac{4 x}{3}\) + 4, respectively. Find the equilibrium point assuming x ≤ 5.
Answer:
The demand function is p = 10e^-x
It is given that p₀ = 1
On putting the value of p₀ = 1 in p = 10e^-x, we get
I = 10e^-x ⇒ e^-x = 10
⇒ x = log_e10
∴ x₀ = log_e10

Then, consumer’s surplus is given by

Or
The demand and supply functions are p= D(x) and p = S(x),
where D(x) = x² – 6x +16 and S(x) = \(\frac{x^{2}}{3}+\frac{4 x}{3}\) + 4

The equilibrium point (x0, p0) is the point at which the demand supply curves intersect
∴D(x) = S(x)
x² – 6x +16 = \(\frac{x^{2}}{3}+\frac{4 x}{3}\) + 4
\(\frac{2}{3}\)x² – \(\frac{22}{3}\)x + 12 + 0
x² – 11x + 18 = 0
(x – 2)(x – 9) = 0 ⇒ x = 2 [∵ x ≤ 5]
On putting x = 2 in D(x), we get
P = (2 )² – 6(2) + 16
p = 4 – 12 + 16 = 8
Hence, (2, 8) is the equilibrium point.

Section – C [16 Marks]

Question 11.
If Mr. Nirav deposits ₹ 250 at the beginning of each month in an account that pays an interest of 6% per annum compounded monthly, how many months will be required for the deposit to amount to at least ₹ 6390?
Answer:
Given, Mr. Nirav deposit amount per month is a = ₹ 250
The total amount of annuity is (M) = ₹ 6390
Rate of interest, r = 6% = \(\frac{6}{100}\) per annum

Let the number of months be n.
We know that

⇒ 0.127164 + 1 = (1.005)ⁿ
⇒ 1.127164 = (1.005)ⁿ
Taking log on both sides of Eq. (i), we get
log 1.127164 = n log 1.005
⇒ n = \(\frac{\log (1.127164)}{\log (1.005)}\) = 24110075
∴Number of months required = 24 months

Question 12.
Mr. Ankit has invested ₹ 6 lakhs in a financial plan and after the completion of 5 yr. He received a sum of ₹ 10 lakhs. Find
(i) the absolute return.
(ii) the simple annual growth rate (SAGR).
(iii) the compound annual growth rate (CAGR). [given, (1.66)^1/5 =1.1067]
Answer:
Given, BV = ₹ 600000
EV = ₹ 1000000
n = 5 yr

Question 13.
In a bank principal increases at the rate of 5% per year. An amount of ₹ 1000 is deposited with this bank, how much will it be worth after 10 yr (given, e^0.5 = 1.648)?
Or
Suppose, it is given that the rate at which some bacteria multiply is proportional to the instantaneous number present. If the original number of bacteria triples in three hours. In how many hours will it be four times.
Answer:
Let P and t be the principal and time, respectively.
It is given that the principal increases continuously at the rate of 5% per year.
So, \(\frac{d P}{d t}\) = 5%of P ⇒ \(\frac{d P}{d t}=\frac{5}{100}\)P
On separating the variable, we get \(\frac{d P}{P}=\frac{1}{20}\) dt

On integrating both sides, we get
∫ \(\frac{d P}{P}\) = ∫ \(\frac{1}{20}\) dt ⇒ log |P| = \(\frac{1}{20}\)t + C …(i)
When t = 0, P = ₹ 1000 (initialy) this
log 1000 = C …(ii)
On putting the value of C in Eq. (i), we get

Hence, after 10 yr, the amount will worth ₹ 1648

Or

Let the original count of bacteria be N₀ and at any time the count of bacteria be N.
Then, \(\frac{d N}{d t}\) ∝ N ⇒ \(\frac{d N}{d t}\) = kN ⇒ \(\frac{d N}{N}\) = kdt

On integrating both sides, we get
∫\(\frac{d N}{N}\) = ∫kdt
⇒ logN = kt + C
⇒ N = e^kt+C
⇒ N = e^Ce^kt
⇒ N = Aêt
When t = O, then N = N₀, we get A = N₀
∴ N = N₀e^kt
When t = 3, N = 3N₀
∴ 3N₀ = N₀e^3k ⇒ e^3k = 3
= e^k = (3)e^1/3
When N = 4N₀
∴ 4N₀ = N₀e^kt
⇒ e^kt = 4
⇒ (3^1/3)^t = 4
⇒ t = \(\frac{3 \log 4}{\log 3}\)h

Case Based/Data Based

Question 14.
A company manufactures three kinds of calculators A, B and C in its two factories I and II. The company has got an order for manufacturing atleast 6400 calculators of kind A, 4000 of kind B and 4800 of kind C. The daily output of factory I is of 50 calculators of kind A, 50 calculators of kind B and 30 calculators of kind C.
The daily output of factory II is 40 calculators of kind A, 20 of kind B and 40 of kind C. The cost per day to run factory I is ₹ 12000 and of factory II is f 15000. Let factory71 run x days and factory II run y days.
On the basis of above information, answer the following question.
(i) Formulate this problem as an LPP.
Answer:
Total cost (in ₹) = 12000x + 15000y
Then, minimise Z = 12000x + 15000y

Subject to constraints are,
50x + 40y ≥ 6400 or 5x + 4y ≥ 640 …(i)
50x +20y ≥ 4000 or 5x +2y ≥ 400 …(ii)
30x + 40y ≥ 4800 or 3x + 4y ≥ 480 …(iii)
and x ≥ 0, y ≥ 0 …………(iv)

(ii) How many days do the factory I has to be in operation to produce the order with the minimum cost?
Answer:
The above Eqs. (i), (ii), (iii) and (iv) can be represented graphically as

Clearly, the feasible region ABCD (shaded region), where comer points are A (160,0), B(80,60), C(32,120)and D(0,200)is unbounded.

The values of Z at comer points are given below:

Corner points	Value of Z = 12000X + 15000y
A(160, 0)	Z = 12000 × 160 + 15000 × 0 = 1920000
B(80, 60)	Z = 12000 × 80 + 15000 × 60 = 1860000 (Minimum)
C(32,120)	Z = 12000 × 32 + 15000 × 120 = 2184000
D(0, 200)	Z = 12000 × 0 + 15000 × 200 = 3000000

In the above table, we find that minimum value of Z is 1860000 occur at the point B (80,60).
But we cannot say that it is a minimum value of Z as region is unbounded.

Therefore, we have to draw the graph of the inequality
12000x + 15000y < 1860000
or
12x + 15y < 1860
or
\(\frac{x}{155}+\frac{y}{124}\) < 1

Now, check whether the resulting open half plane has any point common with feasible region. From figure, we see that it has no point in common.

Thus, the minimum value of Z is ₹ 1860000 attained at the point B(80,60).
Hence, factory I should run for 80 days.

Students can access the CBSE Sample Papers for Class 12 Accountancy with Solutions and marking scheme Term 2 Set 6 will help students in understanding the difficulty level of the exam.

CBSE Sample Papers for Class 12 Accountancy Standard Term 2 Set 6 with Solutions

Time Allowed: 2 Hours
Maximum Marks: 40

General Instructions:

• This question paper comprises two Parts – A and B. There are 12 questions in the question paper. Alt1 questions are compulsory.
• Part-A is compulsory for all candidates.
• Part-B has two options i.e., (i) Analysis of Financial Statements and (ii) Computerized Accounting. Students must attempt only one. of the given options.
• There is no overall choice. However, an internal choice has been provided in 3 questions of three marks and 1 question of five marks.

PART-A
(Accounting for Not-for-Profit Organisations, Partnership Firms and Companies)

Question 1.
From the following information provided by Reunion Club, calculate the amount of subscriptions which will be treated as income for the year ended 31^st March, 2019:
(i) Subscriptions received during the year ended 31^st March, 2019 amounted to ₹ 25,000.
(ii) Subscriptions outstanding in the beginning of the year ended 31st March, 2019 amounted to ₹ 3,000.
(iii) Subscriptions outstanding for the year ended 31^st March, 2019 amounted to ₹ 5,500.
(iv) Subscriptions not yet collected for the year ended 31^st March, 2019 amounted to ₹ 5,000. (2)
Answer:

Question 2.
Babita, Chetan and Dhanush were partners in a firm sharing profits and losses in the ratio of 1 : 4 : 5. On 31^st March, 2020 the firm was dissolved and on that date the Balance Sheet of the firm showed a loan of ₹ 10,000 given by Chetan’s brother Rohan. Chetan agreed to pay his brother’s loan.

Pass necessary journal entry for the above on the firm’s dissolution. (2)
Answer:

Question 3.
Preeti, Kareena and Rani were partners sharing profits in the ratio of their Capital contribution which were ₹ 6,00,000; ₹ 4,00,000 and ₹ 5,00,000 respectively. Their books are closed on 31^st March every year. Preeti dies on 24th August, 2020.

Under the partnership deed, deceased partner is entitled to her share of profit/loss to the date of death based on the average profits of preceding four years.
Profits were:
2016-17 – ₹ 50,000
2017-18 – ₹ 20,000 (Loss)
2018-19 – ₹ 30,000
2019-20 – ₹ 60,000
Pass necessary journal entry for the treatment of profit and also show your workings clearly. (2)
Answer:

Working Notes:
Average Profit/(Loss) = \(\frac{₹ 50,000-₹ 20,000+₹ 30,000+₹ 60,000}{4}\)
= ₹ 30,000
Number of Days from 01.04.20 to 24.08.20 = 30 + 31 + 30 + 31 + 24 = 146
Preeti’s share of Profit upto the date of her death = ₹ 30,000 × \(\frac{6}{15} \times \frac{146}{365}\)
= ₹ 4,800

Question 4.
Show how are the following items dealt with while preparing the final accounts of Fitness Sports Club for the year ended 31^st March, 2020:
(i) Expenditure on construction of Stadium is ₹ 6,00,000. The construction work is in progress and has not yet completed.
(ii) Stadium Fund as at 31^st March, 2019 is ₹ 10,00,000, and Capital Fund as at 31^stMarch, 2019 is ₹ 20,00,000.
(iii) Donation Received for Stadium on 1st January, 2020 is ₹ 5,00,000.
OR
The book value of Machinery on 1^st April, 2020 is ₹ 1,20,000. Half of this Machinery is sold for ₹ 40,000 on 30th September, 2020. Depreciation is to be charged on Machinery @ 10% p.a.
Calculate loss on sale of Machinery. Show how the loss on sale and depreciation on Machinery will be shown in the Income and Expenditure Account for the year ended 31st March, 2021. (3)
Answer:

OR

Working Note:
Calculation of Profit or Loss on Sale of Machinery

Question 5.
In a partnership firm, Guruprakash and Sadguru were partners sharing profits and losses is the ratio of 3 : 1. On 1st April, 2019 partners decided to dissolve the firm.
After transferring the assets (other than cash) and outsider’s liabilities of the firm to Realisation Account, you are given the following information:
(i) A creditor of ₹ 1,44,000 accepted furniture valued at ₹ 2,00,000 and paid to the firm ₹ 56,000.
(ii) A second creditor for ? 20,000 accepted stock at ₹ 18,000 in full settlement of his claim.
(iii) A third creditor amounting to ₹ 36,000 accepted ₹ 18,000 is cash and investment worth ₹ 17,200 is full settlement of his claim.
(iv) Loss on dissolution of the firm was ₹ 6,000.

Pass the necessary journal entries for the above transaction in the books of the partnership firm assuming that all payments were made by cheque. (3)
Answer:

Question 6.
XYZ Ltd. issued 5,000, 10% Debentures of ₹ 100 each on 1^st April, 2015 at a discount of 10%, redeemable at a premium of 10% after four years.
Pass necessary journal entries in the books of XYZ Ltd. for debenture interest for the year ended 31^st March, 2016, assuming that the interest on debentures was payable half-yearly on 30^th September and 31^st March. The rate of tax is 10%.
OR
Dauji Bros. Limited purchased the business of Mohan Bros. Limited consisting assets of the book value ₹ 20,00,000 and the liabilities of ₹ 2,50,000. It was agreed that the purchase consideration, settled at ? 19,00,000 be paid by issuing 12% Debentures of ₹ 100 each.
Pass journal entries in the books of the firm, if the debentures are issued:
(A) at a discount of 10%; and
(B) at a premium of 10%.
It was agreed that any fraction of debentures be paid in cash. (3)
Answer:


OR

(A) When Debentures are issued at 10% Discount:

Working Note:

= \(\frac{₹ 19,00,000}{₹(100-10)}\)
= \(\frac{₹ 19,00,000}{₹(100-10)}\)
= 21,111.11 or 21,111

(B) When Debentures are issued at 10% Premium:

Working Note:

= \(\frac{₹ 19,00,000}{₹(100+10)}\)
= \(\frac{₹ 19,00,000}{₹ 110}\)
= 17,272.72 or 17,272

Question 7.
Balance Sheet of X, Y and Z who shared profits in the ratio of 5 : 3 : 2, as on 31^st March, 2019 was as follows:

Y retired on 1^st April, 2019 and it was agreed between the partners that:
(i) Goodwill of the firm is valued at ₹ 1,12,500 and Y’s share of it be adjusted into the accounts of X and Z who are going to share future profits in the ratio of 3 : 2.
(ii) Fixed Assets be appreciated by 20%.
(iii) Stock of the firm be reduced to ₹ 75,000.
(iv) Y be paid amount brought in by X and Z so as to make their capitals proportionate to their new profit sharing ratio.
Prepare Capital Account of Partners at the time of Y’s retirement and the Balance Sheet of the New Firm.
OR
Balance Sheet of Leena, Meena and Neena as at 31^st March, 2021, who were sharing profits in the ratio of 5 : 3 :1, was:

The partners decided to dissolve the business on 31^st March, 2021.
The Assets of the business were realised as follows:
(i) Stock realised ₹ 23,400.
(ii) Debtors realised 50% amount.
(iii) Other Fixed Assets were realised at 10% less than their book value.
Bills Payable were settled for ₹ 32,000. There was an Outstanding Bill of Electricity of ₹ 800 which was paid off. Realisation expenses ₹ 1,250 were also paid.
You are required to prepare Realisation Account, Partner’s Capital Accounts and Bank Account of the firm. (5)
Answer:

Working Notes:
(1) Calculation of Gaining Ratio:
Old Profit Sharing Ratio of X, Y and Z = 5 : 3 : 2
New Profit Sharing Ratio of X and Z = 3 : 2
Gaining Ratio = New Profit Sharing Ratio – Old Profit Sharing Ratio
X’s Gain = \(\frac{3}{5}-\frac{5}{10}\) = \(\frac{6-5}{10}-\frac{1}{10}\)
Z’s Gain = \(\frac{2}{5}-\frac{2}{10}=\frac{4-2}{10}=\frac{2}{10}\)
Gaining Ratio of X and Z = 1 : 2

(2) Adjustment of Goodwill:
Goodwill of Firm = ₹ 1,12,500
Y’s share of Goodwill = ₹ 1,12,500 × \(\frac{3}{10}\) = ₹ 33,750
which will be compensated by X and Z in their gaining ratio, i.e., 1 : 2
X will compensate = ₹ 33,750 × \(\frac{1}{3}\) = ₹ 11,250
Z will compensate = ₹ 33,750 × \(\frac{2}{3}\) = ₹ 22,500
(3)

(4) Adjustment of Capital:
Adjusted Capital of X = ₹ 1,65,000 + ₹ 11,250 + ₹ 15,000 – ₹ 11,250 = ₹ 1,80,000
Adjusted Capital of Y = ₹ 84,000 + ₹ 6,750 + ₹ 9,000 + ₹ 11,250 + ₹ 22,500 = ₹ 1,33,500
Adjusted Capital of Z = ₹ 66,000 + ₹ 4,500 + T 6,000 – ₹ 22,500 = ₹ 54,000
New Capital of Firm = ₹ 1,80,000 + ₹ 1,33,500 + ₹ 54,000 = ₹ 3,67,500
X’s New Capital = ₹ 3,67,500 x \(\frac{3}{5}\) = ₹ 2,20,500
Z’s New Capital = X 3,67,500 x \(\frac{2}{5}\) = ₹ 1,47,000
X brings \n = ₹ 2,20,500 – ₹ 1,80,000 = ₹ 40,500
Z brings in = ₹ 1,47,000 – ₹ 54,000 = ₹ 93,000
OR

Question 8.
Suhana Textiles Limited was incorporated on 1st April, 2015 with registered office in Gujarat. The company is growing year by year, and begins to expand its operations throughout India. To expand their business in Rajasthan, directors of the company decided to purchase one of the well- known textile firms of Rajasthan, Jaipuriya Textiles Limited,

On 1^st April, 2021 Suhana Textiles Limited bought the business of Jaipuriya Textiles Limited consisting sundry assets of ₹ 36,00,000 and sundry creditors of ₹ 10,00,000 for a consideration of ₹ 30,72,000.

Suhana Textiles Limited issued 12% Debentures of ₹ 100 each fully paid, at a discount of 4% in satisfaction of purchase consideration to Jaipuriya Textiles Limited. On 10th June, 2021, the company also issued 500,10% Debentures of ₹ 100 each credited as fully paid-up to the promoters for their services to incorporate the company.

You are required to answer the following questions:
(A) Calculate the amount of Goodwill purchased by Suhana Textiles Limited of Jaipuriya Textiles Limited.
(B) Pass journal entry for the purchase of business of Jaipuriya Textiles Limited.
(C) Calculate the number of debentures issued to Jaipuriya Textiles Limited.
(D) Pass journal entry for the allotment of debentures to Jaipuriya Textiles Limited.
(E) Pass journal entry for the allotment of debentures to the underwriters. (5)
Answer:
(A) Amount of Goodwill = Purchase Consideration – (Value of Assets – VaLue of Liabilities)
= ₹ 30,72,000 – (₹ 36,00,000 – ₹ 10,00,000)
= ₹ 4,72,000

Question 9.
From the following Receipts and Payments Account and information given below, prepare Income and Expenditure Account and Balance Sheet of Superior Literacy Organisation as on 31^st March, 2020.

Additional Information:
(i) Subscriptions outstanding as on 31^st March, 2019 was ₹ 8,000 and on 31st March, 2020 was ₹ 6,000.
(ii) Fixed Deposit with Bank was made on 30th September, 2019 @10% p.a.
(iii) On 31st March, 2020 Salary outstanding ? 2,400, and one month Rent paid in advance.
(iv) On 1st April, 2019, Superior Literacy Organisation owned Furniture of ₹ 48,000, Books of ₹
20,000. (5)
Answer:


Working Note:
(1) Calculation of Prepaid Rent:
Prepaid Rent (for Year 2020-21) = ₹ 26,000 x \(\frac{1}{13}\) = ₹ 2,000

PART-B
Option-1
(Analysis of Financial Statements)

Question 10.
Identify the following transactions as belonging to Operating Activities, Investing Activities, Financing Activities or Cash and Cash Equivalents:
(A) Cash paid against Services taken.
(B) Bank Overdraft (2)
Answer:
(A) Cash paid against Services taken – Operating Activities
(B) Bank Overdraft – Financing Activities

Question 11.
Explain some advantages of Common Size Statements.
OR
You are provided with the Comparative Balance Sheet of Picasso Limited with missing information. You are required to fill in the blanks:

(3)
Answer:
The advantages of Common Size Statements are as follows:
(i) Easy to Understand: Common Size Statement helps the users of financial statement to make clear about the ratio or percentage of each individual item to total assets/liabilities of a firm. For example, if an analyst wants to know the working capital position he may ascertain the percentage of each individual component of current assets against total assets of a firm and also the percentage share of each individual component of current liabilities.

(ii) Comparison at a Glance: An analyst can compare the financial performances at a glance since percentage of increase or decrease of each individual component of cost, assets, liabilities etc. are available and he can easily ascertain his required ratio.

(iii) Helpful for Time Series Analysis: A Common Size Statement helps an analyst to find out a trend relating to percentage share of each asset in total assets and percentage share of each liability in total liabilities.

(iv) Helpful in analysing Structural Composition: A Common Size Statement helps the analyst to ascertain the structural relations of various components of cost/expenses/assets/liabilities etc. to the required total of assets/liabilities and capital.
OR

Question 12.
Following is the summarised Balance Sheet of Philips India Ltd. as at 31^st March 2020:


Additional Information:
(i) Investments costing ? 24,000 were sold during the year for ₹ 25,500.
(ii) Provision for Tax made during the year was ₹ 27,000.
(iii) During the year, a part of the Fixed Assets costing ₹ 30,000 was sold for ₹ 36,000. The profits were included in the Statement of Profit and Loss.
(iv) The Interim Dividend paid during the year amounted to ₹ 1,20,000.
You are required to prepare Cash Flow Statement for the year ended 31st March, 2020. (5)
Answer:

Students can access the CBSE Sample Papers for Class 12 English with Solutions and marking scheme Term 2 Set 12 will help students in understanding the difficulty level of the exam.

CBSE Sample Papers for Class 12 English Term 2 Set 12 for Practice

Time Allowed: 2 Hours
Maximum Marks: 40

General Instructions:

• The Question Paper contains THREE sections-READING, WRITING and LITERATURE.
• Attempt questions based on specific instructions for each part.

Section – A
Reading (14 Marks)

Question 1.
Read the passage given below.

Child marriages are rampant in North India. The curse continues to blight the lives of people even as the country stands at the threshold of the 21st century. Children bound by marriage are victims of blind customs and superstitions prevalent in rural areas and in certain urban.

5. concentrations as well among the weaker socio-economic groups. Nothing seems to stop this anti-social practice despite the Child Marriage Act passed as early as in 1929, which makes child marriage, a grave offence. Why do marriages take place at all and what could be done to wean the people away from the practice? The evil thrives because of.

10. illiteracy and other related causes-the most important of which is the anxiety of parents to marry off their daughters as early as possible. In many states where illiteracy is high, like in Rajasthan, the practice of child marriage is in vogue. Akhha Teej’ is D-day for parents of minor girls, for on that day, they seek their salvation from the anxiety of girls growing up in their midst.

15. A child marriage is less likely to take place if the parents are literate or at least the father is. He is then aware of the legal minimum age and health hazards his daughter will face by an early marriage. If the mother, otherwise literate, has been exposed to the importance of family planning, she is also less likely to solemnize her daughter’s wedding at an age below the legal minimum.

20. Among the other factors causing parents to give away young daughters in marriage is the need felt by families having more than one daughter, to keep wedding expenses down. By marrying two daughters at the same time parents save on expenses. Parental anxiety about grown up (14 years and above) daughters going astray, forces the less educated to give away their female children in marriage.

25. The existing law was amended in 1978 raising the minimum age of marriage for girls from 15 to 18 years and for boys from 18 to 21 years. The committee on the status of women, in its report in 1974, had recommended that all offences under the child marriage restrained Act should be made cognizable and special officers be appointed to enforce the law. The 30. Government however did not pay heed to it while raising the minimum age of marriage. At the same time, there is no foolproof system of registering births and thus, there is no legally enforceable method for establishing the age of a male or female.

Based on your understanding of the passage, answer ANY EIGHT questions from the six given below. (1 x 8)

(A) Cite a point in evidence, from the text, to suggest that it is impossible to eradicate the practice of child marriage in India. (1)

(B) State any one reason other than illiteracy of parents for marrying their daughters early that is evident from lines 20-25. (1)

(C) The writer feels that the offence of child marriage should be made ‘cognizable’. What does he mean by that? (1)

(D) Why does the writer say that there is no foolproof system of registering births? (1)

(E) Rewrite the given sentence by replacing the underlined phrase with another one, from lines 1-5.

She is not taking any action against him as she is under a marriage commitment. (1)

(F) What does the use of the phrase ‘less likely to solemnize marriage’ suggest in the context of a literate mother. 1

(G) Select a suitable phrase from lines 10-20 to complete the following sentence appropriately.

The match is ………… today as the weather is not clear. (1)

(H) How can the situation of child marriages be better in the nation? (1)

(I) Analyse why child marriages are in vogue in rural areas. (1)

Question 2.
Read the passage given below.

(1) Of all the inventions of science, solar rickshaw is perhaps the most useful on the practical side of life. It is not just any rickshaw but an optimally designed, pedal-operated, and motor-assisted three-wheeler. This zero-carbon, urban transport vehicle or ‘pedicab’ was designed and developed by a team of engineers from the Central Mechanical Engineering Research Institute, Durgapur, West Bengal

(2) Like a solar rickshaw, the gorgeous green phone is another wonderful invention of the scientific mind. We all know that mobile phones are must-have these days. In fact, according to statistics, six out of ten people in this world own a cell phone. So, imagine the energy consumed and the e-waste generated by these devices. With this in mind, many handset manufacturers are going green, while some are even going solar.

(3) Samsung, for instance, has unveiled a solar-powered phone- ‘‘Blue Earth”. It is a touch phone that has a full solar panel on its back which can generate enough power to charge the phone. It is made from recycled plastic from water bottles and has a built-in pedometer to keep a tab on your carbon dioxide emissions. It is also small enough to fit into your pocket.

(4) Like solar-powered homes, solar cars harness energy from the sun by converting it into electricity. This electricity fuels the battery that runs the car’s motor. Instead of using a battery, some solar cars direct the power straight to an electric motor. Great examples of the latest solar-powered cars are the University of Michigan solar car, the MIT solar car, and the Berkeley solar car.

(5) Solar cars use photovoltaic cells to convert sunlight into energy. Photovoltaic cells are the components in solar panels that convert the sun’s energy to electricity. They’re made up of semiconductors, usually silicon, that absorb the light. The sun’s energy frees electrons in the semiconductors, creating a flow of electrons. This flow generates electricity that powers the battery and the specialised motor in solar cars.

On the basis of your understanding of the passage, answer ANY SIX questions from the six given below. (1 x 6)

(A) What does the researcher mean by ‘solar rickshaw is perhaps the most useful on the practical side of life’? (1)

(B) What does the table say about the purpose of crediting state and federal taxes for solar industry? (1)

(C) With reference to fig. 1, write a conclusion about India’s participation in regards with other nations in the solar power consumption. (1)

(D) What can be concluded by the ‘rest of the world’ data of solar consumption participation, with reference to fig. 1? (1)

(E) Scientists have started using solar energy for research purposes from a very long time. Substantiate. (1)

(F) Why are ‘solar-powered phones’ recommended as a significant invention in reducing the energy consumption? (1)

(G) Identify a word from lines 1-10 indicating a three-wheeled vehicle with a hooded carriage for transport. (1)

Section – B
Writing (8 Marks)

Question 3.
As the National Sports Winner, you are invited by the neighbouring school to be the Chief Guest for their 12th Annual Sports Day. Draft a formal reply expressing the regret for being unable to attend it. (3)

Question 4.
Attempt ANY ONE from A and B given below.

(A) You have read an advertisement in the newspaper, ‘India Times’ for the post of software engineer in Alex Software, Thane. You believe that you possess the requisite qualifications and experience and your innovative ideas will prove an asset to the company. Write a job application emphasising your strong points and your suitability for the post. Also include your bio-data. You are Navpreet/Navtej, a resident of 12, Mall Road, Thane.
OR
(B) You are Anamika Khanna, a staff reporter for Deccan Herald. Write a report for your newspaper on miscreants hijacking and looting a bus from Lucknow, bound for Agra, via the Agra-Lucknow Express way in about 1(2)0-150 words, covering all the necessary details like deluxe bus looted on expressway, driver noticed road barricading, women compelled to take off jewellery and men costly items, case registered in Agra Police Station, etc. (5)

Section – C
Literature (18 Marks)

Question 5.
Answer ANY FIVE of the six questions given below, with in 40 words each. (2 x 5)

(A) Give one reason as to why the crofter was so talkative and friendly with the peddler. (2)

(B) Gandhi didn’t want any ‘prop’ to help his cause. Expound.
You may begin your answer like this: Gandhiji always believed that one doesn’t need any ‘prop’…………. (2)

(C) What does Aunt Jennifer desire through embroiding the tigers? Explain. (2)

(D) Rationalize what makes human beings love life in spite of troubles and sufferings. (2)

(E) Why did Jo think Roger Skunk was better off with the new smell? (2)

(F) What reason did Evans give to keep his hat on his head? Validate the actual reason. (2)

Question 6.
Answer ANY TWO of the following in about 120 words each. (4 x 2)

(A) A thing of beauty is a joy forever. Support the statement with reference to the poem ‘A Thing of Beauty’. Write your answer in about 120-150 words. (4)

(B) According to Louis Fischer, Gandhiji succeeded in his Champaran campaign. Examine Indigo in the light of this statement, in about 120-150 words. (4)

(C) Jack was Joanne’s father in the story, ‘Should Wizard Hit Mommy?’ Expound on the impression that you have formed of Jack as a father. Substantiate with reference to text, in about 120-150 words. (4)

Students can access the CBSE Sample Papers for Class 12 Applied Mathematics with Solutions and marking scheme Term 2 Set 4 will help students in understanding the difficulty level of the exam.

CBSE Sample Papers for Class 12 Applied Mathematics Term 2 Set 4 with Solutions

Maximum Marks : 40
Time : 2 Hours

Instructions:

• The question paper is divided into 3 sections-A, B and C
• Section A comprises of 6 questions of 2 marks each. Internal choice has been provided in two questions.
• Section B comprises of 4 questions of 3 marks each. Internal choice has been provided in one question.
• Section C comprises of 4 questions. It contains one case study based question. Internal choice has been provided in one question.

Section – A [12 Marks]

Question 1.
The population of a town grows at the rate of 10% per year. Using differential equation, find how long it will take for the population to grows 3 times.
Or
The marginal cost of producing x pairs of tennis shoes is given by MC = 60 + \(\frac{400}{x+1}\).
If the fixed cost is ₹ 3000, find the total cost function.
Answer:
Let P₀ be the population initially and P be the population after t yr,

On integration both sides, we get
log P = \(\frac{1}{10}\) t + C
When t = 0, then P = P₀
∴ log P₀ = C
From Eq. (i), log P = \(\frac{t}{10}\) + log P₀
⇒ \(\log \left(\frac{P}{P_{0}}\right)=\frac{t}{10}\)
When the population grows 3 times i.e. P = 3 P₀, then log\(\left(\frac{3 P_{0}}{P_{0}}\right)\) = \(\frac{t}{10}\) ⇒ t = 10 log 3
Thus, it takes 10 log 3 years for the population to grow 3 times.

Or

C = 60x + 400 log |(x + 1)| + K ………. (i)
If x = 0, C = ₹ 3000
∴ 3000 = 0 + 400 log(1) + K
⇒ K = 3000
∴ C = 60x + 400 log |(x + 1)| + 3000 [from Eq. (i)]

Question 2.
A random sample of 36 workers is drawn from a factory to test, if their average monthly wages is ₹ 1500 or not. The population wages distribution is assumed to be normal with standard deviation of ₹ 300. The average monthly wages based on the 36 observations comes out to be ₹ 1800. Perform a test at 5% level of significance. Calculate test statistics.
Answer:
Consider, H₀ : µ = 1500
H₁ : µ ≠ 1500
x̄ = 1800, µ₀ = 1500,
σ = 300 and n = 36
∴ Test statistics,

Question 3.
Find the present value of perpetuity of ₹ 900 at end of each quarter, if money is worth 6% compounded quarterly.
Or
To what sum will ₹ 16000 accumulate in 8 yr, if invested at an effective rate of 10%. [given (1.08)⁸ = 1.85]
Answer:
Given, R = ₹ 900
i = \(\frac{0.06}{4}\) = 0.015
Present value of perpetuity,
P = \(\frac{R}{i}=\frac{900}{0.015}\) = ₹ 60000
Or
We have, P = ₹ 16000,
i = \(\frac{8}{100}\) = 0.08
∴ S = P(1 + i)ⁿ
S = 16000(1 + 0.08)⁸
= 16000(1.08)⁸
= 16000(1.85) = 29600
Hence, the required sum is ₹ 29600

Question 4.
At what rate of interest will be present value of a perpetuity of ₹ 500 payable at the end of every 6 months be ₹ 10000?
Answer:
Let the rate of interest be r% per annum.
Then, i = \(\frac{r}{200}\)
Given, R = ₹ 500 and P = ₹ 10000
Using P = \(\frac{R}{i}\)
⇒ i = \(\frac{R}{P}\)
⇒ \(\frac{r}{200}=\frac{500}{10000}\) ⇒ r = 10
Hence, rate of interest is 10% per annum.

Question 5.
The corner points of the feasible region determined by the following systems of linear inequalities
2x + y ≤ 10, x + 3y ≤ 15, x ≥ 0 and y ≥ 0 are (0, 0), (5, 0), (3,4) and (0, 5).
Let Z = px + qy, when p, q ≥ 0, then find the relation between p and q so that the maximum of Z occurs at both points (3, 4) and (0, 5).
Answer:
The values of Z = px + qy at the points (3,4) and (0,5) are 3p + 4q and 5q, respectively.
As, Z has maximum value of both points (3, 4) and (0, 5), we get
3p + 4q = 5q ⇒ 3p = q ⇒ 3p – q = 0
which is the required relation between p and q.

Question 6.
The production of a cement by a firm in 1 to 9 is given below.

Calculate the 3-yearly moving average.
Answer:
Calculation of 3-yearly moving average

Section – B [12 Marks]

Question 7.
Consider a hypothetical population comprising only four values 4, 6, 8 and 10. Find point estimation of population variance (σ²). Also, find standard error of sample variance (S²).
Answer:

Question 8.
Calculate the quarterly trend values by method of least square for quarterly data for last 5 yr given below.

Or
Apply the method of least squares to obtain the trend values from the following data.

Year	Sales (in lakh tonnes)
2006	100
2007	120
2008	110
2009	140

Also, predict the sales for the year 2013.
Answer:
Here, n = 5 (odd)
So, middle year i.e. 1966 is taken as origin, we will fit linear trend equation between average quarterly values (y) and time variable x (in year).

The normal equations for fitting linear trend equations.

∴ Linear trend equation is y_t = 112 + 23 x
From Eqs. (i) and (ii), yearly increment in trend value = b = 23
Quarterly increment = \(\frac{23}{4}\) = 5.75
Here, n = 5 (odd)
So, middle year i.e. 2008 is taken as origin.

The equation of the straight line trend is
y_t = a + bx
Since, Σx = 0, a = \(\frac{\Sigma y}{n}\) = \(\frac{550}{5}\) = 110
and b = \(\frac{\Sigma x y}{\Sigma x^{2}}\) = \(\frac{-20}{10}\) = – 2
The required equation is,
y_t = 110 – 2x
For x = – 2,
y_t = 110 – 2(-2) = 114
Thus, for 2007 the trend value will be
114 – 2 = 112.

Question 9.
Surbhi borrowed a home loan amount of ₹ 150000 from a bank at an interest rate of 12% per annum for 3 yr. Find the monthly installment amount. She has to pay to the bank, [given, (1.01)^-36 = 0.698]
Answer:
If principle, P = ₹ 150000
i = \(\frac{12}{1200}\) = 0.01 and n = 12 × 3 =36
Let E be the monthly installment paid by Surbhi,

Question 10.
Supply function of a producer is given by 40 p = (x + 15)². Find the producer’s surplus, when the market price is ₹ 40.
Answer:
Given, the supply function is
40p = (x + 15)²
At p₀ = 40, we get
40 × 40 = (x₀ +15)²
⇒ x₀ + 15 = 40 ⇒ x₀ = 25
∴ Producer’s surplus,

Section-C [16 Marks]

Question 11.
Consider a bond with a coupon rate of 10% and annual coupons. The par value is ₹ 1000 and the bond has 5 yr to maturity. The yield to maturity is 11%. What is the value of the bond? [given, (1.11)^{– 5} = 0.593451]
Answer:
Given, face value of the bond (F) = ₹ 1000
Coupon rate (id) (annual) = 10% = 0.1
∴ R = F × id = 1000 × 0.1 = ₹ 100
Number of periods before redemption (n) = 5
and yield rate (i) = 11% =0.11.
We know that purchase value

= 100(3.6959) + 593.451
= 369.59 + 593.40
= 962.99 ≅ 963
∴ The value of the bond is ₹ 963.

Question 12.
A propeller costs ₹ 180000 and its effective life is estimated to be 10 yr. A sinking fund is created for replacing the propeller by a new model at the end of its lifetime, when its scrap realises a sum of ₹ 34000 only. The price of the new model is estimated to be 30% more than the price of the present one. What amount should be put into the sinking fund at the end of each year, if it accumulates at 4% per annum compound interest? [given, (1.04)¹⁰ = 1.480]
Answer:
According to the question,
The present value of the machine is ₹ 180000.
Since, the price of new model is 30% more than the price of present machine.
∴ Price of new model 130
= \(\frac{130}{100}\) × 180000 = ₹ 234000
Scrap value of the present machine is ₹ 34000.
The net amount (A) to be paid after 10 yr for new model = 234000 – 34000 = ₹ 200000
Let the value of each sinking fund is a.
The rate of interest for 10 yr is
i = \(\frac{4}{100}\)
We know that
A = \(\frac{R}{i}\)[(1 + i)ⁿ – 1] …….. (i)
Now, we put the value of A, i and n in Eq. (i) to get the value of each instalment

Hence, the value of each sinking fund is ₹ 16666.67 to be paid at the end of each year.

Question 13.
There are two types of fertilisers F₁ and F₂, F₁ consists of 10% nitrogen and
6% phosphoric acid and F₂ consists of 5% nitrogen and 10% phosphoric acid. After testing the soil conditions, a farmer finds that she needs atleast 14 kg of nitrogen and 14 kg of phosphoric acid for her crop. If F₁ costs ₹ 6 per kg and F₂ costs ₹ 5 per kg. Determine how much of each type of fertiliser should be used so that nutrient requirements are met at a minimum cost? What is the minimum cost?
Or
Two godowns A and B have a grain storage capacity of 100 quintals and 50 quintals, respectively. They supply it to 3 ration shops D, E and F, whose requirements are 60, 50 and 40 quintals, respectively. The cost of transportation per quintal from godowns to the shops are given in the following table

How should the supplies be transported in order that the transportation cost is minimum?
Answer:
Suppose, the farmer uses x kg of F₁ and y kg of F₂. We have to construct the following table

Total cost of fertilisers,
Z = 6x + 5y
So, our problem is to minimise
Z = 6x + 5 y
Subject to constraints are,
\(\frac{x}{10}+\frac{y}{20}\) ≥ 14
⇒ 2x + y ≥ 280
\(\frac{6 x}{100}+\frac{10 y}{100}\) ≥ 14
⇒ 3x + 5y ≥ 700
and x, y ≥ 0
Table for line 2x + y = 280 is

X	0	140
y	280	0

So, line passes through the points (0, 280) and (140, 0)

On putting (0, 0) in the inequality
2 x + y ≥ 280, we get
2 × 0 + 0 ≥ 280
⇒ 0 ≥ 280, which is not true.
So, the half plane is away from the origin.
Table for line 3x + 5y = 700 is

X	0	700/3
y	140	0

So, line passes through the points (0, 140) and \(\left(\frac{700}{3}, 0\right)\)
On putting (0, 0) in the inequality 3x + 5y ≥ 700,
we get 3 × 0 + 5 × 0 ≥ 700
⇒ 0 ≥ 700, which is not true.
So, the half plane is away from the origin.
Also, x, y ≥ 0, so the region lies in the 1 quadrant.
On solving the equations
2x + y = 280 and 3x + 5y = 700, we get B(100,80).
It can be seen that the feasible region is unbounded.
The corner points of the feasible region are
A\(\left(\frac{700}{3}, 0\right)\), B(100,80)and C(0,280).
The values of Z at the comer points are given below

Corner points	Value of Z = 6x + 5y
A\(\left(\frac{700}{3}, 0\right)\)	Z = 6 × \(\frac{700}{3}\) + 5 × 0 = 1400
B(100, 80)	Z = 6 × 100 + 5 × 80 =1000
C(0,280)	Z = 6 × 0 + 5 × 280 = 1400

As, the feasible region is unbounded, therefore 1000 may or may not be the minimum value of Z. For this, we draw a graph of the inequality 6x + 5y < 1000 and check whether the resulting half plane has points in common with the : feasible region or not.

It can be seen that the feasible region has no common point with 6x + 5y < 1000. Therefore, 100 kg of fertiliser F1 and 80 kg of fertiliser F₂ should be used to minimise the cost and the minimum cost is ₹ 1000.

Or

Let godown A supplies x and y quintals of grain to the shops D and E, respectively.
Then, (100 – x – y) will be supplied to shop F.
The requirement at shop D is 60 quintals, since x quintals are transported from godown A.
Therefore, the remaining (60 – x) quintals are transported from godown B. Similarly, (50 – y) quintals and 40 – (100 – x – y) = (x + y – 60) quintals will be transported from godown B to shops E and F, respectively. The given problem can be represented diagrammatically as follows

Let Z be the total cost of transportation, then
Z = 6x + 3y + 2.50 (100 – x – y) + 4 (60 – x) + 2 (50 – y) + 3 [(x + y) – 60]
= 6x + 3y + 250 – 2.50x – 2.50y + 240 – 4x + 100 – 2 y + 3x + 3 y – 180
= 2.50 x + 1.50y + 410 …(i)
Subject to constraints,
60 – x ≥ 0
or x ≤ 60 …(ii)
50 – y ≥ 0
or y ≤ 50 …(iii)
100 – (x + y) ≥ 0
or x + y ≤ 100 …(iv)
x + y – 6 ≥ 0
or x + y ≥ 60 …(v)
and x, y ≥ 0 …(Vi)
Table for line x + y = 100 is

x	100	0
y	0	100

So, line passes through the points (100, 0) and (0, 100).
On putting (0, 0) in the inequality x + y ≤ 100, we get
0 + 0 ≤ 100 ⇒ 0 ≤ 100, which is hue.
So, the half plane is towards the origin.
Table for line x + y = 60 is

X	0	60
y	60	0

So, line passes through the points (0, 60) and (60, 0).
On putting (0, 0) in the inequality x + y ≥ 60, we get
0 + 0 ≥ 60 ⇒ 0 ≥ 60, which is not hue.
So, the half plane is away from the origin.
Now, draw the graph of lines x = 60 and y = 50, which is perpendicular to X and Y-axes, respectively.
Clearly, the half planes x ≤ 60 and y ≤ 50 is towards Y and X-axes, respectively.
Also, x, y ≥ 0, so the region lies in the I quadrant.
The points of intersection of lines corresponding to Eqs. (ii), (iii), (iv) and (v) are
A(60, 0), B (60, 40), C (50, 50) and D (10, 50).
The graphical representation of these lines is given below

The shaded region in the graph represents the feasible region and its comer points are
A (60,0), B (60,40), C (50,50) and D (10,50).
The values of Z at the comer points are given below

Corner points	Value of Z =2.5x+1.5y + 410
A (60, 0)	Z =2.5(60)+ 1.5(0)+ 410 = 560
B (60, 40)	Z = 2.5(60) + 1.5 (40) + 410 = 620
C(50, 50)	Z = 2.5(50) + 15(50)+ 410 = 610
D (10, 50)	Z = 2.5(10)+ 1.5 (50)+ 410 = 510 (Minimum)

The minimum value of Z is 510 at D (10,50).
Thus, the amount of grain transported from A to D, E and F is 10 quintals, 50 quintals and 40 quintals, respectively and from B to D, E and F is 50 quintals, 0 quintal and 0 quintal, respectively.
The minimum cost is ₹ 510.

Case Based/Data Based

Question 14.
Following paragraph given to student by the teacher.
The given integral ∫ f(x)dx can be transformed into another form by changing the independent variable x to t by substituting x = g(t).
Consider, I = ∫ f(x) dx
On putting x = g(t), so that \(\frac{d x}{d t}\) = g'(t)
We write, dx = g'(t)dt
Thus, I = ∫ f(x)dx = ∫ f(g(t))g'(t)dt
This change of variable formula is one of the important tools available to us in the name of integration by substitution.
On the basis of above information, answer the following questions.
(i) Evaluate \(\int-\frac{d x}{x^{2}-16}\).
Answer:

(ii) Evaluate \(\int \frac{x}{\sqrt{32-x^{2}}}\) dx.
Answer:
Let I = \(\int \frac{x}{\sqrt{32-x^{2}}}\) dx.
On putting
32 – x² = t
⇒ – 2xdx = dt
⇒ x dx = \(\frac{-1}{2}\) dt
Now,

Students can access the CBSE Sample Papers for Class 12 English with Solutions and marking scheme Term 2 Set 11 will help students in understanding the difficulty level of the exam.

CBSE Sample Papers for Class 12 English Term 2 Set 11 for Practice

Time Allowed: 2 Hours
Maximum Marks: 40

General Instructions:

• The Question Paper contains THREE sections-READING, WRITING and LITERATURE.
• Attempt questions based on specific instructions for each part.

Section – A
Reading (14 Marks)

Question 1.
Read the passage given below.

Every time a child takes a soft drink, he’s laying the ground work for a dangerous bone disease. No, fizzy and sugary drinks don’t cause osteoporosis. But, because they are often a substitute for a glass of milk, kids are not getting the calcium and vitamin D they need to build a strong skeleton. Many of them.

5. also lead a sedentary lifestyle, so they aren’t getting the bone-building benefits from vigorous exercise either. These children tend to suffer from brittle bones and tend to suffer from fractures later on in life. They could be at a risk of being diagnosed with osteoporosis at an early age.

10. The Indian Society for Bone and Mineral Research, a body of osteoporosis experts is trying to spread awareness about this bone crippling disease. Osteoporosis starts in childhood but has consequences later in life. The condition causes bones to become riddled with holes, like the framework of a house that’s been attacked by termites. That can lead to broken bones, which in turn can cause deformity, chronic pain or disability.

15. Osteoporosis can be fatal: up to 25 percent of older people who suffer a broken hip die within a year. Osteoporosis isn’t just your grandmother’s health threat. Although it strikes over 50 million women in India, it also menaces over 12 million men. Osteoporosis causes loss of height, pain in joints and back, fractures and a fear of fractures, and can be very depressing. So, it is important that we.

20. adopt preventive measures, to save millions of people.

There is a new medical understanding of the best ways to protect ourselves and our children. “Simple lifestyle changes and nutrition will help save your bones,” says Dr Mittal. To get us moving in the right direction, 25. he says, “It’s never too late to adopt bone-friendly habits-exercise, get enough sunlight, and have adequate calcium in your diet.

Based on your understanding of the passage, answer ANY EIGHT questions from the six given below. (1 x 8)

(A) Cite a point in evidence, from the text, to suggest that fizzy and sugary drinks indirectly cause osteoporosis? (1)

(B) State any one reason for weak bones that is evident from lines 1-10 other than the deficiency of nutrients. (1)

(C) The writer calls osteoporosis ‘fatal’. Why does he call it ‘fatal’? (1)

(D) Why Indian society for Bone and Mineral Research is spreading awareness about this bone crippling disease? (1)

(E) Rewrite the given sentence by replacing the underlined phrase with another one, from the lines 17-27.

Looking at the current COVID cases, it is very important for families to have precautionary policies. (1)

(F) What does the use of the phrase ‘brittle bones’ suggest in the context of children? (1)

(G) Select a suitable phrase from lines 15-25 to complete the following sentence appropriately.

Online classes …………. for children who are weak in academics. (1)

(H) In what ways does osteoporosis affects us? (1)

(I) Analyse the ways to protect the bones in children. (1)

Question 2.
Read the passage given below.
The passenger pigeon (Ectopistesmigratorius) was once found in huge numbers in North America. Records tell of passing flocks that darkened the skies for several dags at a time. The species may have peaked at five billion individuals. A more conservative estimate is three billion. Within a short time, the species disappeared completely.

5. “Given the huge size of the population, it’s simply amazing that the species disappeared so quickly,” says Tom Gilbert. Gilbert is a professor at the University of Copenhagen’s Centre for GeoGenetics, but he also has a part-time position as an adjunct professor at the Norwegian University of Science and Technology (NTNU).

The history of the passenger pigeon is interesting, partly because it can tell us something about how and why species become extinct. Native Americans also relied on passenger pigeons for food. But at least.

10. in parts of the passenger pigeons’ range, people had learned to harvest the species at a sustainable level that didn’t threaten to eradicate it. It was common in some parts of North America to only eat young pigeons that were hunted at night, since this did not seem to scare away the adult birds or prevent them from re-nesting.

But starting around 1500’s, a more aggressive variant of humans came to the continent.

15. with the arrival of Europeans. The hunt for passenger pigeons grew and culminated in a massive hunt for the species throughout the 1800s, before the species finally collapsed and disappeared. In 2014, a study published in the scientific journal PNAS, strongly suggested that humans were simply the final straw in destroying a species that was already vulnerable and headed to oblivion.

The cladogram below follows the 2012 DNA study showing the position of the passenger pigeon among its closest relatives:

The researchers asserted that despite their enormous numbers, the passenger pigeons.

20. were already in trouble. The population of the species varied greatly, similar to lemmings, but over a longer period of time. When the Europeans arrived, the species was already in a strong decline. The population was plummeting long before Europeans arrived, and perhaps Europeans even contributed to a short-term increase in numbers.

Studies of the genetic variation of the species using an investigative method called PSMC.

25. formed the background for these assertions. And now we have to concentrate a bit. The PSMC method can use the information in the genes of a single individual of a species to map the history of the species.

You should therefore be able to see how the species developed over many generations, and estimate how many individuals there were at any given time, all based on a single genome. Using this method, researchers found that the number of passenger pigeons was in free fall even before the arrival of the Europeans.

30. Although the species might not have become extinct, it would have shrunk significantly in any case, maybe to only a few hundred thousand individuals.

On the basis of your understanding of the passage, answer ANY SIX questions from the six given below. (1 x 6)

(A) What does the researcher mean by ‘Records tell of passing flocks that darkened the skies for several days at a time.’? (1)

(B) What is surprising about Tom Gilbert’s study regarding passenger pigeons? (1)

(C) With reference to fig. 1, write one species that was famous among Old World pigeons. (1)

(D) What can be concluded by the phrase “the population was plummeting tong before Europeans arrived”? (1)

(E) The arrival of Europeans was not the reason for extinction of passenger pigeons Substantiate. (1)

(F) What was the reason behind the species of passenger pigeons finaLly collapsing and disappearing? (1)

(G) Identify a word from the Lines 20-25 indicating a fall or drop at a high speed. (1)

Section – B
Writing (8 Marks)

Question 3.
Your father, Mr Rizwan Ahmed, residing at 21/22, Kamla Nagar, Agra, wants to celebrate the success of your brother Ayan’s clearing the Harvard Entrance Examination and getting admission into the university. Help him by drafting a formal invitation for the party he wants to throw for his son. (3)

Question 4.
Attempt ANY ONE from A and B given below.

(A) You are Amit/Amita of 1/23, Lawyer’s Colony, Agra. You have seen an advertisement in The Times of India for the post of Head Chef in a 3-Star Hotel. Apply for the job to the HR dept, with your complete bio-data. Invent necessary details.
OR
(B) You are Rasheed/Rashida Ahmed, of Delhi PubLic School, Gwatior. As a Fancy Show was held on the Children’s Doy in your school on 14th November, this year, write a report in about 120-150 words on ‘The Fancy Dress Show’ for your school magazine, covering aLL the necessary detaiLs like different themes for Senior and Junior Sections, students dressed up different, winners prized with trophies, runner-ups given ConsoLation prizes, etc. (5)

Section – C
Literature (18 Marks)

Question 5.
Answer ANY FIVE of the six questions given below, within 40 words each. (2 x 5)

(A) How was Gandhiji able to influence the lawyers at Champaran? (2)

(B) Edla was elated on seeing the gift left for her by the peddler. Comment.

You may begin your answer like this:
Edla was extremely happy to see the gift of a rattrap along with a letter. (2)

(C) According to Keats, what spreads the pall of despondence over our dark spirits? How is it removed? Explain. (2)

(D) Give an example which could be used to say that Aunt Jennifer had a mental truma by her husband. (2)

(E) Based on your reading of the chapter ‘Should Wizard hit Mommy?’, how does Jo respond to her father’s storytelling? (2)

(F) Validate what peculiar things does Derry notice about the old man? (2)

Question 6.
Answer ANY TWO of the following in about 120 – 150 words each. (4 x 2)

(A) Do you think the poet in the poem ‘Aunt Jennifer’s Tigers’ tries to convey a message about ‘Feminism’? Write your answer in about 120-150 words. (4)

(B) The ironmaster lacked sympathy and love that his daughter Edla had. Examine the character of the ironmaster with that of his daughter, Edla in the light of this statement, in about 120-150 words. (4)

(C) The question paper and correction slip had a crucial role to play in catching Evans in the chapter ‘Evans Tries an O-Level’. Substantiate with reference to text, in about 120-150 words. (4)

Students can access the CBSE Sample Papers for Class 12 Accountancy with Solutions and marking scheme Term 2 Set 3 will help students in understanding the difficulty level of the exam.

CBSE Sample Papers for Class 12 Accountancy Standard Term 2 Set 3 with Solutions

Time Allowed: 2 Hours
Maximum Marks: 40

General Instructions:

• This question paper comprises two Parts – A and B. There are 12 questions in the question paper. Alt1 questions are compulsory.
• Part-A is compulsory for all candidates.
• Part-B has two options i.e., (i) Analysis of Financial Statements and (ii) Computerized Accounting. Students must attempt only one. of the given options.
• There is no overall choice. However, an internal choice has been provided in 3 questions of three marks and 1 question of five marks.

PART-A
(Accounting for Not-for-Profit Organisations, Partnership Firms, and Companies)

Question 1.
Calculate the amount to be posted to the Income and Expenditure Account for the year ended 31st March 2021 from the information given:
Stock of Stationery on 1st April 2020 – ₹ 3,000
Creditors for Stationery on 1st April 2020 – ₹ 2,000
Amount paid for Stationery during the year – ₹ 10,800
Stock of Stationery on 31st March 2021 – ₹ 500. (2)
Answer:

Question 2.
Pass the necessary journal entries for the following transactions on the dissolution of a partnership firm:
(A) Saran, a partner is paid remuneration of ₹ 40,000 for the dissolution of the firm. Realization expenses of ₹ 64,000 are borne by the firm.
(B) Sanam one of the partners was to receive 2% of the value of assets realized as remuneration for completing the dissolution work and was to bear realization expenses. Realization expenses were ₹ 8,000 paid by Sanam. The assets including cash at Bank ₹ 24,000, realized ₹ 12, 24,000. (2)
Answer:

Question 3.
A, B and C are partners in a firm sharing profit in 3: 2 :1. The firm closes its book on 31st March every year. B died on 12th June 2020. On B’s death, the goodwill of the firm was valued at ₹ 2,40,000. B’s share in the profits of the firm till the date of death from the last Balance Sheet was to be calculated on the basis of previous year’s profit which was ₹ 6,00,000.
Fill in the missing figures in the following journal entries.
(2)
Answer:

Working Notes:
B’s share of profit will his date of death
= ₹ 6,00,000 x \(\frac{73}{365} \times \frac{2}{6}\)
= 40,000

Question 4.
Distinguish between Receipts and Payments Account and Income and Expenditure Account on the basis of:
(A) Nature
(B) Period
(C) Nature of Items
OR
From the information given below, prepare Receipts and Payments Account of Harnaam Club for the year ending on 31st March 2021:

Particulars	Amount (₹)
Cash & Bank as on 1st April, 2020	45,000
Subscriptions (including ₹ 8,000 for 2019-20 and ₹ 12,000 for 2021-22)	4,70,000
12% Investments purchased on 1st April, 2020	1,50,000
Entrance Fee Received	15,000
Sports Materials Purchased	70,000
Furniture purchased	80,000
Sale of Old Furniture (Cost ₹20,000)	5,000
Municipal Taxes	1,000
Printing and Stationery	24,000
Sale of Old Sports Materials	6,000
General Expenses (out of which ₹ 2,000 is yet to be paid)	20,000
Interest Received on Investments	6,000
Tournament Expenses	72,000
Salary paid	84,000
Postage and Courier	2,000

(3)
Answer:
Difference between Receipts and Payments Account and Income and Expenditure Account:

Basis of Difference	Receipts and Payments Account	Income and Expenditure Account
(A) Nature	It is classified summary of cash transactions showing receipts and payments under different heads for the period.	It is Like a Profit and Loss Account
(B) Period	It shows receipts and payments during the year whether they relate to past, current or succeeding year.	It shows incomes and expenditures of the current year only.
(C) Nature of Items	Debit side of this account records receipts and credit side records payments.	Debit side of this account records expenses and Losses and credit side records incomes and gains.

Question 5.
Alia, Kiara, and Sonam are partners is Sunrise Limited sharing profit and losses is the ratio of \(\frac{4}{9}: \frac{1}{3}: \frac{2}{9} \) On 1st April 2021 Kiara gave a notice to retire from the firm. Alia and Sonam decided to share the future profits equally.

The capital accounts of Alia and Sonam after all adjustment showed a balance of ₹ 86,000 and ₹ 1,61,000 respectively. The total amount to be paid to Kiara was ₹ 19,10,000. This amount was to be paid by Alia and Sonam is such a way that their capitals become proportionate to their new profit sharing ratio. Pass the necessary journal entries in the books of Sunrise Limited for the above transactions. Show your working clearly. (3)
Answer:


Working Note:
(1) CalcuLation of total capitaL of new firm:
₹
Adjusted Capital of Alia 8,60,000
Act Adjusted Capital of Sonam 16,10,000
Amount to be paid to Kiaro 19,10,000
Total Capital of New Firm 43,80,000

(2) Calculation of Cash to be brought in or Withdrawn by Alio and Sonam:

Particulars	Alla (₹)	Sonam (₹)
New capital of ALio and Sonam ( ₹ 43.80,000 in new ratio, i.e., 1: 1)	21,90.000	21,90,000
Less Existing capital of Alia and Sonam	8,60,000	16,10,000
Cash to be brought in	13,30,000	5,80,000

Question 6.
On 1st April 2021, Jasmine Limited issued 10,000, 8% Debentures of ₹ 100 each at a discount of 5% redeemable at a premium of 15% at the end of five years. All the debentures were subscribed and allotment was made. The company had balance in Securities Premium Reserve of ₹ 80,000.
OR
Malvika Limited purchased furniture worth ₹ 6,60,000 from Sunaina Limited and paid to Suniana Limited as follows:
(i) 50% of the amount by accepting a bill of exchange payable after one month.
(ii) Balance by issuing 8% debentures of ₹ 100 each at a premium of 10%.
Pass necessary journal entries in the books of Malvika Limited for the purchase of furniture and making payment to Sunaina Limited. (3)
Answer:

Working Note:
Purchase consideration = ₹ 6,60,000
Amount paid by Bilis Payable = 50% of ₹ 6,60,000
= ₹ 3,30,000
Amount paid by issuing debentures = ₹ 6,60,000 – ₹ 3,30,000
= ₹ 3,30,000
Number of debenture issued = \(\frac{\text { Amount paid by Issuing Debentures }}{\text { Issue Price per Debenture }} \)
= \(\frac{₹ 3,30000}{(₹ 100+₹ 10)} \)
= \(\frac{₹ 3,30000}{₹ 110}\)
= 3,000

Question 7.
X, Y, and Z decided to dissolve their partnership firm on 31st March 2021. Their profit sharing ratio was 3:2:1 and their Balance Sheet was as under:

It is agreed as follows:
(i) The stock of value of ₹ 41,660 are taken over by X for ₹ 35,000 and he agreed to discharge bank loan.
(ii) The remaining stock was sold at ₹ 14,000.
(iii) Debtors amounting to ₹ 10,000 realised ₹ 8,000. The remaining debtors realized 50% at their book value.
(iv) Land is sold for ₹ 1,10,000.
(v) The cost of realization amounted to ₹ 1,200.
(vi) There was a typewriter not recorded in the book’s worth of ₹ 6,000 which was taken over by one of the Creditors at this value.
Prepare Realisation Account, Partners’ Capital Accounts, and Cash Account to close the books of the firm.
OR
Kanika, Disha, and Kabir were partners in a partnership firm sharing profits and losses in the ratio
of 2 :1: 1. On 31st March 2019, their Balance Sheet was as under:
Balance Sheet
as at 31st March 2019

Kanika retired on 1st April 2019. For this purpose, the following adjustments were agreed upon:
(i) Goodwill of the firm was valued at 2 years’ purchase of average profits of three completed years preceding the date of retirement. The profits for the year were:
2016- 17 ₹ 1,00,000
2017- 18 ₹ 1,30,000
(ii) Fixed Assets were to be increased to ₹ 3,00,000.
(iii) Stock was to be valued at 120%.
(iv) The amount payable to Kanika was transferred to her Loan Account.
You are required to prepare a Revaluation Account, Capital Accounts of the partners, and the Balance Sheet of the reconstituted firm. (5)
Answer:





Working Note:
Calculation of Goodwill:
Goodwill = Average Profits x Number of Years’ Purchase
Average Profits = \(\frac{\text { Total Profits }}{\text { Number of Years }}\)
= \(\frac{₹ 1,00,000+₹ 1,30,000- ₹ 20,000}{3}\)
= \(\frac{₹ 2,10,000}{3}\)
= ₹ 70,000

Goodwill of the Firm = 70,000 x 2 = 1,40,000
Kanika’s share of Goodwill = 1,40,000 x \(\frac{2}{4}\) = ₹ 70,000
which will be borne by gaining partners in their gaining ratio
Disho will compensate = 70,000 x \(\frac{1}{2}\) = ₹ 35,000
Kabir wilt compensate = 70,000 x \(\frac{1}{2}\) = ₹ 35,000
Note: Since no information is given about the share of the gain, it is assumed that the old partners are gaining in their old profit sharing ratio.

Question 8.
Swadeshi Bites Limited, a FMCG company appointed Mr. Abhimanyu Roy as the Marketing IHead of the company, with a target to enter the international market. Mr. Abhimanyu Roy discussed the ways and means to achieve target of the company with his marketing team.

After reviewing the suggestions given by all the marketing team members and consultation with Finance Head an additional fund of ₹ 2,62,50,000 is required to penetrate their roots in the international market.
After all discussions, on 1st April 2021, the board of directors of Swadeshi Bites Limited decided to issue 9% Debentures of ₹ 1,000 each to the public at a premium of 5%, redeemable after 5 years at a premium of 10% to raise the additional fund.

You are required to answer the following question:
(A) Calculate the number of debentures to be issued to raise additional funds.
(B) Pass journal entry to be passed at the time of allotment of debentures.
(C) Pass journal entry to write off loss on issue of debentures.
(D) Prepare Loss on Issue of Debentures Account.
(E) Calculate the amount of annual fixed obligation associated with debentures. (5)
Answer:
(A) Additional. Funds Raised = 2,62,50,000
Number of Debentures Issued to raise Additional Funds = \(\frac{\text { Additional Funds Raised }}{\text { Issue Price }} \)
= \(\frac{₹ 2,62,50,000}{₹(1,000+50)}\)
= 25,000.


(E) Interest on 9% Debentures = ₹ 2,50,00,000 x\(\frac{9}{100}\) =₹ 22,50,000

Question 9.
From the following Receipts and Payments Account of Harvinder Social Club and the information supplied, prepare Income and Expenditure Account for the year ended 31st March 2020 and Balance Sheet as at that date:
Receipts and Payments Account

Additional Information:
(i) The club has 500 members each paying an annual subscription of ₹ 1,000. Subscriptions Outstanding on 31st March 2019 were ₹ 1,20,000.
(ii) On 31st March 2020, Salaries Outstanding amounted to ₹ 40,000. Salaries paid in the year ended 31st March 2020 included ₹ 1,20,000 for the year ended 31st March 2019.
(iii) On 1st April, 2019, the club owned Land & Building valued at ₹ 40,00,000; Furniture ₹ 4,00,000 and Books ₹ 4,00,000.
(iv) Provide depreciation on Furniture at 10%. (5)
Answer:

PART-B
Option-1
(Analysis of Financial Statements)

Question 10.
State which of the following transactions will result in inflow, outflow or no flow of Cash and Cash Equivalents:
(A) Sale of Marketable Securities for cash at par.
(B) Declaration of Final Dividend ₹ 50,000. (3)
Answer:
(A) Sale of Marketable Securities for cash at par will result in no flow of Cash and Cash Equivalents.
(B) Declaration of Final Dividend ₹ 50,000 wilt result in no flow of Cash and Cash Equivalents.

Question 11.
From the following information provided of Star Ltd., for the year ended 31st March 2020 and
Following is the Balance Sheet of Sumona Trading Limited as at 31st March 2019 and 2020:

Particulars	2020-21	2019-20
Revenue from Operations	₹ 50,00,000	₹ 40,00,000
Employee Benefit Expenses	₹ 20,00,000	₹ 14,00,000
Other Expenses	₹ 4,00,000	₹ 6,00,000
Tax Rate	40%	40%

OR
Following is the Balance Sheet of Surnona Trading Limited os oct 31 March 2019 and 2020:

You are required to prepare Comparative Balance Sheet of Sumona Trading Limited as at 31st March 2019 and 2020. (3)
Answer:

Question 12.
From the following Balance Sheet of Samta Ltd., as at 31st March 2021, prepare Cash Flow Statement for the year ended 31st March 2021:


Additional Information:
(i) During the year a piece of machinery costing ₹ 60,000 on which depreciation charged was ₹ 20,000 was sold at 50% of its book value.
Depreciation provided on tangible assets ₹ 60,000.
(ii) Income tax of ₹ 45,000 was provided.
(iii) Additional Debentures were issued at par on 1st October 2020 and Bank Loan was repaid on the same date.
(iv) At the end of the year, Preference Shares were redeemed at a premium of 5%. (5)
Answer:

(3) CaLcuLation of Interest on Debentures
Interest on Debentures = On ₹ 1,50000 @ 8% for 12 months + On ₹ (2.60,000 – 1,50,000) @ 8% for 6 months
= \(\left(₹ 1,50,000 \times \frac{8}{100}\right)+\left(₹ 1,10,000 \times \frac{8}{100} \times \frac{6}{12}\right)\)
= ₹ 12.000 + ₹ 4,400
= ₹ 16,400.

(4) Calculation of Interest on Bank Loan:
Interest on Bank Loan = On ₹ 50,000 @ 8% for 6 months + On ₹ 40,000 @ 8% for 6 months
= \(\left(₹ 50,000 \times \frac{8}{100} \times \frac{6}{12}\right)+\left(₹ 40,000 \times \frac{8}{100} \times \frac{6}{12}\right)\)
= ₹ 2,000 + ₹ 1,600
= ₹ 3,600

Students can access the CBSE Sample Papers for Class 12 English with Solutions and marking scheme Term 2 Set 10 will help students in understanding the difficulty level of the exam.

CBSE Sample Papers for Class 12 English Term 2 Set 10 for Practice

Time Allowed: 2 Hours
Maximum Marks: 40

General Instructions:

• The Question Paper contains THREE sections-READING, WRITING and LITERATURE.
• Attempt questions based on specific instructions for each part.

Section – A
Reading (14 Marks)

Question 1.
Read the passage given below:

‘Birds of a feather flock together is an old maxim. The teenagers too behave in a similar fashion and are hence more influenced by their peers than by elders. This is quite natural, for the teenager’s mind is impressionable and is influenced by their peers in school or college. So great is this influence that there is a perceptible change

5. in their behaviour and personality as soon as they enter college. The teenagers try to emulate their peers in the dress they wear, their hairstyle, clothes, language and behaviour so much that their personality gets completely transformed.

This happens because they directly relate with them, being in the same age group and class. Quite often, they idolize their peers and have them as their role models.

10. The same is not the case with the adults, whom they perceive as old fashioned and irrelevant. This is on account of the ever-increasing generation gap, which exists between today’s youth and elders.

The teenagers spend most of their time with their peer group and then with adults. It is therefore quite natural for them to imbibe the values, culture and the behaviour of the group. They often succumb to peer pressure and do things that they would.

15. not normally do like smoking, abusing, etc. Some under the influence of peer pressure improve their academic performance, or sporting skills, while others take to drugs and crime. For the momentary thrill and adventure it entails.

The influence of peers is also greater because they feel more comfortable and reassuring in their company. This is contrary to the awkwardness they feel, when.

20. interacting with adults, whom they perceive as old and stern. Shrewd market men exploit this behavioural characteristic to promote the sale of products targeted for them. Thus, we find products like motorcycles, dresses, cosmetics and even lifestyle products being endorsed by peers. They soon become a craze with the teenagers. This in itself is ample proof of the profound influence of the peers on the.

25. teenagers. This influence will increase, with increasing materialistic values permeating the society. It is because of this, parents ensure that they have the right peers in school and college, so that they do not get distracted in their life.

Based on your understanding of the passage, answer ANY EIGHT questions from the nine given below. (1 x 8)

(A) Cite a point in evidence, from the text, to suggest that the teenagers’ minds are impressionable. (1)

(B) State any one trait of the ‘market men’ that is evident from lines 18-26.

(C) Parents want to be sure that their teenagers have good peers. Why do they want so? (1)

(D) Why does the writer say that teenagers succumb to peer pressure? (1)

(E) Rewrite the given sentence by replacing the underlined phrase with another one, from lines 20 – 25.

Teenagers should understand hat doing drugs is just a temporary excitement but an everlasting damage to the body and mind. (1)

(F) What does the use of the phrase ‘Birds of a feather flock together’ suggest in the context of teenagers? (1)

(G) Select a suitable phrase from lines 21-28 to complete the following sentence appropriately.

Pop stars have a ………….. in the young generation. (1)

(H) Teenagers imitate their peers a lot. In what ways do they copy them? (1)

(I) Analyse how can parents control the changes in the behavior of their teenagers under peer pressure. (1)

Question 2.
Read the passage given below:

India’s Labour market is the second-largest in the world, after China, with a working-age population of about 520 miLLion people. In 10 gears, it is expected to be the world’s largest as China’s population aged 15 to 64 drops from 20.5 to 18.3 per cent.

5. While this positive demographic growth should be advantageous for business, only a small portion of India’s working age population is actually engaged in the formal workforce. The primary reason being that barely one in four women are part of the country’s workforce. Today, industry estimates show that women in India only make up five to six per cent of directorships at most listed companies; this after amendments to the Companies Act mandated at least one woman on company boards.

10. These figures underline the highly distorted nature of India’s labour market where women hold 45 per cent of university degrees but are either denied employment opportunities or experience much slower career growth trajectories due to gender-based discrimination.

India has the lowest female labour force participation rate in its neighbourhood.

15. The overall rate of female labour force participation declined as the Indian economy opened up, urbanised, and diversified with the growth of new industries, unlike most other regions in the world. In fact, rapid growth experienced by the US and China in the past century illustrates how improving the gender balance in the workforce contributes to a nation’s economic growth. Female labour force participation is 56 per cent in the US and 64 per cent in China.

20. The above correlation is also strengthened by a 2017 IMF study, which states that increasing the female labour force participation will grow India’s GDP by an estimated 27 per cent. Contrast this with the projections made by the government’s big idea reforms ‘Make in India’ and ‘Digital India’, which aim to boost India’s growth by 16 per cent and 5 per cent, respectively.

25. Yet, GDP goals aside, the gender imbalance in India’s workforce stunts future prospects for inclusive growth in the country. It deprives women and girls from role models in the workplace, reduces their motivation to study further, and perpetuates unhealthy socio-cultural attitudes. Leaving out one half of the population from its workforce will also prolong India’s status as a developing country.

Based on your understanding of the passage, answer ANY SIX out of the seven questions given below. (1 x 6)

(A) What does the researcher mean by ‘barely one in four women are part of the country’s workforce? (1)

(B) Why was this survey on ‘Female Workforce Participation Rate’ under-taken? (1)

(C) With reference to the given table, write one conclusion about Indian female participation in workforce. (1)

(D) What can be concluded by Nepal’s data of women participation in workforce, with reference to the given information? (1)

(E) There is an unhealthy socio-cultural Attitude in india. Substantiate.

(F) What does the researcher mean by ‘distorted nature’ in Indian labour market? (1)

(G) Identify a word from the lines 9-18 indicating the structure of population. (1)

Section – B
Writing (8 Marks)

Question 3.
Draft an informal invitation to invite your family and friends on the occasion of marriage of your elder sister. Prepare the invite card giving necessary details in not more than 50 words. (3)

Question 4.
Attempt ANY ONE from A and B given below.

(A) Write a job application letter in 120-150 words for the post of receptionist advertised in a national newspaper by Aparna Communications, 21 Meera Road, Mumbai. You are Smita Iyer, a resident of 102, Rose villa Apt., Andheri (E), Mumbai.

OR

(B) You are Harish/Harsha Chandwani, Sports Secretary, DAV International. Last week, an inter-school cricket match was played on your school ground. Write a report in about 120-150 words on the match to be given in the school magazine, covering all the essential details like a three-day match, thrilling final match, winner decided on last ball, nail-biting match, etc. (5)

Section – C
Literature (18 Marks)

Question 5.
Answer ANY FIVE of the six questions given below, with in 40 words each. (2 x 5)

(A) Why did the peddler not tell the ironmaster that he was not Nib Olof, his comrade? (2)

(B) Rojkumar ShukLa was resolute. Justify the given statement.

You may begin your answer like this:
Rajkumar Shukla wanted to take Gandhiji aLong with him to Champaran ………. (2)

(C) What are the ‘ordeals’ Aunt Jennifer is surrounded by, why is it significant that the poet uses the word ‘ringed’? Explain. (2)

(D) BriefLy convey the message of the poem, ‘A Thing of Beauty’. (2)

(E) What were the contents of the small brown suitcase that McLeery carried? (2)

(F) As told by Mr Lamb, why did a man lock himself up in his room and what happened to him? Validate. (2)

Question 6.
Answer ANY TWO of the following in about 120 words each. (4 x 2)

(A) According to Keats, men’s evil ways of life has made his life full of miseries and dilemmas. Comment. (4)

(B) The Champaran episode is considered to be the beginning of the Indian struggle for independence. Explain the chapter ‘Indigo’ in the light of this statement. (4)

(C) Mr Lamb was a person who appreciated nature and its bounties. Do you agree? Substantiate with reference to text. (4)